Can someone salve this pleaseeeeeeeee

Answer:

Original number is 86

Step-by-step explanation:

              Original:   10x + y

Double reversed:   2(10y + x)

Constraints:

  x + y = 14                                     ===>            x = 14 - y

  2(10y + x) + 10x + y = 222          ===>           21y + 12x = 222

Substitution to find y:

  21y + 12x = 222

  21y + 12(14 - y) = 222

  21y + 168 - 12y = 222

            9y + 168 = 222

                      9y = 54

                        y = 6

Substitution to find x:

  x = 14 - y

  x = 14 - 6

  x = 8

Original:   10x + y

                 10(8) + (6)

                 80 + 6

                 86

Answer:

In the graph, the y-intercept is -2. The equation of the line is [tex] y = x - 2 [/tex]

Step-by-step explanation:

The equation of the line can be written in the slope-intercept form, y = mx + b.

First we need to find:

The slope = m

the y-intercept = b

Using two points on the line, (0, -2) and (2, 0) the slope can be calculated as follows:

[tex] m = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 -(-2)}{2 - 0} = \frac{2}{2} = 1 [/tex]

The y-intercept is simply the point at which the line intercepts the y-axis. It is the value of y when x = 0.

Therefore, the y-intercept, b, = -2.

Substitute m = 1 and b = -2 into [tex] y = mx + b [/tex].

Thus, the equation if the line would be:

[tex] y = (1)(x) + (-2) [/tex]

[tex] y = x - 2 [/tex]

Answer:

like terms is -7k-k and 12+8

      Rise of the line with 50% slope and 50 feet rise = 100 feet

      Option (A) will be the answer.

         Slope = [tex]\frac{\text{Rise}}{\text{Rus}}[/tex]

Given in the question,

Slope of the line = 50%

                            = [tex]\frac{50}{100}[/tex]

                            = 0.5

Rise has been given as 50 feet.

Substitute the values in the expression for the slope,

[tex]0.5=\frac{50}{\text{Run}}[/tex]

Run = [tex]\frac{50}{0.5}[/tex]

       = 100 feet

    Therefore, run for the given line will be 100 feet.

                      Option A will be the answer.

Learn more about the slope of a line here,

https://brainly.com/question/2514839?referrer=searchResults

Answer:

C. (9, 26)

Step-by-step explanation:

By Substitution:

y = 2x + 8

y = 3x - 1

---------------------

2x + 8 = 3x - 1

-x + 8 = -1

-x = -9

x = 9

Now we can choose either of the two equations given to solve for y:

y = 2x + 8

y = 2(9) + 8

y = 18 + 8

y = 26

(9, 26)

By Elimination:

For this process, I am going to rewrite the equation in "x + y" for as it will make it easier to eliminate the variables

y = 2x + 8

2x - y = -8

y = 3x - 1

-3x + y = -1

-----------------

2x - y = -8

-3x + y = -1

-----------------

-x = -9

x = 9

2x - y = -8

2(9) - y = -8

18 - y = -8

-y = -26

y = 26

(9, 26)

Answer:

4N left

5N left

0N (balanced)

9N right

Step-by-step explanation:

The net force is the vector sum of all of the forces acting on an object. To find the net force when there are two opposite forces subtract the smaller number from the larger, for example, 7-2. Then take to total, 5N, and add the direction of the stronger force. If the equation equals zero that means you have a balanced force. To find the force of two actions in the same direction simply add them.

Answer:

a

Step-by-step explanation:

a

The correct answer for the given inequality 5-x<2(x - 3) + 5 is x<2 Graph A

A relationship between two expressions or values that are not equal to each other is called inequality.

Given that, an inequality 5-x<2(x - 3) + 5

On solving, we get,

5-x < 2x-6+5

5-x < 2x-1

5+1 < 3x

x < 2

Let y₁ = 5-x, and y₂ = 2(x - 3) + 5

Plotting the graph, we get the graph A

Hence, the correct answer for the given inequality 5-x<2(x - 3) + 5 is x<2 Graph A

For more references on inequality, click;

https://brainly.com/question/28823603

#SPJ2

Answer:

d. 90 cm, 1.2 cm

Step-by-step explanation:

Given that:

The sample size n = 36

For the  length of the link:

The mean [tex]\overline x[/tex] = 2.5

The standard deviation s = 0.2 cm

In a chosen 36 links, The mean and standard deviation for the length chain is as follows:

Mean = n[tex]\overline x[/tex]

Mean = 36×2.5

Mean = 90 cm

The Standard deviation = s×√n

The Standard deviation = 0.2×√36

The Standard deviation = 0.2×6

The Standard deviation = 1.2 cm

Answer:

Step-by-step explanation:

d over d x over y=-1 over 2 y plus 3 over 2

Answer:

Q1

|a-b| = b-a when a<b

Q2

104159/33000

Step-by-step explanation:

Q1

If a<b then a-b will always be negative.  To get the absolute value, we can take -(a-b) = -a+b = b-a.

Q2

Let x = 3.12789789789...

We isolate the repeating decimal to start after the decimal, so we multiply by 100.

100x = 312.789789789...

We want to multiply by 10 for each digit that repeats (in this case 3), to get the repeating part to the left of the decimal.

100000x = 312789.789789

Subtracting the two...

x(100000-100) = 312789.789789 - 312.789789

99900x = 312477

x = 312477/99000 = 104159/33000

Step-by-step explanation:

let eqn be y = mx + b.

Since perpendicular, m = - 1/(-0.5) = 2

sub (-8, 0):

0 = 2(8) + b

b = - 16

therefore equation is y = 2x - 16

Topic: coordinate geometry

If you like to venture further, feel free to check out my insta (learntionary). I'll be constantly posting math tips and notes! Thanks!

Answer:

y= −2x/3 + 400

Step-by-step explanation:

Hope this helps :)

Answer: what the other dude said

Step-by-step explanation:

Answer:

$2.50

Step-by-step explanation:

6.25/2.5=2.5

Answer:

Each side is 6 units.

Step-by-step explanation:

The problem is not how to do the question. The problem is how to get your calculator to do the question.

V = s^3

s = ?

V = 216

So what you need is the cube root of 216

s^3 = 216

cube root(s^3) = cube root(216)

s = cube root 216

Your calculator should have a y^x or x ^y key.

Put in 216

Press the y^x key or the x^y key

Put in 0.33333333333

You should get something like 5.999999 which you should round to 6.

Answer:

15x-6

Step-by-step explanation: 4 * 2x = 8x

4*-5 = -20

7*x  = 7x

7*2= 14

Combine like terms 8x + 7x + 14-20

15x-6

Answer:

-0.4522

Step-by-step explanation:

Answer:

5 horas

Step-by-step explanation:

Answer:

Step-by-step explanation:

( [tex]4\frac{3}{4}[/tex] + [tex]3\frac{1}{2}[/tex] + [tex]6\frac{3}{4}[/tex] + [tex]4\frac{1}{2}[/tex] + 6 + 5 ) ÷ 6 =

( 4 + 3 + 6 + 4 + 6 + 5 + [tex]\frac{6}{4}[/tex] + 1 ) ÷ 6 = 30.5 ÷ 6 = [tex]\frac{61}{2}[/tex] × [tex]\frac{1}{6}[/tex] = [tex]\frac{61}{12}[/tex] = [tex]5\frac{1}{12}[/tex] horas al dia

Answer:

0.59, 3/5 0.65

Step-by-step explanation:

3/5 = 0.60

Answer: 0.59, 3/5 (0.60), 0.65

Step-by-step explanation: If you would convert 3/5 into a decimal it would be 0.6, you'd divide 3 by 5. Hope this helps!

Answer:

(1) 0.058

(2) 601

Step-by-step explanation:

(1)

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

[tex]\mu_{\hat p}=p\\[/tex]

The standard deviation of this sampling distribution of sample proportion is:

[tex]\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}[/tex]

As the sample size is large, i.e. n = 350 > 30, the Central limit theorem can be used to approximate the sampling distribution of sample proportion of adults in a certain country work from home.

Compute the probability that fewer than 42 out of a random sample of 350 adults will work from home:

Sample proportion: [tex]\hat p=\frac{42}{350}=0.12[/tex]

[tex]P(\hat p < 0.12)=P(\frac{\hat p-\mu_{\hat p}}{\sigma_{\hat p}}<\frac{0.12-0.15}{\sqrt{\frac{0.15(1-0.15)}{350}}})\\\\=P(Z<-1.57)\\\\=0.05821\\\\\approx 0.058[/tex]

Thus, the probability that fewer than 42 out of a random sample of 350 adults will work from home is 0.058.

(2)

The (1 - α)% confidence interval for population proportion is:

[tex]CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

The margin of error for this interval is:

[tex]MOE= z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

Given:

MOE = 0.04

Confidence level = 95%

Assume that the sample proportion is 50%.

The critical z-value for 95% confidence level is 1.96.

Compute the required sample size as follows:

[tex]MOE= z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

      [tex]n=[\frac{z_{\alpha/2}\cdot\sqrt{\hat p(1-\hat p)}}{MOE}]^{2}\\\\=[\frac{1.96\times \sqrt{0.50(1-0.50)}}{0.04}]^{2}\\\\=600.25\\\\\approx 601[/tex]

Thus, the required sample size is 601.

1. Using the normal approximation to the binomial, it is found that there is a 0.05 = 5% probability that fewer than 42 out of a random sample of 350 adults will work from home.

2. Solving the equation for the margin of error of a confidence interval of proportions, it is found that we must survey 601 randomly selected teenagers.

Question 1:

Normal Probability Distribution

In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

In this problem:

Then, for the approximation:

[tex]\mu = np = 350(0.15) = 52.5[/tex]

[tex]\sigma = \sqrt{np(1-p)} = \sqrt{350(0.15)(0.85)} = 6.68[/tex]

Using continuity correction, the probability is [tex]P(X < 42 - 0.5) = P(X < 41.5)[/tex], which is the p-value of Z when X = 41.5. So:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{41.5 - 52.5}{6.68}[/tex]

[tex]Z = -1.65[/tex]

[tex]Z = -1.65[/tex] has a p-value of 0.05.

0.05 = 5% probability that fewer than 42 out of a random sample of 350 adults will work from home.

Question 2:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem:

We have to solve for n, then:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}[/tex]

[tex]0.04\sqrt{n} = 1.96(0.5)[/tex]

[tex]\sqrt{n} = \frac{1.96(0.5)}{0.04}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96(0.5)}{0.04})^2[/tex]

[tex]n = 600.25[/tex]

Rounding up:

We must survey 601 randomly selected teenagers.

A similar problem is given at https://brainly.com/question/24261244

Answer:

10/24

Step-by-step explanation:

hope this helps :)

Answer:

5/8

Step-by-step explanation:

Have a good day! :)

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Suppose Tetha = alpha = 26°

Then ;

[tex] \tan( \alpha ) = \frac{y}{x} \\ [/tex]

[tex] \tan(26°) = \frac{8}{x} \\ [/tex]

[tex]0.487 = \frac{8}{x} \\ [/tex]

Multiply sides by x

[tex]0.487x = 8[/tex]

Divide sides by 0.487

[tex]x = \frac{8}{0.487} \\ [/tex]

[tex]x = 16.427[/tex]

[tex]x≈ 16.43[/tex]

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Answer:

Your answer would be x = 63

Step-by-step explanation:

What I would do first is to isolate the -1/9x, which means I would subtract 17 on each side, giving me -1/9x = -7

Next I would multiply -9 (which is the inverse of -1/9) on both sides, negating the negative sign and making 63 positive, and thus isolating x as well.

Answer:12

Step-by-step explanation:

18/6=3 cups in each box

3*2=6 cups broke=2 boxes

18-6=12 cups are unbroken

Answer:

y= -5

Step-by-step explanation:

Answer:

y= -5

Step-by-step explanation:

Answer:

0

Step-by-step explanation:

From the given information;

Let x be the number of trails on which the [tex]r^{th}[/tex] defective occurs.

Let the probability that an occurrence of a defective be p = 0.10

Suppose x is a random variable that follows a negative binomial distribution with parameters r and p.

Then the probability mass function of X can be expressed as:

[tex]P(X=x) = \bigg (^{x-1}_{r-1} \bigg)p^r (1 - p) ^{x-r} \ \ \ \ ; x=r, \ r+1 , \ r+2 , ...[/tex]

[tex]P(X=x) = \bigg (^{x-1}_{r-1} \bigg)(0.10)^r (1 - 0.10) ^{x-r}[/tex]

[tex]P(X=x) = \bigg (^{x-1}_{r-1} \bigg)(0.10)^r ( 0.90) ^{x-r} \ \ ... \ \ (1)[/tex]

We are to find the probability of the fourth defective engine will be found on the second trial.

i.e. r =  4 and x = 2

[tex]P(X=2) = \bigg (^{2-1}_{4-1} \bigg)(0.10)^4 ( 0.90) ^{2-4}[/tex]

[tex]P(X=2) = \bigg (^1}_{3} \bigg)(0.10)^4 ( 0.90) ^{-2}[/tex]

[tex]P(X=2) = \bigg (\dfrac{1!}{3!(1-3)!} \bigg)(0.10)^4 ( 0.90) ^{-2}[/tex]

[tex]\mathbf{P(X=2) = 0}[/tex]