Can someone help me out, thanks

Can Someone Help Me Out, Thanks

Answers

Answer 1

Answer:

See EXPLANATION

Explanation:

We must bear in mind that in balancing chemical reaction equations, the number of atoms of each element on the right hand side must be the same as the number of atoms of the same element on the left hand side of the reaction equation. This follows from the law of conservation of mass.

Based on this;

There are two oxygen atoms on the  left hand side of the reaction equation, thus total mass of oxygen = 2 * 16 amu = 32 amu

There are two oxygen atoms on the product side of the reaction equation, thus the total mass of oxygen = 2 * 16 amu = 32 amu


Related Questions


At 27.0°C, the volume of a gas is 630 L. At the same pressure, its volume is 92,0 mL at a temperature of

Answers

Answer:

–272.96 °C

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 27.0 °C

Initial volume (V₁) = 630 L.

Final volume (V₂) = 92.0 mL

Final temperature (T₂) =?

Next, we shall convert 27.0 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 27.0 °C

Initial temperature (T₁) = 27.0 °C + 273

Initial temperature (T₁) = 300 K

Next, we shall convert 92.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

92 mL = 92 mL × 1 L / 1000 mL

92 mL = 0.092 L

Next, we shall determine the final temperature.

Initial temperature (T₁) = 300 K

Initial volume (V₁) = 630 L.

Final volume (V₂) = 0.092 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

630 / 300 = 0.092 / T₂

2.1 = 0.092 / T₂

Cross multiply

2.1 × T₂ = 0.092

Divide both side by 2.1

T₂ = 0.092 / 2.1

T₂ = 0.04 K

Finally, we shall convert 0.04 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

Final temperature (T₂) = 0.04 K

Final temperature (T₂) = 0.04 – 273

Final temperature (T₂) = –272.96 °C

Study the reaction.
CH4 + 2O2 → CO2 + 2H2O
If 7.4 moles of carbon dioxide (CO2) form at the end of the reaction, how many moles of methane (CH4) and oxygen gas (O2) entered the reaction?

? moles of methane and
? moles of oxygen gas

Answers

7.4 moles of methane (CH₄)

14.8 moles of oxygen gas (O₂)

A bottle labeled 0.01 M HCl is found in the laboratory. Assuming that the HCl is completely ionized calculate the [H+], [OH-] and the pH of the solution. ​

Answers

Answer:

[H⁺] = 0.01 M[OH⁻] = 1x10⁻¹² MpH = 2

Explanation:

The assumption that the HCl is completely ionized means that the original concentration of the acid is equal to [H⁺].

[H⁺] = 0.01 M

With [H⁺], we can calculate [OH⁻], by using the following formula:

[H⁺] * [OH⁻] = 10⁻¹⁴0.01 M * [OH⁻] = 10⁻¹⁴[OH⁻] = 1x10⁻¹² M

Finally we calculate the pH of the solution:

pH = -log[H⁺]pH = 2

How much heat must be absorbed by 375 grams of water to raise its temperature by 25 degrees Celsius? Specific heat for water= 4.184 J/g/C or K

Answers

Answer:

[tex]3.9*10^4 J[/tex]

Explanation:

See image for explanation!

Answer:

[tex]\boxed {\boxed {\sf 39, 225 \ Joules}}}[/tex]

Explanation:

Since we are given the mass, temperature, and specific heat, we should use the following formula to calculate heat energy.

[tex]q=mc \Delta T[/tex]

We have 375 grams of water, the specific heat of water is 4.184 J/g ° C, and the temperature is raised 25 degrees Celsisus. Therefore:

m= 375 g c= 4.184 J/g °C ΔT= 25°C

Substitute the values into the formula.

[tex]q= (375 \ g)(4.184 \ J/g \textdegree C)(25 \textdegree C)[/tex]

Multiply the first two values together. The units of grams will cancel.

[tex]q=1569 \ J/ \textdegree C(25 \textdegree C)[/tex]

Multiply again. This time, the degrees Celsius cancel, so we are left with only the units of Joules.

[tex]q= 39225 \ J[/tex]

39,255 Joules of heat must be absorbed by the water.

Calculate the molarity of the two solutions.
The first solution contains 0.200 mol of NaOH in 2.00 L of solution.
The second is 15.5G of NaCl in 671mL of solution

Answers

Answer:

a) 0.100 M

b) 0.395 M

Explanation:

a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution

We will use the following expression for molarity.

[NaOH] = moles of solute / liters of solution

[NaOH] = 0.200 mol/2.00 L = 0.100 M

b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution

We will use the following expression for molarity.

[NaCl] = mass of solute / molar mass of solute × liters of solution

[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M

8
What happens to solid waste in the circulatory system?
A it's expelled through the lungs
B
It pumps into the coronary circulation
C
It's dropped off in the kidneys
D
It's deposited in the aorta

Answers

Answer:c it’s dropped off in the kidneys

Explanation:

I took the quiz

The solid wastes are from the circulatory system is expelled to the kidney where, the nitrogenous wastes like urea and uric acid is excreted as urine from the body.

What is circulatory system ?

A circulatory system is an organ system, where the blood is purified and oxygenation of blood takes place. Through circulatory system, the blood reaches throughout the body pumped from the heart through veins.

The organs included in circulatory system are lungs, heart, aorta, veins, blood vessels etc. There are various kinds of blood vessels each having specific functions.

There is a network of blood vessels including arteries and large veins, capillaries that join the venules and other veins. All the nutrients and ions are circulated throughout the body through blood and solid wastes are then expelled to kidney.

Kidney function as a sieve to clean the good fluid from waste products. Uric acid and urea along with water excreated as urine then. Thus, option C is correct.

To find more about circulatory system, refer the link below:

https://brainly.com/question/10103458

#SPJ6

I need guidance on this question

Answers

Answer:

(C) NO2 has covalent bonds.

Consider the aldol-dehydration reaction. Draw the two possible products of the reaction between benzaldehyde and methylethylketone. (Do not draw the products of the double-condensation.)

Answers

Solution :

An [tex]$\text{aldol condensation}$[/tex] reaction is a type of [tex]\text{condensation reaction}[/tex] in organic chemistry where the enol or an enolate ion reacts with the carbonyl compound and forms a [tex]$\beta$[/tex]-hydroxyaldehyde or a [tex]$\beta$[/tex]-hydroxyketone, and then followed by a dehydration to give conjugated enone.  

Benzaldehyde reacts with methylketone and forms two products:  

Give the ratio that balances out the following equation: ___Cr + ___Pb(NO3)4 ---> ___ Cr(NO3)3 + ____ Pb

Answers

Answer:  Ratio : 4, 3, 4, 3 are the answers.

Explanation:

HCN
H:C:N:
3.
Is this Lewis Structure correct?

Answers

Answer:

No, your missing some bonds

what do adamantium,vibranium and unobtainum have in common

Answers

Answer:

they're all fake

Explanation:

What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?

Answers

Answer:

32.5 moles of O2(g) are necessaries for a complete reaction

Explanation:

Based on the reaction of combustion of C4H10(g):

C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.

That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:

5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =

32.5 moles of O2(g) are necessaries for a complete reaction

Determine the hydroxide ion concentration in
a solution that is 0.00034 M Ca(OH)2.
Answer in units of M.

Answers

Answer:

[tex]0.00068M[/tex]

Explanation:

Hello there!

In this case, according to the ionization of calcium hydroxide, a strong base:

[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]

Thus, since there is a 1:2 mole ratio of calcium hydroxide to hydroxide ions, we apply the following proportional factor to obtain:

[tex]0.00034\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\=0.00068\frac{OH^-}{L}\\\\=0.00068M[/tex]

Regards!

[H+] [OH-] =

NEED HELP ASAP!!!

Answers

Hopes this helps:

Answer: h^2o

If this doesn’t help than I am so sorry that I couldn’t help.

The cation that has the same number of electrons (isoelectronic) as Ne is
None of the listed options
O Na
Mg 2-
All of the listed options
O AI 3-

Answers

Ne is isoelectronic with Na+ ion.

Do u believe that you are beautiful/handsome?


Yes or No?

Answers

i think i’m beautiful some days but other days no. Mainly only depends on my mood.

If 3.13 mol of an ideal gas has a pressure of 2.33 atm and a volume of 72.31 L, what is the temperature of the sample in degrees Celsius?

Answers

Answer:

382.49 C degree Celsius

Explanation:

Hello,

This problem deals with understanding the ideal gas law which hopes to predict how ideal gases might behave in any given condition. I listed the formula below and we are basically just going to solve for temperature by rearranging the equation as seen on the picture (there's also other rearranged ones in case you need to solve for those).

Universal gas constant R has a value of 0.0821 L * atm/(mole * K) when working with these given units so it will be part of this equation. R value changes based on what units you have.

T = PV/nR

   = (2.33) (72.31) / (3.13)(0.0821)

   = 655.64 K

Question is asking temperature in celsius so we employ the formula attached below:

C = K - 273.15

   = 655.64-273.15

    = 382.49 degree Celsius

382.49 degree Celsius is the answer!

What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe reacts with 2.1 g of O2?

4 Fe + 3O2 —> 2Fe2O3

Answers

Answer:

Fe is limiting reactant and 3.00g of Fe2O3 will be produced

Explanation:

To solve this question we must convert the mass of each reactant to moles and, using the reaction we can find limiting reactant. With moles of limiting reactant we can find moles of Fe2O3 and its mass as follows:

Moles Fe -Molar mass: 55.845g/mol-

2.1g * (1mol / 55.845g) = 0.0376 moles

Moles O2 -Molar mass: 32g/mol-

2.1g * (1mol / 32g) = 0.0656 moles

For a complete reaction of 0.0656 moles of O2 are needed:

0.0656moles O2 * (4mol Fe / 3 mol O2) = 0.0875 moles Fe

As there are just 0.0376 moles,

Fe is limiting reactant

The mass of Fe2O3 is:

Moles:

0.0376 moles Fe* (2mol Fe2O3 / 4mol Fe) = 0.0188 moles Fe2O3

Mass:

0.0188 moles Fe2O3 * (159.69g / mol) =

3.00g of Fe2O3 will be produced

Which of the following is true for a gas under conditions of very high pressure? (5
points)
1) PV > nRT, because the real volume of the gas would be more than the ideal
volume.
2) PV = nRT, because intermolecular forces are considerable at very high
pressures.
3) PV = nRT, because all gases behave as ideal gases at very high pressures.
04) PV = nRT, because the volume of the gas would become negligible.

Answers

Answer:

1) PV > nRT, because the real volume of the gas would be more than the ideal

volume.

Explanation:

According to the ideal gas equation; PV = nRT.  Let us recall that this equation only holds under ideal conditions.

Gases exhibit ideal behavior under high temperature and low pressure. At higher pressure, the real volume of the gas is larger than the ideal volume of the gas.

Thus, at high pressure,  PV > nRT, because the real volume of the gas would be more than the ideal  volume.

Answer:

1) PV > nRT, because the real volume of the gas would be more than the ideal volume.

Explanation:

just took the test :)

How many moles are in 3.72 x 10^27 atoms of iron?

Answers

Answer: There are [tex]0.617 \times 10^{4}[/tex] moles present in [tex]3.72 \times 10^{27}[/tex] atoms of iron.

Explanation:

According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in one mole of a substance.

Hence, moles present in [tex]3.72 \times 10^{27}[/tex] atoms are calculated as follows.

[tex]Moles = \frac{3.72 \times 10^{27}}{6.022 \times 10^{23}}\\= 0.617 \times 10^{4} mol[/tex]

Thus, we can conclude that there are [tex]0.617 \times 10^{4}[/tex] moles present in [tex]3.72 \times 10^{27}[/tex] atoms of iron.

If the pH of a solution is 6.96, then the solution is a

Answers

Answer:

acid

Explanation:

solution with pH less than 7 is acid

those with more that 7 is base

those equal to 7  is neutral

mrs tuckers class is doing an experiment they fill up a cup with ice water they measure the temperature of both the water and the classroom after one hour . what will mrs tucker observe about the temperature of ice water after one hour

A. The temperature will increase
B. The temperature Will remain the same
C. The temperature will decrease greatly
D. The temperature Will decrease slightly

Answers

C.


Hope this is the correct answer

Answer:

Ofc D. bc if the temp decreases, that means it is getting colder u dummy! But if it increases, it is getting warmer.

Explanation:

I got it right on USATestprep for using common sense, mark me the brainliest.

A community located downwind from a coal-fired power plant has seen a recent increase in the number of dead and dying trees. A so scientist measured values for the following parameters before and after the trees died off. Which of the following oil data should be used to determine if the coalfired power plant emiations were the cause of the damage to the trees
a. Moisture content and water retention
b. Parent material composition
c. Pesticide and herbicide residue levels
d. Calcium and aluminum levels

Answers

Answer:

Option D, Calcium and Aluminum levels

Explanation:

The coal fired power plant releases huge amount of particulate and gaseous emissions such as mercury, sulphur dioxide, nitrogen oxide etc. When there is rain, these gaseous and particulate matter comes to the ground along with rain water and pollute the soil. There are also chances of acid rain due to the presence of sulphur dioxide. Polluted soil and acid rain negatively impact the growth of the plants and causes leaching of Aluminium thereby decreasing the availability of calcium for the plants. Thus, the trees die. Hence, if the amount of Aluminium and Calcium in soil is determined, one can easily deduce the cause of death of trees.

Hence, option D is correct

4. The device shown is a
that's used to measure the heat transferred by a reaction under constant volume.
A. bomb calorimeter
B. reaction vessel
C. thermometer
D. coffee-cup calorimeter

Answers

Answer:

The device shown is a calorimeter that used to measure the heat transfer by a reaction under constant volume.

Explanation:

Ice melts after adding heat. The free energy is ————— !

A. Exothermic
B. Not temperature dependent
C. Temperature dependent
D. Depended on how it is heated
E. React with active metals to form h2 gas
F. Endothermic

Answers

Answer: F. Endothermic…………………

What compound(s) does pure water contain?

Answers

oxygen hydrogen beau clutch

How do the equilibrium concentrations of the reactants compare to the equilibrium concentrations of the product?

Answers

Answer: It depends equilibrium constant K

Explanation:   You need to to have reaction formula.

If K >> 1 then concentrations of products are much bigger than

concentrations of reactants. If K < < 1, concentration of products is small.

in writing a chemical equation that produces hydrogen gas, the correct representation of hydrogen gas is
a.H
b.2H
c.H2
d.OH

Answers

Answer:

h2

Explanation:

Which of the following substances can be dissolved in pure water to give a basic solution?

Hydrogen chloride

Sodium bromide

Sodium hydroxide

Sodium chloride

Answers

Maybe the 2nd one??? Not sure

I think it's sodium hydroxide

Explanation:

sodium hydroxide is a base

PLEASE HELP!! ORGANIC CHEMISTRY

A sample of a diatonic gas is loaded into an evacuated bottle at STP. The 0.25 L bottle contains 1.76 grams of the unidentified gas. Calculate the molar mass of the gas. What is the identity of the diatomic gas?

Answers

Answer:

(a) 157.7 g

(b) 7.04 g/dm³

Explanation:

(a) From the question,

According to Avogadro's Law,

1 mole of every gas at STP occupies a volume of 22.4 dm³

But mass of 1 mole of the diatomic gas  = molar mass of the gas.

This Implies that,

The molar mass of the gas at STP occupies a volume of 22.4 dm³

From the question,

If,

0.25 L bottle contain 1.76 g of the gas,

Therefore,

Molar mass of the gas = (1.76×22.4)/0.25

Molar mass of the gas = 157.7 g.

(b) Density of the gas = mass/volume

D = m/v

Given: m = 1.76 g, v = 0.25 L = 0.25 dm³

Therefore,

D = 1.76/0,25

D = 7.04 g/dm³

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