CH3-CHCl-CH2-CH2-CH2CHCl-CH3 +concentrated KCN

Answer:

Explanation:

a. change of colour:

A chemical reaction rearranges the constituent atoms of the reactants to create different substances as products. The products have different molecular structures than the reactants. Different atoms and molecules radiate different colours of light. Hence, there usually is a change in colour during a chemical reaction.

Eg: copper reactions with the elements

b. Evolution of gas:

A gas evolution reaction is a chemical reaction in which one of the end products is a gas such as oxygen or carbon dioxide.

Eg: ammonium hydroxide breaks down to water and ammonia gas.

c. Change of smell :

Production of an Odor Some chemical changes produce new smells.  ... The formation of gas bubbles is another indicator that a chemical change may have occured.

Eg: The chemical change that occurs when an egg is rotting produces the smell of sulfur.

d. Change of state:

A chemical reaction is a process in which one or more substances, also called reactants, are converted to one or more different substances, known as products.

Eg: candle wax (solid) melts initially to produce molten wax (liquid)

plz mark as brainliest!!!!

Answer:

The main component of natural gas is methane (CH4) at 60 to 90% followed by various combination of ethane, propane, and butane whose percentage can vary from 0 to 20% each. For each unit mass of alkanes, the combustion energy (energy released when the fuel reacts with oxygen) released is very high about 13 to 15 kcal/g, which is higher than even those generated by petrol or diesel. So, for heating or other energy generation purpose for household purposes, this source of energy is used.

The equation for combustion of methane is shown below. Upon combustion, carbondioxide and water is produced with simultaneous generation of heat which is the source of energy used for consumption.

CH4 + 2O2 --> CO2+ 2H2O + heat [ For methane, the combustion energy is ~ 6kcal/g]

As the CH2 units are increased in the alkanes, the combustion energy increases, for e.g., ethane has combustion energy of 7 kcal/g and propane has about 12 kcal/g.

Explanation:

Answer:

3 RbOH + H₃PO₄ → Rb₃PO₄ + 3 H₂O

Explanation:

Let's consider the double-replacement reaction between rubidium hydroxide and phosphoric acid to form rubidium phosphate and water. The cation rubidium replaces the cation hydrogen and the anion hydroxyl replaces the anion phosphate. The balanced chemical reaction is:

3 RbOH + H₃PO₄ → Rb₃PO₄ + 3 H₂O

Answer:

Explanation:

Volume of silver cube = 2.42³ = 14.17 cm³

mass of silver cube = volume x density

= 14.17 x 10.49 = 148.64 gm

Volume of gold cube = 2.75³ = 20.8  cm³

mass of gold cube =  20.8 x 19.3 = 401.44 gm

specific heat of silver and gold are .24 and .129 J /g°C

mass of 112 mL water = 112 g

Heat absorbed = heat lost = mass x specific heat x temperature fall or rise

Heat lost by metals

= 148.64 x .24 x ( 85.4 -T) + 401.44 x .129 x ( 85.4 - T )

= (35.67 + 51.78 ) x ( 85.4 - T )

87.45 x ( 85.4 - T )

= 7468.23 - 87.45 T

Heat gained by water

= 112 x 1 x ( T - 20.5 )

= 112 T - 2296

Heat lost = heat gained

7468.23 - 87.45 T = 112 T - 2296

199.45 T = 9764.23

T = 48.95° C

Explanation:

5.5 billion grains of sand ( 5.5×109 grains)

If the concentration of brown sand is 6.0% , how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

Brown grains = 0.06 *  5.5×10^9  = 0.33 x 10^9 = 3.3 x 10^8 grains

If the concentration of brown sand is 6.0 ppm, how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

6ppm = 6 / 1000000 = 0.000006

Brown grains =  0.000006  *  5.5×10^9  = 3.3 x 10^4 grains

If the concentration of brown sand is 6.0 ppb, how many grains of brown sand are in the bucket?

Number of grains = Concentration of brown side *  Bucket of sand

6ppb = 6 / 1000000000 = 0.000000006

Brown grains =  0.000000006  *  5.5×10^9  = 3.3 x 10^1 = 33 grains

Answer:

Metallic bonding

Explanation:

Ionic bonding involves the transfer of electrons from a highly electropositive metal to a highly electronegative nonmetal.

The metallic bond is somewhat similar to the ionic bond since there are also charged positive metal ions. The only difference is that there isn't any electronegative element that accepts the electrons.

In a metallic bond, the positively charged metal ions are bound together by a sea of mobile electrons. The attractive force between the metal ions and the mobile electrons hold the metallic crystal lattice together.

Answer:

Path A-B-D involves a catalyst and is slower than A-C-D

Explanation:

The diagram above illustrates both the catalyzed path and the uncatalyzed path of a chemical reaction.

The catalysed path is the path expressed with broken lines and the uncatalyzed path is the path expressed with thick small line as shown in the diagram above.

The catalyzed path has a higher activation energy than the uncatalyzed path.

Therefore, the catalyzed path will be slower that the uncatalyzed path because, the catalyzed path will require a higher energy to overcome the activation energy in order for the reaction to proceed to product.

On the other hand, the uncatalyzed path has a lower activation energy and a lesser amount of energy is needed to overcome it in order for the reaction to proceed to product.

Answer:

See explanation

Explanation:

We have to remember that theory behind the carbohydrates. Carbohydrates are molecules with several hydroxyl groups in which the main functional group can be an aldehyde or a ketone.

If we have an aldehyde as a main functional group we will have an "aldose". If we have a ketone as a main functional group we will have a "ketose".

We can also, classify the carbohydrates using the number of carbons. So, for example, if we have 5 carbons and a ketone as the main functional group we will have a "keto-pentose". If we have for example 4 carbons and an aldehyde as the main functional group we will have a "tetra-aldose".

In this case, we have an aldohexose, so we will have 6 carbons and an aldehyde as main functional group. So, we can draw a structure with 6 carbons, in carbon 1 we have to put the aldehyde group and in the other carbons we have to put "OH" groups.

See figure 1

I hope it helps!

Answer:

E) Al³⁺

Explanation:

A reaction involving a gain of electrons is known as a reduction reaction because the oxidation number of the species gaining the electron is reduced.

In the given question, the oxidation number (charge) of particle accepting two electrons will decrease by 2. From the given options;

A. K is a neutral atom with oxidation number of 0. If is accepts two electrons, its oxidation number becomes -2.

K + 2e⁻  ----> K⁻²

B) Fe²⁺ has a charge of +2. If it accepts two electrons, its charge comes 0.

Fe⁺ + 2e⁻  ----> Fe

C) O²⁻ has a charge of -2. if it accepts two electrons, it will have a charge of -4.

O²⁻ + 2e⁻  ---->  O⁴⁻

D) Ne has a charge of zero. If it accepts two electrons, its charge becomes -2.

Ne + 2e⁻   ---->   Ne²⁻

E) Al³⁺ has a charge of +3. If it gains two electrons, its charge becomes +1.

Al³⁺ + 2e⁻   ---->   Al⁺

Answer:

C. Grinding the solute down into tiny particles.

Explanation:

The dissolution of a solute has something to do with particle size. The size of solute particles usually determines how quickly a solute dissolves in a solvent. When large solute particles are introduced into the solvent, the large solute particles do not easily interact with solvent particles hence preventing easy dissolution in the solvent.

However, when the solute is ground into tiny particles, smaller solute particles interact more effectively with solvent particles hence dissolution is faster.

Therefore, tiny solute particles will dissolve faster in a solvent than a lump of solute. Summarily, small particle size enhances dissolution of a solute in the appropriate solvent.

Answer: stirring the solution vigorously

Grinding the solute down into tiny particles

gently heating the solution

Explanation:

A dissolution will proceed more readily when heated . Breaking up the solute as much as possible will aid in overcoming the solute-solute interaction, as will stirring the solution

Answer:

C. Potential energy

Explanation:

Kinetic energy and gravitational potential energy are both forms of potential energy. Potential energy is stored energy, when an object is not in motion it has stored energy. When an object is an motion it has kinetic energy. An object posses gravitational potential energy when it is above or below the zero height.

Answer: An ion of a single pure element always has an oxidation number of

zero.

Explanation:

Answer:

[tex]3.65~M[/tex]

Explanation:

We have to remember the molarity equation:

[tex]M=\frac{mol}{L}[/tex]

So, we have to calculate "mol" and "L". The total volume is 100 mL. So, we can do the conversion:

[tex]100~mL\frac{1~L}{1000~mL}=~0.1~L[/tex]

Now we can calculate the moles. For this we have to calculate the molar mass:

O: 16 g/mol

H: 1 g/mol

C: 12 g/mol

[tex](16*1)+(1*4)+(12*1)=32~g/mol[/tex]

With the molar mass value we can calculate the number of moles:

[tex]1.7~g~of~CH_3OH\frac{1~mol~CH_3OH}{32~g~of~CH_3OH}=0.365~mol~CH_3OH[/tex]

Finally, we can calculate the molarity:

[tex]M=\frac{0.365~mol~CH_3OH}{0.1~L}=3.65~M[/tex]

I hope it helps!

Answer:

The correct answer is - Al(OH)3

Explanation:

At the point when a substance is blended in with a soluble, there are a few potential outcomes. The deciding variable for the outcome is the solubility of the substance, which is characterized as the maximum concentration of the solute. These rules help figure out which substances are solvent, and how much.

According to the 11 rules of solubility rules, the insoluble compound in water is - Al(OH)3

Answer:

Na2So4

Explanation:

If you consult a table of solubility rules, like the one below, you will see that sodium sulfate (Na2SO4) is soluble in water.

Answer:

The answer is C love.

Explanation:

Answer:

a) It is when a solid is going into the liquid stage. The molecules are really close together.

b) The water could have impurities, altitude could effect the boiling point or the temperature could of been measured wrong.

c) The gas was colorless and odorless therefore it is Hydrogen gas.

d) In a Scientific setting finding the boiling point of a new unknown substances can help identify and organize them. In a commercial setting chemicals need to be stored a certain way according to their boiling point. Stored incorrectly could cause the substance to evaporate.

Answer:

The correct answer is 199.66 grams per mole.

Explanation:

Based on law of effusion given by Graham, a gas rate of effusion is contrariwise proportionate to the square root of molecular mass, that is, rate of effusion of gas is inversely proportional to the square root of mass. Therefore,  

R1/R2 = √ M2/√ M1

Here rate is the rate of effusion of the gas expressed in terms of number of mole per uni time or volume, and M is the molecular mass of the gas.  

Rate Q/Rate N2 = √M of N2/ √M of Q

The molecular mass of N2 or nitrogen gas is 28 grams per mole and M of Q is molecular mass of Q and based on the question Q needs 2.67 times more to effuse in comparison to nitrogen gas, therefore, rate of Q = rate of N2/2.67

Now putting the values we get,  

rate of N2/2.67/rate of N2 = √28/ √M of Q

√M of Q = √ 28 × 2.67

M of Q = (√ 28 × 2.67)²

M of Q = 199.66 grams per mole

Answer:

[tex]V_2 = 4.87 * 10^3[/tex]

Explanation:

This question is an illustration of ideal Gas Law;

The given parameters are as follows;

Initial Temperature = 25C

Initial Volume = 4.5 * 10³L

Required

Calculate the volume when temperature is 50C

NB: Pressure remains constant;

Ideal Gas Law states that;

[tex]PV = nRT[/tex]

The question states that the pressure is constant; this implies that the constant in the above formula are P, R and n

Divide both sides by PT

[tex]\frac{PV}{PT} = \frac{nRT}{PT}[/tex]

[tex]\frac{V}{T} = \frac{nR}{P}[/tex]

Represent [tex]\frac{nR}{P}[/tex] with k

[tex]\frac{V}{T} = k[/tex]

[tex]k = \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

At this point, we can solve for the required parameter using the following;

[tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

Where V1 and V2 represent the initial & final volume and T1 and T2 represent the initial and final temperature;

From the given parameters;

V1 = 4.5 * 10³L

T1 = 25C

T2 = 50C

Convert temperatures to degree kelvin

V1 = 4.5 * 10³L

T1 = 25 +273 = 298K

T2 = 50 + 273 = 323K

Substitute values for V1, T1 and T2 in [tex]\frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex]

[tex]\frac{4.5 * 10^3}{298} = \frac{V_2}{323}[/tex]

Multiply both sides by 323

[tex]323 * \frac{4.5 * 10^3}{298} = \frac{V_2}{323} * 323[/tex]

[tex]323 * \frac{4.5 * 10^3}{298} = V_2[/tex]

[tex]V_2 = 323 * \frac{4.5 * 10^3}{298}[/tex]

[tex]V_2 = \frac{323 * 4.5 * 10^3}{298}[/tex]

[tex]V_2 = \frac{1453.5 * 10^3}{298}[/tex]

[tex]V_2 = 4.87 * 10^3[/tex]

Hence, the final volume at 50C is [tex]V_2 = 4.87 * 10^3[/tex]

Answer:

Hydrogen, carbon reaction

Answer:

6.0 moles NO2(g)

Explanation:

Based on the reaction every 2 moles N2O5(g) gives reaction with 4 moles NO2(g).Then when we have 3.0 mol N2O5(g),

2 moles N2O5(g)       4 moles NO2(g)

3 moles N2O5(g)        ? moles NO2(g)

______________________________________

3 *4 / 2 = 6.00 moles NO2(g)

Answer:

There are 6 mol of NO2 with respect to 3 mol of N2O5

Explanation:

Approach 1 ( dimensional analysis ) :

3 Moles of N2O5 [tex]*[/tex] ( 4 moles of NO2 / 2 Moles of N2O5 ) - moles of N2O5 cancel out, leaving you with the moles of NO2 -

3 [tex]*[/tex] 4 / 2 = 12 / 2 = 6 moles of NO2

So as you can see in the formula there are 4 moles of NO2 present per 2 Moles of N2O5 - " 4NO2 and 2N2O5. " As we wanted the moles of N2O5 to cancel out, the 2 moles of N2O5 was kept as the denominator, and hence we received the fraction we needed.

Approach 2 :

There are 3 Moles of N2O5. The ratio of Moles of N2O5 to moles of NO2 is provided by the reaction -

Moles of N2O5 : Moles of NO2,

2 : 4,

1 : 2

Therefore the moles of NO2 will be two times as much as the given moles of N2O5, or 3 [tex]*[/tex] 2 = 6 moles of NO2

Answer:

21.88mL is the volume of base required for the titration.

Explanation:

For an acid-base titration trying to find the concentration of an acid, you must add a known quantity of the acid and titrate it with an standarized base.

If you know the moles of base you add to the acid solution, these moles are equal to moles of acid.

In the buret of the titration, initial volume is 1.94mL and final volume is 23.82mL. The volume you are adding is the difference between initial and final volume, that is:

23.82mL - 1.94mL

Answer:

Fermentation

Explanation:

Fermentation is the general term used to describe the process by which sugars such as glucose, starch or cellulose are converted to ethanol and carbon (iv) oxide. It is anaerobic process meaning that it occurs in the absence of air or in very low oxygen concentrations.

Yeast and other microorganisms ferment glucose into ethanol and carbon (iv) oxide with the help of the enzyme zymase. Polysaccharides such as starch and cellulose are first broken down into glucose by enzymes such as diastases, maltase and cellulase, before it is then converted into ethanol and carbon (iv) oxide.

The equation for the conversion of glucose to ethanol and carbon (iv) oxide is as follows:

C₆H₁₂O₆(aq) -----> 2C₂H₅OH(aq) + 2CO₂(g)

Answer:

molality

Explanation:

The SI unit for molality is moles per kilogram of solvent. A solution with a molality of 3 mol/kg is often described as "3 molal", "3 m" or "3 m". hope this helps you :)

Answer:

200g

Explanation:

n = CV

n = mass/molar mass

mass/molar mass = CV

mass/40 = 2 x 2.5

mass/40 = 5

mass = 5x 40

mass = 200g

Answer:

The answer is option A.

I hope this helps you.

Answer:

Macro Algae

Explanation:

probz

Answer:

[tex]\large \boxed{1.77 \times 10^{-5}\text{ mol/L}}[/tex]

Explanation:

Assume that you have mixed 135 mL of 0.0147 mol·L⁻¹ NiCl₂ with 190 mL of 0.250 mol·L⁻¹ NH₃.

1. Moles of Ni²⁺

[tex]n = \text{135 mL} \times \dfrac{\text{0.0147 mmol}}{\text{1 mL}} = \text{1.984 mmol}[/tex]

2. Moles of NH₃

[tex]n = \text{190 mL} \times \dfrac{\text{0.250 mmol}}{\text{1 mL}} = \text{47.50 mmol}[/tex]

3. Initial concentrations after mixing

(a) Total volume

V = 135 mL + 190 mL = 325 mL

(b) [Ni²⁺]

[tex]c = \dfrac{\text{1.984 mmol}}{\text{325 mL}} = 6.106 \times 10^{-3}\text{ mol/L}[/tex]

(c) [NH₃]

[tex]c = \dfrac{\text{47.50 mmol}}{\text{325 mL}} = \text{0.1462 mol/L}[/tex]

3. Equilibrium concentration of Ni²⁺

The reaction will reach the same equilibrium whether it approaches from the right or left.

Assume the reaction goes to completion.

                        Ni²⁺             +             6NH₃       ⇌       Ni(NH₃)₆²⁺

I/mol·L⁻¹:    6.106×10⁻³                     0.1462                       0

C/mol·L⁻¹:  -6.106×10⁻³         0.1462-6×6.106×10⁻³             0

E/mol·L⁻¹:           0                              0.1095                6.106×10⁻³

Then we approach equilibrium from the right.

                            Ni²⁺   +   6NH₃       ⇌       Ni(NH₃)₆²⁺

I/mol·L⁻¹:              0           0.1095                6.106×10⁻³

C/mol·L⁻¹:            +x            +6x                           -x

E/mol·L⁻¹:             x         0.1095+6x            6.106×10⁻³-x

[tex]K_{\text{f}} = \dfrac{\text{[Ni(NH$_{3}$)$_{6}^{2+}$]}}{\text{[Ni$^{2+}$]}\text{[NH$_{3}$]}^{6}} = 2.0 \times 10^{8}[/tex]

Kf is large, so x ≪ 6.106×10⁻³. Then

[tex]K_{\text{f}} = \dfrac{\text{[Ni(NH$_{3}$)$_{6}^{2+}$]}}{\text{[Ni$^{2+}$]}\text{[NH$_{3}$]}^{6}} = 2.0 \times 10^{8}\\\\\dfrac{6.106 \times 10^{-3}}{x\times 0.1095^{6}} = 2.0 \times 10^{8}\\\\6.106 \times 10^{-3} = 2.0 \times 10^{8}\times 0.1095^{6}x= 345.1x\\x= \dfrac{6.106 \times 10^{-3}}{345.1} = 1.77 \times 10^{-5}\\\\\text{The concentration of Ni$^{2+}$ at equilibrium is $\large \boxed{\mathbf{1.77 \times 10^{-5}}\textbf{ mol/L}}$}[/tex]

Answer:

0.583M NaCl

Explanation:

Molarity is an unit of concentration defined as the ratio between moles of solute and liters of solution.

In the puddle, the solute is sodium chloride that is dissolved in water and you have 0.449 moles of NaCl per liter of water

When the solution begins to evaporate, amount of water decreases whereas moles of NaCl remain constant.

As 23% of the water evaporates, amount of water that remains is 100-23 = 77%, that means now you have 0.449 moles of NaCl per 77% of a liter, 0.770L. The new concentration is:

0.449 moles NaCl / 0.770L =

Answer:

Kinetic energy = 1/2mv²

where m is the mass

v = velocity

m = 5.31 × 10^-23 kg

v = 1.00 × 10^2 m/s

Kinetic energy = 1/2 × 5.31 × 10^-23 × ( 1.00 × 10^2)²

= 2.655 × 10^-19 Joules

Hope this helps

Answer:

Option B is correct.

Only this option has the first underlined element with a lower oxidation number than the second amongst the options.

Explanation:

Complete Question

In which pair of substances does the first underlined atom have a lower oxidation number than the second?

A. NH₃OH⁺, NH₄⁻ (N is underlined)

B. H₂O, H₂O₂ (O is underlined)

C. SO₃, SO₄²⁻ (S is underlined)

D. HCHO, C (C is underlined)

Solution

In determination of the oxidation number of an atom in a compound, we first name the unknown oxidation number x.

Then, the total oxidation number of the atoms in the compound is equal to the charge of on the compound (or radical).

So, elements in their neutral state have no charge and no oxidation number.

A. NH₃OH⁺, NH₄⁻ (N is underlined)

N in NH₃OH⁺

Oxidation number of N = x

Oxidation number of H = +1

Oxidation number of O = -2

x + (3×+1) + (-2) + (+1) = +1

x - 3 - 2 + 1 = 1

x = +5

N in NH₄⁻

Oxidation number of N = x

Oxidation number of H = +1

x + (4×1) = -1

x + 4 = -1

x = -1 - 4 = -5

First underlined element has a greater oxidation number than the second. So, this doesn't qualify.

B. H₂O, H₂O₂ (O is underlined)

O in H₂O

Oxidation number of H = +1

Oxidation number of O = x

(2×1) + x = 0

2 + x = 0

x = -2

H₂O₂

Oxidation number of H = +1

Oxidation number of O = x

(2×1) + (2×x) = 0

2 + 2x = 0

2x = -2

x = (-2/2) = -1.

First underlined element has a lower oxidation number than the second. So, this qualifies.

C. SO₃, SO₄²⁻ (S is underlined)

S in SO₃

Oxidation number of S = x

Oxidation number of O = -2

x + (3×-2) = 0

x - 6 = 0

x = +6

SO₄²⁻

Oxidation number of S = x

Oxidation number of O = -2

x + (4×-2) = -2

x - 8 = -2

x = 8 - 2 = +6

First underlined element has the same oxidation number as the second. So, this doesn't qualify.

D. HCHO, C (C is underlined)

C in HCHO

Oxidation number of H = +1

Oxidation number of C = x

Oxidation number of O = -2

+1 + x + 1 - 2 = 0

x = 0

C in C

Oxidation number of C = x

x = 0

First underlined element has the same oxidation number as the second. So, this doesn't qualify.

Hope this Helps!!!

Answer:

Mg²⁺

Explanation:

Electronic configuration = 1s22s22p6 (or [Ne] )

Charge = -2

This means the element has two extra electrons. So total electrons = 12.

The lement is Magnesium and the ion is Mg²⁺