Can someone help me please

Answer:

The correct answer is B.

Step-by-step explanation:

The opposite of Square root is squaring, which is ².

Answer:

[tex] \frac{ \sqrt{a} }{ \sqrt{b} } = x \\ [/tex]

squaring both the sides

[tex]{( \frac{ \sqrt{a} }{ \sqrt{b} }) }^{2} = x ^{2} \\ [/tex]

B. [tex] \frac{ {a} }{ {b} } = x {}^{2} \\ [/tex]

Answer:

add two and five is the first step beacuse there in ()

Step-by-step explanation:

Answer:

Parentheses. Add 2 and 5.

Step-by-step explanation:

Use the P.E.M.D.A.S expression. (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.) As you can see, there are parentheses in your expression, so use PEMDAS to do order of operations problems like this.

Answer:

x=2at/(1+t²)

dx/dt =[(1+t²)(2at)'-(2at)(1+t²)']/(1+t²)²

dx/dt=[(1+t²)(2a)-(2at)(2t)]/(1+t²)²

dx/dt=[2a+2at²-4at²]/(1+t²)²

dx/dt=[2a-2at²]/(1+t²)²

y=[b(1-t²)]/(1+t²)

dy/dt=[(1+t²)(b(1-t²))'-b(1-t²)(1+t²)']/(1+t²)²

dy/dt=[((1+t²)(-2bt)-b(1-t²)(2t)]/(1+t²)²

dy/dt=(-2bt-2bt³-2bt+2bt³)/(1+t²)²

dy/dt=(-4bt)/(1+t²)²

dy/dx=(dy/dt)/(dx/dt)

dy/dx=[(-4bt)/(1+t²)²]/[(2a-2at²)/(1+t²)²]

Cancelling common denominator

dy/dx=(-4bt)/(2a-2at²)

dy/dx=(-2bt)/(a-at²)

dy/dx=(2bt)/(at²-a)

Differentiating the above equation

y''=d²y/dx²=D[(2bt)/(at²-a)]

y''=[(at²-a)D(2bt)-(2bt)D(at²-a)]/(at²-a)²

y''=[(at²-a)(2b)(dt/dx)-(2bt)(2at)(dt/dx)]/(at²-a)²

dt/dx=(1+t²)²/(2a-2at²)

y''=[(at²-a)(2b)[(1+t²)²/(2a(1-t²))]-

(4abt²)[(1+t²)²/(2a-2at²)]/(at²-a)²

y''=[(-b)(1+t²)²-(2bt²)[(1+t²)²/(1-t²)]/(at²-a)²

y''=[(-b)(1+t²)²(1-t²)-(2bt²)(1+t²)²]/[(1-t²)(at²-a)²]

y''=[b(1+t²)²(t²-1)-2bt²(1+t²)²]/[(1-t²)(at²-a)²]

Step-by-step explanation:

Answer:

x = 142/83

y = 111/83

z = 452/83

Answer:

13. zero slope

14. 1/2

15. undefined slope

16.-3/2 slope

Answer:

cosine

Step-by-step explanation:

fundamental trigonometric identities

If square C is 64 in^2, then its dimensions are 8 x 8.

If square D is 81 in^2, then its dimensions are 9 x 9.

Since D is bigger than C and I sits in that extra space, then the dimensions of I are 1 x 1.

Since H is smaller than C, specifically I smaller, than its dimensions are 7 x 7.

Then, H and C make up one side of B, so 7 + 8 = 15. The dimensions of B are 15 x 15.

Since E is bigger than D by I, then the dimensions of E are 10 x 10.

If we find the length of the right side (B + C + D), which is 15 + 8 + 9 = 32, then we know that F + E + D must also add up to 32. F + 10 + 9 = 32 || F = 13. The dimensions of F are 13 x 13.

Then, F is E + G, so 13 = 10 + G. G = 3. The dimensions of G are 3 x 3.

Lastly, since we know the side length of the whole square is 32, then A + F must equal 32. 32 = A + 13. A = 19. The dimensions of A are 19 x 19.

A = 19 x 19 = 361 in^2

B = 15 x 15 = 225 in^2

C = 8 x 8 = 64 in^2

D = 9 x 9 = 81 in^2

E = 10 x 10 = 100 in^2

F = 13 x 13 = 169 in^2

G = 3 x 3 = 9 in^2

H = 7 x 7 = 49 in^2

I = 1 x 1 = 1 in^2

Hope this helps!! :)

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{f(x) = 2\dfrac{1}{2}-3\dfrac{1}{3}}[/tex]

[tex]\rightarrow\mathsf{y = 2\dfrac{1}{2}- 3\dfrac{1}{3}}[/tex]

[tex]\rightarrow\mathsf{y = \dfrac{5}{2}- \dfrac{10}{3}}[/tex]

[tex]\rightarrow\mathsf{y =( \dfrac{5}{2}\times\dfrac{3}{3}) - (\dfrac{10}{3}\times\dfrac{2}{2})}[/tex]

[tex]\mathsf{5\times3=\boxed{\bf 15}}\\\\\mathsf{2\times3=\boxed{\bf 6}}}\\\\\mathsf{10\times2=\boxed{\bf 20}}\\\\\mathsf{3\times2=\boxed{\bf 6}}[/tex]

[tex]\rightarrow{\mathsf{y =\dfrac{15}{6}-\dfrac{20}{6}}[/tex]

[tex]\rightarrow\mathsf{y = \dfrac{15-20}{6}}[/tex]

[tex]\mathsf{15-20=\boxed{\bf -5}}\\\\\\\mathsf{6= \boxed{\bf 6}}\textsf{ because \underline{6} is the LCD (\underline{L}east \underline{C}ommon \underline{D}enominator}[/tex]

[tex]\boxed{\mathsf{y =\bf -\dfrac{5}{6}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \bf y = }\mathsf{\bf -\dfrac{5}{6}}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

[tex]12.6\pi\:\mathrm{km^2}\:\text{or }\frac{63}{5}\pi\:\mathrm{km^2}[/tex]

Step-by-step explanation:

The area of a sector with measure [tex]\theta[/tex] in degrees is given by [tex]r^2\pi\cdot\frac{\theta}{360}[/tex], where [tex]r[/tex] is the radius of the sector.

What we're given:

Substituting given values, we get:

[tex]A_{sec}=6^2\pi \cdot\frac{126}{360}=\boxed{12.6\pi\:\mathrm{km^2}}[/tex]

The square of z varies inversely as the square root of e. If z=36 when w=16, then value of z is 24 when w=81.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0.

The square of z varies inversely as the square root of e.

If z=36 when w=16

The value of z when w is 81 we need to find

z²=k/√e

where k is a proportionality constant

36²=k/√16

36²=k/4

Apply cross multiplication

1296(4)=k

5184=k

Now let us find when k is 5184 and w is 81

z²=5184/9

z²=576

Take square root on both sides

z=24

Hence, the value of z is 24 when w is 81.

To learn more on Ratios click:

https://brainly.com/question/13419413

#SPJ2

Answer: 16%

Step-by-step explanation:

Notice that 154 minutes is one standard deviation greater than the mean. Based on the empirical rule 68% of the finishing times are within one standard deviation of the mean, so 100%-68%=32% of the finishing times are outside of one standard deviation from the mean one either direction. Since the normal distribution is symmetric , half of the 32% will be less than the mean and half will be greater, so 16% of the finishing times are greater than the one standard deviation more than the mean.

The probability that race participant had a finishing time of greater than 154 minutes is 16%

The empirical rule states that for a normal distribution, 68% are within one standard deviation from the mean, 95% are within two standard deviation from the mean and 99.7% are are within three standard deviation from the mean.

Given that mean (μ) = 143, standard deviation σ = 11

The probability that race participant had a finishing time of greater than 154 minutes is 16% [(100% - 68%)/2]

Find out more at: brainly.com/question/12660012

Answer:

w = 5

Step-by-step explanation:

The perimeter of a rectangle is given by

P = 2(l+w)

28 = 2(2w-1 + w)

Combine like terms

28 =2(3w-1)

Divide each side by 2

28/2 = 2/2(3w-1)

14 = 3w-1

Add 1 to each side

14+1 = 3w-1+1

15 = 3w

Divide each side by 3

15/3 =3w/3

5 =w

Answer:

=13 :D

Step-by-step explanation:

Im bIg BrAiN

Answer:

x=13

Step-by-step explanation:

See image below:)

Answer:

Step-by-step explanation:

We first turn 3x+4y=12 into standard form:

4y=-3x+12

y=-3/4x+3

By knowing the 2nd line is parallel to the first, the slopes are the same:

y=-3/4x+b

Plugging in (5,4) into the equation:

4=-15/4+b

b=1/4

Final equation=y=-3/4+1/4.

Answer:

B. -.9,-4, 1, .2, .8

Hope this helps!:)

Answer:

B not sure cuz i lit bit cant recognize the question

Step-by-step explanation:

Answer:

(-8,-3)

(-4,-1)

(0,1)

(2,2)

(6,4)

Step-by-step explanation:

One by one, substitue the x values and solve for y

Answer:

negative 4

Step-by-step explanation:

go

Answer:

C

Step-by-step explanation:

Open up = positive number that multiplies x^2

x - value of the vertex = -b/2a

C -> -10/2 = -5

Answer:

it is a process of produce

Answer:

91 degree

Step-by-step explanation:

Since opposite sides are parallel, the figure is a parallelogram

In a parallelogram, adjacent sides are supplementary, i.e, equal to 180.

89 + <DAB = 180

<DAB = 180-89

<DAB = 91

Hope u understand

Please mark brainliest

Thank You

Answer:

[tex]Area= 37193\ cm^2[/tex]

Step-by-step explanation:

Given

[tex]q = 590cm[/tex]

[tex]r = 310cm[/tex]

[tex]\angle P =24^o[/tex]

Required

The area of [tex]\triangle PQR[/tex]

This is calculated as:

[tex]Area= \frac{1}{2} * qr* \sin(P)[/tex]

So, we have:

[tex]Area= \frac{1}{2} * 590cm * 310cm* \sin(24^o)[/tex]

[tex]Area= \frac{1}{2} * 590cm * 310cm* 0.4067[/tex]

[tex]Area= 37192.715cm^2[/tex]

[tex]Area= 37193\ cm^2[/tex] ----- approximated

Answer:

The correct answer is 5 2/15

Step-by-step explanation:

Since the numerators on both numbers are opposite, you have to go through an equation to make them equal.

4/5 and 1/3 don't have the same numerator. Because of this, you have to find the least common multiple.

5, 10, 15

3, 6, 9, 12, 15

Now that we found said number, we have to multiply the denominators so they match as well. How we do that is by multiplying the number by how many times the numerator has been multiplied to.

Since 5 had to be multiplied by 3 to get to 15, you would multiply 4 by three, giving you 12/15. Same goes with the other fraction, 3 times 5 got us 15, so we would multiply 1 by 5, giving us 5/15.

Now it's as simple as adding. 12/15 + 5/15 = 17/15, which will make 1 2/15. Add that to the whole numbers you have and you will get 5 2/15. (Note: You cannot simplify 2/15, so you leave it as is)

Answer:

your image has the answer

Step-by-step explanation:

you can go type triangle calculator and type in everything

Step-by-step explanation:

Edge 2021

Answer:      g(x) = Negative two-fifths(10)x

Step-by-step explanation:

In order to reflect a function over the x-axis, you have to multiply the function by minus one.

Given the function:

f(x) = 2/5(10)^x

Its reflection over the x-axis is:

-f(x) = -2/5(10)^x = g(x)

Answer:

the latter is ten meters long

Step-by-step explanation:

its just ten meters long

Answer:

its 4 or B for the value of X

Answer:

its jess

here is ur ans

first option is your answer

• ANGLE 2 AND ANGLE 6 ARE CONGRUENT BECAUSE THEY ARE CORRESPONDING ANGLES.

Answer:

A and C

Step-by-step explanation:

I got 100% on quiz

Answer:

A and C

Step-by-step explanation:

try it it works

Answer:

An essay is, generally, a piece of writing that gives the author's own argument, but the definition is vague, overlapping with those of a letter, a paper, an article, a pamphlet, and a short story. Essays have traditionally been sub-classified as formal and informal. Formal essays are characterized by "serious purpose, dignity, logical organization, length," whereas the informal essay is characterized by "the personal element (self-revelation, individual tastes and experiences, confidential manner), humor, graceful style, rambling structure, unconventionality or novelty of theme," etc.[1]

Essays are commonly used as literary criticism, political manifestos, learned arguments, observations of daily life, recollections, and reflections of the author. Almost all modern essays are written in prose, but works in verse have been dubbed essays (e.g., Alexander Pope's An Essay on Criticism and An Essay on Man). While brevity usually defines an essay, voluminous works like John Locke's An Essay Concerning Human Understanding and Thomas Malthus's An Essay on the Principle of Population are counterexamples.

In some countries (e.g., the United States and Canada), essays have become a major part of formal education. Secondary students are taught structured essay formats to improve their writing skills; admission essays are often used by universities in selecting applicants, and in the humanities and social sciences essays are often used as a way of assessing the performance of students during final exams.

The concept of an "essay" has been extended to other media beyond writing. A film essay is a movie that often incorporates documentary filmmaking styles and focuses more on the evolution of a theme or idea. A photographic essay covers a topic with a linked series of photographs that may have accompanying text or captions.

Contents

1 Definitions

2 History

2.1 Montaigne

2.2 Europe

2.3 Japan

2.4 China

3 Forms and styles

3.1 Cause and effect

3.2 Classification and division

3.3 Compare and contrast

3.4 Expository

3.5 Descriptive

3.6 Dialectic

3.7 Exemplification

3.8 Familiar

3.9 History (thesis)

3.10 Narrative

3.11 Argumentative

3.12 Process

3.13 Economic

3.14 Reflective

3.15 Other logical structures

4 Academic

5 Magazine or newspaper

6 Employment

7 Non-literary types

7.1 Film

7.2 Music

7.3 Photography

7.4 Visual arts

8 See also

9 References

10 Further reading

11 External links

Step-by-step explanation:

Step-by-step explanation:

6% of 35000

6/100×35000

=2100

hope it helps you

Step-by-step explanation:2100