Answer:
a. 72
b. 816
c. 570
d. 30
Step-by-step explanation:
Given the graph is a bell - shaped curve. So, we understand that this is a normal distribution and that the bell - shaped curve is a symmetric curve.
Please refer the figure for a better understanding.
a. In a normal distribution, Mean = Median = Mode
Therefore, Median = Mean = 72
b. We have to know that 68% of the values are within the first standard deviation of the mean.
i.e., 68% values are between Mean Standard Deviation (SD).
Scores between 63 and 81 :
Note that 72 - 9 = 63 and
72 + 9 = 81
This implies scores between 63 and 81 constitute 68% of the values, 34% each, since the curve is symmetric.
Now, Scores between 63 and 81 =
= 68 X 12 = 816.
That means 816 students have scored between 63 and 81.
c. We have to know that 95% of the values lie between second Standard Deviation of the mean.
i.e., 95% values are between Mean 2(SD).
Note that 90 = 72 + 2(9) = 72 + 18
Also, 54 = 63 - 18.
Scores between 54 and 90 totally constitute 95% of the values. So, Scores between 72 and 90 should amount to of the values.
Therefore, Scores between 72 and 90 =
= 570.
That is a total of 570 students scored between 72 and 90.
d. We have to know that 5 % of the values lie on the thirst standard Deviation of the mean.
In this case, 5 % of the values lie between below 54 and above 90.
Since, we are asked to find scores below 54. It should be 2.5% of the values.
So, Scores below 54 =
= 2.5 X 12 = 30.
That is, 30 students have scored below 54.
Step-by-step explanation:
It is found that score of 62 is not within one standard deviation of the mean.
What is z - score?The Z-score measures how many standard deviations the measure is from the mean. If we've got a normal distribution, then we can convert it to standard normal distribution and its values will give us the z score.
If we have [tex]X \sim N(\mu, \sigma)[/tex]then it can be converted to standard normal distribution as
[tex]Z = \dfrac{X - \mu}{\sigma}, \\\\Z \sim N(0,1)[/tex]
In a set with mean and standard deviation, the z- score of a measure X is given by:
[tex]Z = \dfrac{X - \mu}{\sigma},[/tex]
Z-score, we look at the z-score table and find the p-value associated with this z-score.
Given that Mean score of 54 and a standard deviation of 6.
This means to see if a score of 62 is within one standard deviation of the mean.
Is Z between -1 and 1 when X = 62.
[tex]Z = \dfrac{X - \mu}{\sigma},\\Z = \dfrac{62 - 54}{6},[/tex]
Z = 1.33
Therefore, It is found that score of 62 is not within one standard deviation of the mean.
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Rectangle A’B’C’D’ is the image of rectangle ABCD after which of the following rotations?
Answer:
You're right!
Step-by-step explanation:
Answer:
Were you right?
Step-by-step explanation:
Which of these is a biomorphic shape? Choose the answer.
O a capital letter W
O a microphone
an outline of a pine tree
O a pyramid
Answer:
Option C: an outline of a pine tree
Step-by-step explanation:
Artists usually use two main types of shapes when drawing. One is geometric shape and the other is bimorphic shape.
A geometric shape simply refers to common regular and precise shapes like triangles, rectangles, squares which are commonly found in man made objects. Whereas, a bimorphic shape is one that is basically rounded or irregular and depicts natural things or living organisms.
Now, from the question, the only thing there that refers to a natural occurring object is "an outline of a pine tree".
Thus, it is a bimorphic shape.
Answer:
C. an outline of a pine tree
Step-by-step explanation:
I just took the test!
3g+h=18 2g+3h=26 what is h and what is g
Answer:
g=4 h=6
Step-by-step explanation:
3g +h = 18 (Equation 1)
2g+3h=26 (Equation 2)
From equation 1
3g+ h =18
h= 18-3g (equation 3)
substitute equation 3 into equation 2
2g+3h= 26
2g+ 3(18-3g)= 26
2g+3×18+3(-3g)=26
2g+54-9g=26
9g-2g= 54-26
7g=28
7g÷7 = 28÷7
g= 4
substitute g into equation 1
3g+h=18
3(4)+ h= 18
12+h= 18
h=18-12
h= 6
Answer:
g = 4; h = g
Step-by-step explanation:
When solving an equation with two variables, the goal is to isolate at least one of the variables so that you can plug it in to the equation to get the other. There are multiple ways to solve this so I'll just be giving one.
3g + h = 18
2g + 3h = 26
In these two equations, I notice that if I multiply the first equation by 3, the two equations will have the same values of h, so I'd be able to isolate g:
9g + 3h = 54
2g + 3h = 26
Now, subtract the second equation from the first to isolate g:
9g + 3h = 54
-2g + 3h = 26
= 7g = 28
= g = 4
Now that we have solved for g, we can plug it into either of the equations and solve for h:
2(4) + 3h = 26
= 8 + 3h = 26
= 3h = 18
= h = 6
And in conclusion, g = 4 and h = 6.
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.18 F and a standard deviation of 0.65 F. Using the empirical rule, find each approximate percentage below.
a.
What is the approximate percentage of healthy adults with body temperatures within 3 standard deviation of the mean, or between 96.23 F and100.3 F?
Answer:
99.7%
Step-by-step explanation:
Empirical rule formula states that:
• 68% of data falls within 1 standard deviation from the mean - that means between μ - σ and μ + σ.
• 95% of data falls within 2 standard deviations from the mean - between μ – 2σ and μ + 2σ.
• 99.7% of data falls within 3 standard deviations from the mean - between μ - 3σ and μ + 3σ.
From the question, we have mean of 98.18 F and a standard deviation of 0.65 F
The approximate percentage of healthy adults with body temperatures between 96.23 F and100.13 F is
μ - 3σ
= 98.18 - 3(0.65)
= 98.18 - 1.95
= 96.23 F
μ + 3σ.
98.18 + 3(0.65)
= 98.18 + 1.95
= 100.13 F
Therefore, the approximate percentage of healthy adults with body temperatures between 96.23 F and 100.13 F which is within 3 standard deviations of the mean is 99.7%
Suppose that Elsa and Frank determine confidence intervals based on the same sample proportion and sample size. Elsa uses a larger confidence level than Frank. How will midpoint and width of confidence intervals compare
Answer:
elsa's interval width will be greater than that of frank
Step-by-step explanation:
first of all we are told that both Elsa and Frank have the same sample proportion so their midpoint is also going to be the same.
now as the confidence level goes higher, so also would the margin of error increase. then the width of the confidence interval would rise so it can be more confident.
from this question elsa has a larger confidence level therefore her intervals width will be greater than franks own.
________ and ________ are two ways that substances pass through a cell membrane out of the cell. A Photosynthesis, diffusion B Diffusion, active transport C Active transport, mitosis D Photosynthesis, mitosis
Answer:
b. diffusion and active transport
Step-by-step explanation:
these are two ways that substances, like nutrients, pass through cell membranes.
Answer:
b
Step-by-step explanation:
suppose that the life distribution of an item has the hazard rate function of what is the probability that
Answer:
that what
Step-by-step explanation:
What is the midpoint of the segments with endpoints (3,7) and (9,15)
Answer:
(6,11)
I can confirm that this question is right.
12/2 22/2
(6 , 11)
Suppose that minor errors occur on a computer in a space station, which will require re-calculation. Assume the occurrence of errors follows a Poisson process with a rate of 1/2 per hour. (a) Find the probability that no errors occur during a day. (b) Suppose that the system cannot correct more than 25 minor errors in a day, in which case a critical error will arise. What is the probability that a critical error occurs since the start of a day? Keep up to the 6th decimal place in your answer. (c) Suppose the error correction protocols reset themselves so long as there are no more than five minor errors occurring within a 2 hour window. The system just started up and an error occurred. What is the probability the next reset will occur within 2 hours?
Answer:
a
[tex] P(X = 0) = 0.6065 [/tex]
b
[tex]P(x < 25 ) = 1.18 *10^{-33} [/tex]
c
[tex] P(x \le 5 ) = 0.9994 [/tex]
Step-by-step explanation:
From the question we are told that
The rate is [tex]\lambda = \frac{1}{2}\ hr^{-1}[/tex] = 0.5 / hr
Generally Poisson distribution formula is mathematically represented as
[tex]P(X = x) = \frac{(\lambda t) ^x e^{-\lambda t }}{x!}[/tex]
Generally the probability that no error occurred during a day is mathematically represented as
Here t = 1 hour according to question a
So
[tex]P(X = x) = \frac{\lambda^x e^{-\lambda}}{x!}[/tex]
Hence
[tex][tex]P(X = 0) = \frac{\frac{1}{2} ^0 e^{-\frac{1}{2}}}{0!}[/tex]
=> [tex] P(X = 0) = 0.6065 [/tex]
Generally the probability that a critical error occurs since the start of a day is mathematically represented as
Here t = 1 hour according to question a
So
[tex]P(X = x) = \frac{\lambda^x e^{-\lambda}}{x!}[/tex]
Hence
[tex]P(x \ge 25 ) = 1 - P(x < 25 )[/tex]
Here
[tex]P(x < 25 ) = \sum_{x=0}^{24} \frac{e^{-\lambda} * \lambda^{x}}{x!}[/tex]
=> [tex]P(x < 25 ) = \frac{e^{-0.5} *0.5^{0}}{0!} + \cdots + \frac{e^{-0.5} *0.5^{24}}{24!}[/tex]
[tex]P(x < 25 ) = 0.6065 + \cdots + \frac{e^{-0.5} *0.5^{24}}{6.204484 * 10^{23}}[/tex]
[tex]P(x < 25 ) = 0.6065 + \cdots + 6.0*10^{-32}[/tex]
[tex]P(x < 25 ) = 1.18 *10^{-33} [/tex]
Considering question c
Here t = 2
Gnerally given that the system just started up and an error occurred the probability the next reset will occur within 2 hours
[tex]P(x \le 5 ) = \sum_{n=0}^{5} \frac{(\lambda t) ^x e^{-\lambda t }}{x!}[/tex]
=> [tex]P(x \le 5 ) = \frac{(0.5 * 2) ^ 0 e^{- 0.5 * 2 }}{0!} + \cdots + \frac{(0.5 * 2) ^ 5 e^{- 0.5 * 2 }}{5!}[/tex]
=> [tex]P(x \le 5 ) = \frac{1* 2.7183 }{1 } + \cdots + \frac{1 *2.7183 }{120}[/tex]
=> [tex]P(x \le 5 ) = 2.7183 + \cdots + 0.0226525[/tex]
[tex] P(x \le 5 ) = 0.9994 [/tex]
.
***
9. The game of euchre uses only the 9s, 10s, it is
jacks, queens, kings, and aces from a standard
deck of cards. How many five-card hands have
a) all red cards?
b) at least two red cards?
c) at most two red cards?
Answer
a) From those information we know that have 24 card
In those cards it have 12 red.
12C5=792
B)
at least 2 red card=No restriction- without red card- at least one red card
= 24C5-(12C0*12C5)-(12C1*12C4)
=35772
C) at most 2 red card
24C5-(12C0*12C5)-(12C1*12C4)-(12C2*12C3)
=21252
A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. The probability of at most 2 red cards is 0.5.
What is Binomial distribution?A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,
P(x) = ⁿCₓ (pˣ) (q⁽ⁿ⁻ˣ⁾)
Where,
x is the number of successes needed,
n is the number of trials or sample size,
p is the probability of a single success, and
q is the probability of a single failure.
Using the given information the number of cards is 24 out of which 12 are red. Therefore, the probability of getting a red card is 0.5.
A) All red cards.
P(X=5) = ⁵C₅ (0.5⁵) (0.5⁰)
= 0.03125
B.) at least two red cards.
P(X≥2) = 1 - ⁵C₀ (0.5⁰) (0.5⁵) - ⁵C₁ (0.5¹) (0.5⁴)
= 0.8125
C.) At most 2 red cards.
P(X≤2) = ⁵C₀ (0.5⁰) (0.5⁵) + ⁵C₁ (0.5¹) (0.5⁴) + ⁵C₂ (0.5²) (0.5³)
= 0.5
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170% of what is 166?
Answer:
97.65
Step-by-step explanation:
97.65
Step-by-step explanation
Tickets for a drumline competition cost $5 at the gate and $3 in advance. One hundred more tickets were sold in advance than at the gate. The total revenue from ticket sales was $1990. How many tickets were sold in advance?
Answer:
The number of tickets sold at the gate is [tex] G = 211.25[/tex]
The number of tickets sold in advance is [tex] A = 311.25 [/tex]
Step-by-step explanation:
From the question we are told that
The cost of a tickets at the gate is [tex]a = \$ 5[/tex]
The cost of a ticket in advance is [tex]b = \$ 3[/tex]
Let the number of ticket sold in the gate be G
Let the number of ticket sold in advance be A
From the question we are told that
One hundred more tickets were sold in advance than at the gate and this can be mathematically represented as
[tex]G + 100 = A[/tex]
From the question we are told that
The total revenue from ticket sales was $1990 and this can be mathematically represented as
[tex]5 G + 3A = 1990[/tex]
substituting for A in the equation above
[tex]5 G + 3[G + 100]= 1990[/tex]
[tex]5 G + 3G + 300= 1990[/tex]
[tex] 8G + 300= 1990[/tex]
[tex] 8G = 1690[/tex]
=> [tex] G = 211.25[/tex]
Substituting this for G in the above equation
[tex]5 [211.25] + 3A = 1990[/tex]
=> [tex] 3A = 1990 - 1056.25[/tex]
=> [tex] A = 311.25 [/tex]
If you roll a die once, what is the probability of rolling a 3?
Answer:
1/6
Step-by-step explanation:
there are 6 sides, and 3 is one of the 6 sides. thus, the answer is 1/6
Answer:
1/6
Step-by-step explanation: there are 6 incomes and 1 number 3 in a die
function rule y=3x-3
Answer:
-15, -9, -3, 3
Step-by-step explanation:
First One:
y =3(-4)-3 is -15
Second:
y= 3(-2)-3 is -9
Third:
y= 3(0)-3 is -3
Last One:
y= 3(2)-3 is 3
Find the surface area of the cube shown below 2.3
Answer:
2 2/3 or 8/3
Step-by-step explanation:
Formula for each side = 2/3 x 2/3
2/3 x 2/3 = 4/9
6 sides
4/9 x 6 or 4/9 + 4/9 + 4/9 + 4/9 + 4/9 + 4/9
=2 2/3 or 8/3
Answer:
2 2/3
Is the answer
What formula is used to
determine the expected value for a variable?
Question 3 of 6 (1 point) Attempt 33 of Unlimited View question in a popup
2.4 Section Exercise 6
In a study of 550 meals served at 75 campus cafeterias, 77 had less than 10 grams of fat but not less than 350 calories; 81 had
less than 350 calories but not less than 10 grams of fat; 186 had over 350 calories and over 10 grams of fat.
Part: 0/2
E
Part 1 of 2
(a) What percentage of meals had less than 10 grams of fat? Round your answer to the nearest tenth of a percent.
of the meals studied, 1% of them had less than 10 grams of fat.
Answer:
10%
Step-by-step explanation:
(a) What percentage of meals had less than 10 grams of fat?
(b) Round your answer to the nearest tenth of a percent.
To find the percentage of meals with less than 10 grams of fat, count the number of meals with less than 10 grams of fat and divide by the total number of meals; multiply this figure by a hundred.
(A) Total number of meals = 550
Number of meals having less than 10 grams of fat = 77
Percentage of meals having less than 10 grams of fat = 77/550 × 100
= 0.14 × 100 = 14%
(B) Rounding the answer to the nearest tenth of a percent means approximating it to the nearest multiple of 10 that is not more than 100 (where 100 here represents a full cent or 'percent').
The multiples of 10 that are close to 14 are 10 and 20. The closest being 10, your answer becomes 10%
Graph the line y-3=-1/3(x+2)
Slope: 1/2
y-intercept(s): (0, 7/3)
x: 0, 7
y: 7/3, 0
Step-by-step explanation:
y=-3 -1/3(1+2)=2/3.3=1.3=3
y=3
A company sells widgets. The amount of profit, y, made by the company, is related to the selling price of each widget, x, by the given equation. Using this equation, find out what price the widgets should be sold for, to the nearest cent, for the company to make the maximum profit.
y=-10x^2+600x-3588
y=−10x
2
+600x−3588
Answer:
Step-by-step explanation:
The maximum profit will be found in the vertex of the parabola, which is what your equation is. You could do this by completing the square, but it is way easier to just solve for h and k using the following formulas:
[tex]h=\frac{-b}{2a}[/tex] for the x coordinate of the vertex, and
[tex]k=c-\frac{b^2}{4a}[/tex] for the y coordinate of the vertex.
x will be the selling price of each widget and y will be the profit. Usually, x is the number of the items sold, but I'm going off your info here for what the vertex means in the context of this problem.
Our variables for the quadratic are as follows:
a = -10
b = 600
c = -3588. Therefore,
[tex]h=\frac{-600}{2(-10)}=30[/tex] so the cost of each widget is $30. Now for the profit:
[tex]k=-3588-(\frac{(600)^2}{4(-10)})[/tex] This one is worth the simplification step by step:
[tex]k=-3588-(\frac{360000}{-40})[/tex] and
k = -3588 - (-9000) and
k = -3588 + 9000 so
k = 5412
That means that the profit made by selling the widgets at $30 apiece is $5412.
Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].
What is the maximum profit?
Maximum profit, or profit maximisation, is the process of finding the right price for your products or services to produce the best profit.
Here given that,
A company sells widgets. The amount of profit, [tex]y[/tex], made by the company, is related to the selling price of each widget, [tex]x[/tex], by the given equation.
As the maximum profit found in the vertex of the parabola,
Here, [tex]x[/tex] will be the selling price of each widget and [tex]y[/tex] will be the profit.
The number of items sold is [tex]x[/tex].
So, the quadratic equation is:-
[tex]a = -10b = 600c = -3588.[/tex]
Therefore, so the cost of each widget is $[tex]30[/tex].
For the profit:-
[tex]k = -3588 - (-9000) andk = -3588 + 9000 sok = 5412[/tex]
Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].
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Try it
Solve the system of equations.
2x + 3y = 1
5x + 2 = 8
What is the solution?
Answer:
x=6/5 ,y= -7/15
Step-by-step explanation:
we are going to solve this simultaneously.
2x+3y=1.......(i)
and
5x+2=8
5x=6
x= 6/5 .......(ii)
Now let's put value of x into equation number (i)
2x+3y=1
2(6/5) +3y=1
12/5 +3y =1
3y= 1-(12/5)
3y = -7/5
y = (-7/5) ÷3
y= -7/15
Find the unknown angle measures.
Answer:
x = 9°
y = 119°
Step-by-step explanation:
Given,
y° = 61°+58° { the exterior angle formed by producing the side of triangle is equal to two non-adjacent angle}
or, y° = 119°
therefore, y° = 119°
Now,
52°+y°+x° = 180°{the sum of angle if triangle is 180°}
or, 52°+119°+x°= 180°
or, 171°+x° = 180°
or, x° = 180°-171°
or, x° = 9°
therefore, x° = 9°
3s (s - 2) =12s, please help me this. Thank you!
Answer:hbjnhbgfvrdfghjhgfdfghjhgfghjkl
What is the slope of the line? Select the correct choice below and, if necessary, fill in the answer box to complete
your choice.
O A. The slope of the line is
(Type an integer or a simplified fraction.)
O B. The slope of the line is undefined.
[tex]\tt Step-by-step~explanation:[/tex]
Slope = rise/run
[tex]\tt Steps:[/tex]
Rise: The line travels 5 units vertically (up) from the first point to the second.
Run: The line goes 6 units horizontally (left) from the first point to the second.
Slope = rise/run; Slope = 5/6
[tex]\Large\boxed{\tt The~slope~of~the~line~is:~\frac{5}{6}~units }[/tex]
Answer:
Slope = rise/run
Step-by-step explanation:
Does anyone have the answer?
Answer:
hi to what. good bye???????
Ten less than 5 times the value of a number is equal to 10 times the quantity of
12 more than one-fourth of the number. If a is the number, what is the value of a?
Answer:
52
Step-by-step explanation:
given that the number is a
The expression for Ten less than 5 times the value of a number is given by
5a - 10
10 times the quantity of 12 more than one-fourth of the number.
a/4 is one-fourth of number
12 more than one-fourth of the number
a/4 + 12
expression for 10 times the quantity of 12 more than one-fourth of the number. is given by
10(a/4 + 12) = 10a/4 + 12*10 = 2.5a + 120
Given that the above two expression are equal
equating them we have
5a - 10 = 2.5a + 120
adding 10 both sides
=>5a - 10+ 10 = 2.5a + 120 + 10
=> 5a = 2.5a + 130
subtracting 2.5a from both sides
=> 5a - 2.5a = 2.5a + 130 - 2.5a
=> 2.5a = 130
dividing both side by 2.5
=> a = 130/2.5 = 52
Thus, value of a is 52
solve for z 3=(z+1) write your answers as integers or as proper or improper fractions
Answer:
z=2
Step-by-step explanation:
Just solve
1 + z = 3 (minus 1 on both sides)
z = 2
Plug in
3=(2+1)
3 = 3
A lumber supplier sells 96-inch pieces of oak. Each piece must be within ¼ of an inch of 96 inches. Write and solve an inequality to show acceptable lengths.
Answer:
[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]
Step-by-step explanation:
Given that a lumber supplier sells 96 inch Pieces of oak which must be within 1/4 of an inch.
This situation can be represented by the following absolute value inequality:
[tex]|x \: - 96| \: \leqslant \: \frac{1}{4} [/tex].
The absolute value can be thought of as the size of something because length cannot be negative. The length must be no more than 1/4 away from 96.
To simplify this, pretend this is a standard equality, |x-96| = 1/4. 1/4 is the range of acceptable length, 96 is the median of the range, and x is the size of the wood.
First apply the rule |x| = y → x = [tex]\pm[/tex]y
|x-96| = 1/4
x - 96 = [tex]\pm[/tex]1/4
x = [tex]96 \pm 1/4[/tex]
(These are just the minimum, and maximum sizes)
Now with a less than or equal to, the solutions are now everything included between these two values.
Therefore:
[tex]96 - 1/4 \: \leqslant x [/tex] [tex]\leqslant \: 96 + 1/4 [/tex]
With less than inequalities, you must have the lower value on the left, and the higher value on the right.
If x represents the size of the pieces, then the acceptable lengths are represented by this following inequality:
[tex]95 \frac{3}{4} \: inch \leqslant x \leqslant 96 \frac{1}{4} \: inch[/tex]
This is interpreted as x (being the size of the oak) is greater than or equal to 95 3/4, and less than or equal to 96 1/4 in inches.
Order from least to greatest:
-5/6,0.567,-0.11,-1/4
Answer:
-5/6,-1/4,-0.11,0.567
Step-by-step explanation:
From a circular sheet of paper with a radius 20 cm, four circles
of radius 5 cm each are cut out. What is the ratio of the uncut to
the cut portion?
Answer:
3 : 1
Step-by-step explanation:
The biggest circle has a radius of 20 cm
So that means, its area will be,
Area = [tex]\pi r^{2}[/tex]
Area = [tex]\pi * 20^{2}[/tex]
A = [tex]\pi * 400[/tex]
=> A = 400[tex]\pi[/tex]
We do not need to solve this because it is nit required
Then, one small circle has an area of,
Area = [tex]\pi r^{2}[/tex]
Area = [tex]\pi *5^{2}[/tex]
Area = [tex]\pi *25[/tex]
=> Area = 25[tex]\pi[/tex]
As there are 4 circles in, we get that the area covered by the small squares,
=> [tex]25\pi * 4[/tex]
=> [tex]100\pi[/tex]
So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)
=> 1/4
So, there is 1 cut region and the remaining is the uncut region,
As we need to find uncut to cut, the ratio will be,
=> remaining : 1
=> 3 : 1
If my answer helped, kindly mark me as the brainliest!!
Thanks!!
The length of a rectangle is 2 times the width. If the perimeter is to be less than 96 meters. What are the possible
values for the width? (Use w as the width)
Preview
TIP
Enter your answer using inequality notation. Example: 3 <=w<4
Use or to combine intervals. Example: w< 2 or w >= 3
Enter all real numbers for solutions of that type
Enter each value as a number (like 5, -3, 2.2172) or as a calculation (like 5/3, 243,
5+4)
Enter DNE for an empty set. Use oo to enter Infinity.
Answer:
W>16
Step-by-step explanation:
The formula for calculating the perimeter of a rectangle:
P = 2L+2W
L is the length of the rectangle
W is the width of the rectangle:
Given
P = 96m
If the length of a rectangle is 2 times the width, then L = 2W
Substitute into the formula:
Since the perimeter is less than 96m
96 < 2(2W)+2W
96 < 4W+2W
96 < 6W
Divide both sides by 6:
96/6 < 6W/6
16 < W
W>16
Hence the possible values of the width are all values greater than 16.