Can someone help me solve this

Answer:

15 + 2j

Step-by-step explanation:

Sum, which means addition, is used to say that 15 will be added to something.

That "something" is twice Jose's score, which is 2 * j, since j is the score.

15 + 2 * j, or just 15 + 2j

one third of 33 is 11

one fifth of 45 is 9.

Answer:

7.2

Step-by-step explanation:

468/65 = 7.2

The coordinates of the fourth vertex are (-3, -1).

In order to determine the midpoint of a line segment with two (2) endpoints, we would add each point together and divide by two (2).

Midpoint = [(x₁ + x₂)/2, (y₁ + y₂)/2]

Substituting the given parameters into the midpoint of a line segment formula, the midpoint of the diagonal is given by;

Midpoint = [(5 - 5)/2, (-3 - 5)/2]

Midpoint = [0/2, -8/2]

Midpoint = (0, -4).

For the fourth vertex, we have:

Midpoint = [(x₁ + x₂)/2, (y₁ + y₂)/2]

(0, -4) = [(3 + x₂)/2, (-7 + y₂)/2]

3 + x₂ = 2(0)

x₂ = -3

-7 + y₂ = 2(-4)

-7 + y₂ = -8

y₂ = -8 + 7

y₂ = -1.

Therefore, the fourth vertex = (-3, -1).

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According to the question the solution to the given IVP is [tex](ln(9/8))(e^{2t} - te^{2t} + 1).[/tex]

IVP stands for Initial Value Problem. It is a mathematical problem where an initial value is given at a certain point in time, and the goal is to find the solution for the function at all other points in time. An IVP is important in the study of differential equations, which are used to model a wide range of phenomena in science, engineering, and economics.

The given IVP is a second order linear differential equation with constant coefficients, so the general solution can be written as
[tex]y(t) = c_1e^{2t} + c_2te^{2t} + d[/tex]
where c_1, c_2, and d are constants to be determined.
Substituting the initial conditions into the general solution yields
[tex]y(-ln2) = c_1(-ln2)^2 + c_2(-ln2) + d = 0[/tex]
and
[tex]y'(-ln2) = 2c_1(-ln2) + c_2e^{2(-ln2)} = ln(9/8).[/tex]
Solving these two equations for c_1 and c_2 yields
[tex]c_1 = -(ln(9/8) + d)/2(-ln2)^2[/tex]
and
[tex]c_2 = (ln(9/8) + 2d)/2(-ln2)[/tex]
Substituting these values into the general solution and solving for d yields
d = ln(9/8).
Therefore, the solution to the given IVP is
[tex]y(t) = -(ln(9/8) + ln(9/8))e^{2t}/2(-ln2)^2 + (ln(9/8) + 2ln(9/8))te^{2t}/2(-ln2) + ln(9/8)[/tex]
= [tex](ln(9/8))(e^{2t} - te^{2t} + 1).[/tex]

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Answer: (2x+4)

Step-by-step explanation:

The term (4x+8) is in brackets. That means whatever you do to it will affect every term in the bracket.

This time, you are dividing by 2

Thus, (4x+8)/2 = 4x/2+8/2

=2x+4

Hope this helps! :)

Answer:  we move (5, 1/3) to (5-3, 1/3*3) = (2, 1)

Step-by-step explanation:

This answer can be derived from the equation h(t)=-4.9t²+19t+19.

An equation is a mathematical statement that two expressions are equal. Equations are used to describe relationships between numbers, variables, and constants. They are typically written in the form of an expression on the left of an equal sign and the result of the expression on the right. For example, 2 + 3 = 5 is an equation that states that the sum of two and three is five. Equations can be used to solve problems and express relationships in science, engineering, economics, and many other fields.

The equation represents a parabola, so the maximum height is found at the vertex of the parabola. The x-coordinate of the vertex can be found by setting the derivative of the equation equal to zero, which gives us the equation -4.9×2t + 19 = 0. Solving this equation for t gives us the answer of t = 1.914 seconds.

This is happening because of the kinematic equation which describes the motion of objects in terms of their displacement, velocity, and acceleration. In this equation, h(t) is the displacement of the ball as a function of time. The derivative of the displacement equation with respect to time gives us the equation for the velocity of the ball, which identifies the point at which the ball reaches its maximum height. Since velocity is equal to zero at the highest point of the ball's trajectory, this equation can be used to find the time it takes for the ball to reach its maximum height.

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Answer:

1) 4x -28 - 2x = 0

2) 2x = 28

3) x = 14

Step-by-step explanation:

1) 4 * (-7) = -28

2) 4x - 2x = 28

   2x = 28

3) x = 28/2

   x = 14

The solution to the inequality is p > -2 and p < -1, expressed in interval notation as -2>p>-1.

Interval notation is a mathematical notation for expressing ranges of values between two numbers. It is used to describe the set of real numbers that are bounded between two specified numbers, such as [x, y]. The interval notation is composed of two numbers (x and y) separated by a comma and enclosed in square brackets. The notation is used to represent the entire set of values that lie between the two boundaries.

This is expressed in interval notation as -2>p>-1. This can be solved by isolating the variable p, first by subtracting 31 from both sides of the equation. This leaves -6 + 12p > -24. Then, divide both sides by 12, which gives p > -2. To check the solution, the original equation can be substituted with the value of p. If the equation is true, the solution is correct.

To solve the inequality -6+12p+31 > 7, first subtract 31 from both sides of the equation to isolate the variable. This leaves -6 + 12p > -24. Then, divide both sides by 12 to get p > -2. Finally, check the solution by substituting the value of p in the original equation. If the equation is true, the solution is correct. The solution to the inequality is p > -2 and p < -1, expressed in interval notation as -2>p>-1.

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[tex] \mathbb{ANSWER:}[/tex]

[tex] \sf 3x + 2y = 4[/tex]

[tex] \sf x = 0 \\ \sf \cancel{3(0) }+ 2y = 4 \\ \sf \frac{2y}{2} = \frac{4}{2} \\ \sf y = \boxed{ \sf 2}[/tex]

[tex] \sf x = - 2 \\ \sf 3( - 2)+ 2y = 4 \\ \sf - 6 + 2y = 4 \\ \sf \cancel{- 6 + 6} + 2y = 4 + 6 \\ \sf \frac{2y}{2} = \frac{10}{2} \\ \sf y = \boxed{ \sf 5}[/tex]

[tex] \sf x = 1 \\ \sf 3(1)+ 2y = 4 \\ \sf 3 + 2y = 4 \\ \sf \cancel{3 - 3} + 2y = 4 - 3 \\ \sf \frac{2y}{2} = \frac{1}{2} \\ \sf y = \boxed{ \sf \frac{1}{2} }[/tex]

[tex] \sf x = 4 \\ \sf 3(4)+ 2y = 4 \\ \sf 12 + 2y = 4 \\ \sf \cancel{- 12 - 12} + 2y = 4 - 12 \\ \sf \frac{2y}{2} = \frac{ - 8}{2} \\ \sf y = \boxed{ \sf - 4}[/tex]

The quadrilaterals which have diagonals that are perpendicular are Kite, Rhombus, Square.(option A)

Diagonals are the part of a shape, in geometry. In Mathematics , a  diagonal is a line that connects two vertices of a polygon or a solid, whose vertices are not on the same edge. in general, a diagonal is defined as a sloping line or the slant line , that connects to the vertices of a shape. diagonals are defined as lateral shapes that have sides/ edges and corners.

Kite

Rhombus

Square

these are the quadrilaterals that have diagonals that are perpendicular.

hence the answer is option A.

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Answer:

-----------------------------------

The scale factor k affects the points with the rule:

Apply the rule to the given points, given k = 3:

After answering the presented question, we can conclude that As a triangle result, the figure has a surface area of 24.5 square millimeters.

Because it has four or more pieces, a triangle is a polygon. It has a straightforward rectangular shape. A triangle ABC is a rectangle with A, B, and C edges. Euclidean geometry provides a single plane and cube when the sides are not collinear. A polygon is a triangle with three components and three angles. The corners of a triangle are the spots where the three edges meet. A triangle's sides add up to 180 degrees.

To calculate the area of the figure, we must first calculate the areas of each shape and then add them together.

c² = a² + b²5² = 4

_g² +b²25 = 16+ b²_9_ = 3

As a result, the base of the second triangle is 3mm. We can now pinpoint its location:

A = 1/2 * 3mm * 3mm * 3mm = 4.5mm2

A is equal to (5mm + 5mm) * 4mm / 2 = 20mm2.

We can now add the regions of all three shapes:

Total surface area = 4.5mm2 + 20mm2 = 24.5mm2

As a result, the figure has a surface area of 24.5 square millimeters.

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The correct statements are A and E.

A sample is a subset of a larger population that is selected for research or analysis. The sample should be representative of the population to ensure accurate and unbiased conclusions.

A. Amy should have included students from one other science class because the sample should be representative of the entire middle school population, and including students from only one class may not provide a representative sample.

B. To get a good estimate, Amy does not necessarily need all the students at the school to answer the question. However, a larger sample size would increase the accuracy and precision of the estimate.

C. Mixing up the data from the science class would not be necessary if the sample is random and representative of the middle school population.

D. Amy's results can be used to estimate the average number of hours of sleep a typical student at her middle school gets on Saturday nights, provided the sample is random and representative of the middle school population.

E. The sample Amy used may not be a true random sample if it was only taken from one science class. The sample should be randomly selected from the entire middle school population to be representative.

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George can build a section of fence per hour, thus 2/3 is the fraction that indicates that.

A fraction is a component of a whole. Mathematically, the number is expressed as a fraction, where the both the numerator and the denominator are divided. In a simple fraction, both are integers. A complex fraction has a fraction in both the numerator and denominator. A correct fraction has a lower denominator than its numerator.

George builds 1/3 of the fence every 1/2 hour.

We need to understand how many sections the fence he can construct in an hour in order to calculate the percentage of fence he can construct each hour.

George may construct 2 × (1/3) or 2/3 of the fence in an hour because 1 hour as equal to 2 of a 1/2-hour periods.

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The measure in radians of angle POQ is given as follows:

π/4 radians.

The measure of angle POQ is obtained applying the proportions in the context of the problem.

Angle POR is one fourth of the unit circle, which is of 360º, hence it's measure is given as follows:

POR = 0.25 x 360

POR = 90º.

Angle POQ is halfway between 0 radians and angle POR, hence it's measure is given as follows:

POQ = (0 + 90)/2 = 45º.

180º is equivalent to π radians, and 180/45 = 4, hence the measure in radians of angle POQ is given as follows:

π/4 radians.

The diagram is given by the image presented at the end of the answer.

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Answer:

348 in²

Step-by-step explanation:

[tex] \frac{ad \times (cd + ab)}{2} [/tex]

[tex] \frac{19.2(16 + 24)}{2} [/tex]

384 in²

Given:-

To find:-

Answer:-

Since a flag is of rectangular shape, its perimeter would be;

P = 2( l + b )

where ,

Now let us assume the breadth to be " x " , then its length will be " x + 250 " . Now substitute the respective values in the given formula as ;

2460 = 2 ( x + x + 250)

2460/2 = 2x + 250

1230 = 2x + 250

2x = 1230 - 250

2x = 980

x = 980/2

x = 490

Hence,

Hence the flag's width is 490ft. Its length is 740ft.

and we are done!

_

6thMarch , 3:57 pm

Step-by-step explanation:

the perimeter of a rectangle is

2×length + 2×width

length = width + 250

2×length + 2× width = 2460

now we use the first equation in the second equation abd get

2×(width + 250) + 2×width = 2460

2×width + 500 + 2×width = 2460

4×width = 1960

width = 1960/4 = 490 ft

length = width + 250 = 490 + 250 = 740 ft

Answer:

Step-by-step explanation:

it will take 4 days to pay of the loan

To simplify the given product, we can use the properties of radicals. By assuming d ≥ 0 the product is [tex]3^{(3/2)} \times d^{(3/2)}.[/tex]

Specifically, the product of radicals with the same index can be expressed as a single radical by multiplying their radicands.

In this case, we have:

3√d × 3√d × 3√d

We can write this as a single radical by multiplying the radicands:

[tex]3 \sqrt{d} \times 3\sqrt{d} \times 3\sqrt{d} = (3 \sqrt{d})^3[/tex]

To evaluate this expression, we can use the property of exponents that states that the cube of a number is equal to that number raised to the third power.

Thus:

[tex](3 \sqrt{d})^3 = 3 \sqrt{d} \times 3\sqrt{d} \times 3 \sqrt{d}[/tex]

           [tex]= 3^{(3/2)} \times d^{(3/2)}[/tex]

Therefore, the simplified product is [tex]3^{(3/2)} \times d^{(3/2)}.[/tex]

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Answer: The total number of dogs at the event will depend on the number of playpens in each tent and the number of tents.

In each tent, there are x puppy playpens and y senior dog playpens, and there are 4 dogs in each playpen.

To find the total number of dogs at the event, we need to multiply the number of playpens in each tent by the number of dogs per playpen, and then multiply that by the number of tents.

So the expressions that represent the total number of dogs at the event are:

5xy(4) (multiplying the number of playpens in each tent by the number of dogs per playpen, and then by the number of tents).

20xy (combining the multiplication).

4(5xy) (multiplying the number of dogs per playpen by the number of playpens in each tent, and then by the number of tents).

20xy (combining the multiplication).

Therefore, the expressions that represent the total number of dogs at the event are 20xy and 4(5xy).

Step-by-step explanation:

The number of puppies at the event is represented by the expression 20x, and the number of senior dogs at the event is represented by the expression 20y.

The total number of dogs at the event can be calculated by adding the number of puppies and senior dogs. Since there are x puppy playpens and y senior dog playpens in each tent, and there are 5 tents, we would have 5 * x playpens for puppies and 5 * y playpens for senior dogs. Each playpen holds 4 dogs, so the number of puppies would be 4 * 5 * x, and the number of senior dogs would be 4 * 5 * y. Therefore, the expressions that represent the total number of dogs at the event are 20x (for the puppies) and 20y  (for the senior dogs).

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The number of litres of gasoline that would be needed to fill 5 similar containers is 200 litres.

A litre is a measure of volume

Since a containers when 3/8 full holds 15 litres of gasoline. We need to find how many litres of gasoline would be needed to fill 5 similar containers.

Let x be the volume of the container.

Since a containers when 3/8 full holds 15 litres of gasoline, we have that

3x/8 = 15

Solving for x, we have that

3x/8 = 15

Multiplying through by 8, we have that

3x = 15 × 8

Dividing through by 3, we have that

x = 15 × 8/3

x = 5 × 8

x = 40 litres.

Since one container contains 40 litres, then 5 containers would contain  V = 5 × 40 litres

= 200 litres.

So, 5 containers would contain 200 litres

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When interpreted, the figures of the delivery times of the pizza shops shows that D. The means are nearly equal, but the variation is significantly greater for the second shop than for the first.

This means that, on average, the second pizza shop delivers pizzas slightly faster than the first shop. However, the delivery times for the first shop are more consistent (less variable) than the second shop.

The standard deviation for the first shop (4 minutes) is much lower than the second shop (21 minutes), indicating that the delivery times for the first shop are clustered closely around the mean delivery time, whereas the delivery times for the second shop are more spread out. If delivery time is the only consideration, one may prefer the first shop as it has more consistent delivery times.

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Answer:1/9 i gotchu

Step-by-step explanation:

Answer:

4/8

Step-by-step explanation:

The value of y is given as follows:

y = 35.

A diagonal trapezoid, also known as a trapezium, is a quadrilateral with two parallel sides that are of different lengths. In a diagonal trapezoid, the non-parallel sides are not perpendicular to the parallel sides. This means that the two non-parallel sides are slanted or tilted, forming a diagonal line that connects them.

In a diagonal trapezoid, the diagonals are congruent, meaning that they have the same length.

The diagonals are HJ and IK, hence the value of y is obtained as follows:

5y - 1 = 4y + 34

y = 35.

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The critical points are A = -5 and B = 7, and the function is increasing on the interval (-∞, -5] ∪ [7, ∞), and decreasing on the interval [-5, 7].

To find A and B, we need to find the critical points of the function f(x) and determine the intervals of increase and decrease.

First, we find the derivative of f(x) as:

f'(x) = 6x^2 - 12x - 210

Next, we find the critical points by setting f'(x) = 0:

6x^2 - 12x - 210 = 0

Simplifying, we get:

x^2 - 2x - 35 = 0

Factoring, we get:

(x - 7)(x + 5) = 0

So the critical points are x = 7 and x = -5.

Now we can determine the intervals of increase and decrease. We create a sign chart based on the sign of f'(x) in each interval:

Interval | f'(x) | f(x) increasing/decreasing

(-∞, -5) | - | decreasing

(-5, 7) | + | increasing

(7, ∞) | - | decreasing

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There are 6 ways tο chοοse 2 οbjects withοut replacement frοm 3 οbjects if the chοice matters and 3 ways tο chοοse 2 οbjects withοut replacement frοm 3 οbjects if the chοice dοes nοt matter.

The prοduct οf all pοsitive integers less than οr equal tο a given pοsitive integer and denοted by that integer and an exclamatiοn pοint. Thus, factοrial seven is written 7!, meaning 1 × 2 × 3 × 4 × 5 × 6 × 7. Factοrial zerο is defined as equal tο 1.

If the chοice matters (i.e., the οrder οf the chοsen οbjects matters), then there are 3 pοssible chοices fοr the first οbject and 2 pοssible chοices fοr the secοnd οbject.

Thus, there are 3 * 2 = 6 ways tο chοοse 2 οbjects withοut replacement frοm 3 οbjects if the chοice matters.

If the chοice dοes nοt matter (i.e., the οrder οf the chοsen οbjects dοes nοt matter), then there are 3 chοοse 2 = 3!/((3-2)!*2!) = 3 ways tο chοοse 2 οbjects withοut replacement frοm 3 οbjects if the chοice dοes nοt matter.

Therefοre,  there are 6 ways tο chοοse 2 οbjects withοut replacement frοm 3 οbjects if the chοice matters and 3 ways tο chοοse 2 οbjects withοut replacement frοm 3 οbjects if the chοice dοes nοt matter.

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Answer:kwbebrhdjejhehe

Step-by-step explanation:

Answer:

We can use the following formula to calculate the amount of direct materials purchased during the month:

Direct Materials Purchased = Ending Direct Materials Inventory Balance - Beginning Direct Materials Inventory Balance + Direct Materials Issued to Production

Substituting the given values, we get:

Direct Materials Purchased = $38,500 - $31,000 + $185,000

Direct Materials Purchased = $192,500

Therefore, the amount of direct materials purchased during the month was $192,500.