Can you please simplify c5 x c

Answer:

explain further or send a picture of what you mean and then I can help you

Answer:

the fraction and its decimal equivalent for the mark on the ruler

= 59/64 = 0.921875

Step-by-step explanation:

Given that;

A CARPENTER 's ruler is marked in thirty  seconds

mark on the ruler between 29/32 and 30/32​ is the average of the values

we know that average is the summation of all terms divided by the number of appearance of terms

so

= (29/32 + 30/32​) / 2

= ((29 + 30) / 32) / 2

= (59 / 32) / 2

= 59 / 64

= 0.921875

therefore the fraction and its decimal equivalent for the mark on the ruler = 59/64 = 0.921875

Answer:

Decision rule  is  

Fail to reject the null hypothesis

 The conclusion is  

There is sufficient evidence that indicate that there is a significant difference between the two treatments

Step-by-step explanation:

From the question we are told that  

    The sample size is  n =  12

    The first  mean is  [tex]M_1  =  55[/tex]

    The variance is  [tex]s^2_1 =  8[/tex]

    The second mean is  [tex]M_2  =  52[/tex]

     The second variance is [tex]s^2_2 =  4[/tex]

Let the level of significance be  [tex]\alpha  =  0.05[/tex]

The null hypothesis is  [tex]H_o  :  M_1 = M_2[/tex]

The alternative hypothesis is [tex]H_a  :  M_1 \ne M_2[/tex]

  Generally the test statistics is mathematically

     [tex]t = \frac{M_1 - M_2 }{ \sqrt{\frac{s_1^2}{n_1} +\frac{s_2^2}{n_2}} }[/tex]

=>   [tex]t = \frac{55 - 52 }{ \sqrt{\frac{8}{12} +\frac{4}{12 }} }[/tex]

=>   [tex]t = 1.1619 [/tex]

Generally the degree of freedom is mathematically represented as

      [tex]df = 12 -1[/tex]

=>    [tex]df = 11 [/tex]

Generally  from the t- distriibution table the critical  value  of  [tex]\alpha[/tex] at a degree of freedom of [tex]df = 11 [/tex]  is

    [tex]t_{0.05 , 11} =  2.20098516[/tex]

Here given that the critical value is greater than the t statistics value the

Decision rule  is  

Fail to reject the null hypothesis

 The conclusion is  

There is sufficient evidence that indicate that there is a significant difference between the two treatments

9514 1404 393

Answer:

  yes

Step-by-step explanation:

Yes, you can find the distance between two lines using the formula for the distance to a line.

In general, the notion of distance between two lines only make sense when the lines are parallel.

The usual formula for the distance between a point (x, y) and the line ...

  ax +by +c = 0

is ...

  d = |ax +by +c|/√(a^2 +b^2)

Two lines that are parallel will differ only in their values of 'c'. That is, if the two lines are ...

we can arrive at the formula by considering a point (x, y) such that it satisfies the equation for line 2: ax +by +c2 = 0. The distance of that point from line 1 will be ...

  d = |ax +by +c1|/√(a^2 +b^2)

Since we can add or subtract 0 from anything without changing its value, we choose to subtract 0 from the numerator:

  d = |(ax +by +c1) -(ax +by +c2)|/√(a^2 +b^2)

Simplifying gives ...

  d = |c1 -c2|/√(a^2 +b^2)

Step-by-step explanation:

Perimeter of a rectangle = 2(L+W)

L is the length of the rectangle:

W is the width of the rectangle.

Given

Perimeter = 214feet

If the length is 41 ft longer than the width, then L = 41+W

Substitute L = 41+W into the formula:

P = 2(L+W)

214 = 2(41+W+W)

214 = 2(41+2W)

214 = 82+4W

4W = 214-82

4W = 132

W = 132/4

W = 33 feet

Since L = 41+W

L = 41+33

L = 74 feet

Hence the dimension of the field is 74ft by 33ft

The width of the playing field is 33feet

Answer:

Explained below.

Step-by-step explanation:

Let X represents the tree heights.

It is provided that X follows a normal distribution with mean μ = 112 inches and standard deviation σ = 10 inches.

(a)

Compute the 22nd percentile of the tree heights as follows:

[tex]P(X<x)=0.22\\\\P(Z<z)=0.22[/tex]

The z-score for the corresponding probability is, z = -0.77.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\-0.77=\frac{x-112}{10}\\\\x=112-(0.77\times 10)\\\\x=104.3[/tex]

Thus, the 22nd percentile of the tree heights is 104.3 inches.

(b)

Compute the 80th percentile of the tree heights as follows:

[tex]P(X<x)=0.80\\\\P(Z<z)=0.80[/tex]

The z-score for the corresponding probability is, z = 0.84.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\0.84=\frac{x-112}{10}\\\\x=112+(0.84\times 10)\\\\x=120.4[/tex]

Thus, the 80th percentile of the tree heights is 120.4 inches.

(c)

Compute the first quartile of the tree heights as follows:

[tex]P(X<x)=0.25\\\\P(Z<z)=0.25[/tex]

The z-score for the corresponding probability is, z = -0.67.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\-0.67=\frac{x-112}{10}\\\\x=112-(0.67\times 10)\\\\x=113.3[/tex]

Thus, the first quartile of the tree heights is 113.3 inches.

(d)

The tallest 1% of the trees, i.e. P (X > x) = 0.01.

That is, P (X < x) = 0.99.

⇒ P (Z < z) = 0.99

The corresponding z-value is, z = 2.33.

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\0.99=\frac{x-112}{10}\\\\x=112+(0.99\times 10)\\\\x=121.9[/tex]

Thus, the tallest 1% of the trees are more than 121.9 inches tall.

Answer:

x=-7

Step-by-step explanation:

4(1-x)+2x=-3(x+1)

4-4x+2x=-3x-3

4-2x=-3x-3

-2x=-3x-7

x=-7

Step-by-step explanation:

−2x+5y=−15 and 5x+2y=−6

Rewrite equations:

−2x+5y=−15;5x+2y=−6

Step: Solve−2x+5y=−15for x:

−2x+5y=−15

−2x+5y+−5y=−15+−5y(Add -5y to both sides)

−2x=−5y−15

−2x−2=−5y−15−2(Divide both sides by -2)

x=52y+152

Step: Substitute52y+152forxin5x+2y=−6:

5x+2y=−6

5(52y+152)+2y=−6

292y+752=−6(Simplify both sides of the equation)

292y+752+−752=−6+−752(Add (-75)/2 to both sides)

292y=−872

292y292=−872292(Divide both sides by 29/2)

y=−3

Step: Substitute−3foryinx=52y+152:

x=52y+152

x=52(−3)+152

x=0(Simplify both sides of the equation)

Answer:

x=0 and y=−3

Answer:

1

General Formulas and Concepts:

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

a - b + c

a = 4

b = 2

c = -1

Step 2: Solve

Answer:

904

Step-by-step explanation:

8 x 113 = 904

Answer:

which one equals 12? option C

Step-by-step explanation:

Answer:

The rearrangement can be 45, 987 , 310

Step-by-step explanation:

Here, we want to rearrange the number such that 9 is worth 10 times as what it is worth presently

The value of 9 presently is 90,000

So 10 times as worth will be 10 * 90,000 = 900,000

So we can have the new arrangement as;

45, 987, 310

-4 is the x intercept.as in the values on the x-axis

Answer:

Im pretty sure it the first one

Step-by-step explanation:

Answer:

the first one

Step-by-step explanation: it is your answer because when you solve it i gt that answer i calculated it in a calculator and then showed to the teahcre and said that it was crrect please mark me as brainlist

Answer:

1000-20

Step-by-step explanation:

Answer:

a) -16

b)7

c) -4

d) 9

Step-by-step explanation:

by solving

Answer: −2x+y=−11

(4,-3) = −2x+y=−11.

Answer: −2x+y=−11.

Convert any mixed numbers to fractions.

Then you get your initial equation

Applying the fractions formula for subtraction

Simplifying 72/16, the answer is

4 1/2

Answer:

940,000

Step-by-step explanation:

Since there is a 6 in 936,292, that gives you the right to make the ten thousandth higher if that makes sense

Answer:

965314

Step-by-step explanation:

Please mark me brainlest and hope that help (=

Answer:

-1

Step-by-step explanation:

When you make the number line, go to the middle then move left once. Then mark that  " -1 " and you put the dot over that.

It's hard to explain how to write number lines.

Anyways, the problem equals -1 because 6-7 is negative 1. The + is there to confuse you.

Mark brainliest if possible please :)

Answer:

the anwer is 5*6

Answer:when he was doing the multipleis of 8 he put 20 when there is no 20

Step-by-step explanation:

Answer:

The probability that the household has only cell phones and has high-speed Internet is 0.408

Step-by-step explanation:

Let A be the event that represents U.S. households has only cell phones

Let B be the event that represents U.S. households have high-speed Internet.

We are given that 51% of U.S. households has only cell phones

P(A)=0.51

We are given that 70% of the U.S. households have high-speed Internet.

P(B)=0.7

We are given that U.S. households having only cell phones, 80% have high-speed Internet. A U.S household is randomly selected.

P(B|A)=0.8

[tex]\frac{P(A\capB)}{P(A)}=0.8\\P(A\capB)=0.8 \times P(A)\\P(A\capB)=0.8 \times 0.51\\P(A\capB)=0.408[/tex]

Hence the probability that the household has only cell phones and has high-speed Internet is 0.408

Answer:

6 1/6

Step-by-step explanation:

six goes into 42 seven times that leaves you with one number so it can go in six times evenly and that leaves you with 1/6

Answer:

c = 4

Step-by-step explanation:

Solve for"c" in the following equation:

- 8 c + 7 = - 25

Subtract 7 from both sides:

- 8 c = - 25 - 7

combine like terms

- 8 c = -32

divide both sides by "-8" to isolate c on the left

c = - 32 / (-8)

c = 4

Answer:

divide by 2 equals 30.5 minus 7 equals to 23,5

Step-by-step explanation:

smaller is 23,5

B is 37.5

Answer:

Angle: 22.5 deg, Complement: 67.5 deg, Supplement: 157.5 deg

Step-by-step explanation:

22.5 is 1/3 of 67.5

so compliment is 67.5.

Supplement is just adding another angle so I chose 7.

I did 22.5 x 7 = 157.5

Another example would be:

Angle: 10 deg, Complement: 30 (because 10 x 3), Supplement: 70 (because 10 x 7)

Hope this helps :)