can someone help me with this
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Answer:

 K_a = 8,111 J

Explanation:

This is a collision exercise, let's define the system as formed by the two particles A and B, in this way the forces during the collision are internal and the moment is conserved

initial instant. Just before dropping the particles

          p₀ = 0

final moment

          p_f = m_a v_a + m_b v_b

          p₀ = p_f

          0 = m_a v_a + m_b v_b

tells us that

          m_a = 8 m_b

           0 = 8 m_b v_a + m_b v_b

           v_b = - 8 v_a                    (1)

indicate that the transfer is complete, therefore the kinematic energy is conserved

starting point

           Em₀ = K₀ = 73 J

final point. After separating the body

          Em_f = K_f = ½ m_a v_a² + ½ m_b v_b²

           K₀ = K_f

           73 = ½ m_a (v_a² + v_b² / 8)

we substitute equation 1

           73 = ½ m_a (v_a² + 8² v_a² / 8)

           73 = ½ m_a (9 v_a²)

           73/9 = ½ m_a (v_a²) = K_a

            K_a = 8,111 J

Answer:

Kindly check explanation

Explanation:

Given the data:

Trial V (volts) I (mA)

1 1.00 7.2

2 2.10 14.0

3 3.10 20.7

4 4.00 27.2

5 4.90 32.2

Slope = Rise / Run

Rise = y2 - y1 = 32.2 - 7.2 = 25

Run = x2 - x1 = 4.9 - 1.0 = 3.9

Slope = 25 / 3.9 = 6.410

y = mx + c

The intercept, c

Take the point ( 1; 7.2)

Put x = 0

7.2 = 6.410(1) + C

7.2 - 6.410 = C

C = 0.79

Answer:

This can help you! Pictures tell more than 100s of word.

Explanation:

Answer:

a) 5.64 C

b) 3.5*10¹⁹ protons

Explanation:

a)

       [tex]Q_{n} = \frac{Q_{tot}}{4} = \frac{22.57C}{4} = 5.64 C (1)[/tex]

b)

Answer:

dude the answer is upright

Answer:

[tex]\boxed{\text{\sf \Large 2.0 m/s^2 $}}[/tex]

Explanation:

Use acceleration formula

[tex]\displaystyle \text{$ \sf acceleration=\frac{change \ in\ velocity}{change \ in \ time} $}[/tex]

[tex]\displaystyle a=\frac{65-47}{12.0-3.0} =2.0[/tex]

Answer:

Vf = 69.61 m/s

Explanation:

We will use the third equation of motion to solve this problem:

[tex]2gh = V_{f}^2 - V_{i}^2\\[/tex]

where,

g = acceleration due to gravity = 9.81 m/s²

h = height of cliff = 247 m

Vf = final velocity = ?

Vi = initial velocity = 0 m/s (boulder breaks loose from rest)

Therefore,

[tex](2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\[/tex]

Vf = 69.61 m/s

Answer:

the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          K = E - Ф

Explanation:

The photoelectric effect is the emission of electrons from the surface of a metal.

This was correctly explained by Einstein, in his explanation the energy of the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          E = hf

          E = K + Ф

          K = E - Ф

The energy of the photons is given by the Planck relation E = hf and according to Einstein the number of joints must be added

            E = n hf

Therefore, depending on the value of this energy, the emitted electrons can have energy from zero onwards.

Answer:

* roller skates and ice skates.

* roller coaster

Explanation:

One of the best examples for this situation is when we are skating, in the initial part we must create work with a force, it compensates to move, after this the external force stops working and we continue movements with kinetic energy, if there are some ramps, we can going up, where the kinetic energy is transformed into potential energy and when going down again it is transformed into kinetic energy. This is true for both roller skates and ice skates.

Another example is the roller coaster, in this case the motor creates work to increase the energy of the car by raising it, when it reaches the top the motor is disconnected, and all the movement is carried out with changes in kinetic and potential energy. In the upper part the energy is almost all potential, it only has the kinetic energy necessary to continue the movement and in the lower part it is all kinetic; At the end of the tour, the brakes are applied that bring about the non-conservative forces that decrease the mechanical energy, transforming it into heat.

Answer:

1920Joules

Explanation:

The formula for calculating the kinetic energy of a body is expressed as;

KE = 1/2 mv²

m isthe mass

V is the speed

For the two masses, the combined KE is expressed as;

KE  = 1/2(m1+m2)v²

KE = 1/2(45+15)(8)²

KE  = 1/2 * 60 * 64

KE  = 30 * 64

KE  = 1920J

Hence the combined kinetic energy of the boy and the bicycle is 1920Joules

The combined kinetic energy of the boy and the bicycle is of 1920 J.

Given data:

The mass of boy is, m = 45.0 kg.

The mass of bicycle is, M = 15.0 kg.

The speed of bicycle is, v = 8.00 m/s.

The kinetic energy of an object is defined as the energy possessed by an object by virtue of motion of object. The combined kinetic energy of the boy-bicycle system is given as,

[tex]KE = \dfrac{1}{2}(m+M)v^{2}[/tex]

Solve by substituting the values as,

[tex]KE = \dfrac{1}{2}(45+15) \times 8^{2}\\\\KE = 1920 \;\rm J[/tex]

Thus, we can conclude that the combined kinetic energy of the boy and the bicycle is of 1920 J.

Learn more about the concept of kinetic energy here:

https://brainly.com/question/12669551

Answer:

a) [tex]W=9810\: N[/tex]

b) [tex]F_{1}=251.14\: N[/tex]        

c) [tex]V_{g}=0.012\: m^{3}[/tex]

Explanation:

a)

El peso del cuerpo es:

[tex]W=mg[/tex]

g es la gravedad (9.81 m/s²)

[tex]W=1000*9.81[/tex]

[tex]W=9810\: N[/tex]

b)

Usando el principio de Pascal tenemos:

[tex]P_{1}=P_{2}[/tex]

y la presion es la fuerza sobre el area.

[tex]\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{2}}[/tex]

Despejando F(1):

[tex]F_{1}=F_{2}\frac{A_{1}}{A_{2}}[/tex]

el area del plato es: [tex]A=\pi R^{2}[/tex]

[tex]F_{1}=F_{2}\frac{\pi R_{1}^{2}}{\pi R_{2}^{2}}[/tex]

[tex]F_{1}=F_{2}\frac{R_{1}^{2}}{R_{2}^{2}}[/tex]

F(2) es el peso del cuerpo de 1000 kg (W)

[tex]F_{1}=9810\frac{8^{2}}{50^{2}}[/tex]

Por lo tanto, la fuerza que se debe hacer es:

[tex]F_{1}=251.14\: N[/tex]          

c)

Como tenemos un sistema cerrado el volumen de agua que desciende por el embolo pequeño debe ser igual al que sube por el grande, por lo tanto:

[tex]V_{p}=V_{g}[/tex]

Vp es el volumen de agua en el émbolo pequeño

Vg es el volumen de agua en el émbolo grande

Como sabemos que son cilindros (V=πR²h)

[tex]\pi R^{2}h=V_{g}[/tex]

Entonces el volumen del émbolo mayor será:

[tex]V_{g}=\pi 0.08^{2}0.6[/tex]

[tex]V_{g}=0.012\: m^{3}[/tex]

Espero te haya sido de ayuda!

Answer:

8: More

9: More

10: More

11: Less

12: Less

12: More

In a series circuit . . .

-- The total resistance is the sum of the individual resistors.

-- The current is the same at every point in the circuit.

The total resistance in this circuit is (3Ω + 6Ω )  =  9Ω

The current at every point is (V/R) = (12v / 9Ω ) = 1.33 A .

Pick choice (a).

The current flowing through the 6 Ohms resistor is: a.  1.33 A

Given the following data:

To find the current flowing through the 6 Ohms resistor:

First of all, we would determine the total equivalent resistance of the resistors connected in series.

[tex]T_eq = Resistor \; A + Resistor\; B\\\\T_eq = 3 + 6[/tex]

Total equivalent resistance = 9 Ohms

Note: The current flowing through both resistors are the same since they are connected in series.

From Ohm's law, we have:

[tex]Current = \frac{Voltage}{Resistor}\\\\Current = \frac{12}{9}[/tex]

Current = 1.33 Amperes

Therefore, the current flowing through the 6 Ohms resistor is 1.33 Amperes.

Answer:

I only know number 4 is correct

Explanation:

Answer:

conduction is the correct answer

Answer:

Gravitational

Tension

Normal

Friction.

Explanation:

The forces acting on the sled are:

Tension: the tension from the rope, this is the force that "moves" the sled.

Friction: kinetic friction between the sled and the ground as the sled moves.

There are another two forces that also act on the sled, but that "has no effect"

Gravitational force: This force pulls the sled down, against the floor.

Normal force: This force "opposes" to the gravitational one, so they cancel each other.

These two forces cancel each other, so they have no direct impact on the movement of the sled. BUT, the friction force depends on the weight of the moving object, and the weight of the moving object depends on the gravitational force, so we need gravitational force in order to have friction force.

Then we can conclude that the forces acting on the sled are:

Gravitational

Tension

Normal

Friction.

Answer:

you have to times them all ti get the answer

Answer:

Dakota moves a magnetic toy train toward a magnet that cannot move. What happens to the potential energy in the system of magnets during the movement? The potential energy increases because the train moves against the magnetic force. The potential energy decreases because the train moves against the magnetic force.

I hope this helps you :)

Answer:

12164.4 Nm

Explanation:

CHECK THE ATTACHMENT

Given values are;

m1= 470 kg

x= 4m

m2= 75kg

Cm = center of mass

g= acceleration due to gravity= 9.82 m/s^2

The distance of centre of mass is x/2

Center of mass(1) = x/2

But x= 4 m

Then substitute, we have,

Center of mass(1) = 4/2 = 2m

We can find the total torque, through the summation of moments that comes from both the man and the beam.

τ = τ(1) + τ(2)

But

τ(1)= ( Center of m1 × m1 × g)= (2× 470× 9.81)

= 9221.4Nm

τ(2)= X * m2 * g = ( 4× 75 × 9.81)= 2943Nm

τ = τ(1) + τ(2)

= 9221.4Nm + 2943Nm

= 12164.4 Nm

Hence, the magnitude of the torque about the point where the beam is bolted into place is 12164.4 Nm

Answer: 52 kg skydiver: 9.09 m/s and 522.55 s

              95 kg skydiver: 12.3 m/s and 386.2 s

Explanation: Drag Force is an opposite force when an object is moving in a fluid.

For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the Terminal Velocity.

Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:

[tex]F_{G}=F_{D}[/tex]

[tex]mg=\frac{1}{2}C \rho Av_{T}^{2}[/tex]

[tex]v_{T}=\sqrt{\frac{2mg}{\rho CA} }[/tex]

where

m is mass in kg

g is acceleration due to gravitational force in m/s²

ρ is density of the fluid in kg/m³

C is drag coefficient

A is area of the object in the fluid in m²

Calculating:

The 52kg skydiver has terminal velocity of:

[tex]v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }[/tex]

[tex]v_{T}=[/tex] 9.09

The 95kg skydiver's terminal velocity is

[tex]v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }[/tex]

[tex]v_{T}=[/tex] 12.3

The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.

The time each one will reach the floor will be:

52 kg at 9.09 m/s:

[tex]t=\frac{4750}{9.09}[/tex]

t = 522.5

95 kg at 12.3 m/s:

[tex]t=\frac{4750}{12.3}[/tex]

t = 386.2

The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.

Answer:

Focal length(f)= -15 cm, magnification= -3 (image is real). So, -v/u=-3 ; or v=3u {v=image distance and u=object distance}. Using mirror formula,

1/f= 1/v + 1/u

-1/15 = 1/3u + 1/u

4/3u = -1/15

u= -20 cm

v =3u= 3×(-20)= -60 cm

So object is 20 cm and image is 60 cm in front of the mirror.

Explanation:

Answer:

[tex]-18.43^{\circ}[/tex]

Explanation:

Let [tex]\theta[/tex] be the polar angle of −3i + j. We can find it using the formula as follows :

[tex]\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{1}{-3}\\\\\theta=\tan^{-1}(\dfrac{1}{-3})\\\\\theta=-18.43^{\circ}[/tex]

So, the required polar angle is [tex]-18.43^{\circ}[/tex].

Answer:

Break down small pebbles and sediments, like sand

Break down large rocks like mountains

Explanation:

Answer:

B.22,5000

Explanation:

SANA MAKATULONG

The momentum of a compact car that is 750 kg and is travelling 30 m/s be 22500 N-s.

The relationship between a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force applied on a particle is equal to the time rate of change of momentum.

Given parameters:

Mass of the compact car: m = 750 kg.

Speed of the car: v = 30 m/s.

Hence, magnitude of momentum of the car is = mv

= 750×30 N-s

= 22500 N-s.

Learn more about momentum here:

https://brainly.com/question/29113044

#SPJ2

Answer:

The correct answer is "21195 N".

Explanation:

The given values are:

Tensile strength,

= 3000 MN/m²

Diameter,

= 3.0 mm

i.e.,

= 3×10⁻³ m

Now,

The maximum load will be:

=  [tex]Tensile \ strength\times Area[/tex]

On substituting the values, we get

=  [tex](3000\times 10^6)(\frac{\pi}{4} (3\times 10^{-3})^2)[/tex]

=  [tex](3000\times 10^6)(\frac{3.14}{4} (3\times 10^{-3})^2)[/tex]

=  [tex]21195 \ N[/tex]

Answer:

D Galileo Galilae

Explanation:

It's now understood that English astronomer Thomas Harriot, (1560-1621) made the first recorded observations of the Moon through a telescope, a month before Galileo

Answer: Galileo Galilae

Explanation:

Answer: A is correct because

A.70 as a range

B. 8 as an range

C.26 as an range

D.18 as an range

Answer:

a) El valor de la densidad es 0.79 [tex]\frac{g}{cm^{3} }[/tex] o 790 [tex]\frac{g}{cm^{3} }[/tex]

b) El peso especifico es 7749.9[tex]\frac{N}{m^{3} }[/tex]

Explanation:

a) La densidad se define como la propiedad que tiene la materia, ya sean sólidos, líquidos o gases, para comprimirse en un espacio determinado. En otras palabras, la densidad es una magnitud que permite medir la cantidad de masa que hay en determinado volumen de una sustancia. Entonces, la expresión para el cálculo de la densidad es el cociente entre la masa de un cuerpo y el volumen que ocupa:

[tex]d=\frac{m}{V}[/tex]

En este caso:

Reemplazando:

[tex]d=\frac{237 g}{300cm^{3} }[/tex] →  d=0.79 [tex]\frac{g}{cm^{3} }[/tex]

[tex]d=\frac{0,237 kg}{0,0003m^{3} }[/tex]→  d=790 [tex]\frac{g}{cm^{3} }[/tex]

El valor de la densidad es 0.79 [tex]\frac{g}{cm^{3} }[/tex] o 790 [tex]\frac{g}{cm^{3} }[/tex]

b) El peso específico es la relación existente entre el peso y el volumen que ocupa una sustancia en el espacio.

Entonces, en este caso, siendo el peso:

P= m*g= 0,237 kg* 9,81 [tex]\frac{m}{s^{2} }[/tex]= 2,32497 N

el peso especifico es calculado como:

[tex]Pe=\frac{Peso}{Volumen}= \frac{2,32497N}{0,0003 m^{3} }[/tex]

Pe= 7749.9[tex]\frac{N}{m^{3} }[/tex]

El peso especifico es 7749.9[tex]\frac{N}{m^{3} }[/tex]