Can you find the missing segment to the triangle in the image attached

Can You Find The Missing Segment To The Triangle In The Image Attached

Answers

Answer 1

Answer:

missing segment= 25

the answer and how to do the problem in paper

Can You Find The Missing Segment To The Triangle In The Image Attached

Related Questions

Please I need help in this question, Best answer gets BRAINLIEST

Answers

Answer:

1 - a/variable

2 - d/statistic

3 - b/population

4 - c/data

5 - e/parameter

6 - f/sample

I did comment asking if the two you'd already selected were definitely correct, but no answer was given, so I apologise if this is wrong. This is what I would put.

Which choice shows the image of quadrilateral WXYZ after a reflection over the y-axis followed by a translation down 2 units?

Answers

Answer:

Choices are not provided, but you can answer the question as follows: take the coordinates of quadrilateral WXYZ and apply:

W(xW, yW) -> W'(-xW, yW-2)

X(xX, yX) -> X'(-xX, yX-2)

Y(xY, yY) -> Y'(-xY, yY-2)

Z(xZ, yZ) -> Z'(-xZ, yZ-2)

For example, if point W is located at (1, 1), W' would be located at (-1, -1)

Step-by-step explanation:

Reflection over the y-axis transforms point (x, y) into (-x, y)

Translation down 2 units transforms point (x, y) into (x, y-2)

Answer:

The first choice hope this helps :)

Step-by-step explanation:

Pls help me I need the help!

Answers

Answer:

1a) 15, 7, x+5

1b) 7

2a) 18, 3r

Step-by-step explanation:

1a) Since Claire is 5 years older, she will always be her cousin's age plus 5

1b) Claire is 5 years older, so Claire's cousin is 5 years younger. So, Claire's cousin is Claire's age minus 5

2a) Diego will have the amount of Han's books times 3

Answer:

Clare Questions:

Cousin: 10, Clare: 15

Cousin: 2, Clare: 7

Cousin: x, Clare: x + 5

Cousin: 7, Clare: 12

Diego Questions:

Han: 6, Diego: 18

Han: can't tell if it is a 0 or n, Diego: 0 or 3n, respectively

Step-by-step explanation:

Since Clare is older than her cousin by 5, they will both age at the same rate, thus she will always be 5 years older.

example: if her cousin is 10, Clare will be 10 + 5 years older, therefore being 15.

Since DIego has 3 times as many books than Hans, it multiplies by 3.

example: if Han has 6 books, multiply 6 by 3 and you get Diegos amount, 18.

A point located at (6, 4) is reflected over the x-axis. What are the coordinates of the image?
(6,4)
(-6,-4)
(-6,4)
(-4, 6)​

Answers

Answer:

(6,-4)

Step-by-step explanation:

Reflecting over the x axis means flipping the point or line over it. Therefore the point's y value would the opposite from the beginning.

Answer:

(6, -4)

Step-by-step explanation:

For any point reflected over the x-axis, the x-coordinate stays the same and the y-coordinate becomes negative.

6 stays the same

4 becomes -4.

I'm always happy to help :)

A merchant has coffee worth $30 a pound that she wishes to mix with 20 pounds of coffee worth $60 a pound to get mixture that can be sold for $50 a pound. How many pounds of the $30 coffee should be used?

Answers

13 1/3 pounds of coffee should be used
13 1/2 pounds of coffee should be used

help please heeeeeeeeeeeeeeeeeeeeeeeeeeelp

Answers

Answer:

8.29166

Step-by-step explanation:

3.5_0.375+5.166666

Answer:

[tex]8 \frac{7}{24} [/tex]

Step-by-step explanation:

Please see attached picture for full solution.

If the sum of the integers from 15 to 50,
inclusive, is equal to the sum of the integers
from n to 50, inclusive, and n<15, then n=

A)-49
B)-35
C)-15
D-14​

Answers

Answer:

n = -15

Step-by-step explanation:

Given

Sum of Integers from 15 to 50 (inclusive) = Sum of integers from n to 50 (inclusive)

n < 15

Required

Find n

We can split the given parameters to 2

i. Sum of Integers from 15 to 50 (inclusive)

ii. Sum of integers from n to 50 (inclusive)

Solving for (i): Sum of Integers from 15 to 50 (inclusive)

We'll make use of sum of n terms of an arithmetic;

This is given as follows

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where n is the number of terms from 15 to 50

T1 is the first term; T1 = 15

Tn is the last term; Tn = 50

n is calculated using

[tex]n = T_n - T_1 + 1[/tex]

[tex]n = 50 - 15 + 1[/tex]

[tex]n = 36[/tex]

The formula becomes

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]S_n = \frac{36}{2}(15 + 50)[/tex]

[tex]S_n = \frac{36}{2}(65)[/tex]

[tex]S_n = 18(65)[/tex]

[tex]S_n = 1170[/tex]

Solving for (ii): Sum of integers from n to 50 (inclusive)

We'll also make use of the same formula used above

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

Where n is the number of terms from n to 50

T1 is the first term; T1 = n

Tn is the last term; Tn = 50

n is calculated using

[tex]n = T_n - T_1 + 1[/tex]

[tex]n = 50 - n + 1[/tex]

[tex]n = 50 + 1 - n[/tex]

[tex]n = 51 - n[/tex]

The formula becomes

[tex]S_n = \frac{n}{2}(T_1 + T_n)[/tex]

[tex]S_n = \frac{51 - n}{2}(n + 50)[/tex]

Recall that the Sum of Integers from 15 to 50 (inclusive) = Sum of integers from n to 50 (inclusive);

This implies that

Sn (i) = Sn (ii)

As such; we have

[tex]S_n = \frac{51 - n}{2}(n + 50) = 1170[/tex]

[tex]\frac{51 - n}{2}(n + 50) = 1170[/tex]

Multiply both sides by 2

[tex]2 * \frac{51 - n}{2}(n + 50) = 1170 * 2[/tex]

[tex](51 - n)(n + 50) = 1170 * 2[/tex]

[tex](51 - n)(n + 50) = 2340[/tex]

Open Brackets

[tex]51(n + 50) - n(n + 50) = 2340[/tex]

[tex]51*n + 51 * 50 - n * n - n * 50 = 2340[/tex]

[tex]51n + 2550 - n^2 - 50n = 2340[/tex]

Reorder

[tex]-n^2 + 51n - 50n + 2550 = 2340[/tex]

[tex]-n^2 + n + 2550 = 2340[/tex]

Subtract 2340 from both sides

[tex]-n^2 + n + 2550 -2340 = 2340 -2340[/tex]

[tex]-n^2 + n + 210 = 0[/tex]

Multiply both sides by -1

[tex]-1(-n^2 + n + 210) = -1 * 0[/tex]

[tex]n^2 - n - 210 = 0[/tex]

At this point, we have a quadratic equation; as such, it'd be solved as follows:

[tex]n^2 - n - 210 = 0[/tex]

Expand

[tex]n^2 + 15n - 14n - 210 = 0[/tex]

Factorize

[tex]n(n + 15) - 14(n + 15) = 0[/tex]

[tex](n - 14)(n + 15) = 0[/tex]

Split the above expression

[tex](n - 14) = 0 \ or\ (n + 15) = 0[/tex]

[tex]n - 14 = 0 \ or\ n + 15 = 0[/tex]

[tex]n = 14\ or\ n = -15[/tex]

The question states that n < 15;

This means that we'll discard the value of n = 14

Hence, n = -15

an = -2 + 3/2 (n-1)
What is the 21st term of the sequence?​

Answers

Answer:

[tex]a_{n} = -83/40[/tex]

Step-by-step explanation:

Given

[tex]a_{n} = -2 + 3/2 (n-1)[/tex]

In this problem to find 21st term we put 21 in place of n in the equation

[tex]a_{n} = -2 + 3/2 (21-1) = \\a_{n} = -2 + 3/2 (20)\\a_{n} = -2 + 3/40 = (-2*40 +3)/40 \\a_{n} = -83/40\\[/tex]

Thus, 21st term is -83/40.

Which statements could he include in his explanation?
Select two options.
Keshawn is asked to compare and contrast the domain
and range for the two functions.
f(x) = 5x
g(x) = 5
The domain of both functions is all real numbers.
The domain of f(x) is x>5.
The domain of g(x) is x > 5.
The range of f(x) is y> 0.
The range of g(x) is y>0.

Answers

Answer:

Option 1: Domain of both functions are all real numbers.

Step-by-step explanation:

f(x) = 5x

Domain: All Real Numbers

Range: All Real Numbers

g(x) = 5

Domain: All Real Numbers

Range: y > 5

Answer: Option 1

Step-by-step explanation:

f(x) = 5x

Domain: All Real Numbers

Range: All Real Numbers

g(x) = 5

Domain: All Real Numbers

Range: y > 5


The following is a geometric sequence. Find the next number in this sequence.
1, -2, 4

Answers

Answer:8

Might I be right

Step-by-step explanation:

Identify the explicit function for the sequence in the table.

Answers

Answer:C

Step-by-step explanation: substitute n=3 for all equations and see which equation accurately correlates to the graph for when x=3. When you do this you see that only option C is the correct equation

Answer:

C). [tex]a(n) = 7 + (n - 1) * 12[/tex]

Step-by-step explanation:

Plugin values into the equation.

The total amount of water a tank can hold is 14 and one-half gallons. Raul wants to find out how many 1 and one-fourth-gallon buckets of water can be used to fill the tank. Which expressions could be used to represent this scenario? Select two options.. StartFraction 29 over 2 EndFraction divided by StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction times StartFraction 4 over 5 EndFraction StartFraction 2 over 29 EndFraction times StartFraction 5 over 4 EndFraction StartFraction 29 over 2 EndFraction divided by StartFraction 4 over 5 EndFraction

Answers

Answer:

Water a tank can hold = 14 1/2 = 29/2

Volume of bucket 1 1/4 = 5/4

The expresson can be

29/2 / 5/4

No. of buckets used = 29/2 x 4/5

Answer:

b and e

Step-by-step explanation:

Find the value of x in this figure

A. 120
B. 105
C. 115
D. 110

Answers

Answer:

A. 120

Step-by-step explanation:

To find the measure of x, you would need to subtract the major arc minus the minor arc. A circle is 360 degrees so, 360-60=300. That is the major arc. Now, we use the formula, x=1/2(major-minor). When we plug the information in, we get 1/2(300-60)...1/2(240)...x=120.

Hence,

the correct option would be 120.

Hope this helps!!! PLZ MARK BRAINLIEST!!!

Use the tables below to find (p - 9)(2).

Answers

Answer:

5

Step-by-step explanation:

p(2) - q(2)

3 - (-2)

3 + 2

= 5

Find the volume of a pyramid with a square base, where the area of the base is
14.1 in' and the height of the pyramid is 11.1 in. Round your answer to the nearest
tenth of a cubic inch.

Answers

I think its 57.17 or about 52.2cubic inch

Mr. Prasad has a Savings Account in a bank. How much money will he have in his account at the end of the first year if he saves $55.00 every
month?​

Answers

Answer: $660

Step-by-step explanation:

If he saves $ 55 every month, he will have

55 x 12 = 660

Please help with this

Answers

Answer:

5/2

Step-by-step explanation:

We take the ratio of a side of ABC over the same side on DEF

AB/ DE

35/14

Divide top and bottom by 7

5/2

Find the amount in an account where $500 in invested at 2.5% compounded quarterly for a period of 10 years.

Answers

Answer: $641.51

Step-by-step explanation:

A = p (1+ r/n)^nt

A = 500 (1 + 0.025/4)^4*10

A = 641.51

The amount in an account where $500 in invested at 2.5% is $641.51.

Using this formula

A = p (1+ r/n)^nt

Where:

A=Amount

P= Principal=$500

R=Rate=2.5% or 0.025

n=4 (Quarterly)

T=Time=10 years

Let pug in the formula

A = $500(1 + 0.025/4)^4×10

A=$500(1.28302)

A =$641.51

Inconclusion the amount in an account where $500 in invested at 2.5% is $641.51.

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What is the maximum number of y-intercepts a line can have?
I will mark brainliest!

Answers

Answer:

one

Step-by-step explanation:

The maximum number of y intercepts a line can have is one

A line can only cross the y axis one time

A line can only cross the x axis one time

Otherwise it is not linear

Given a graph for the transformation of f(x) in the format g(x) = f(kx), determine the k value. two parabolas open up with f of x passing through 8 comma 6 and g of x passing through 2 comma 6 k = −4 k = negative one fourth k = one fourth k = 4

Answers

Here we have a problem of transformations, particularly, horizontal dilations.

We will find that the correct option is k = 4.

We have two functions:

f(x) and g(x) = f(k*x)

We know that:

f(x) passes through the point (8, 6)

This means that:

f(8) = 6

And we know that g(x) passes through (2, 6)

this means that:

g(2) = 6

Using these two and the representation of g(x), we can see that:

g(2) = f(k2) = 6

and we knew that f(8) = 6

then

k2 = 8

k = 8/2 = 4

Then the value of k is 4.

If you want to learn more, you can read:

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Answer:

k = 4

Step-by-step explanation:

i took the test and got it right just wanted to confirm th other answer cause the score isnt super good

Solve 3n - 5p + 2n = 10p for n

Answers above

Answers

Answer:

D

Step-by-step explanation:

3n - 5p + 2n = 10p

Add like terms.

5n - 5p = 10p

Add 5p to both sides.

5n = 10p + 5p

5n = 15p

Divide both sides by 5.

n = 15/5p

n = 3p

The solution of expression for n is,

⇒ n = 3p

We have to given that,

An expression to solve,

⇒ 3n - 5p + 2n = 10p

Now, We can solve the expression for n as,

⇒ 3n - 5p + 2n = 10p

Combine like terms,

⇒ 3n + 2n = 10p + 5p

⇒ 5n = 15p

Divide by 5 both side,

⇒ n = 15p/5

⇒ n = 3p

Therefore, The correct option is,

D. n = 3p

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Triangle △ABC has an altitude CD . Which of the three points, A, B, D are between the other two if angles A and B are both acute?

Answers

Hi!

Out of the three points D is between the other two acute angles if A and B are both acute.

Hope this helps!

D is point lies between A and B.

Triangle △ABC has an altitude CD.
angles A
and B are both acute.

What is altitude?

Altitude is perpendicular bisector to side of triangle from opposite vertex of triangle.

Since △ABC
A
and B are acute angles, and that altitude CD has one vertex at c and other is between A and B i.e. D

Thus, the required point of Altitude CD D lies between A and B.

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HELPPPPP NEEDED FIRST GETS BRAINLLEST !!!! Kobe, Amari, and DJ raised $125.45 for their football team. Kobe collected $24.55 more than Amari, and DJ collected $15.60 less than Kobe. If x = the amount raised by Amari, choose the expressions that represent the amount each other player raised. x + 24.55 x + 8.95 2x – 15.60 3x + 24.55

Answers

Answer:

Kobe raised x + 24.55

Amari raised x

DJ raised 2x – 15.60

PLEASE HELP WILL MARK BRAINLIEST Simplify by removing parentheses​ and, if​ possible, combining like terms. 6m-2(-7m+3)

Answers

Answer:

20m-6

Step-by-step explanation:

[tex]6m-2(-7m+3)=\\6m+14m-6=\\20m-6[/tex]

Answer:

20m - 6

Step-by-step explanation:

6m - 2(-7m + 3)

Expand brackets.

6m + 14m - 6

Add like terms.

20m - 6

Find the missing side length and angles of △ABC given that m∠A=56∘, b=9, and c=11. In triangle A B C, side A B is 11 units long, side A C is 9 units long, and side B C is labeled a. Angle A measures 56 degrees.

Answers

Answer:

1) Side a = 9.55

2) Angle B = 51.36°

3) Angle C = 72.67°

Step-by-step explanation:

We would be solving the above questions using Law of Cosines

1) To find Side a using Law of cosines

a² = b² + c² - 2bc × Cos A

a = √(b² + c² - 2bc × Cos A)

a = unknown

b = 9

c = 11

Angle A = 56°

a = √(9² + 11² - 2 × 9 × 11 × Cos 56°

a = 9.55405

Approximately a = 9.55

2) To find Angle B

We would use the Law of Cosines as well

b² = a² + c² - 2ac × Cos B

Cos B = a² + c² - b²/2ac

B = arc cos ( a² + c² - b²/2ac)

a = 9.55

c = 11

b = 9

B = arc cos (9.55² + 11² - 9²/2 × 9.55× 11)

B = 51.36°

3) To find Angle C

We would use the Law of Cosines as well

c² = a² + b² - 2ac × Cos C

Cos C = a² + b² - c²/2ab

C= arc cos ( a² + b² - c²/2ab)

a = 9.55

b = 9

c = 11

C = arc cos (9.55² + 9² - 11²/2 × 9.55× 9)

C= 72.67°

Represent the number of feet in y yards, f feet
and i inches.​

Answers

Answer: there a 3 feet to a yard a 36 inches to a yard( 12 inches to a foot) 1/3 of a yard is a foot hope this helps

Step-by-step explanation:

Line l has a slope of...

Answers

Hey there! :)

Answer:

Option C.

Step-by-step explanation:

A perpendicular line to 2/3 will be the reciprocal and negative of this fraction. Therefore:

Slope of perpendicular line = -3/2.

Remember, the equation for solving for the slope is:

[tex]m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

We must find points that when plugged into this equation, equal to -3/2.

Plugging in the points in option A:

[tex]\frac{2}{3} \neq \frac{-3}{2}[/tex]

Option B:

[tex]\frac{3}{4} \neq \frac{-3}{2}[/tex]

Option C: This is the correct answer.

[tex]\frac{-3}{2} = \frac{-3}{2}[/tex]

Option D:

[tex]\frac{2}{10}\neq \frac{-3}{2}[/tex]

Hi the answer is c. Hope this helped:)

which properties do equilateral triangles and isosceles triangles have in common? A: 0 sides of equal length. B: 2 sides of equal lengths. C: 3 sides of equal length. D: 3 equal angles. Multiple choice

Answers

Answer:

2 sides of equal length, 3 sides of equal length

Step-by-step explanation:

your welcome✌

The property which equilateral and isosceles triangle have in common is 2 sides of equal length

What Is an Isosceles Triangle?

A triangle with two sides of equal length is an isosceles triangle. The isosceles triangle has three acute angles, meaning that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°.

In an isosceles triangle, the two equal sides are called legs, and the remaining side is called the base. The angle opposite the base is called the vertex angle

The three types of Isosceles Triangles are :

Isosceles acute triangle

Isosceles right triangle

Isosceles obtuse triangle

Given data ,

Let the triangle be represented as ΔABC

Now , A triangle with two sides of equal length is an isosceles triangle.

Both equilateral triangles and isosceles triangles have at least 2 sides of equal length, but only equilateral triangles have all three sides of equal length.

Hence , the triangles have at least 2 sides of equal lengths

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What is the explicit formula for this geometric sequence? 64, 16, 4, 1, ...

Answers

Answer:

C.

Step-by-step explanation:

Explicit Formula: an = a1(r)^(n-1)

Our r = 1/4 because to get 64 down to 16 you need to divide by 4 or multiply by 1/4

Our a1 is the 1st term of the sequence, which is 64.

Plug it in: an = 64(1/4)^(n-1)

So our only viable option is C.

Answer:

Option C

Step-by-step explanation:

=> [tex]a_{n} = a_{1} * r^{(n-1)[/tex]

Where a1 = 64, r = 1/4

So,

=> [tex]a_{n} = 64 * (\frac{1}{4}) ^{n-1}[/tex]

You want to design a survey to determine how much money people are willing to spend
on concert tickets. Which of the following methods would be most practical and have
the least bias?
Choose 4 neighborhoods at random and poll every home in those
neighborhoods.
Poll 10% of the homes in the area chosen at random.
Poll the first 100 people who enter the mall.
Poll everyone in the area.

Answers

Answer:

The correct option is;

Choosing 4 neighborhoods at random and poll every home in those neighborhoods

Step-by-step explanation:

Given that the survey relate to how much money people are willing to spend on on concert tickets with the goal of being practical and unbiased, we have;

Required sampling = Random Sampling

The preferable type of random sampling is either;

1) Simple random sampling

Sampling a given percentage of the homes in the area randomly

2) Clustered random sampling

Completely polling entire population of randomly selected area

Given the practicability of sampling concert goers, since people may have different interests, a better representative sample will be to perform the clustered random sampling approach by choosing 4 neighborhoods at random and poll every home in those neighborhoods.

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