Answer:
Part A:
The other two ways we can rewrite F = m·a are;
1) F = dp/dt
2) F = m × d(v)/dt
Part B:
The mass of the wheelbarrow is 60 kg
Explanation:
Part A:
The other two ways of rewriting the equation are;
1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and
2) From the above equation, where, m is constant, we have;
F = d(m·v)/dt = m × d(v)/dt
∴ F = m × d(v)/dt
Part B:
The force with which we push the wheelbarrow = 240 N
The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²
From F = m × a
Where;
m = The mass of the wheelbarrow
m = F/a = 240 N/(4 m/s²) = 60 kg
The mass of the wheelbarrow = m = 60 kg.
If you could change one property of a substance ( solid, liquid, and gas) you have to use in your daily life, what would it be and why?
Please hurry
I will give you BRAINLIEST!!!!!!
And pleaseee write 5 sentences why??
Answer
Soap into a liquid
Explanation:
Which one of the following is not a member of the solar family: (a) Morning Star (b) Evening Star (c) Pole Star (d) Tailed Star plzzz answer this...
Answer:
Tailed star
Explanation:
Tailed star
Un automóvil se mueve a velocidad constante v = 60 [km/h]. Si el tiempo de reacción del conductor al ver la luz roja de una intersección es de 0.5 [s], y ´este desacelera a razón de 40 [m/s2 ] ¿Qué distancia recorre el automóvil desde el instante en que el conductor nota la se˜nal hasta detenerse por completo? Entiéndase por tiempo de reacción, el intervalo de tiempo transcurrido entre el instante en que se percibe la señal y el instante en que se lleva a cabo la acción (instante en que el conductor activa el sistema de frenado).
Answer:
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
Explanation:
De acuerdo con el enunciado, el conductor nota la luz roja, empieza a decelerar 0.5 segundos después y decelera hasta detenerse. La distancia total recorrida por el automóvil desde el instante en que el conductor nota la luz roja ([tex]\Delta s_{T}[/tex]), medida en metros:
[tex]\Delta s_{T} = \Delta s_{1}+\Delta s_{2}[/tex] (1)
Donde:
[tex]\Delta s_{1}[/tex] - Distancia recorrida a velocidad constante, medida en metros.
[tex]\Delta s_{2}[/tex] - Distancia recorrida hasta alcanzar el reposo, medida en metros.
Si suponemos que la segunda etapa describe un movimiento uniformemente acelerado, entonces la distancia recorrida total que representada por la siguiente fórmula:
[tex]\Delta s_{T} = v_{o}\cdot \Delta t_{o} + \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial del automóvil, medida en metros por segundo.
[tex]v_{f}[/tex] - Velocidad final del automóvil, medida en metros por segundo.
[tex]\Delta t_{o}[/tex] - Tiempo de reacción del conductor, medido en segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Si conocemos que [tex]v_{o} = 16.667\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex], [tex]\Delta t_{o} = 0.5\,s[/tex] y [tex]a = -40\,\frac{m}{s^{2}}[/tex], entonces la distancia recorrida total es:
[tex]\Delta s_{T} = \left(16.667\,\frac{m}{s} \right)\cdot (0.5\,s)+\frac{\left(0\,\frac{m}{s} \right)^{2}-\left(16.667\,\frac{m}{s}\right)^{2}}{2\cdot \left(-40\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\Delta s_{T} = 11.806\,m[/tex]
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
1. A man is running on the straight road with the uniform velocity
3 m/s. Calculate acceleration produced by him.
why watchman does no work but gets tired ?
Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.
Explanation:
explain why an inflated balloon is likely to burst if you leave it near a window with the sun streaming it?
Answer:
the sun light will heat up the balloon causing it to burst
Why do women typically tend to have slightly greater stability than men?
A.
Women are shorter than men, and shorter people are more stable.
B.
Men have more muscle mass in their lower bodies that makes them stiff and less stable.
C.
Women have lower centers of gravity, and lower centers of gravity provide more stability.
D.
The increased muscle mass in their upper bodies makes their centers of gravity difficult to find.
Please select the best answer from the choices provided.
A
B
C
D
Answer:
C
Explanation:
I figured it sounded more accurate
What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Answer:
5.
Explanation:
From the question given above, the following data were obtained:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =?
Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:
Mechanical advantage = length /height
MA = L/H
With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:
Length (L) of ramp = 25 feet
Height (H) of ramp = 5 feet
Mechanical advantage (MA) of ramp =.?
MA = 25 / 5
MA = 5
The, the mechanical advantage of the ramp is 5.
Calculate the kinetic energy of a 50 kg cart moving at a speed of 18.6 m/s.
Answer:
8649 J
Explanation:
KE = 1/2mv^2
1/2(50)(18.6)^2
1/2(50)(345.96) = 8649 J
When the net force on an object is zero, what do we know about the motion of that object
Answer:
The objects speed or motion does not change if the net force is 0.
Explanation: There basically doesn't have anything acting on it so it stays put.
An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.
Answer:
The final velocity, [tex]v_{f}[/tex], is gd.
Explanation:
The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;
[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs
where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.
Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.
So that;
[tex]v_{f}[/tex] = 0 + 2gd
= 2gd
[tex]v_{f}[/tex] = 2gd
When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.
Then;
[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]
[tex]v_{f}[/tex] = g x d
When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.
Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
covered by Asha.(a) (Numbering problem)_
Distance walked to the west= 15m
" " " " north= 20m
" " " " east = 15m
Total Distance= (15+ 20+ 15) m
= 50m
Asha covered 50m distance in total.
When food is digested, the
smell changes considerably.
What would you call this type
of change?
A. A physical change
B. A chemical change
C. A solution change
Answer:
Chemical change
Explanation:
A chemical change is what happens. The food digested changes smell due to some enzyme the has acted on the food which catalyzes the rate of digestion. The enzymes acts on the food in order to speed up the rate of the reaction (digestion) and in turn causing the smell.
Which best defines gravity?
A. The tendency of objects to fall from trees
B. An attractive force between two objects due to their mass
C. The amount of matter in an object
D. The rate at which objects fall to earth
Answer:
B. An attractive force between two objects due to their mass
Explanation:
Answer:
B
Explanation:
Gravity is a force that pulls 2 objects towards each other and varies depending on mass. The earth for example is large enough to have a gravitational force that keeps us down. The sun has a gravitational force that keeps the Earth in orbit.
An object has a force of 29.43 N acting on it. Its acceleration is 3.5 m/s2. What is the mass of this object?
Answer:
The mass of the object is 8.41 Kg.
Explanation:
Mechanical Force
The second Newton's law states that the net force exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object. The SI unit for the force is the Newton: [tex]1\ Nw = 1~Kg.m/s^2[/tex]
We are given the net force of F=29.43 N acting on an object and producing an acceleration of a=3.5~m/s^2.
To calculate the mass of the object, we solve the above equation for m:
[tex]\displaystyle m=\frac{F}{a}[/tex]
[tex]\displaystyle m=\frac{29.43}{3.5}[/tex]
Calculating:
m = 8.41 Kg
The mass of the object is 8.41 Kg.
Calculate the mass of a man jogging north along the highway at a rate of 2.65 m/s and a momentum of 225.3 kg*m/s
Answer:
85.02 kgExplanation:
The mass of the man can be found by using the formula
[tex]m = \frac{p}{v} \\ [/tex]
v is the velocity
p is the momentum
From the question we have
[tex]m = \frac{225.3}{2.65} \\ = 85.01886...[/tex]
We have the final answer as
85.02 kgHope this helps you
Which of the following is the most sensible way to conserve natural resources?
O Don't use any products made from trees
O Stop using electricity entirely
Never ride in a car
O Bike or walk to school instead of taking a gasoline-powered car.
Answer:Bike or walk to school instead of taking a gasoline powered car.
Explanation: gasoline is not infinite. trees can be replanted and regrown. electricity can by generated and is not a natural recourse.
Directions: Summarize the main ideas of this lesson by answering the question below.
How might a person acquire a fear of or aversion to something even though it has no negative effect
on him or her?
Answer:
Explanation:
Trypophobia is a fear or disgust of closely-packed holes. People who have it feel queasy when looking at surfaces that have small holes gathered close together.A person may start by imagining what they fear, then looking at pictures of the fear object, and then finally being near or even touching the source of their anxiety. In the case of trypophobia, a person with symptoms may start by simply closing his eyes and imagining something such as a honeycomb or seed poThey can help you find the root of the fear and manage your symptoms. Last medically reviewed on July 20, 2017 Medically reviewed by Timothy J. Legg, Ph.D., CRNP — Written by Annamarya Scaccia ...
Calculate the kinetic energy of a 50 kg cart moving at a speed of 7.1 m/s.
ill give u 100 points if you give me the right answer.
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HOPE IT HELPS
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Please Mark As
[tex]\huge\underline{ \mathbb\red{Brilliant}\:\mathbb\purple{Answers}}[/tex]
Brilliant Answers
Choose the answer that is most descriptive of the Solar System. Sun, planets, moons, asteroids, comets Nebulas, star clusters, super nova, black holes, binary stars Jupiter, Neptune, Saturn, Uranus, dwarf planets Jupiter, Great Red Spot, 8 regular moons, ±58 irregular moons
Answer:
The correct option is;
Sun, planets, moons, asteroids, comets
Explanation:
The Solar System consists of the system of celestial bodies bound gravitationally to the Sun, which includes the 8 regular planets, 2 dwarf planets, 796, 354 known minor planets, 4,143 comets, moons, which are natural satellites, an asteroid belt, which consists of a belt of rock and metal containing celestial bodies moving in a belt round the Sun
the diagram shows the apparent motion of the sun across the sky?
Answer:
The earth rotates west to east
Explanation:
Considering that the sun doesn't really move and the earth is rotating around the sun, and it is moving from east to west with us (the earth) facing it in which means the earth rotates around the sun west to east!
The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7 x 10 to the -9th power coulombs what is the distance between the two charges
Answer:
0.28 m
Explanation:
The following data were obtained from the question:
Force (F) = 5×10¯⁶ N
Charge 1 (q₁) = 6.7×10¯⁹ C
Charge 2 (q₂) = 6.7×10¯⁹ C
Electrical constant (K) = 9×10⁹ Nm²C¯²
Distance apart (r) =?
Thus, the distance between the two charges can be obtained as follow:
F = Kq₁q₂/r²
5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²
5×10¯⁶ = 4.0401×10¯⁷ / r²
Cross multiply
5×10¯⁶ × r² = 4.0401×10¯⁷
Divide both side by 5×10¯⁶
r² = 4.0401×10¯⁷ / 5×10¯⁶
Take the square root of both side
r = √(4.0401×10¯⁷ / 5×10¯⁶)
r = 0.28 m
Therefore, the distance between the two charges is 0.28 m
Which best compares radiation and conduction?
A. Both transfer thermal energy from warm objects to cooler objects.
B. Both can transfer energy through empty space.
C. Both transfer thermal energy by electromagnetic waves.
D. Both involve the transfer of energy through direct contact.
And also who likes Rick and Morty OwO
Answer:
A
Explanation:
A child pushes a 100 kg refrigerator with a force of 50 N, but the refrigerator does not move. Suppose the coefficient of static friction between the floor and the refrigerator is 0.4. What is the force due to friction in this scenario
Answer:
50 N
Explanation:
Since the refrigerator doesn’t move, that means the force of friction equals the amount of force the child exerts on the fridge. If the friction force were greater than the force by the child, the fridge would start accelerating towards the child. If it were less than the force the child exerted, the fridge would start accelerating away from the child. Therefore, the net force must be 0, in this case, the friction force is equal to the force the child exerted, for it to stay at rest (as Newton’s First Law stated).
I hope this helps! :)
A washing machine is being dragged with a starting force of 380.8 N to the West, but this is reduced by friction. If the mass of the washing machine is 37 kg
and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?
A 10.27 m/s^2 South
B 5 m/s^2 South
C 19.01 m/s^2 South
D 7.6 m/s^2 South
Answer:
B. [tex]5\,\frac{m}{s^{2}}[/tex] South
Explanation:
The correct statement is:
A washing machine is being dragged with a starting force of 380.8 N to the South, but this is reduced by friction. If the mass of the washing machine is 37 kg and the coefficient of friction is 0.54, what was the Net acceleration experienced by the washing machine?
The net force of the washing machine moving on the horizontal ground is equal to the external force minus the friction force, where the normal force from the ground on the washing machine is equal to its weight. The free body diagram of the washing machine is presented below. The equation of equilibrium associated with the acceleration of the washing machine is:
[tex]\Sigma F = P -\mu_{k}\cdot m \cdot g = m\cdot a[/tex] (1)
Where:
[tex]P[/tex] - External force exerted on the washing machine, measured in newtons.
[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.
[tex]m[/tex] - Mass, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]a[/tex] - Net acceleration of the washing machine.
If we know that [tex]P = 380.8\,N[/tex], [tex]m = 37\,kg[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\mu_{k} = 0.54[/tex], then the net acceleration experienced by the washing machine is:
[tex]a = \frac{P}{m}-\mu_{k}\cdot g[/tex]
[tex]a = \frac{380.8\,N}{37\,kg}-(0.54)\cdot \left(9.807\,\frac{m}{s^{2}} \right)[/tex]
[tex]a = 4.996\,\frac{m}{s^{2}}[/tex]
The correct answer is B.
Which of the following does not illustrate a complete circuit?
Answer:
I think A
Explanation:
because it dosn't have enough tools
A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?
Answer:
[tex]2.33\ m/s^2[/tex]
Explanation:
Net Force
According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:
Fn = m.a
Where a is the acceleration of the object. The net force is the sum of the individual vector forces applied to the object.
The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.
The net force is Fn = 5000 N - 1500 N = 3500 N
To find the acceleration, we solve the equation for a:
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
[tex]\displaystyle a=\frac{3500}{1500}[/tex]
[tex]\boxed{a = 2.33\ m/s^2}[/tex]
The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]
Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above
Answer:
Explanation:
Hell im good dude
How long will it take an object traveling at 7 m/s to reach a distance of 26 meters
Answer:
3 hours 71 minutes
Explanation:
As because Speed= distance/time taken
so time taken= 3.71
A train travels with a speed of 115km/hr. How much time does it take to cover a distance of 470km.
It would take approximately 4 hours for the train to cover a distance of 470km.
4 hours 5 minutes 13.04 seconds