can someone help me with this please?

Can Someone Help Me With This Please?

Answers

Answer 1

Answer:

1) m∠AB'C = 41°

2) m∠BAC = 49°

3) m∠B'AC = 49°

4) m∠ACB = 90° Given

5) m∠ACB' = 90°

6) [tex]\overline {AB'}[/tex] = 24

7) Isosceles triangle

8) True

Step-by-step explanation:

Given that triangle ΔABC, is the reflection of ΔAB'C, and given that a reflection is a rigid transformation, we have;

1) ΔABC ≅ ΔAB'C Given

∴ m∠AB'C ≅ m∠ABC given that Corresponding Parts of Congruent Triangles are Congruent (CPCTC)

m∠AB'C = m∠ABC by the definition of congruency

∴ m∠AB'C = m∠ABC = 41°

2) Similarly, we have;

m∠BAC = 180° - (90° + 41°) = 49° Given the sum of interior angles of a triangle theorem

m∠BAC = 49°

3) m∠BAC = m∠B'AC by CPCTC

∴ m∠B'AC = m∠BAC = 49° by transitive property

m∠B'AC = 49°

4) m∠ACB = 90° Given

5) ∴ m∠ACB' = 90° given that the sum of angles on a straight line is 180°

6) [tex]\overline {AB}[/tex] = 24 Given

[tex]\overline {AB}[/tex] ≅ [tex]\overline {AB'}[/tex]  given that ΔABC ≅ ΔAB'C and CPCTC

[tex]\overline {AB}[/tex] = [tex]\overline {AB'}[/tex]

[tex]\overline {AB'}[/tex] = [tex]\overline {AB}[/tex] = 24

[tex]\overline {AB'}[/tex] = 24

7) In ΔABB', [tex]\overline {AB'}[/tex] = [tex]\overline {AB}[/tex] = 24 therefore, ΔABB' has two sides equal and ΔABB' Is an isosceles triangle

8) True, the angles opposite the congruent sides are the base angles of the isosceles triangle and they are therefore congruent


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Complete question :

Swim team Hanover High School has the best women’s swimming team in the region. The 400- meter freestyle relay team is undefeated this year. In the 400-meter freestyle relay, each swimmer swims 100 meters. The times, in seconds, for the four swimmers this season are approximately Normally distributed with means and standard deviations as shown. Assuming that the swimmer’s individual times are independent, find the probability that the total team time in the 400-meter freestyle relay is less than 220 seconds. Follow the four-step process

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