Cells are made of cells true or false

Answer:

CH4

Explanation:

Tetra is the prefix for four. Hence the H4

Mono is the prefix for one, Hence the C

Methane (aka Tetrahydrogen monocarbide) written as CH4

Explanation:

I don't really understand the question

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

[tex]NH_3+H_2O\rightleftharpoons NH_4^++OH^-[/tex]

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

[tex]Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}[/tex]

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

[tex]1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M[/tex]

Which is also:

[tex][OH^-]=1.643x10^{-3}M[/tex]

Thereafter we can compute the pOH first:

[tex]pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784[/tex]

Finally, the pH turns out:

[tex]pH=14-2.784\\\\pH=11.216[/tex]

Regards!

Answer:

To calculate the concentration of the acid solution, use three steps.

1. Use the volume of base used at the endpoint and the known concentration of the base solution to find the moles of base used.

2. Use the stoichiometry to find the moles of acid from the moles of base.

3. Divide the moles of acid by the volume of acid used in the titration to find the concentration of acid.

Explanation:

Titration is the process used in volumetric analysis to determine the amount of a substance present in a given sample.

In any titration, a solution of known concentration known as the standard solution is used to react with a solution of of unknown concentration. The reacting volumes of the solutions are then used to calculate the unknown  concentration of the second solution.

In acid-base neutralization reactions, an equivalence point/endpoint of the neutralization titration is obtained and is the point at which the moles of H+ is equal to the moles of OH- . An indicator is used to indicate the equivalence point during a titration by a color change observed in the indicator.

In order to calculate the concentration of an acid, we need to know accurately, use three steps:

1. Use the volume of base used at the endpoint and the known concentration of the base solution to find the moles of base used.

2. Use the stoichiometry of the reaction to find the moles of acid from the moles of base.

3. Divide the moles of acid by the volume of acid used in the titration to find the concentration of acid.

In order to calculate the concentration of a base, use three steps:

1. Use the volume of acid used at the endpoint and the known concentration of the acid solution to find the moles of acids used.

2. Use the stoichiometry of the reaction to find the moles of base from the moles of acid.

3. Divide the moles of base by the volume of base used in the titration to find the concentration of base.

Answer:

.4 moles

Explanation:

this is if it's 35 grams

Answer:

potential energy

Explanation:

Answer:

It’s 10

Explanation:

I looked it up

To solve this we must be knowing each and every concept related to  energy and its calculations. Therefore,  at point b, 10joule of energy is present.

Energy is defined in physics as the ability to accomplish work or heat items. It's a scalar measurement with magnitude but no direction. Energy is maintained, which implies it can change forms but is not generated or destroyed. potential energy transforms into kinetic energy.

One type of energy can be transferred into another without breaking a thermodynamic rule. Not all of these energy sources are equally beneficial in practical applications. At point a the object has 30 joules of energy. At point b, 10joule of energy is present.

Therefore,  at point b, 10joule of energy is present.

To learn more about energy, here:

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Answer:

[tex]v = s \div t[/tex]

[tex]t = s \div v[/tex]

[tex]t = 300 \div 1500 = 0.2s[/tex]

Answer:

molar mass of  unknown monoprotic acid = 114.1 g / mole.

Explanation:

Note: This question is incomplete and lacks necessary data to solve for the required calculation. However, I have similar question on the internet and seen the question completely and will be using that data to solve for this question in order to solve required calculation. Besides that, complete question asks us to solve for molar mass of the acid used.

Note: I have attached the screenshot of the complete question, please have a look on it in the attachment below.

Calculation:

Volume = 34.81mL

34.81 mL of 0.4346 M potassium hydroxide

= 0.03481 L * 0.4346 mole / L

= 0.01513 mole.

Balance equation:

HA + KOH ----> KA + H2O

As we know from the question,

one mole HA neutralize with 1 mole KOH.

mole of unknown monoprotic acid = 0.01513 mole.

And we know that the formula for mole is:  

mole = mass / molar mass

Making molar mass as the subject:

 Molar mass = mass / mole

Molar mass = 1.726 g / 0.01513 mole

Molar mass = 114.1 g / mole.

So,  

Molar mass of  unknown monoprotic acid = 114.1 g / mole.

Explanation:

X = Group 1 metal

Y = Group 7 Non metal

The dots basically signifies the group.

Metal loses electrons and non metal gains electron. The valency of X is 1 and that of Y is 7.

X atom loses one electron and Y atom gains one electron.

The bond that forms between a metal and a non metal is an ionic bond.

Answer:

(i) Concentrated HNO3 can be stored and transported in aluminium containers as it reacts with aluminium to form a thin protective oxide layer on the aluminium surface. This oxide layer renders aluminium passive. (ii) Sodium hydroxide and aluminium react to form sodium tetrahydroxoaluminate(III) and hydrogen gas.

Answer:

uhhh not really i don't even know what that is LOL

Answer:

metal

Explanation:

it's a soft silvery metal

Answer:

plants and animals

Explanation:

Answer:

water, light, wind, soil, humidity, minerals, gases

Explanation:

i just know

Answer:

See explanation

Explanation:

Full molecular equation;

2NH3(aq) + AgNO3(aq) -------> [Ag(NH3)2]NO3(aq)

Full ionic equation

2NH3(aq) + Ag^+(aq) + NO3^-(aq) --------> [Ag(NH3)2]^+(aq) + NO3^-(aq)

Net ionic equation;

2NH3(aq) + Ag^+(aq) -------->  [Ag(NH3)2]^+(aq)

When Silver nitrate is mixed with a solution of aqueous ammonia, a white and cloudy solution was observed.

hope it helps you ❣❣

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oxygen  is needed as a reactant for cellular respiration

Cellular respiration can be defined as the process  which occurs in every cells mainly mitochondria of plants and animals, it involve in the break down of sugars in the presence of oxygen and releases energy in the form of ATP.

The waste product of this process are carbon dioxide and water during exhalation process done  by lungs,  breathing and cellular respiration are related to each other.

At every step of cellular respiration energy is used in the form of ATP and carry out the normal function. It can aerobic and anaerobic respiration on the basis of use of oxygen.

For more details regarding cellular respiration, visit

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Answer:

Mouthing is the answer to your question

Answer: To be separated using GC, analytes must be volatile.

An air peak is commonly used to determine the dead time when using a TCD detector.

An FID is insensitive to non-combustible gases such as water and carbon dioxide.

A column temperature equal to or slightly above the average boiling point of the sample components results in a reasonable elution time.

Explanation:

The gas chromatography works on the principle of separation of gaseous substances based on the differences of vapor pressure. The thermal conductivity detector works on the principle of detection of effluents from the has chamber and the air peak gives indication of the retention time of the effluents. Flame ionization detector can be used for the detection of organic compounds but insensitive for the detection of halogens, non-combustible substances like carbon dioxide and water. The temperature of the column is kept higher than the average boiling point of the substance so as to attain separation of substances by the differences in the elution time.

Answer:

Explanation:

Mass = 66.6 gram

Density = 0.790 g/mL

Volume = Mass ÷ Density

Volume = 66.6 ÷ 0.790

Volume = 84.30 mL

Answer:

Yes, they work in space. I forgot an example, will edit the post when I found it

Hope this helps!

Answer:

the answers are in the pic

Explanation:

Answer:

12.36, 52.49, 40.13

Explanation:

Step 5 for the copper one

Answer:

Pb(NO₃)₂ is the limiting reactant.

The equation is: Pb(NO₃)₂ (aq) + 2KCl (aq) →  PbCl₂ (s) ↓  + 2KNO₃ (aq)

Explanation:

We identify our reactants:

Pb(NO₃)₂ → Lead (II) nitrate

KCl → Potassium chloride

Our reaction is:

Pb(NO₃)₂ (aq)  +  2KCl (aq) →  PbCl₂ (s) ↓  + 2KNO₃ (aq)

1 mol of Lead (II) nitrate reacts to 2 moles of KCl, in order to produce 2 moles of potassium nitrate and 1 mol of slid Lead (II) chloride.

We determine the moles of the reactants:

6.06 g . 1mol /331.2 g = 0.0183 moles of Lead (II) nitrate

6.58 g . 1mol / 74.55g = 0.0882 moles of KCl

2 moles of KCl react to 1 mol of Pb(NO₃)₂

Then, 0.0882 moles of KCl may react to (0.0882 . 1) /2 = 0.0441 moles

We have 0.0183 moles of Pb(NO₃)₂ and we need 0.441 moles. Then, the

Pb(NO₃)₂ is our limiting reactant.

Answer:

[tex]\boxed {\boxed {\sf 5.2 *10^{22} \ molecules \ NaCl}}[/tex]

Explanation:

1. Convert grams to moles

First, convert grams to moles using the molar mass. This can be found on the Periodic Table.

Sodium (Na) has an oxidation state of +1 and chlorine (Cl) has an oxidation state of -1, so they combine in a 1:1 ratio for a formula of NaCl. We can simply add their moles masses.

Use this as a ratio.

[tex]\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Multiply by the given number of grams.

[tex]5.0 \ g \ NaCl *\frac {58.4397693 \ g \ NaCl}{ 1 \ mol \ NaCl}[/tex]

Flip the fraction so the grams of sodium chloride cancel.

[tex]5.0 \ g \ NaCl *\frac {1 \ mol \ NaCl}{ 58.4397693 \ g \ NaCl}[/tex]

[tex]5.0 *\frac {1 \ mol \ NaCl}{ 58.4397693 }=\frac {5.0 \ mol \ NaCl} { 58.4397693 } = 0.0855581749 \ mol \ NaCl[/tex]

2. Convert moles to molecules

We must use Avogadro's Number. This tells us the amount of particles (molecules, atoms, etc.) in 1 mole of a substance. In this case, it is molecules of sodium chloride.

[tex]\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

Multiply by the number of moles we calculated.

[tex]0.0855581749 \ mol \ NaCl*\frac{6.022*10^{23} \ molecules \ NaCl} {1 \ mol \ NaCl}[/tex]

The moles of sodium chloride cancel.

[tex]0.0855581749 *\frac{6.022*10^{23} \ molecules \ NaCl}{1}=5.15231329*10^{22} \ molecules \ NaCl[/tex]

The original measurement of grams has 2 (2 and 0) significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 5 in the hundredth place tells us to round the 1 to a 2.

[tex]5.2 *10^{22} \ molecules \ NaCl[/tex]

C. picking a tray in the cafeteria line

Answer:

Shared (bonding) electrons : 8

Unshared (lone, non-bonding) electrons : 16

Explanation:

The Lewis dot stricture of the molecule attached to this answer shows us all the valence electrons present in the molecule.

Altogether, we have a total number of 24 valence electrons in SO3.

There are eight electrons shared between atoms of elements, these are the bonding electrons.

There are sixteen electrons that are not shared between atoms of elements, These are the lone or non-bonding electrons.

Hence, there are four shared pairs of electrons and eight pairs of unshared electrons.

Answer:

1.) Eyewash station --> D

2.) Absorbent material --> G

3.) Fire extinguisher --> F

4.) Safety Shower --> E

5.) Biohazard container --> J

6.) Broken glass container --> I

7.) Safety goggles --> C

8.) Lab apron --> H

9.) asbestos gloves --> A

10.) Latex gloves --> B

Explanation:

In an equipped laboratory, alot of safety equipments are made available and kept in area that it could be easily accessed in the laboratory. Safety or protective equipments are those materials that helps protect a laboratory personnel while at work on the lab.

These equipments include:

--> Eyewash station: This is an equipment used in the laboratory during emergency to rinse chemical from the eye. Therefore option D is correct.

--> Absorbent material: They are used to contain small spills in the laboratory. Therefore option G is correct.

--> Fire extinguisher: This equipment is used to put out small fires. Therefore F is correct.

--> Safety Shower: This is used to rinse away chemical from clothes and on skin during emergency. Therefore option E is correct.

--> Biohazard container: This container is used to safely dispose bacteria culture, blood and other living tissues. Therefore option J is correct.

--> Broken glass container: This is used to dispose cracked, chipped or broken bottle in the laboratory. Therefore option I is correct.

--> Safety goggles: This helps to protect the eye from chemical and broken glasses. Therefore option C is correct.

--> Lab apron: This is worn by the laboratory personnel to help protect the skin from chemical and biohazards. Therefore option H is correct.

--> Asbestos gloves: these are heat resistant gloves used to protect the hands from heat. Therefore option A is correct.

--> Latex gloves: these are equally worn by the laboratory personnel to protect the hands from chemicals and biohazards

[tex]Answer :—✔[/tex]