Can two fraction with the same numerator and different denominators be equal? Use words and numbers to explain.

Answers

Answer 1

Step-by-step explanation:

Since equivalent fractions do not always have the same numerator and denominator, one way to determine if two fractions are equivalent is to find a common denominator and rewrite each fraction with that denominator. Once the two fractions have the same denominator, you can check to see if the numerators are equal.

Answer 2

The two fractions with the same numerator and different denominators can not be equal.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

A division number is a number that addresses the piece of the entire, where the entire can be any number. It is a numerator and a denominator.

The fraction is in the form of a numerator and denominator. The two fractions can be equal if and only if their numerator and denominator are equal.

The two divisions with similar numerators and various denominators can not be equivalent.

More about the Algebra link is given below.

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Related Questions

Of the factors of 12 shown, which also have a sum of 7?

A: 12,1

B: 2,6

C: 3,4

Answers

The answer is C because 3 and 4 add together to equal 7

Please please please hellllllppp meeeeee !!!!!!!!!

Answers

ANSWER: 77
Explanation: Making 88 in 8 minutes means that the machine is making 11 per minute thus being said if the machine worked for 7 minutes it would make 77 pens.
88/8=11
11*7=77

What is the value of the expression shown? 4[4.5 − 2(1.2)]

Answers

8.4 or 8 2/5 or 42/5

2x1.2
4(4.5-2.4)
4 x 2.1
8.4

ANSWER: 8.4 or 8 2/5 or 42/5

please mark brainliest if my answer is correct;)

The rational function f is defined as, where h and g are polynomials.
The degree of h is m and the degree of g is n.
Which of the following statements are TRUE?


I. If m > n the absolute value of the function approaches positive infinity as x gets very large.


II. If m < n the value of the function approaches zero as x gets very large.


III. If m = n the value of the function approaches a constant as x gets very large.

Answers

Answer:

g

Step-by-step explanation:

x goes to f m to 5 :-)

please help with this question (d+2)(-7)

Answers

Answer:

-7d-14

Step-by-step explanation:

First, let's distribute -7 to (d+2)

-7xd

-7x2

We will get -7d-14

The answer is -7d - 14!

Lacey is buying a new car. She can get a station wagon, a truck, a hatchback, or a convertible. The outside paint comes in yellow or green. The seats can be covered with white leather or gray fabric. Given these choices, how many different combinations does Lacey have to choose from?

Answers

Step-by-step explanation:

4 different vehicles,

2 different paints,

2 different seats.

Total number of combinations = 4 * 2 * 2 = 16.

a) Solve x² + 4x - 8 = 0 by completing the square​

Answers

Answer:

x = 2 + 2i, x = 2 - 2i

Step-by-step explanation:

[tex] {x}^{2} - 4x + 8 = 0 \\ \\ {x}^{2} - 4x + 4 + 4= 0 \\ \\ {x}^{2} - 4x + {(2)}^{2} = - 4 \\ \\ {(x - 2)}^{2} = - 4 \\ \\ x - 2 = \pm \sqrt{ - 4} \\ \\ x - 2 = 2i \\ \\ x = 2 \pm 2i \\ \\ x = 2 + 2i, \: \: \: x = 2 - 2i[/tex]

Bea is asked to graph this system of equations:
8x - 6y=3
-3y + 4x + 4
How many times will the lines intersect?

Answers

Answer:

The lines will not intersect, because this system has no solutions

Step-by-step explanation:

Answer:

They will not intersect!

Step-by-step explanation:

A-P-E-X

Which of these graphs represents a function?
A)
A
B)
B
C)
С
D)
D

Answers

Do the vertical line test and draw a straight line.

Solution: C represents a function
B represents a function

simplify x^2 + ax - 2a^2÷
3a^2 - 2ax - x^2?

Answers

Answer:

[tex] - \frac{x + 2a}{3a + x} [/tex]

Step-by-step explanation:

[tex] \frac{ {x + ax - 2 {a}}^{2} }{3a {}^{2} - 2ax - {x}^{2} } [/tex]

i) write ax as a difference

[tex] \frac{ {x}^{2} + 2ax - ax - 2 {a}^{2} }{3 {a}^{2} - 2ax - x {}^{2} } [/tex]

ii) write -2ax as a difference

[tex] \frac{ {x}^{2} + 2ax - ax - 2a {}^{2} }{3a {}^{2} + ax - 3ax - x {}^{2} } [/tex]

iii) factor out x from the expression

[tex] \frac{x(x + 2a) - ax - 2 {a}^{2} }{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]

iv) factor out -a from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{3 {a}^{2} + ax - 3ax - {x}^{2} } [/tex]

v) factor out a from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - 3ax - {x}^{2} } [/tex]

vi) factor out -x from the expression

[tex] \frac{x(x + 2a) - a(x + 2a)}{a(3a + x) - x(3a + x)} [/tex]

vii) factor out x+2a from the expression

[tex] \frac{(x + 2a)(x - a)}{a(3a + x) - x(3a + x)} [/tex]

viii) factor out 3a+x from the expression

[tex] \frac{(x + 2a)(x - a)}{(3a + x)(a - x)} [/tex]

ix) factor out the negative sign from the expression and rearrange the term

[tex] \frac{(x + 2a)( - ( - a - x))}{(3a + x)(a - x)} [/tex]

x) reduce the fraction a-x

[tex] \frac{(x + 2a)( - 1)}{(3a + x)} [/tex]

[tex] - \frac{x + 2a}{3a + x} [/tex]

Evaluate the limit, if it exists. PLEASE SHOW WORK
lim x 5 x^2-3x-10\2x-10

Answers

Answer:

-350

Step-by-step explanation:

5×2-3×-10/2×-10

=10-3×-50

=7×-50

=-350

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that​ sport's league? 278 279 185 299 245 281 291 234 278 227 281

Answers

Answer:

Mean = 261.63 poundsMedian = 278 poundsModes: 278 & 281Mid-range = 242Yes all the results will be able to represent all players in the sports league

Step-by-step explanation:

First of all, we will sort the data.

185 227 234 245 278 278 279 281 281 291 299

Mean:

Mean is defined as the sum of values divided by the number of values.

n = 11

[tex]Mean = \frac{sum}{n}\\= \frac{185+227 +234+ 245+ 278+ 278+ 279+ 281+ 281+ 291+ 299}{11}\\=\frac{2878}{11}\\=261.63\ pounds[/tex]

Median:

As the number of values is odd,

The median will be:

[tex]Median = (\frac{n+1}{2})th\ value\\= \frac{11+1}{2}\\=\frac{12}{2}\\=6th\ value[/tex]

The 6th value is 278

Median = 278

Mode:

Mode is the most frequent value in a data set.

In the given dataset,

278 and 281 are modes as both are repeated twice

Mid-range:

Mid-range is the average of maximum and minimum value

So,

Min = 185

Max = 299

So,

[tex]Mid-range = \frac{Max+Min}{2}\\= \frac{185+299}{2}\\= \frac{484}{2}\\= 242[/tex]

Hence,

Mean = 261.63 poundsMedian = 278 poundsModes: 278 & 281Mid-range = 242Yes all the results will be able to represent all players in the sports league

There are 65 people coming to your party and each person will need one cup. How many packages of cups should you buy if one package contains 3 cups?


ANWSER:





STEP BY STEP EXAMPLE:​

Answers

Answer: 22

Step-by-step explanation: 65 divided by 3 is 22

Answer:

21or22

Step-by-step explanation:

65/3

HELP ME PLZ
What is the slope of a parallel to the line that passes through (- 3, 1) and (3, 7)

Answers

Answer:

[tex]\frac{2}{3}[/tex]

Step-by-step explanation:

To find the slope, you need to find the [tex]\frac{rise}{run}[/tex] between two points.

[tex]\frac{rise}{run}[/tex] = [tex]\frac{7-1}{3-(-3)}[/tex]

     = [tex]\frac{7-1}{3+3}[/tex]

     = [tex]\frac{6}{9}[/tex]

     = [tex]\frac{2}{3}[/tex]

Answer:

To calculate slope with any two given points the formula is y2 - y1 / x2 - x1. So to solve the problem just plug in the values: 7 - 1 / 3 - (-3),  6 / 6, the slope is 1

The regular price of a hooded jacket is $25.75. During a sale, the jacket was marked as 20% off. What was the approximate price of the jacket during the sale?
A.
$5.15
B.
$20.60
C.
$21.62
D.
$23.75

Answers

Answer:

5.15 hope this help!!!

Step-by-step explanation:

give this brainlieast so other people can know its not 20.60

Suppose a country's population at any time t grows in accordance with the rule dP dt = kP + I where P denotes the population at any time t, k is a positive constant reflecting the natural growth rate of the population, and I is a constant giving the (constant) rate of immigration into the country. If the total population of the country at time t = 0 is P0, find an expression for the population at any time t.

Answers

Answer:

[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]

Step-by-step explanation:

Given that:

A country population at any given time (t) is:

[tex]\dfrac{dP}{dt}= kP+I[/tex]

where;

P = population at any time t

k = positive constant

I = constant rate of immigration into the country.

Using the method of separation of the variable;

[tex]\dfrac{dP}{kP+1}= dt[/tex]

Taking integration on both sides:

[tex]\int \dfrac{dP}{kP+I}= \int \ dt[/tex]

[tex]\dfrac{1}{k} log (kP + I) = t+c_1 \ \ \ here: c_1 = constant \ of \ integration[/tex]

[tex]log (kP + I) =k t+kc_1[/tex]

By applying the exponential on both sides;

[tex]e^{log (kP + I) }=e^{k t+kc_1 }[/tex]

[tex]KP+I = e^{kt} *e^{kc_1}[/tex]

Assume [tex]e^{kc_1 }= C[/tex]

Then:

[tex]kP + I = Ce^{kt}[/tex]

[tex]kP = Ce^{kt}-I[/tex]

[tex]P =\dfrac{ Ce^{kt}-I}{k} \ \ \---- Let \ that \ be \ equation \ (1)[/tex]

When time t = 0, The Total population of the country is also [tex]P_o[/tex]

[tex]P_o = \dfrac{Ce^{0(t)} -I}{k}[/tex]

[tex]P_o = \dfrac{Ce^{0} -I}{k}[/tex]

[tex]P_o = \dfrac{C-I}{k}[/tex]

C - I = kP₀

C =  kP₀ + I

Substituting the value of C back into equation(1), we have:

[tex]P =\dfrac{ (kP_o+1)e^{kt}-I}{k}[/tex]

[tex]P =\dfrac{ (kP_o+1)e^{kt}}{k} - \dfrac{I}{k}[/tex]

[tex]\mathbf{P =\bigg (P_o +\dfrac{ I}{k} \bigg)e^{kt}- \dfrac{I}{k}}[/tex]

HELPPPPP ME PLEASEEEE


the product of 9/10 and 8/9 is...
A: between 0 and 1
B: between 1 and 2
C: between 2 and 3
D: greater than 3

Answers

Between 0 and 1 I think because you have to find common denominators
It would be B: between 1 and 2 because the answer to that is 1.8 (rounded) so it is more than one but less than 2.

Please help me out !!!

Answers

Answer:

If the segments AU and UT are equal then AT equals 66, if the segments are not equal then AT equals 6x+24. Depends on what you are learning. Use what you need!

Step-by-step explanation:

4x+5 = 2x+19

2x=14

x=7

4(7)+5+2(7)+19 = 42+24 = 66

12 points!! PLEASE

y =(x-3) - 4

rewrite these in standard and factored form!!

Answers

Standard form:

x - y = 7

Factored form:

y = x - 7

Answer:

y = x - 3 - 4

y = x - 7

(x - 7 = y)

(x = y + 7)

Step-by-step explanation:

Hope you got it.

Help please!!!

Triangle ABC is similar to triangle PQR, as shown below​

Answers

Answer:

b:q

Step-by-step explanation:

im pretty sure its that. ive learned this before.

if you flipped them so that c and r were facing the same direction, then b and q would be too.

Draw a scaled copy of the circle
using a scale factor of 2.

How does the circumference of the scaled copy compare to the circumference of the original circle?
How does the area of the scaled copy compare to the area of the original circle?

Answers

Answer:

the circumfrence is the diameter times pi so if the diameter was 3 you would time that by 3.14 to get the circumfrence hope that helps

Step-by-step explanation:

The circumference of the scaled copy is half the circumference of the original circle.

The area of the scaled circle is half the area of the original circle.

What is a scale factor?

A scale factor is defined as the ratio between the scale of a given original object and a new object,

We have,

Let the radius of the circle = r

The circumference of the circle = 2πr

The area of a circle = πr²

Now,

Scale factor = Original circle / Scaled circle

Now,

Scale factor = 2

2 = Circumference of the Original circle / Circumference of the Scaled circle

Circumference of the Scaled circle = (1/2) Circumference of the Original circle

Again,

Scale factor = 2

2 = Area of the Original circle / Area of the Scaled circle

Area of the scaled circle = (1/2) Area of the original circle

Thus,

The circumference of the scaled copy is half the circumference of the original circle.

The area of the scaled circle is half the area of the original circle.

Learn more about scale factors here:

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Solve the following for y: 9x − 3y = 18 (5 points) y = −3x − 6 y = 3x − 6 y = −3x + 6 y = 3x + 6

Answers

Answer:

Y = 3x - 6

Step-by-step explanation:

- 3y = -9x + 18

divide by -3

y = 3x - 6

What is the GCF of the expression -x2y22 - xy2z?​

Answers

Answer:

i dont onderstand Thais

In a class 3/4 of the boys like math, 1/2 like science, 1/4 of those who like science do not like math. How many boys like neither math nor science?
A. 1/4
B. 1/6
C. 1/2
D. 1/8​

Answers

Brainiest Answer:
D.1/8

complete the table of values for y=2-x
x= -1, 0, 1, 2, 3, 4,
y= , , , , -1, ,

Answers

Answer:

x = -1, 0, 1, 2, 3, 4

y = 3, 2, 1, 0, -1, -2

Answer:

x = -1, 0, 1, 2, 3, 4

y = 3, 2, 1, 0, -1, -2

yall the answer is 0.17 hope this help

Answers

Answer:

I just saw a girl post the nastiest nu!des EVER

PLZ HELP ME WITH THIS!!! I WOULD MARK YOU BRAINLIEST!!!

Answers

the answer will be 2.5 hope that helps you

Answer:

2.5 or in other terms 2 1/2

Step-by-step explanation:

6 ×3(2+9)..can you give the answer of it please ​

Answers

Answer:

Hope this may helps you

Step-by-step explanation:

6×3(11)

6×33

198

Answer:

198

Step-by-step explanation:

6 ×3(2+9)

= 6×3×11

= 6×33

= 198

Haya la integral de xarcsenx/((1-x^2)^1/2). Utiliza la sustitución de t= arcsenx
Mi duda está la final, cuando queda - tcost + sent + k, no sé cómo sustituir t= arcsent

Answers

Answer:

Explicación más abajo

Step-by-step explanation:

Integración Indefinida

La integral

[tex]I=\int \dfrac{x .arcsen\left(x\right)}{\sqrt{1-x^2}}[/tex]

Se resuelve con el cambio de variables:

t=arcsen(x)

Una vez hechos los cambios, la integral se resuelve en función de t:

[tex]I=sen(t)-t.cos(t)+C[/tex]

Hay que devolver los cambios para mostrarla en función de x.

El cambio de variables también se puede escribir:

x=sen(t)

Recordando que

[tex]cos(t)=\sqrt{1-sen^2(t)}[/tex]

Entonces:

[tex]cos(t)=\sqrt{1-x^2}[/tex]

Devolviendo los cambios:

[tex]I=sen(t)-t.cos(t)+C=x-arcsen(x)\sqrt{1-x^2}+C[/tex]

Es la respuesta correcta

If point C lies between two points A and B such that AC=BC, then

Answers

Answer:

If point C lies between two points A and B such that AC=BC, then point C is the bisector of A and B, that means it is at right the centre.

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