Can someone please help with this 4 mark question!

Answer:

Option C (1.2 L) is the correct option.

Explanation:

The given values are:

Pressure,

[tex]P_1=1.9 \ atm[/tex]

[tex]P_2=3.8 \ atm[/tex]

Volume,

[tex]V_1=2.3 \ L[/tex]

[tex]V_2=?[/tex]

As we know,

The gas equation is:

⇒  [tex]PV=nRT[/tex]

At constant temperature,

⇒  [tex]P_1 V_1=P_2 V_2[/tex]

or,

⇒      [tex]V_2=\frac{P_1 V_1}{P_2}[/tex]

By substituting the values, we get

⇒           [tex]=\frac{1.9\times 2.3}{3.8}[/tex]

⇒           [tex]=\frac{4.37}{3.8}[/tex]

⇒           [tex]=1.15 \ L[/tex]

or,

⇒           [tex]=1.2 \ L[/tex]

Explanation:

asexual reproduction involves 1 parent and produces offspring that are genetically identical to each other and parent.

Sexual reproduction involves 2 parents and produces offspring that are genetically unique.

Answer:

250cm³ de disolución se deben preparar

Explanation:

El porcentaje volumen volumen (%v/v) se define como el volumen de soluto -En este caso, H2O2- en 100cm³ de disolución.

Se desea preparar una solución que contenga 20cm³ de H2O2 por cada 100cm³

Como solamente se cuenta con 50cm³ de H2O2, el volumen que se debe preparar es:

50cm³ H2O2 * (100cm³ Disolución / 20cm³ H2O2) =

Answer:

II would say there is co2 so i would say 30.4

Explanation:

Hope this helps

Solution :

[tex]$H_2 +I_2\rightleftharpoons 2HI$[/tex]

Initial concentration               Equilibrium concentration           [tex]$K_c=\frac{[HI]^2}{[H_2][I_2]}$[/tex]

  (mol/L)                                           (mol/L)

[tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]    [tex]$[H_2]$[/tex]                 [tex]$[I_2]$[/tex]            [tex]$[HI]$[/tex]

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.38 \times 10^{-2}$[/tex]  0     [tex]$1.14 \times10^{-2}$[/tex]    [tex]$0.12 \times 10^{-2}$[/tex]  [tex]$2.52 \times 10^{-2}$[/tex]        46.42

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.68 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.20 \times 10^{-2}$[/tex]  [tex]$2.96 \times 10^{-2}$[/tex]        47.61

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.98 \times 10^{-2}$[/tex]  0     [tex]$0.77 \times10^{-2}$[/tex]    [tex]$0.31 \times 10^{-2}$[/tex]  [tex]$3.34 \times 10^{-2}$[/tex]        46.73

[tex]$2.4 \times 10^{-2}$[/tex]     [tex]$1.76 \times 10^{-2}$[/tex]  0     [tex]$0.92 \times10^{-2}$[/tex]    [tex]$0.22 \times 10^{-2}$[/tex]  [tex]$3.08 \times 10^{-2}$[/tex]        46.86

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$3.04 \times 10^{-2}$[/tex]     [tex]$0.345 \times10^{-2}$[/tex]    [tex]$0.345 \times 10^{-2}$[/tex]  [tex]$2.35 \times 10^{-2}$[/tex] 46.39

[tex]$0$[/tex]                  [tex]$0$[/tex]        [tex]$7.58 \times 10^{-2}$[/tex]     [tex]$0.86 \times10^{-2}$[/tex]    [tex]$0.86 \times 10^{-2}$[/tex]  [tex]$5.86 \times 10^{-2}$[/tex]     46.42

Average [tex]$K_c=46.738$[/tex]

Answer:

The respiratory system is the network of organs and tissues that help you breathe. basically your airways, lungs, and blood vessels so you quite literally need these to survive I mean your muscles need oxygen to function and your brain needs oxygen to function so without your respiratory system you wouldn't be able to move much and you would quickly pass out and die from the lack of oxygen to your brain there are other body processes that need oxygen as well but these are just two examples.

Explanation:

Answer:

Maybe it’s dark ??????????????

Explanation:

Hm

Answer:

D ) Chemical Change

Explanation:

Answer:

100 L

Explanation:

Use Boyle's Law, p1v1 = p2v2.

p1 = 4 atm

v1 = 50L

p2 = 2 atm

v2 = ?

p1v1 = p2v2

(4 atm) (50L) = (2 atm) (v2)

v2 = (4 atm)(50L) / (2 atm) = 100 L

Explanation:

amount of baking soda = 2.01 g

---> 2.01 g NaHCO3 × (1 mol NaHCO3/84.007 g NaHCO3)

= 0.024 mol NaHCO3

mass of the product = 1.28 g

Possible reactions:

NaHCO3(s) ---> NaOH(s) + CO2(g)

0.024 mol NaHCO3 × (1 mol NaOH/1 mol NaHCO3)

= 0.024 mol NaOH × (39.997 g NaOH/1.mol NaOH)

= 0.96 g NaOH

2NaHCO3(s) ---> Na2O(s) + 2CO2(g) + H2O(g)

0.024 mol NaHCO3 × (1 mol Na2O/2 mol NaHCO3)

= 0.012 mol Na2O × (61.9789 g Na2O)

= 0.73 g Na2O

2NaHCO3(s) ---> Na2CO3(s) + CO2(g) + H2O(g)

0.024 mol NaHCO3 × (1 mol Na2CO3/2 mol NaHCO3)

= 0.012 mol Na2CO3 × (105.9888 g Na2CO3/1 mol Na2CO3)

= 1.27 g Na2CO3

Conclusion:

Based on the mass of the product in the crucible and comparing it with the predicted product mass in different reactions, I conclude that Na2CO3 is the most likely product in the crucible.

Answer:

D . It describes a compound being broken down into the elements from which it was formed.

Explanation:

A compound consists of two or more elements chemically combined together in a chemical reaction. The compound carbon monoxide is represented by the chemical symbol, CO. This means that it contains 1 atom of the carbon element and 1 atom of the Oxygen element.

This compound is formed when carbon is directly oxidized in a limited supply of oxygen. In the above reaction, this compound is disintegrated into its individual components, namely, carbon and oxygen.

Answer:

"0.24 J/g.k" is the appropriate solution.

Explanation:

Mass of substance,

m = 110.00 g

Heat,

q = 396 J

Change in temperature,

ΔT = 15.0°C  

Now,

The specific heat will be:

⇒  [tex]q=ms \Delta T[/tex]

On putting the given values, we get

⇒  [tex]396=110.00\times s\times 15.0[/tex]

⇒  [tex]396=s\times 1650[/tex]

⇒      [tex]s=\frac{396}{1650}[/tex]

⇒         [tex]=0.24 \ J/g.k[/tex]

Answer:

D

Explanation:

Because it has equal number of elements on each side of the arrow

Answer:

A. 5.3 X 10^-2

Explanation:

I got 100 on PLATO

Answer:

P2 = 4.76 atm

Explanation:

Given:

T1 = 235K. P1 = 3.80 atm

T2 = 298K. P2 = ?

Here, we use Gay-Lussac's law:

P1/T1 = P2/T2

Solving for P2, we get

P2 = (T2/T1)P1

= (298K/238K)(3.80 atm)

= 4.76 atm

Answer:

Electrons and protons are not positively charged

Explanation:

Neutrons are the only ones positively charged in the structure of an atom.... Also like charges repel which means a -ive and a - ive will repel when together

Answer:

0.702 /s

Explanation:

Rate constant at [tex][298 \mathrm{~K}, \mathrm{~K}_{1}=3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]

Rate constant at [tex]350 \mathrm{~K}, \mathrm{~K}_{2}=?[/tex]

[tex]T_{1}=298 \mathrm{~K}[/tex]

[tex]T_{2}=350 \mathrm{~K}[/tex]

Activation energy, [tex]\mathrm{Ea}=50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}[/tex]

Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]

Use the following equation to calculate [tex]K_{2}$ at $350 \mathrm{~K}[/tex]

[tex]\ln \frac{\mathrm{K}_{2}}{\mathrm{~K}_{1}}=\frac{\mathrm{Ea}}{\mathrm{R}}\left[\frac{1}{\mathrm{~T}_{1}}-\frac{1}{\mathrm{~T}_{2}}\right][/tex]

Therefore,

 [tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{1}{298 \mathrm{~K}}-\frac{1}{350 \mathrm{~K}}\right][/tex]

[tex]\ln \left(\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}}\right) &=\frac{50.2 \times 10^{3} \mathrm{~J} / \mathrm{mol}}{8.314 \mathrm{JK}^{-1} \mathrm{~mole}^{-1}}\left[\frac{52 \mathrm{~K}}{298 \mathrm{~K} \times 350 \mathrm{~K}}\right][/tex]

[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=\mathrm{e}^{3.01}[/tex]

[tex]\frac{K_{2}}{3.46 \times 10^{-2} \mathrm{~s}^{-1}} &=20.3[/tex]

[tex]K_{2} &=20.3 \times 3.46 \times 10^{-2} \mathrm{~s}^{-1}[/tex]

[tex]&=0.702 \mathrm{~s}^{-1}[/tex]

hence, the rate constant at [tex]350 \mathrm{~K} [/tex] is 0.702[tex]\mathrm{~s}^{-1}[/tex]

Answer:

a) pentane

b) 1,3-dimethyl butane

c) 3,4-diethyl-5-methlyl heptane

d) 1,3,5-triethyl-2,4,6-trimethyl  cyclohexane

Explanation:

The essence of IUPAC nomenclature is to provide a generally accepted nomenclature for chemical compounds which enables the structure of a compound to be drawn from its name without ambiguity.

In order to name straight chain organic compounds, we have to identify the parent chain and then give numbers to the substituents or locants such that they have the lowest possible numbers in alphabetical order.

The correct names of the organic compounds in the question are;

a) pentane

b) 1,3-dimethyl butane

c) 3,4-diethyl-5-methlyl heptane

d) 1,3,5-triethyl-2,4,6-trimethyl cyclohexane

It's ammonia (NH3).....

Answer:

A molecule with one lone pair and three bond pair

- Ammonia

Answer:

To find the relative formula mass (M r) of a compound, you add together the relative atomic mass values (A r values) for all the atoms in its formula.

Explanation: Find the M r of carbon monoxide, CO. Find the M r of sodium oxide, Na 2O. The relative formula mass of a substance, shown in grams, is called one mole of that substance.

Answer:

1045 J

Explanation:

By using the formula Eh= mass×specific heat capacity × change in tempreture

With it being a known fact that the specific heat capacity of water is 4.16g/j/°c

Answer:

The arrangement of electrons within an atom is called electron configuration

If I help you, will you help other people?

Actually "this is the worst question i've ever seen use the internet bud" why don't you do that.

What were Lamarck's ideas about evolution and Why were those ideas incorrect?

→ These and other examples show that Lamarck's theory does not explain how life formed and became the way it is. The other way that Lamarck's theory has been proven wrong is the study of genetics. Darwin knew that traits are passed on, but he never understood how they are passed on.

Answer:

2Cu2O + C --> 4Cu + CO2

Explanation

The Law of conservation of Mass states You can not destroy or create math in a chemical reaction, meaning you must have the same amount at the beginning and the end. This equation keeps the same amount of atoms on both sides.

Answer: Yes, it is a balanced equation.

Explanation:

https://chemequations.com/en/?s=Cu2O+%2B+C+%3D+Cu+%2B+CO2

This is where I got the answer so you know.  Hope this helps :)

Answer:

4.17M

Explanation:

m1v1/m2v2=n1/n2

Answer:

water vapor (gas) is becoming liquid

Answer:

A. 2AgI + Na2S → Ag2S + 2NaI

B. Na3PO4 + 3HCl → 3NaCl + H3PO4

C. Ba3N2 + 6H2O → 3Ba(OH)2 + 2NH3

D. TiCl4 + 2H2O → TiO2 + 4HCl

E. 3CaCl2 + 2Na3PO4 → Ca3(PO4)2 + 6NaCl

Explanation:

Equation balance:

2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O

2Al(OH)3+3H2SO4

H=12

SO4=3

O=6

Al=2

Al2(SO4)3+6H2O

H=12

SO4=3

O=6

Al=2