Can you explain these words Rate, Per, Divide, Unit and the connections you see between them. Thank you very kind!!!

Answer:

105/136 ≈ 0.772

Step-by-step explanation:

There are 3 socks and 2 colors, so they are either all the same color or 2 will be different colors.

P(different colors)

= 1 − P(same color)

= 1 − ₁₀C₃/₁₇C₃ − ₇C₃/₁₇C₃

= 1 − 120/680 − 35/680

= 1 − 155/680

= 1 − 31/136

= 105/136

≈ 0.772

Answer:

123454321

Step-by-step explanation:

it's a palendrome, made out of a number of numbers in the sqquence.

Answer:

A =1017.9 cm^2

Step-by-step explanation:

The area of a circle is given by

A = pi r^2

A = pi * (18)^2

Using the pi button

A =1017.87602 cm^2

Rounding to 1 decimal place

A =1017.9 cm^2

Answer:

0.49

Step-by-step explanation:

From the Venn diagram:

The number of students that study biology and physics = 2

The number of students that study biology and chemistry = 6

The number of students that study chemistry and physics = 4

The number of students that study only physics = 5

The number of students that study only biology = 7

The number of students that study only chemistry = 8

The number of students that study all 3 subjects = 3

The number of students that study none = 6

Therefore the total number of students = 2 + 6 + 4 + 5 + 7 + 8 + 3 + 6 = 41 students

The number of students that study chemistry = 8 + 6 + 3 + 4 = 21 students

The number of student that does not study chemistry = 41 - 21 = 20 students

the probability chosen at random that that child does not study chemistry =  number of student that does not study chemistry / total number of students  = 20/41 = 0.49

Answer:

A) [tex]a_{1}[/tex] = 1, [tex]a_{2}[/tex] = 4

B) [tex]a_{n}[/tex] = 2[tex]a_{n-1}[/tex] + 2

C)    [tex]a_{n} = 2^{n-1} + 2^n -2\\a_{n} = 2^n + 2^{n-1} -2[/tex]

Step-by-step explanation:

For n ≥ 1 ,

S is a set containing 2^n distinct real numbers

an = no of comparisons to be made between pairs of elements of s

A)

[tex]a_{1}[/tex] = no of comparisons in set (s)

that contains 2 elements = 1

[tex]a_{2}[/tex] = no of comparisons in set (s) containing 4 = 4

B)  an = 2a[tex]_{n-1}[/tex] + 2

C) using the recurrence relation

a[tex]_{n}[/tex] = 2a[tex]_{n-1}[/tex] + 2

substitute the following values  2,3,4  .......... for n

a[tex]_{2}[/tex] = 2a[tex]_{1}[/tex] + 2

a[tex]_{3}[/tex] = 2a[tex]_{2}[/tex] + 2 = [tex]2^{2} a_{1} + 2^{2} + 2[/tex]

a[tex]_{4}[/tex] = [tex]2a_{3} + 2 = 2(2^{2}a + 2^{2} + 2 ) + 2[/tex]

    = [tex]2^{n-1} a_{1} + \frac{2(2^{n-1}-1) }{2-1}[/tex]   ---------------- (x)

since  2^1 + 2^2 + 2^3 + ...... + 2^n-1 =  [tex]\frac{2(2^{n-1 }-1) }{2-1}[/tex]

applying the sum formula for G.P

[tex]\frac{a(r^n -1)}{r-1}[/tex]

Note ; a = 2, r =2 , n = n-1

a1 = 1

so equation x becomes

[tex]a_{n} = 2^{n-1} + 2^n - 2\\a_{n} = 2^n + 2^{n-1} - 2[/tex]

Answer:

100%

Step-by-step explanation:

Total = 7

Odd or less than 7 = 6+1

=> 7

P(odd or less than 7) = 7/7

In %age:

100%

Answer:

100%

Step-by-step explanation:

Number of cards= 7

Odd or less than 7= 7

P= 7/7=1=100%

Answer:

Step-by-step explanation:

With regards to the factor 'walking device used', the ANOVA conducted on the cadence data revealed a main effect of walking device, and also with the results of the experiment giving rise to a p - value less than 0.05, we can reject the null hypothesis which says, there is no effect of the walking device factor.

We can thus conclude that there is not enough statistics evidence to prove that there is no interaction between the two factors or that there is no effect of the walking device given the cadence data.

Answer:

Option A

Step-by-step explanation:

Given equation is

=> 3y = 6x + 3

In slope-intercept form, it becomes

=> 3y = 3(2x+1)

=> y = 2x+1

So, Slope = m = 2

Parallel lines have equal slope, So any line parallel to the above line would have its slope equal to 2

=> Line parallel to 3y = 6x + 3 is y = 2x + 10

Answer:

Step-by-step explanation:

The complete statement would be "if a line is perpendicular to one of two parallel lines, then it is also perpendicular to the other".

The reason for this is because parallel lines have the same slope, that's the condition. On the other hand, parallel lines have opposite and reciprocal slopes.

So, if you think this through, if a line is perpendicular to another, then it's going to be perpendicular to all different lines which are parallel to the first one, because all their slopes are equivalent, and they will fulfill the perpendicularity condition.

Answer:

Parallel line

Step-by-step explanation:

Hope It Helps

Answer:

A. Reflectional symmetry

Step-by-step explanation:

If the shape is the same characteristics after being reflected, then it is A.

The type of symmetry is Reflectional symmetry.

Reflection symmetric is a symmetry that revolves around reflections. It is characterized as reflection symmetry if, at most, one line splits an image into two halves, with one half being the mirror reflection of the other.

Given that, we need to find that which is best described as the quality a design has if it maintains all of its characteristics when it is reflected over an axis lying in its plane,

So, according to the definition of the reflection symmetry the design will attain its exact position before and after the reflection when is reflected over an axis lying in its plane, is a reflection symmetry.

Hence, the type of symmetry is Reflectional symmetry.

Learn more about Reflectional symmetry click;

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Answer:

Step-by-step explanation:

No, it is not an even function.  The graph is not symmetric about the y-axis.

Answer:

work shown and pictured

Answer:

The 97% upper confidence limit for the proportion of green items is 0.502.

Step-by-step explanation:

We have to calculate a 97% upper confidence limit for the proportion.

The sample proportion is p=0.294.

[tex]p=X/n=5/17=0.294\\[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.294*0.706}{17}}\\\\\\ \sigma_p=\sqrt{0.01221}=0.11[/tex]

The critical z-value for a 97% upper confidence limit is z=1.881.

The margin of error (MOE) can be calculated as:

[tex]MOE=z\cdot \sigma_p=1.881 \cdot 0.11=0.208[/tex]

Then, the upper bound is:

[tex]UL=p+z \cdot \sigma_p = 0.294+0.208=0.502[/tex]

The 97% upper confidence limit for the proportion of green items is 0.502.

ANSWER :

Percentage = 50%

(if it odd and even then its 100%)

Answer:

100%

Step-by-step explanation:

There is a 100% chance rolling an odd or even since all the faces of this die are odd or even.

Answer:

(a) The probability you pass the exam is 0.0000501.

(b) The expected number of correct guesses is 7.5.

(c) The standard deviation is 2.372.

Step-by-step explanation:

We are given that you take a 30-question, multiple-choice test, in which each question contains 4 choices: A, B, C, and D. And you randomly guess on all 30 questions.

Since there is an assumption of only 1 correct choice out of 4 which means the above situation can be represented through binomial distribution;

[tex]P(X =x) = \binom{n}{r}\times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,3,......[/tex]

where, n = number of trials (samples) taken = 30

           r = number of success = at least 60%

           p = probbaility of success which in our question is the probability

                 of a correct answer, i.e; p = [tex]\frac{1}{4}[/tex] = 0.25

Let X = Number of questions that are correct

So, X ~ Binom(n = 30 , p = 0.25)

(a) The probability you pass the exam is given by = P(X [tex]\geq[/tex] 18)

Because 60% of 30 = 18

P(X [tex]\geq[/tex] 18) = P(X = 18) + P(X = 19) +...........+ P(X = 29) + P(X = 30)

= [tex]\binom{30}{18}\times 0.25^{18}\times (1-0.25)^{30-18} + \binom{30}{19}\times 0.25^{19}\times (1-0.25)^{30-19} +.......+ \binom{30}{29}\times 0.25^{29}\times (1-0.25)^{30-29} + \binom{30}{30}\times 0.25^{30}\times (1-0.25)^{30-30}[/tex]

= 0.0000501

(b) The expected number of correct guesses is given by;

  Mean of the binomial distribution, E(X) =  [tex]n \times p[/tex]

                                                                =  [tex]30 \times 0.25[/tex] = 7.5

(c) The standard deviation of the binomial distribution is given by;

      S.D.(X)  =  [tex]\sqrt{n \times p \times (1-p)}[/tex]

                    =  [tex]\sqrt{30 \times 0.25 \times (1-0.25)}[/tex]

                    =  [tex]\sqrt{5.625}[/tex]  =  2.372                

Answer:

Step-by-step explanation:

x represents the number of miles you have walked

y represents your distance from home in miles.

The relationship between these two variables can be expressed by the following equation: y=x+5

The dependent variable is that whose value changes whenever the value of the independent variable is changed.

From the equation above:

We can clearly see that y changes for different values of x.

Therefore:

Answer:

1dependant

2independant

Step-by-step explanation:

Answer:

The  interval is  [tex]0.7187 < p < 2.421[/tex]

Step-by-step explanation:

From the question we are told that

      The  sample size is  [tex]n = 100[/tex]

       The  population  proportion is [tex]p = 0.81[/tex]

       The  confidence level is  C =  98%

The level of significance is mathematically evaluated as

     [tex]\alpha = 100 -98[/tex]

    [tex]\alpha = 2%[/tex]%

    [tex]\alpha = 0.02[/tex]

Here this level of significance represented the left and the right tail

The degree of  freedom is evaluated as

     [tex]df = n-1[/tex]

substituting value  

    [tex]df = 100 - 1[/tex]

     [tex]df = 99[/tex]

Since we require the critical value of one tail in order to evaluate the  98% confidence interval that estimates the proportion of them that are involved in an after school activity. we will divide the level of significance by 2

The  critical value of  [tex]\frac{\alpha}{2}[/tex] and the evaluated degree of freedom is  

      [tex]t_{df , \alpha } = t_{99 , \frac{0.02}{2} } = 2.33[/tex]

this is obtained from the critical value table  

The standard error is mathematically evaluated as

             [tex]SE = \sqrt{\frac{p(1-p )}{n} }[/tex]  

substituting value  

           [tex]SE = \sqrt{\frac{0.81(1-0.81 )}{100} }[/tex]  

           [tex]SE = 0.0392[/tex]  

The 98%  confidence interval is evaluated as

      [tex]p - t_{df , \frac{\alpha }{2} } * SE < p < p + t_{df , \frac{\alpha }{2} }[/tex]

substituting value  

     [tex]0.81 - 2.33 * 0.0392 < p < 0.81 +2.33 * 0.0392[/tex]

      [tex]0.7187 < p < 2.421[/tex]

Answer:

p=0.9

Step-by-step explanation:

Total Sample of Candles =100

Number of defective Candles = 10

Therefore, the number of fault-free candles =100-10=90

A point estimate of the probability that a fault-free candle is produced is:

[tex]p=\dfrac{90}{100}\\\\ p=0.9[/tex]

Answer:

thank u

Step-by-step explanation:

Answer:

1/9

Step-by-step explanation:

Separate the fraction (1/9) from the variable x:

y = (1/9)x.

1/9 is the constant of proportionality.

Answer:

P10 = 27.4

P90 = 22.0

It helps the producer to know the higher (P10) and lower estimates (P90) for the amount of chocolate chips per cookie.

Step-by-step explanation:

In P10 and P90 the P stands for "percentile".

In the case of P10, indicates the value X of the random variable for which 10% of the observed values will be above this value X.

In the case of P90, this percentage is 90%.

In this case, we can calculate from the z-values for each of the percentiles in the standard normal distribution.

For P10 we have:

[tex]P(z>z_{P10})=0.1\\\\z_{P10}=1.2816[/tex]

For P90 we have:

[tex]P(z>z_{P90})=0.9\\\\z_{P90}=-1.2816[/tex]

Then, we can convert this values to our normal distribution as:

[tex]P10=\mu+z\cdot\sigma=24.7+1.2816\cdot 2.1=24.7+2.7=27.4 \\\\P90=\mu+z\cdot\sigma=24.7-1.2816\cdot 2.1=24.7-2.7=22.0[/tex]

Answer:

Critical value zc = 1.6449.

As the test statistic z=1.3881 is smaller than the critical value zc=1.6449, it falls in the acceptance region and the null hypothesis is failed to be rejected.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that more than 22% of the population will like the new soft drink.

Then, the null and alternative hypothesis are:

[tex]H_0: \pi=0.22\\\\H_a:\pi>0.22\\[/tex]

The significance level is 0.05.

The sample has a size n=400.

The sample proportion is p=0.25.

[tex]p=X/n=100/400=0.25[/tex]

The standard error of the proportion is:

[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.22*0.78}{400}}\\\\\\ \sigma_p=\sqrt{0.000429}=0.0207[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.25-0.22-0.5/400}{0.0207}=\dfrac{0.0288}{0.0207}=1.3881[/tex]

As this is a right-tailed test, there is only one critical value and it is, for a significance level of 0.05, zc=1.6449.

As the test statistic z=1.3881 is smaller than the critical value zc=1.6449, it falls in the acceptance region and the null hypothesis is failed to be rejected.

Answer:

33

Step-by-step explanation:

An = 6n+3

so the first five terms in sequences is A5= 6*5 +3 = 33

Answer:

unit rate of lemonade to cranberry juice

= 5:1

Step-by-step explanation:

A recipe for fruit punch calls for 1/2 liter of lemonada and 1/10 liter of cranberry juice

1/2 liter of lemonada= 0.5

1/10 liter of cranberry juice = 0.1

unit rate of lemonade to cranberry juice

= 0.5/0.1

unit rate of lemonade to cranberry juice

= (5*10^-1)/(1*10^-1)

unit rate of lemonade to cranberry juice

= 5/1 *(10^-1)/10^-1)

unit rate of lemonade to cranberry juice

= 5/1

unit rate of lemonade to cranberry juice

= 5:1

The unit rate of lemonade to cranberry juice is 5 : 1.

1/2 liters of lemonada are to be mixed with 1/10 litres of cranberry juice.

In ratio form this is:

1/2 : 1/10

To make it a unit rate of lamonada, you should divide both sides by the ratio of lamonada to cranberry juice in order to take lomonada's ratio to 1.

= 1/2 ÷ 1/2 :  1/10 ÷1/2

= 1 : 0.2

You then need to make the decimal a whole number by dividing both sides by the decimal:

= 1 ÷ 0.2 : 0.2 ÷0.2

= 5 : 1

The unit rate of lamonada to cranberry juice is therefore 5 : 1.

Find out more at https://brainly.com/question/18314944.

Answer:

Options (D), (E) and (F) are the correct options.

Step-by-step explanation:

From the figure attached,

1). Angle 4 is the exterior angle of the given triangle having interior angles 1, 2 and 3.

Therefore, by the property of exterior angle,

∠4 = ∠1 + ∠2

2). Since ∠4 = ∠1 + ∠2,

Therefore, ∠4 will be greater than ∠1

 Similarly, ∠4 will be greater than ∠2

Therefore, Options (D), (E) and (F) are the correct options.

Answer:

SOLUTION SET={x/x>-1} and SOLUTION SET={x/x<-1}

Step-by-step explanation:

1)4x-39>-43

evaluating the inequality

adding 39 on both sides

4x-39+39>-43+39

4x>-4

dividing 4 on both sides

4x/4>-4/4

x>-1

SOLUTION SET={x/x>-1}

2)8x+31<23

evaluating the inequality

subtracting 31 on both sides

8x+31-31<23-31

8x<-8

dividing 8 on both sides

8x/8<-8/8

x<-1

SOLUTION SET={x/x<-1}

i hope this will help you :)

Answer: There are no solutions

Step-by-step explanation:Khan Academy

Answer:

option 3 is the answer.

Answer:

The breadth is 16m because a square is a quadrilateral (four sided shape) that has all its side to be of equal measure.

Answer:

A

Step-by-step explanation:

9-2x≤3x+24

-15≤5x

-3≤x

so it's:

[-3,∞)

Answer:

The equation is:

[tex]L=3\,\,d^2\\[/tex]

and a beam with 10 in diagonal will support 300 lb

Step-by-step explanation:

The mathematical expression that represents the statement:

"The maximum load a beam will support varies directly with the square of the diagonal of the beam’s cross-section. "

can be written as:

[tex]L=k\,\,d^2[/tex]

where k is the constant of proportionality

To find the constant we use the data they provide: "A beam with diagonal 6 in will support a maximum load of 108 lb.":

[tex]L=k\,\,d^2\\108 = k\,\,(6)^2\\k=\frac{108}{36} \,\,\frac{lb}{in^2}\\ k = 3\,\,\frac{lb}{in^2}[/tex]

Now we can use the proportionality found above to find the maximum load for a 10 in diagonal beam:

[tex]L=3\,\,d^2\\L=3\,\,(10)^2\\L=300 \,\,lb[/tex]

Answer:

L=3d^2 the beam will support 300 pounds

Step-by-step explanation:

108=k x 6^2

Dividing by 6^2=36 gives k=3, so an equation that relates L and d is

L=3d^2 d=10 yields

3(10)^2=300

So a beam with a 10in diagonal will support a 300lb load.

Answer:

Lower Quartile: 62

Upper Quartile: 81

Interquartile Range: 19

Step-by-step explanation:

To find the lower quartile, you want to find the median from the minimum to the median.

49, 55, 62, 64, 67

The median of this is 62. Therefore, 62 is the lower quartile.

To find the upper quartile, you want to find the median from the median to the maximum.

76, 79, 81, 82, 83

The median of this is 81. Therefore, 81 is the upper quartile.

To find the interquartile range, you subtract the upper and lower quartile.

81-62=19

The difference is 19. Therefore, the interquartile range is 19.