Can someone please help me with questions 18 and 19 please. Will give brainilist to best answer.

Can Someone Please Help Me With Questions 18 And 19 Please. Will Give Brainilist To Best Answer.

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Answer 1
18 big cirlce ls 7.85 and tha small cirlce to 18 is 18.85

Related Questions

help asap plz i just cant

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Answer:

(0,-7)

(1,-9)

(-1,-5)

(-2,-3)

Step-by-step explanation:

Your slope would be 2/3

I think this is right. Let me know if you know the formula and i can explain it to you!

(-6,5)

(-4,1)

(2,-9)

(-5,3)

help me with this please show work thanks

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First do you need to do 5×4 which equals 20 and then you need to do 8×2 which equals 16 so your answer would be 16 at the top and then 20th the bottom

Answer:

first thing is first u have to do 5+2 =7 then do 8+4=12 your answer will be 7/12

Step-by-step explanation:

What unit should be placed on a volume answer? cubed or squared

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Answer:

volume is cubed

area is squared

Step-by-step explanation:

The unit placed on a volume answer is cubed and area is squared

Please help! This is due today! I just need help with this one problem!

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Linear equations are 2a + 3b = 82 and a + b = 38
A = 32
B = 6
The answer: A=32
B=6

Simplify the algebraic expression:

2(y + 5) + 3y - 4

Answers

Answer:

2y +10 +3y-4

5y+6

Step-by-step explanation:

Answer: 5y + 6

Step-by-step explanation:

1. Distribute:

=2(y+5)+3y-4

=2y+10+3y-4

2. Subtract

=2y+10+3y-4

=2y+6+3y

3. Combine Like Terms

=2y+6+3y

=5y+6

A jar contains 2 red, 5 green, 2 blue and 6 yellow marbles. A marble is chosen at random from the jar. After replacing it, a second marble is chosen. What is the probability of choosing a green and then a yellow marble?​

Answers

Answer:

Step-by-step explanation:

The probability of picking an item A in a box of N items depends on nA, the amount of items A in the box at the time of picking, with the kinda instinctive value:

p = nA / N

then it means that if you have no green ball, the probability is 0/N = 0, if you only have green balls, it means you have a probability of N/N = 1 = 100%, and if you have as many green balls as non-green balls, you have a probability of nA/(2nA) = 0.5 = 50%.

Here the probability of first picking a green ball (nG=5) in a box of N=3+5+2+6=16 for the 1st pick is:

pG1 = 5/16

Now the trick here is that once you picked the green ball, you put it back in the box before picking another ball. So you still have N=16 balls for the second pick, and the probability of picking a yellow ball (nY=6) for the 2nd pick is:

pY2 = 6/16 = 3/8

(it would have been slightly higher, at 6/15, if you did NOT put back the green marble in the box).

Now you want BOTH events to be true. So you want G1 to be true AND Y2 to be true. The two events are independent (the probability of Y2 is 6/16 if you had G1 but is also 6/16 if you failed G1), so the probability of having both is simply done by multiplicating them:

pG1Y2 = pG1 * pG2 = 15/128

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