Can y’all help me with this question

Answer:

0.2 mole

Explanation:

From the question given above, the following data were obtained:

Number of molecules = 12.06×10²²

Number of mole =?

From Avogadro's hypothesis,

6.02×10²³ molecules = 1 mole

Therefore,

12.06×10²² molecules = 12.06×10²² / 6.02×10²³

12.06×10²² molecules = 0.2 mole

Thus, 12.06×10²² molecules is equivalent to 0.2 mole

Answer:

+3

Explanation:

NH₄F

=> N + 4H + F = 0

=> N + 4(+1) + 1(-7) = 0

=> N = 7 - 4 = +3

Answer:

1:aerobic

2:anaerobic

3:aerobic

Answer:

Living things need nonliving things to survive. Without food, water, and air, living things die. Sunlight, shelter, and soil are also important for living things. ... Plants use water from the soil, carbon dioxide from the air, and energy from sunlight to make their own food.

Explanation:

Answer: yes they do here are is an example a tree depends on water to keep it hydrated.  

Explanation:

Hi there!

[tex]\large\boxed{4.04g}[/tex]

To solve, we can use dimensional analysis to convert from molecules to grams.

We must use Avogadro's number (6.02 × 10²³) in converting from molecules to moles.

After converting, multiply by the atomic mass, or grams per mole.

[tex]1.204 * 10^{24} moles *\frac{1 mol}{6.02*10^{23}moles}* \frac{2.02g}{1mol }= 4.04g[/tex]

Answer:C

Explanation:

It would be the most visually understandable.It would be easyer to understand what you are modeling.

Answer:

[tex]6molNa\\\\9molN_2[/tex]

Explanation:

Hello there!

In this case, given the chemical reaction:

[tex]2NaN_3\rightarrow 2Na+3N2[/tex]

It is possible to evidence the 2:2 mole ratio of the reactant to Na and the 2:3 mole ratio of the reactant to the N2; therefore, the following setups allows us to compute the moles of products:

[tex]6molNaN_3*\frac{2molNa}{2molNaN_3}=6molNa\\\\6molNaN_3*\frac{3molN_2}{2molNaN_3}=9molN_2[/tex]

Best regards!

139 g Cu

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 2.18 mol Cu

[Solve] grams Cu

Step 2: Identify Conversion

[PT] Molar Mass of Cu - 63.55 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

138.539 g Cu ≈ 139 g Cu

Answer:

Radio waves are able to penetate the earth's atmosphere due to their low frequency and long wavelength.

Let me know if this helps!

Answer:

Without the process of cell differentiation, multicellular organisms would not be possible.

Answer:

C₃H₃O₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 0.5242 g

Mass of CO₂ = 0.9740 g

Mass of H₂O = 0.1994 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:

For carbon, C:

Mass of CO₂ = 0.9740 g

Molar mass of CO₂ = 12 + (16×2)

= 12 + 32 = 44 g/mol

Mass of C = 12/44 × 0.9740

Mass of C = 0.2656 g

For hydrogen, H:

Mass of H₂O = 0.1994 g

Molar mass of H₂O = (2×1) + 16

= 2 + 16 = 18 g/mol

Mass of H = 2/18 × 0.1994

Mass of H = 0.0222 g

For oxygen, O:

Mass of compound = 0.5242 g

Mass of C = 0.2656 g

Mass of H = 0.0222 g

Mass of O =?

Mass of O = (Mass of compound) – (Mass of C + Mass of H)

Mass of O = 0.5242 – (0.2656 + 0.0222)

Mass of O = 0.5242 – 0.2878

Mass of O = 0.2364 g

Finally, we shall determine the empirical formula. This can be obtained as follow:

Mass of C = 0.2656 g

Mass of H = 0.0222 g

Mass of O = 0.2364 g

Divide by their molar mass

C = 0.2656 /12 = 0.0221

H = 0.0222 /1 = 0.0222

O = 0.2364 /16 = 0.0148

Divide by the smallest

C = 0.0221 / 0.0148 = 1.5

H = 0.0222 / 0.0148 = 1.5

O = 0.0148 / 0.0148 = 1

Multiply through by 2 to express in whole number.

C = 1.5 × 2 = 3

H = 1.5 × 2 = 3

O = 1 × 2 = 2

Empirical formula => C₃H₃O₂

Answer:

The frequency of the electromagnetic wave is 7.22891566 × 10¹⁴ Hz

Explanation:

The wavelength of the electromagnetic wave, λ = 415 nm

The speed of an electromagnetic wave, c ≈ 3.0 × 10⁸ m/s

Given that an electromagnetic wave is a periodic wave, we have;

The speed of the electromagnetic wave, c = f×λ

Where;

f = The frequency of the electromagnetic wave

Therefore, we have;

f = c/λ

From which we have;

f = (3.0 × 10⁸ m/s)/(415 nm) = 7.22891566 × 10¹⁴ /s = 7.22891566 × 10¹⁴ Hz

The frequency of the electromagnetic wave, f = 7.22891566 × 10¹⁴ Hz

Answer:

3.34 M

Explanation:

Step 1: Given data

Step 2: Calculate the moles of acetic acid

The molar mass of acetic acid is 60.05 g/mol.

100 g × 1 mol/60.05 g = 1.67 mol

Step 3: Calculate the molarity of acetic acid

The molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

M = 1.67 mol/0.5000 L = 3.34 M

Answer:

41000 is the answer

The amount of microliters in 41.0 mL is 41,000 microliters

To convert milliliters (mL) to microliters (µL), you need to multiply the value in milliliters by 1000 because there are 1000 microliters in 1 milliliter.

So, to convert 41.0 mL to microliters:

41.0 mL * 1000 = 41,000 µL

Therefore, there are 41,000 microliters in 41.0 mL.

Learn more about microliters at

https://brainly.com/question/32138755

#SPJ6

Answer:

Both the system and the surroundings are losing 260 J. The system is gaining 260 J, while the surroundings are losing 260 J. Both the system and the surroundings are gaining 260 J. The system is losing 260 J, while the surroundings are gaining 260 J. None of the above is true.

Answer:

1. Causes air to vibrate 2. A hydroelectric dam generating electricity on a river

Answer:

Mn= +3 charge

Explanation:

if you take what we know, and that would be the charge of oxygen, we know that oxygen has a 2- charge and there are 3 sets of O^2-  so multiply the number of oxygen times the charge and you get 6-.

Next set up an equation as listed in the picture  which will be 2(x)=6

and that is the charge of the Mn ion.

Answer:

Cathode: Mn → Mn²⁺  +  2e⁻    (Oxidation)

Anode: Zn²⁺  +  2e⁻  →  Zn   (Reduction)

Mn | Mn²⁺ ||  Zn²⁺  | Zn

Explanation:

To identify the half reaction we need to see the oxidation states.

Mn(s) → Ground state → Oxidation state = 0

Mn(NO₃)₂ → Mn²⁺  → The oxidation state has increased.

This is the oxidation reaction. It has released two electrons:

Mn → Mn²⁺  +  2e⁻

Zn(NO₃)₂ →  Zn²⁺

Zn → Ground state → The oxidation state was decreased.

This is the reduction reaction. It has gained two electrons:

Zn²⁺  +  2e⁻  →  Zn

Cathode: Mn → Mn²⁺  +  2e⁻

Anode: Zn²⁺  +  2e⁻  →  Zn

Mn | Mn²⁺ ||  Zn²⁺  | Zn

about the door is locked and I think I have a few questions about the door is locked and I think I have

Explanation:

can you tell me what the door is locked and I think I have a few questions about the door is locked and I think I have a few questions

Answer:

aluminum nitrate

Explanation:

We already know that calcium carbonate is insoluble in water hence it will not even dissolve in the water.

Mercury(I) nitrate is soluble in water, when sodium sulfate (Na2SO4) is added to mercury(I) nitrate (Hg2(NO3)2), a pale yellow precipitate is formed.

Aluminum nitrate is soluble in water and reacts with Na2SO4(aq) solution according to the reaction, 2Al(NO3)3(aq)+3Na2SO4(aq) ---> Al2(SO4)3(s)+6NaNO3(aq). The precipitate, Al2(SO4)3(s) is a white crystalline hygroscopic solid.

Answer:

Pure Water

Explanation:

The common ion effect describes the effect on ​equilibrium that occurs when a common ion (an ion that is already contained in the solution) is added to a solution. The common ion effect generally decreases ​solubility of a solute(Khan Academy).

NaCl, AgNO3, KCl, BaCl2 solutions all have a common ion with AgCl. As a result of this, AgCl will be much less soluble in these solvents than it is in pure water.

Therefore, AgCl will have the highest solubility in pure water compared to all the solutions listed above.

Answer:

Explanation:Reaction NaHCO3 + HCl ⇒ NaCl + H2O + CO2

Molar mass M = (22.99+1.008+ 12.01+3·16 ) g/mol. Calculate

Amount of substance n =m/M, n(NaCl) is equal.

M(NaCl) = 58.44 g/mol and mass m= n·M

0.127 mol Au

Math

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Stoichiometry

Step 1: Define

[Given] 25.0 g Au

[Solve] moles Au

Step 2: Identify Conversions

[PT] Molar Mass of Au - 196.97 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

0.126923 mol Au ≈ 0.127 mol Au

Answer:

[tex]\boxed {\boxed {\sf 0.127 \ mol \ Au}}[/tex]

Explanation:

To convert from mass to moles, the molar mass must be used. This can be found on the Periodic Table.

Use this number as a ratio.

[tex]\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]

Multiply by the given number of grams.

[tex]25.0 \ g \ Au*\frac {196.96657 \ g\ Au }{1 \ mol \ Au}[/tex]

Flip the fraction so the grams of gold will cancel.

[tex]25.0 \ g \ Au*\frac {1 \ mol \ Au}{196.96657 \ g\ Au }[/tex]

[tex]25.0*\frac {1 \ mol \ Au}{196.96657 }[/tex]

[tex]\frac {25.0 \ mol \ Au}{196.96657 }[/tex]

[tex]0.1269250919 \ mol \ Au[/tex]

The original measurement has 3 significant figures, so the answer must have the same. For the number we calculated that is the thousandth place. The 9 in the ten thousandth place tells us to round the 6 to a 7.

[tex]0.127 \ mol \ Au[/tex]

25.0 grams of gold is about 0.127 moles of gold.

Answer:

Electrical energy

Explanation:

The wind Mill is an example of a device that converts wind energy into electrical energy

Explanation:

If we compare its solubility products without any calculation then, Magnesium hydroxide is more soluble than compound A and C. Magnesium hydroxide is less soluble than compound D.

- The solubility product of magnesium hydroxide and zinc carbonate is same so it is not possible to determine whether it is more or less soluble than compound B

Answer: The answer is both diseases and availability of resources can limit the growth of a population of organisms which is A

Explanation:

Answer:

1. Barium Acetate.

2. Formula: Ba(C2H3O2)2.

3. Molar Mass: 255.415.

Explanation:

Answer:

1. Dynamic equilibrium is a equilibrium in which the rate of forward direction is equal to the rate of backward direction. It is represented by a right left arrow.

2) Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]  

For the given chemical reaction:

[tex]Fe^{3+}(aq)+SCN^-(aq)\rightleftharpoons [Fe(SCN)]^{2-}(aq)[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[[Fe(SCN)]^{2-}]}{[Fe^{3+}][SCN^-]}[/tex]

3) The value of [tex]K_c[/tex] is 1000 , which means the products are more favoured as compared to reactants and that the equilibrium lies more towards product side.