Can someone help me with this?

Find x. Round to the nearest tenth.
xº
13
15

Step-by-step explanation:

[tex]f(x) = {x}^{2} + 2x - 10 \\ f( - 2) = { (- 2)}^{2} + 2( - 2) - 10 = \\ = 4 - 4 - 10 = - 10[/tex]

Answer:

-2x²+490x+2500

Step-by-step explanation:

Given that,

Demand, D(x) = 500-2x

The price for the product, P(x) = x+5

We need to find the revenue for the product. The formula for the revenue is given by :

Revenue = price × demand

Substitute all the values,

R = (x+5)(500-2x)

= 500x -2x² + 2500 -10x

= -2x²+490x+2500

So, the expression for the revenue function is "-2x²+490x+2500".

Answer:

True

Step-by-step explanation:

When she divides both numbers, she can find out how many stamps she bought. When you solve the equation, we can see that she bought 244 stamps. We can check this by doing inverse operations. 244 x 0.65 (the price for each stamp) = 158.60

i hope that this helps you :)

Answer:

~114.56

Step-by-step explanation:

Because you're asked to find the number so that x% is y, we will have to find that number. The equation in that case would be NUM * 0.934 = 107. Divide both sides by .934 to get an answer of approximately 114.56.

Answer:

The answer should be C

Step-by-step explanation:

I hope that helps you!

Answer:

1. half angle

2. x

Step-by-step explanation:

The missing parts of the proof is the variable x.

Trigonometric functions are those functions which are the ratio of the sides of a right angled triangle.

Given,

sin² (x) = [1 - cos (2x)] / 2

We have to prove sin ([tex]\frac{x}{2}[/tex]) = ± [tex]\sqrt{\frac{1-cos (x)}{2} }[/tex]

First, we have

sin² (x) = [1 - cos (2x)] / 2

Substituting x/2 in place of x, we get,

sin² (x/2) = [1 - cos (2x/2)] / 2

sin² (x/2) =  [1 - cos (x)] / 2

sin² ([tex]\frac{x}{2}[/tex]) = [tex]{\frac{1-cos (x)}{2} }[/tex]

Taking square root on both sides,

sin ([tex]\frac{x}{2}[/tex]) = ± [tex]\sqrt{\frac{1-cos (x)}{2} }[/tex]

Hence it is proved.

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Answer:

3 seconds

Step-by-step explanation:

Initial height = 144 feet

t = Time taken

The equation of the height from the ground is

[tex]h(t)=-16t^2+\text{Initial height}[/tex]

The time taken to reach the ground is needed. Here the ground is taken as reference so [tex]h(t)=0[/tex]

[tex]0=-16t^2+144\\\Rightarrow -144=-16t^2\\\Rightarrow t=\sqrt{\dfrac{144}{16}}\\\Rightarrow t=3\ \text{s}[/tex]

So, time taken by the quarter to reach the ground is 3 seconds.

Step-by-step explanation:

i think it's a b and answer my new question it's 100 point question I really need the answer pls help me

Answer:

35 (C)

Step-by-step explanation:

Answer:

B) 30

Step-by-step explanation:

This is a pretty tricky question. If you draw the line of best fit and go to 9 salespeople, it would be closer to 30 compared to any of the other choices.

Answer:

the answer qould be 4x if you are just simplifying

Answer:

i think it would be the first one i am not 100% sure just a gues

Step-by-step explanation:

Answer:

1/12

Step-by-step explanation:

if Mr.Tough can grade 1 in 12 hours he can do 1/12

The fraction of the exams that Mr Tough and Mrs Nice grade in 1 hour if they work together is 3/20

A fraction is used to denote a portion or component of a whole. Numerator and denominator are the two components that make up a fraction. There are three types of fractions: proper, incorrect, and mixed.

Using, rate × time = work done

So, Mr Tough's rate:

Mr Tough's rate × 12 hours = final exam

Mr Tough's rate = 1/12

and, Mrs. Nice's' rate:

Mrs .Nice's' rate × 15 hours = final exam

Mrs .Nice's' rate = 1/15

So, Total time:

T(1/12 hours + 1/15 hours) = final exam

T =  final exam / (1/12 + 1/15)

T =  final exam / (0.15)

Now, 1 hour =  final exam / (0.15)

final exam = 1 × 0.15

                = 0.15

                = 15/ 100

                = 3/20

Therefore, 3/20 fraction of the final exam.

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Answer:

28

Step-by-step explanation:

Answer:

The student got 28 questions correct and 7 wrong.

Answer:

Expression of the statement = 18 - 2x

Answer:

18 - 2x

Step-by-step explanation:

Answer:

4/6

Step-by-step explanation:

the total time the dice roll over four.. which is also 4/6

Answer:

12

Step-by-step explanation:

Answer: 9/8 , 18/16 , 27/24 , 36/32 , 45/40 , 54/48 , 63/56

The minimum value of both sine and cosine is -1. However the angles that produce the minimum values are different, [tex]-\pi/2, \pi[/tex] for sine and cosine respectively.

The question is, can we find an angle for which the sum of sine and cosine of such angle is less than the sum of values at any other angle.

Here is a procedure, first take a derivative

[tex]\frac{d}{dx}(\sin x+\cos x)=\cos x -\sin x[/tex]

Then compute critical points of a derivative

[tex]\cos x-\sin x=0\implies x_1=\frac{\pi}{4},x_2=\frac{5\pi}{4}[/tex].

Then evaluate [tex]\sin x +\cos x[/tex] at [tex]x_1,x_2[/tex].

You will obtain global maxima and global minima [tex]\sqrt{2}, -\sqrt{2}[/tex] respectively.

The answer is [tex]-\sqrt{2}[/tex].

Hope this helps.

3 : 5

x : 125

125 ÷ 5 = 25

25 × 3 = 75

no. of hens = 75

Answer:

9,160,000 tons

Answer:

A) = m

Step-by-step explanation:

Answer:

17.2 in

Step-by-step explanation:

The formula for arc length is s = rФ.  Here we are to find r.  Solving this formula for r, we get:

r = s/Ф

So, in this problem, r = (9 in) / (π/6) = 54/π in ≈ 17.2 in

Answer:

○ B. [tex]\displaystyle 186\:square\:units[/tex]

Explanation:

All edges conjoin to form right angles, therefore you have these:

[tex]\displaystyle \boxed{186} \hookrightarrow 121 + 30 + 35 \Rightarrow 11^2 + 5 \times 6 + 5 \times 7[/tex]

OR

[tex]\displaystyle \boxed{186} \hookrightarrow 120 + 66 \Rightarrow 24 \times 5 + 6 \times 11[/tex]

I am joyous to assist you at any time.

Answer:

first and last expressions are correct.

The roots of x^2 + (1 - k).x+k-3 = 0 are real for all real values of k

The equation is given as:

x^2 + (1 - k).x+k-3 = 0

For an equation to have real root, then the following must be true:

[tex]b^2 \ge 4ac[/tex]

In x^2 + (1 - k).x+k-3 = 0, we have:

a = 1

b = 1 - k

c = k - 3

So, we have:

[tex](1 - k)^2 \ge 4 * 1 * (k - 3)[/tex]

Evaluate

[tex]1 - 2k + k^2 \ge 4k - 12[/tex]

Collect like terms

[tex]k^2 - 2k - 4k + 1 + 12 \ge 0[/tex]

[tex]k^2 - 6k + 13 \ge 0[/tex]

Using a graphing calculator, the value of k is all real numbers

Hence, the roots of x^2 + (1 - k).x+k-3 = 0 are real for all real values of k

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