Can the surface area of a sphere and the volume of a sphere be the same numerical value if the units are measured relative to the same unit of length?
A. Yes; the radius would need to be the unit radius, 1.
B. Yes; the radius would need to be 3.
C. No, the surface area would always be greater than the volume.
D. No, the volume would always be greater than the surface area.

Answer:

the height is 20 cm.

tsa is 940 cm square

Step-by-step explanation:

volume of cuboid = l*b*h

1800 = 9*10*h

h= 20 cm

TSA = 2(L*B+ B*H + L*H)

= 2(9*10 + 10*20 + 9*20)

=940 cm square

The height of the cuboid will be 20 cm

The total surface area of cuboid will be 940 cm²

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

The length of cuboid = 9 cm

The breadth of cuboid = 10 cm

And, The volume of cuboid = 1800 cm³

Now,

We know that;

Volume of cuboid = Length × Breadth × Height

⇒ 1800 = 9 × 10 × h

⇒ 1800 / 90 = h

⇒ h = 20 cm

And, The total surface area of cuboid = 2lw + 2lh + 2hw

Substitute all the values, we get;

⇒ The total surface area of cuboid = 2 (9 × 10 + 9 × 20 + 20 × 10)

                                                      = 2 (90 + 180 + 200)

                                                      = 2 × 470

                                                      = 940 cm²

Learn more about the multiply visit:

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Answer:

5 x 2 -3 = 7

Step-by-step explanation:

i mean.... thats all

Answer:

Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], you can use a normal distribution to approximate the binomial distribution.

The mean is of 11.1 and the standard deviation is of 2.64.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Using the normal distribution to approximate the binomial distribution.

This is possible if:

[tex]np \geq 10, n(1-p) \geq 10[/tex]

A survey of U.S. adults found that 37% have been to court. You randomly select 30 U.S.

This means that [tex]p = 0.37, n = 30[/tex]

Test if it is possible:

[tex]np = 30*0.37 = 11.1[/tex]

[tex]n(1-p) = 30*0.63 = 18.9[/tex]

Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], you can use a normal distribution to approximate the binomial distribution.

Mean and standard deviation:

[tex]E(X) = np = 30*0.37 = 11.1[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.37*0.63} = 2.64[/tex]

The mean is of 11.1 and the standard deviation is of 2.64.

Answer:

Manuel owns 5 DVDS

Step-by-step explanation:

3/5 = 12/20

12 - 7 = 5

you watch seven deadly sins?

Answer:

√14 or 3.74

Step-by-step explanation:

_________________

Answer:

√14 or 3.74

Step-by-step explanation:

x = 3.74

Answer:

1.375 ft

Step-by-step explanation:

10/2.5 = 4

5.5 / 4 = 1 1.5/4 = 1 3/8 = 1.375 ft

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

[tex]\sigma_x= 1.75\%[/tex]

Step-by-step explanation:

Given

[tex]n = 64[/tex]

[tex]\mu = 78\%[/tex]

[tex]\sigma = 14\%[/tex]

Required

The sample standard deviation

This is calculated as:

[tex]\sigma_x= \frac{\sigma}{\sqrt n}[/tex]

This gives:

[tex]\sigma_x= \frac{14\%}{\sqrt {64}}[/tex]

[tex]\sigma_x= \frac{14\%}{8}[/tex]

[tex]\sigma_x= 1.75\%[/tex]

Answer:

1x 2x 3x

Step-by-step explanation:

Answer:

Segment

Step-by-step explanation:

Its only part of the line.

Answer:

The answer is ray

Step-by-step explanation:

I'd say 13, hope this helps

Step-by-step explanation:

Answer: 36 ft^2

Step-by-step explanation: 4x3/2=6. 6x2=12. 3x2=6. 4x2=8. 5x2=10. 12+8+6+10=36

•ω• Hewo fren!

☆☆●◉✿Answer:✿◉●☆☆

The letters of hippopotamus is H-I-P-P-O-P-O-T-A-M-U-S

☆☆●◉✿Step-by-step explanation:✿◉●☆☆

I’m sowy, I didn’t really understand your question... did you want to learn about a hippopotamus? If so, please tell me in the comments I would answer there too!

HOPE I HELPED!  ∧∧

→⇒brainliest please? ∑(OΔO )♥♥︎

Answer:

C

Step-by-step explanation:

18 boys

Answer:

i think 18 msy be

Step-by-step explanation:

Answer:

The appropriate set of hypothesis for his significance test is null hypothesis [tex]H_0: p = 0.06[/tex] and alternate hypothesis [tex]H_1: p \neq 0.06[/tex]

Step-by-step explanation:

Elliot read a report from a previous year saying that 6%, percent of adults in his city biked to work. He wants to test whether this proportion has changed.

At the null hypothesis we test if the proportion is still the same, that is, of 6%. So

[tex]H_0: p = 0.06[/tex]

At the alternate hypothesis, we test if the proportion has changed, that is, it is different of 6%. So

[tex]H_1: p \neq 0.06[/tex]

What is an appropriate set of hypotheses for his significance test?

The appropriate set of hypothesis for his significance test is null hypothesis [tex]H_0: p = 0.06[/tex] and alternate hypothesis [tex]H_1: p \neq 0.06[/tex]

CORRECT (SELECTED)

z=\dfrac{0.1-0.06}{\sqrt{\dfrac{0.06(0.94)}{240}}}z=

240

0.06(0.94)

​

​

0.1−0.06

​

230FT

Regular tetrahedron

Solve for volume

V≈1.15×107

Use the formula for the volume of a triangular pyramid: V=13Ah , where A = area of the triangular base, and H = height of the pyramid.

Answer:

Letter a)

Step-by-step explanation:

quizlet

Answer:

the second company

Step-by-step explanation:

the second company produces 50,000 more crackers an hour than the first company

Answer:

A. flipping a coin to decide whether test subjects should use their left or right hand

Step-by-step explanation:

Since a coin has two outputs: heads or tails, it it has a binomial distribution

Answer:

(A) There should have been 5 outcomes of HT

(B) The experimental probability is greater than the theoretical probability of HT.

Step-by-step explanation:

Given

[tex]S = \{HH,HT,TH,TT\}[/tex] -- Sample Space

[tex]n(S) = 4[/tex] --- Sample Size

Solving (a); theoretical outcome of HT in 20 tosses

First, calculate the theoretical probability of HT

[tex]P(HT) = \frac{n(HT)}{n(S)}[/tex]

[tex]P(HT) = \frac{1}{4}[/tex]

Multiply this by the number of tosses

[tex]P(HT) * n= \frac{1}{4} * 20[/tex]

[tex]P(HT) * n= 5[/tex]

Solving (b); experimental probability of HT

Here, we make use of the table

[tex]P(HT) = \frac{n(HT)}{n(S)}[/tex]

[tex]P(HT) = \frac{6}{20}[/tex]

[tex]P(HT) = 0.30[/tex] ---- Experimental Probability

In (a), the theoretical probability is:

[tex]P(HT) = \frac{1}{4}[/tex]

[tex]P(HT) = 0.25[/tex] ---- Experimental Probability

By comparison;

[tex]0.30 > 0.25[/tex]

Answer:

7 students.

Step-by-step explanation:

1/6 of 30 is 5

3/5 of 30 is 18

18+5=23

30-23=7

Answer:

a. At the 0.05 level of significance,  there is evidence that the mean life is different from 6,500 hours.

b. The p value= ≈ 0.00480 for z- test which is less than 0.05 and H0 is rejected .

The p value= 0.006913 for t- test which is less than 0.05 and H0 is rejected for 49 degrees of freedom.

c. CI [6583.336 ,6816.336]

d.  The range of CI [6583.336 ,6816.336] tells that the cfls having a different mean life lie in this range.

Step-by-step explanation:

Population mean = u= 6500 hours.

Population standard deviation = σ=500 hours.

Sample size =n= 50

Sample mean =x`=  6,700 hours

Sample standard deviation=s=  600 hours.

Critical values, where P(Z > Z) =∝ and P(t >) =∝

Z(0.10)=1.282  

Z(0.05)=1.645  

Z(0.025)=1.960  

t(0.01)(49)= 1.299

t(0.05)= 1.677  

t(0.025,49)=2.010

Let the null and alternate hypotheses be

H0: u = 6500 against the claim Ha: u ≠ 6500

Applying Z test

Z= x`- u/ s/√n

z= 6700-6500/500/√50

Z= 200/70.7113

z= 2.82=2.82

Applying  t test

t= x`- u /s/√n

t= 6700-6500/600/√50

t= 2.82

a. At the 0.05 level of significance,  there is evidence that the mean life is different from 6,500 hours.

Yes we reject H0  for z- test as it falls in the critical region,at the 0.05 level of significance, z=2.82 > z∝=1.645

For t test  we reject H0   as it falls in the critical region,at the 0.05 level of significance, t=2.82 > t∝=1.677 with n-1 = 50-1 = 49 degrees of freedom.

b. The p value= ≈ 0.00480 for z- test which is less than 0.05 and H0 is rejected .

The p value= 0.006913 for t- test which is less than 0.05 and H0 is rejected for 49 degrees of freedom.

c. The 95 % confidence interval of the population mean life is estimated by

x` ±  z∝/2  (σ/√n )

6700± 1.645 (500/√50)

6700±116.336

6583.336 ,6816.336

d. The range of CI [6583.336 ,6816.336] tells that the cfls having a different mean life lie in this range.

Step-by-step explanation:

a) A=π302=900π CM2 =2,827 CM 2

b) V=Ah=900=72000 π cm 3 = 226,195 cm3

Answer:83.3

Step-by-step explanation:

Answer:

-86

Step-by-step explanation:

3x10=30

22-3=19-3=16-3=13

so if its tthe 37th term, lets do 30x3=90

now 13-90=-77

-77=34th term

now just -3 until 37

-80

-83

-86

the 37th term is -86

Answer:

2/4

Step-by-step explanation:

Answer:

Common factor

Factor by grouping

Factor by grouping

−

2

−

2

+

1

-x^{2}-2x+1

−x2−2x+1

−

1

(

2

+

2

−

1

)

{\color{#c92786}{-1(x^{2}+2x-1)}}

−1(x2+2x−1)

Solution−

-1(x²+ 2x-1 )