Answers
The domain of the given function is the one in option A,
Domain = 4 ≤x ≤13
What is the domain of the function in the graph?To identify this, just look at the horizontal axis (which is the axis of the inputs, and we know that the domain is the set of the inputs of the function), here we can see that the graph (which is the bell-shaped curve) starts at 4 and ends at 13.
Then the domain is the set of all values between these two, we can write this as:
Domain = 4 ≤x ≤13
Thus the correct option is A.
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Related Questions
one hundred sixty people who suffer from painful diabetic neuropathy have volunteered to participate in a study. eighty are selected at random and are given the drug gabapentin, while the remaining participants are given a placebo. a neurologist evaluates the symptoms of all volunteers after two months to determine if there has been substantial improvement in the severity of the symptoms. does the use of volunteers make this study invalid?
Answers
Overall, while the use of volunteers does not automatically make the study invalid, it is important to carefully consider probability of bias and take steps to minimize them in the study design and analysis.
The use of volunteers in this study does not necessarily make it invalid, but it could introduce potential sources of bias. Volunteers may not be representative of the larger population of individuals with painful diabetic neuropathy, as they may be more willing to participate in the study or may have different levels of disease severity or other factors that could affect their response to treatment.
Additionally, the random assignment of participants to the gabapentin or placebo group helps to minimize bias, but there is still a possibility of confounding variables that could influence the results. For example, if individuals who were assigned to the gabapentin group were more likely to adhere to the treatment regimen or had more social support, this could influence the outcome of the study independent of the drug's effectiveness.
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Given f(x)=x−2
, g(x)=x^3−8
, and h(x)=5x
, perform the indicated operation.
g(x)⋅h(x)
Answers
The composition of function is g ( x ) f ( x ) = 5x⁴ - 40x
Given data ,
Let the first function be g ( x ) = x³ - 8
Let the second function be h ( x ) = 5x
So, the composition of functions , g(x) x h(x) would be:
(x³ - 8) (5x)
We can distribute the multiplication to get:
5x ( x³ ) - 5x ( 8 )
On simplifying , we get
A = 5x⁴ - 40x
Hence , the result of the operation g(x) x h(x) is 5x⁴ - 40x
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a rancher has 160 feet of fencing with which to enclose two adjacent rectangular corrals (see figure). what dimensions should be used so that the enclosed area will be a maximum?
Answers
The optimal dimensions for the two adjacent rectangular corrals are: length = 80 feet, width = 20 feet.
Let's call the dimensions of the two adjacent rectangular corrals "width" and "length," and represent them by the variables w and l, respectively. The total length of fencing available is 160 feet, so the total amount of fencing used is:
P = 2w + 3l
The factor of 3l in this equation is due to the fact that there are three sides of length l: two of them are shared by the two corrals, and the other one is the outer side of one of the corrals.
The enclosed area of the two corrals is:
A = 2wl
To find the dimensions that maximize the enclosed area, we need to express A in terms of a single variable, either w or l. To do this, we can solve the equation P = 160 for one of the variables:
2w + 3l = 160
2w = 160 - 3l
w = 80 - (3/2)l
Substituting this expression for w into the equation for A, we get:
A = 2(80 - (3/2)l)l
Simplifying and expanding, we get:
A = 160l - (3/2)l^2
This is a quadratic function of l, with a maximum at the vertex of the parabola. The x-coordinate of the vertex is given by:
l = -b / (2a)
where a = -(3/2) and b = 160. Substituting these values, we get:
l = -160 / (2 * -(3/2)) = 80
Therefore, the optimal length of the two corrals is 80 feet. To find the corresponding width, we can use the equation we derived earlier:
w = 80 - (3/2)l = 80 - (3/2)(80) = 20
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Mr.Simon has 20 containers of soup.3 containers of soup feeds 4 people.At this rate,how many people can he serve with 20 containers
Answers
Mr. Simon can serve 26 people with 20 containers of soup.
How many people can Mr.Simon serve with 20 containers?Given that: Mr.Simon has 20 containers of soup. 3 containers of soup feeds 4 people.
Frst, we need to know how many people can be fed by one container of soup.
We are given that 3 containers of soup can feed 4 people.
Hence, we can calculate how many people one container of soup can feed by dividing 4 people by 3 containers
One person ⇒ 4/3
Next, we multiply the number of people per container by the total number of containers, which is 20 in this case.
This gives us:
= 20 × (4/3)
= 80/3
= 26.667
≈ 26
Mr. Simon can feed 80/3 people with 20 containers of soup. However, since we cannot serve a fractional part of a person, we should round the answer to a whole number. In this case, rounding down gives us 26.
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determine the number of outcomes in the event . then decide whether the even is a simpe event or not. you roll a six sided die event b is rolling an even number
Answers
When rolling a six-sided die, there are six possible outcomes: 1, 2, 3, 4, 5, or 6. Event B is rolling an even number, which means there are three possible outcomes: 2, 4, or 6. Since there are only three possible outcomes in Event B, it is a simple event.
Let's analyze the event and outcomes when rolling a six-sided die.
Event B: Rolling an even number.
Step 1: Identify the possible outcomes.
When rolling a six-sided die, the outcomes are numbers 1 to 6 (1, 2, 3, 4, 5, and 6).
Step 2: Determine the outcomes in the event.
For Event B, the even numbers are 2, 4, and 6. So, there are 3 outcomes in Event B.
Step 3: Decide if the event is a simple event or not.
An event is considered a simple event if it has only one possible outcome. Since Event B has 3 possible outcomes (2, 4, and 6), it is not a simple event.
Event B (rolling an even number) has 3 possible outcomes (2, 4, and 6), and it is not a simple event.
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True or false: A 5Ã5 real matrix has an even number of real eigenvalues
Answers
This statement is not necessarily true.
A real matrix can have real or complex eigenvalues.
A real matrix can have real or complex eigenvalues. The number of real eigenvalues of a matrix may be even or odd, and there is no general rule that determines the parity of the number of real eigenvalues.
For example, the 5x5 real matrix
```
[ 0 1 0 0 0 ]
[ 1 0 0 0 0 ]
[ 0 0 0 1 0 ]
[ 0 0 1 0 0 ]
[ 0 0 0 0 1 ]
```
has two real eigenvalues (1 and -1), which is an even number.
On the other hand, the 5x5 real matrix
```
[ 1 1 0 0 0 ]
[ 1 1 0 0 0 ]
[ 0 0 1 1 0 ]
[ 0 0 1 1 0 ]
[ 0 0 0 0 0 ]
```
has three real eigenvalues (2, 0, and -1), which is an odd number.
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Problem 6: (12 pts] Give an example of the requested vector or vector-valued function for each statement below, or state that no such vector exists. In order to receive full credit, you must show that your vector meets the requested criteria or explain why no such vector exists. Answers with no justification will receive a score of 0. 1. [4 pts) Suppose that ū = (1, 2). Find a vector ū so u + = vor explain why no such vector exists. II. [4 pts) Suppose that u = (2,1,3). Find a nonzero vector v so u xv = u + v or explain why no such vector exists. = 4 or explain why no such III. [4 pts) A vector-valued function r(t) = (x(t), y(t)) for which vector-valued function exists.
Answers
There is no such vector-valued function r(t) that satisfies the given condition.
I. There is no such vector ū that satisfies u + ū = (1, 2) because if we add any vector to u, we change its direction and magnitude, but the vector ū should have the same magnitude and opposite direction to u.
II. Let v = (1, 3, -1). Then u + v = (2+1, 1+3, 3-1) = (3, 4, 2) and u x v = (-5, 7, -1). So u x v = u + v. Therefore, v satisfies the given condition.
III. There is no such vector-valued function r(t) because if r(t) = (x(t), y(t)) satisfies the condition that r'(t) = 2r(t), then we have:
x'(t) = 2x(t) and y'(t) = 2y(t)
These are two separate first-order differential equations, which have general solutions of the form:
x(t) = c1e^(2t) and y(t) = c2e^(2t)
where c1 and c2 are constants determined by the initial conditions. However, the vector-valued function r(t) = (x(t), y(t)) cannot have a constant magnitude because its components are functions of t that grow exponentially with time. Therefore, there is no such vector-valued function r(t) that satisfies the given condition.
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a polynomial of degree four with leading coefficient 1 and integer coefficients has two real zeros, both of which are integers. which of the following can also be a zero of the polynomial? A. 1+i√11/2B. 1+i/2C. 1/2+iD. 1+i/2E. 1+i√13/2
Answers
If we let a = 0, b = 1, and c = 1, then the polynomial
[tex]x(x-1)(x^2 +[/tex]
Since the polynomial has integer coefficients, if one of the roots is a complex number, then its conjugate must also be a root. Therefore, options A and E cannot be roots of the polynomial, since they have non-real conjugates.
We know that the polynomial has degree 4, so it has four roots in total (counting multiplicities). We also know that two of the roots are integers, so let's call them a and b. Then the polynomial can be written as:
[tex](x - a)(x - b)(cx^2 + dx + e)[/tex]
where c, d, and e are integers (because they are the coefficients of the quadratic factor). We know that the leading coefficient is 1, so c must be nonzero.
Since the polynomial has two real roots, its discriminant must be nonnegative:
[tex]d^2 - 4ce > = 0[/tex]
We can use this inequality to rule out some of the answer choices. For example, option C cannot be a root, because if we substitute x = 1/2 + i into the polynomial, we get:
([tex](1/2 + i) - a)((1/2 + i) - b)(c((1/2 + i)^2) + d(1/2 + i) + e)[/tex]
The real part of this expression is:
(1/4 - a + 1/4 - b)(c(1/4 - 1) + d/2 + e) = -(a + b - 1/2)(3c/4 + d/2 + e)
If we assume that a and b are integers, then this expression is an integer multiple of 3c/4 + d/2 + e. However, we can choose values of c, d, and e such that 3c/4 + d/2 + e is not an integer (for example, if c = 4, d = 1, and e = 0, then 3c/4 + d/2 + e = 4.5). Therefore, the real part of the expression cannot be zero, and option C cannot be a root.
We can also rule out option D using the same argument. If we substitute x = 1 + i/2, then the real part of the expression is:
((1 + i/2) - a)((1 + i/2) - b)(c((1 + i/2)^2) + d(1 + i/2) + e)
(1 - a + i/2)(1 - b + i/2)(c(5/4 + i) + d(3/2 + i/2) + e)
The real part of this expression is an integer multiple of c(5/4) + d(3/2) + e, which can be non-integer for some choices of c, d, and e.
Therefore, the only possible answer choices are A and B. To determine whether they are roots of the polynomial, we can use the fact that the sum and product of the roots are given by:
a + b + (complex roots) = -d/c
ab(complex roots) = e/c
We know that a and b are integers, so if we can find a polynomial with integer coefficients that has roots a, b, and either A or B, then that root is also a root of the original polynomial.
For option A, we have:
1 + i√11/2 = 2(cos(75°) + i sin(75°))
Therefore, if we let a = 0, b = 1, and c = 1, then the polynomial
[tex]x(x-1)(x^2 +[/tex]
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the diameter of a cylinder is 7yrds. the height is 12 yards. what is the volume, in terms of 3.14 and the nearest cubic yard, of the cylinder
Answers
Step-by-step explanation:
Area of the circular end x height = volume
pi r^2 * h = volume r = 1/2 * 7 = 3.5 yds
pi * (3.5^2) * 12 =~ 462 yd^3
Simplify the expression (4 − 3)( + 5). A. 42 − 17 + 15 B. 42 − 17 − 15 C. 42 + 17 + 15 D. 42 + 17 − 15
Answers
By simplifying the expression, (4 − 3)( + 5) we have 5 as the final answer.
What is simplificationSimplification in mathematics is the process of reducing a mathematical expression into a simpler or more compact form, without changing the value of the expression.
The process of simplification are:
removing bracketcollecting like termsrearranging the termsSimplification is often used to make calculations and problem-solving easier and more efficient, and to help identify patterns and relationships between mathematical concepts. Simplification is an important skill in mathematics, as it can help to make complex problems more accessible and understandable, and can also lead to more elegant and insightful solutions.
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An phone playlist has songs of various genres
according to the table below. What is the probability
that, of three random songs, the first two are country
and the third is R&B? Once a song is played it will not
be repeated until all other songs are played.
Genre
Rock
Country
R&B
Classical
Number of Songs
12
15
10
3
Answers
The probability that of three random songs, the first two are Country and the third is R&B is 0.024. In percentage, we say 2.4%.
Understanding ProbabilityLet's denote the event that a song is from a certain genre as
R for Rock,
C for Country,
RB for R&B, and
Cl for Classical.
The total song = 12 + 15 + 10 + 3 = 40 songs
Probability that the first song is from Country is :
P(C₁) = 15/40
Probability that the second song is also from Country is:
P(C2|C1) = 14/39
Note: This is a probability selection without replacement that is why the total songs reduced from 40 to 39
Probability that the third song is R&B is:
P(RB₃|C₁C₂) = 10/38 (there are 10 R&B songs left out of a total of 38 remaining songs)
To find the probability that the first two songs are Country and the third song is R&B, we multiply these probabilities together:
P(C₁C₂RB₃) = P(C1) × P(C₂|C₁) × P(RB₃|C₁C₂)
= (15/40) × (14/39) × (10/38)
= 0.024
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Find a 99% confidence interval for the average number of hours a student spends studying for a statistics exam if o is known to be 6.25 hours and a sample of 50 students has x=4 (3.176.4.824)(1.941, 6.059)(3.307, 4.693) (3.090,4.910(3.650.4.350) (1.724,6 276)
Answers
The 99% confidence interval for the average number of hours a student spends studying for a statistics exam is (2.059, 5.941) hours.
To find a 99% confidence interval for the average number of hours a student spends studying for a statistics exam, we can use the formula:
CI = x ± z*(o/sqrt(n))
where CI is the confidence interval, x is the sample mean, z is the z-score for the desired confidence level (in this case, 99%), o is the population standard deviation, and n is the sample size.
Plugging in the given values, we get: CI = 4 ± 2.576*(6.25/sqrt(50)) CI = 4 ± 1.941 CI = (2.059, 5.941)
Therefore, the 99% confidence interval for the average number of hours a student spends studying for a statistics exam is (2.059, 5.941) hours.
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PLEASE HELP I INCLUDED THE PROBLEM IN IMAGE I WROTE IT DOWN!!!
Answers
Answer:
the answer is B
Step-by-step explanation:
you find the answer by exchanging and canceling the number to find the value of x
[tex]/ \frac{x}{3} \leqslant - 6 \\ (\frac{1x}{3}) \frac{3}{1} \leqslant - 6( \frac{3}{1} ) \\ x = - 18[tex]/
Find the values of x1 and x2 where the following two constraints intersect. ( Negative values should be indicated by a minus sign. Round your answer to 3 decimal places.
1. 9x1 + 7x2 ≥ 57
2. 4x1 + 6x2 ≥ 3
Answers
To find the intersection point of the two constraints of x1 and x2, we need to solve the system of inequalities simultaneously.
First, we can rewrite each inequality in slope-intercept form:
1. 9x1 + 7x2 ≥ 57 -> x2 ≥ (-9/7)x1 + 57/7
2. 4x1 + 6x2 ≥ 3 -> x2 ≥ (-2/3)x1 + 1/2
The intersection point will occur where the two lines intersect, so we can set the two equations equal to each other:
(-9/7)x1 + 57/7 = (-2/3)x1 + 1/2
Simplifying:
(-9/7 + 2/3)x1 = 1/2 - 57/7
(-15/21)x1 = -163/42
x1 = (163/42)/(15/21)
x1 = 1.634
To find x2, we can substitute this value back into either of the original equations:
9(1.634) + 7x2 = 57
7x2 = 57 - 14.706
x2 = 6.32
Therefore, the values of x1 and x2 where the two constraints intersect are x1 = 1.634 and x2 = 6.32.
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Find a₁ for the geometric series described.
Sn = -26,240, n = 8, r = -3
Answers
The first term of the geometric series is 16.
How to find the a₁ for the geometric seriesUsing the formula for the sum of a geometric series to solve for the first term (a₁):
Sn = a₁(1 - rⁿ)/(1 - r)
Substituting the given values, we get:
-26,240 = a₁(1 - (-3)⁸)/(1 - (-3))
Simplifying the exponent and denominator, we get:
-26,240 = a₁(1 - 6,561)/(4)
-26,240 = a₁(-6,560/4)
-26,240 = a₁(-1,640)
Dividing both sides by -1,640, we get:
a₁ = 16
Therefore, the first term of the geometric series is 16.
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Find the measures of the interior angles of a triangle when angle C=68 angle b=x-24 and angle A=x what is the measurement of angle B and A
Answers
A=68,B=44
the interior angle of triangle is 180
A+B+C=180
x+x-24+68=180
2x+44=180
2x=180-44
2x=136
x=68
A=x=68
B=68-24=44
angle <1 and angle <2 are complementary angles. The measure of angle <1 is 42 degrees. The measure of angle <2 is 4x degrees. Find the value of x. The figure is not drawn to scale.
Answers
The value of x is 12.
we have, <1 = 42 degree
<2 = 4x degree
As, <1 and <2 are Complementary Angle.
So, the sum of <1 and <2 will be 90 degree
<1 + <2 = 90
42 + 4x = 90
4x = 90-42
4x = 48
x= 48/4
x= 12
Thus, the value of x is 12.
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URGENT PLEASE HELP I’M TRYING TO GET MY GRADE TO A C OR B!!!
Solve for c.
(c+9)^2=64
Responses
c=−17, c=−1
c equals negative 17, , , c equals negative 1
c=−73−−√, c=73−−√
, c equals negative square root of 73 , c equals square root of 73
c=−55−−√, c=55−−√
c equals negative square root of 55, , , c equals square root of 55
c = 1, c = 17
Answers
Answer:
√(c+9)² =√64
c+9 =8
c=8-9
c=-1
Sheena is stocking a shalf with bags of flour that weigh 5 1 /4
5 4/ 1 pounds each. If Sheena stocks the shelf with 13 bags of flour, find the combined weight of the 13 bags.
Answers
Answer:
68 1/4 lbs
Step-by-step explanation:
its just the answer
find the area of the triangle
Answers
The area of the triangle in this problem is given as follows:
A = 479.3 m².
How to obtain the area of the triangle?First we must use the law of sines to obtain the measure of angle A as follows:
sin(A)/31 = sin(105º)/50
Hence:
sin(A) = 31 x sine of 105 degrees/50
sin(A) = 0.5989
A = arcsin(0.5989)
A = 36.8º.
Considering that the sum of the measures of the internal angles of a triangle is of 180º, the measure of angle B is given as follows:
36.8º + <B + 105º = 180º
<B = 180 - (36.8 + 105)
<B = 38.2º.
We have two sides of 50m and 31m, with an angle between them of 38.2º, hence the area of the triangle is given as follows:
A = 0.5 x 50 x 31 x sine of 38.2 degrees
A = 479.3 m².
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P( factor of 72 and even) please answer in decimal
Answers
The probability of having factor of 72 and even will be 0.75.
How to calculate the probabilityThe prime factorization of 72 is 2^3 * 3^2. It should be noted that to find the number of factors of 72, one must add 1 to each exponent in the prime factorization and multiply accordingly: (3+1) * (2+1) = 12.
Therefore the factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36 and 72.
Evidently, 9 of these 12 factors will be even since they contain at least one factor of 2; thus, 6 of the factors of 72 are even.
The probability will be:
= 9/12
= 0.75
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A coin is tossed nine times. Find the probability of getting exactly six heads.
Answers
Answer:
When a coin is tossed 9 times the probability of getting exactly six heads is obtained with the help of Bernoulli trials. The probability of getting exactly six heads is 21/128.
How many repeating digits are in the smallest group of repeating digits in the decimal equivalent
of 2/9?
A. 1
C. 3
B. 2
D. 4
Answers
The number of repeating digits in the group is 1
How many repeating digits are in the groupFrom the question, we have the following parameters that can be used in our computation:
Number = 2/9
When evaluated, we have
Number = 0.222.....
The above nummber has repeating digits
When approximated, we have
Number = 0.2
In the above number, the number of repeating digits is 1
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1. 4<7 Multiply both sides by 7 , then by 6, then by 3, then by 10 2. 11>-2 Add 5 to both sides, then add 3, then add (-4) 3. -4<-2 Subtract 6 from both sides, then 8, and then 2 4. -8<8 Divide both sides by -4, then by -2 5. Write a short explanation of the effects of the above operations. Did this affect the inequality sign? Was it still true? Why or why not?
Answers
The inequalities are solved and the operations does not change
Given data ,
a)
Let the inequality be 4 < 7
Multiplying both sides by 7: 47 < 77, which simplifies to 28 < 49.
Multiplying both sides by 6: 628 < 649, which simplifies to 168 < 294.
Multiplying both sides by 3: 3168 < 3294, which simplifies to 504 < 882.
Multiplying both sides by 10: 10504 < 10882, which simplifies to 5040 < 8820.
The inequality sign remained "<" (less than), and the inequality was still true. Multiplying by a positive number does not change the direction of the inequality
b)
Let the inequality be 11 > -2
Adding 5 to both sides: 11 + 5 > -2 + 5, which simplifies to 16 > 3.
Adding 3 to both sides: 16 + 3 > 3 + 3, which simplifies to 19 > 6.
Adding (-4) to both sides: 19 + (-4) > 6 + (-4), which simplifies to 15 > 2.
The inequality sign remained ">" (greater than), and the inequality was still true. Adding a positive number to both sides of an inequality does not change the direction of the inequality
c)
Let the inequality be -4 < -2
Subtracting 6 from both sides: -4 - 6 < -2 - 6, which simplifies to -10 < -8.
Subtracting 8 from both sides: -10 - 8 < -8 - 8, which simplifies to -18 < -16.
Subtracting 2 from both sides: -18 - 2 < -16 - 2, which simplifies to -20 < -18.
The inequality sign remained "<" (less than), and the inequality was still true. Subtracting a positive number from both sides of an inequality does not change the direction of the inequality
d)
Let the inequality be -8 < 8
Dividing both sides by -4: -8/-4 < 8/-4, which simplifies to 2 < -2.
Dividing both sides by -2: 2/-2 < -2/-2, which simplifies to -1 < 1.
The inequality sign remained "<" (less than), but the inequality is not true anymore. Dividing both sides of an inequality by a negative number changes the direction of the inequality.
Hence , the inequalities are solved
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21 kg of bannanas cost 147. How much would 9 kg cost
Answers
Answer:
$63
Step-by-step explanation:
First find the cost of bananas per kilogram. To find that, divide $147 by 21
147/21=7
One kilogram of bananas costs $7
Now that you know the cost per kilogram, multiply $7 by the number of kilograms asked in the question, which in this case is 9
7*9=$63
9 kilograms of bananas costs $63
Answer: 63
Step-by-step explanation:
You can set up a proportion cost/weight=cost/weight
[tex]\frac{147}{21} = \frac{x}{9}[/tex] Costs go on the top so x is cost for 9 kg
[tex]x=\frac{147*9}{21}[/tex]
x=63
Out of all the readers who visit a blog, 11% click on an advertisement. Predict how many readers will click on an advertisement if 500 people visit the blog in one day.
Answers
55
Explanation:
If 500 people visit the blog in one day, and 11% of people click on the advertisement, then you find 11% of 500 by dividing 500 by .11 to get 55.
Hope this helps! :)
How do we classify the critical point if both eigenvalues are real and equal???
Answers
They may require more advanced techniques from dynamical systems theory to fully understand the behavior of the system.
What is the eigenvalues of a critical point of a linear system?If both eigenvalues of a critical point of a linear system of differential equations in two dimensions are real and equal, the critical point is a degenerate node.
The behavior of the solutions near a degenerate node depends on the higher-order terms in the Taylor series expansion of the vector field around the critical point. Specifically, the critical point is asymptotically stable if the higher-order terms in the Taylor series expansion satisfy certain conditions, and unstable otherwise.
If the higher-order terms in the Taylor series expansion satisfy the so-called "center manifold" conditions, then the critical point is a center, and the solutions near the critical point exhibit periodic behavior.
In general, the classification of a critical point with real and equal eigenvalues can be more complicated than the case where the eigenvalues have different signs, and may require more advanced techniques from dynamical systems theory to fully understand the behavior of the system.
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Use the image to determine the line of reflection.
An image of polygon VWYZ with vertices V at negative 11, 2, W at negative 11, 0, Y at negative 5, 0, and Z at negative 5, 2. A second polygon V prime W prime Y prime Z prime with vertices V prime at 7, 2, W prime at 7, 0, Y prime at 1, 0, and Z prime at 1, 2.
Reflection across the x-axis
Reflection across the y-axis
Reflection across x = −2
Reflection across y = 2
Answers
The polygon VWXY is reflection across y = 2. Therefore, option D is the correct answer.
Given that, polygon VWYZ with vertices V at (-11, 2), W at (-11, 0), Y at (-5, 0) and Z(-5, 2).
A second polygon V' at (7, 2), W' at (7, 0), Y'(1, 0) and Z'(1, 2).
We know that, the reflection of point (x, y) across the y-axis is (-x, y).
The polygon VWXY is reflection across y = 2
Therefore, option D is the correct answer.
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The following table provides a probability distribution for the random variable y.y f(y) 2 0.10 4 0.40 7 0.20 8 0.30(a) Compute E(Y).(b) Compute Var(y) and o.
Answers
The expected value E(Y) = 5.6, Var(Y) = 326.64 and σ ≈ 18.07.
(a) To compute the expected value E(Y), we need to multiply each value of y with its corresponding probability and sum them up. Here's the calculation:
E(Y) = (2 * 0.10) + (4 * 0.40) + (7 * 0.20) + (8 * 0.30) = 0.2 + 1.6 + 1.4 + 2.4 = 5.6
(b) To compute the variance Var(Y) and standard deviation σ, we first need to find E(Y^2) and then use the formula Var(Y) = E(Y^2) - (E(Y))^2.
E(Y^2) = (2^2 * 0.10) + (4^2 * 0.40) + (7^2 * 0.20) + (8^2 * 0.30) = 4 + 64 + 98 + 192 = 358
Now, we can compute Var(Y):
Var(Y) = E(Y^2) - (E(Y))^2 = 358 - (5.6)^2 = 358 - 31.36 = 326.64
Finally, we can compute the standard deviation σ:
σ = sqrt(Var(Y)) = sqrt(326.64) ≈ 18.07
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Sobre una plancha de metal se han perforado dos orificios con diámetros de 3/4 de pulgada y 1 pulgada, respectivamente. Si el orificio menor es muy estrecho y el mayor, muy holgado, ¿qué medida podría tener el diámetro del orificio q se ajusta mejor a los requerimientos?
Answers
If the smaller hole is very narrow and the larger one is very loose, a size which the diameter of the hole could have that best fits the requirements is: C. 7/8 inch.
What is measurement?In Mathematics and Geometry, a measurement can be defined as an act or process through which the size, weight, magnitude, quantity, volume (capacity), dimensions, or distance traveled by a physical object or body is taken, especially for the purpose of an experiment.
Assuming small holes of 3/4 and 1 inch in diameters are made on a metal plate, and we realize that the 3/4 inch hole is very narrow and the 1 inch hole is very loose, a standard measurement and size that the diameter would be an intermediate value is given by;
3/4 = 12/16
12/16, 13/16, 14/16, 15/16, ......, 1
Required size = 14/16 = 7/8 inch.
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Complete Question:
Two holes with diameters of 3/4 inch and 1 inch, respectively, have been drilled on a metal sheet. If the smaller hole is very narrow and the larger one is very loose, what size could the diameter of the hole have that best fits the requirements?