can someone explain how to find the tangent line of something :D

Answers

Answer 1

Answer:

This can help you! Pictures tell more than 100s of word.

Explanation:

Can Someone Explain How To Find The Tangent Line Of Something :D
Can Someone Explain How To Find The Tangent Line Of Something :D

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A 4400 Kg Track Travelling at Intial speed 52m\s can be stopeed in 42 sec. By Gently Break, also the track can be stoped
in 7.6 m\s if the driver hit the wall.
a. What is the Impulse Excerted on the Vehicle?
b. Whta is the Averge force is exeted on the Track in each stops ?

Answers

Answer:

(a) J = 10560  kg-m/s (b) 251.42 N

Explanation:

Given that,

Mass, m = 4400 kg

Initial speed, u = 5.2 m/s

Final speed, v = 7.6 m/s

Time, t = 42 s

(a) Let J be the impulse exerted on the vehicle. Impuse is equal to the change in momentum such as :

J = m(v-u)

J = 4400 (7.6-5.2)

J = 10560  kg-m/s

(b) Impulse = Force × t

[tex]F=\dfrac{J}{t}\\\\F=\dfrac{10560}{42}\\F=251.42\ N[/tex]

Hence, this is the required solution.

Your friend said that the star in this picture with the highest apparent magnitude must definitely have the highest absolute brightness as well.

Answers

Answer:

A white dwarf, also called a degenerate dwarf

Explanation:

sorry if im wrong im kind of du-m

Please help! Due in 5 min! I will pick brainiest! Thanks! YOU ROCK!
The resistance of an electric stove burner element is 11 ohms. What current flows through this
element when it runs off a 220 volt line?

Answers

Answer:

Current flow I =  20 ampere

Explanation:

Given:

Resistance R = 11 ohms

Voltage V = 220 volts

Find:

Current flow I

Computation:

Current flow I = V / R

Current flow I = 220 / 11

Current flow I =  20 ampere

The amount of current flow through the element is of 20 A.

Given data:

The magnitude of resistance of Electric stove is, R = 11 ohms.

The magnitude of potential difference in a line is, V' = 220 V.

Here we can simple go for Ohm's law. As per the Ohm's law, the potential difference across the element is proportional to the current flow and the resistance of the element.

The expression is,

V' = I × R

here, I is the amount of current flowing through the element.

Solving as,

220 = I × 11

I = 20 A

Thus, we can conclude that the amount of current flow through the element is of 20 A.

Learn more about the Ohm's law here:

https://brainly.com/question/10006666

A wet towel spread out and hung outside on a day without wind dries faster than an identical wet towel left rolled up in a plastic bag.
Explain why.

Answers

Even without wind the sun help evaporate the water so it would dry faster. The other towel is in a bag so the moist and water has nowhere to go, therefor staying in the towel.

A runner taking part in the 200-m dash must run around the end of a track that has a circular arc with a radius of curvature of 29.5 m. The runner starts the race at a constant speed. If she completes the 200-m dash in 24.4 s and runs at constant speed throughout the race, what is her centripetal acceleration as she runs the curved portion of the track

Answers

Answer: [tex]2.27\ m/s^2[/tex]

Explanation:

Given

Length of the race track [tex]L=200\ m[/tex]

the radius of curvature of the track [tex]r=29.5\ m[/tex]

time taken to run on track is [tex]t=24.4\ s[/tex]

Speed of runner is

[tex]\Rightarrow v=\dfrac{L}{t}=\dfrac{200}{24.4}\\\\\Rightarrow v=8.196\ m/s[/tex]

Centripetal acceleration is

[tex]\Rightarrow a_c=\dfrac{v^2}{r}=\dfrac{8.196^2}{29.5}\\\\\Rightarrow a_c=2.27\ m/s^2[/tex]

d. Two point charges, q1 = +25 nC and q2 = -75 nC, are separated by a distance of 3.0 cm. Find the magnitude and direction of; i. the electric force q1 exerts on q2 [5] ii. the force that q2 exerts on q1 [4] (take k = 9.0 x 109 N.m2 /C2 )

Answers

Answer:

a) F₂₁ = 0.02 N, attracting.

b) F₁₂ = 0.02 N, attracting.

Explanation:

a)

The magnitude of the force that q₁ exerts on q₂ (F₂₁) is given by Coulomb's Law, as follows:

      [tex]F_{21} = k * \frac{q_{1} *q_{2}}{r_{12}^{2} } = 9e9 N.m2/C2 * \frac{(25e-9C)*(75e-9C)}{(0.03m)^{2}} = 0.02 N (1)[/tex]

Since q₁ and q₂ have opposite signs, the force between them will be always attractive, i.e., from q₂ towards q₁, along the line that joins both charges.

b)

The magnitude of the force on q₁ due to q₂ can be obtained applying Newton's 3rd Law, or using (1), because all parameters are the same, so F₁₂ (in  magnitude) = F₂₁ = 0.02 NAs we have already said, it must be opposite to the one found in a) so it must go from q₁ towards q₂, it is an attracting force also.

when an object slides over a smooth horizontal surface, how does the force of friction depend on the surface area of blocks that's are in contact with the table?​

Answers

Answer: with a greater surface area, there will be a greater force of friction

Explanation:

Where do animals such as snakes and frogs, which do not make their own body heat, usually get their heat?

fuel
the sun
hot lava
friction

plssssssss answer correctly

Answers

The answer to this question is the Sun.

As im writing this, 12,826 people vote the Sun.

animals such as snakes and frogs, which do not make their own body heat. They usually get their heat from the sun. Hence option B is correct.

What is Cold-blooded animals ?

A body temperature that is only slightly higher than the ambient temperature. This condition differentiates cold-blooded, or homoiothermic, animals from fishes, amphibians, reptiles, and invertebrates (birds and mammals). Due of their reliance on external warmth for metabolic activity, terrestrial cold-blooded species are restricted to locations with temperatures ranging from 5-10° to 35-40° C (41-50° to 95-104° F).

Cold-blooded creatures cannot create their own body heat, but they may control it by modifying their surroundings. Alligators and other reptiles frequently lay in the sun to warm up. They, on the other hand, cool off by swimming, going into a burrow in the earth, or moving inside the sade of a rock.

Hence option B is correct.

To know more about Cold-blooded animals :

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Fifty grams of ice at 0◦ C is placed in a thermos bottle containing one hundred grams of water
at 6◦ C. How many grams of ice will melt? The heat of fusion of water is 333 kJ/kg and the
specific heat is 4190 J/kg · K.Immersive Reader

Answers

Answer:

7.55 g

Explanation:

Given that:

Heat of fusion = 333kj/kg

Heat capacity, c = 4190 j/kg /k

The Number of grams of ice that will melt can be represented as y:

Number of grams of ice that will melt * heat of fusion = specific heat capacity * temperature change

y * 333 * 10^3 J = (4190) * (6 - 0)

333000y = 25140

y = 25140 / 333000

y = 0.0754954 kg

y = 0.0754954 * 100

y = 7.549 g

Hence, Number of grams of ice that will melt = 7.55 g

what is the quantum and its types?​

Answers

Answer:

It is the physics that explains how everything works, the nature of the particles that make up matter and the forces with which they interact.

Its types: Electromagnetism, the strong nuclear force, and the weak nuclear force.

Hope this help :)

A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 ×102 T, what is the number of turns per meter for this solenoid?

Answers

Correct question:

A solenoid of length 0.35 m and diameter 0.040 m carries a current of 5.0 A through its windings. If the magnetic field in the center of the solenoid is 2.8 x 10⁻² T, what is the number of turns per meter for this solenoid?

Answer:

the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.

Explanation:

Given;

length of solenoid, L= 0.35 m

diameter of the solenoid, d = 0.04 m

current through the solenoid, I = 5.0 A

magnetic field in the center of the solenoid, 2.8 x 10⁻² T

The number of turns per meter for the solenoid is calculated as follows;

[tex]B =\mu_o I(\frac{N}{L} )\\\\B = \mu_o I(n)\\\\n = \frac{B}{\mu_o I} \\\\n = \frac{2.8 \times 10^{-2}}{4 \pi \times 10^{-7} \times 5.0} \\\\n = 4.5 \times 10^3 \ turns/m[/tex]

Therefore, the number of turns per meter for the solenoid is 4.5 x 10³ turns/m.

How many electron flow through a light bulb each second if the current flow through the light bulb 0.75A.The electric charge of one electron is 1.6 x 10-19C

Answers

Answer:

[tex]n=4.68\times 10^{18}[/tex]

Explanation:

The current through the bulb, I = 0.75 A

We need to find the number of electrons flowing per second. We know that the electric current is given by :

[tex]I=\dfrac{ne}{t}\\\\n=\dfrac{It}{e}\\\\n=\dfrac{0.75\times 1}{1.6\times 10^{-19}}\\\\n=4.68\times 10^{18}[/tex]

So, there are [tex]4.68\times 10^{18}[/tex] electrons flowing per second.

There are "[tex]4.68\times 10^{18}[/tex]" electron flowing per second.

Electric charge:

Whenever retained inside an electric as well as the magnetic field, this same basic physical attribute of matter which thus permits it to perceive a force, is considered as Electric charge.

According to the question,

Current flow, I = 0.75 A

Electric charge of one electron, e = 1.6 x 10⁻¹⁹ C

As we know the relation,

Current, I = [tex]\frac{ne}{t}[/tex]

or,

→ n = [tex]\frac{It}{e}[/tex]

By substituting the given values in the above formula, we get

      = [tex]\frac{0.75\times 1}{1.6\times 10^{-19}}[/tex]

      = [tex]4.68\times 10^{18}[/tex]

Thus the approach above is appropriate.

Find out more information about electric charge here:

https://brainly.com/question/14372859

Light undergoes refraction as it travels from water to glass. The refractive index of water = 1.33 and refractive index of glass = 1.5. Calculate the angle of refraction inside glass if angle of incidence in the water is 32 degrees

Answers

Answer:

28°

Explanation:

Snell's Law and equation

This figure shows a sinusoidal wave that is traveling from left to right, in the +x-direction. Assume that it is described by a frequency of 57.1 cycles per second, or hertz (Hz).
7.60 cm4.80 cm
A sinusoidal wave lies on an unlabeled coordinate system. One of the wave's maxima lies on the vertical axis. The horizontal distance from the first maximum to the first minimum is labeled 4.80 cm and the vertical distance between a maximum and a minimum is labeled 7.60 cm.
(a)
What is the wave's amplitude (in cm)?
cm
(b)
What is the wavelength (in cm)?
cm
(c)
Calculate the wave's period (in s).
s
(d)
Compute the speed of this wave (in m/s).
m/s

Answers

Answer:

a)  A = 3.80 cm, b)   λ = 9.60 cm, c)  T = 1.75 10⁻² s, d)    v = 5.48 m / s

Explanation:

The wave is a way of transporting energy and moment without the need to transport the material. They are described by expressions of the type

           x = A sin (kx - wt)

where the amplitude A is the distance from the point of zero intensity to the maximum.

Frequency is the number of times the wave oscillates per unit of time

the wavelength is the distance necessary for the wave to start repeating.

a) In the exercise it tells us that the vertical distance from a machismo to a minimum that is worth 7.60 cm

when checking the definition of amplitude is from zero to a maximum, therefore the value given is twice the amplitude

          2A = 7.60

            A = 3.80 cm

b) the distance between a minimum and the next maximum is 4.80 cm

Using the definition of wavelength the given value corresponds to half wavelength

          λ/ 2 = 4.80

          λ = 9.60 cm

c) frequency and period are related

          f = 1 / T

          T = 1 / f

we calculate

           T = 1 / 57.1

           T = 0.0175 s

           T = 1.75 10⁻² s

d) the speed of the wave is related to the frequency and the wavelength

          v = λ f

          v = 0.0960 57.1

          v = 5.48 m / s

what happens to the loudness of the sound as the amplitude increases

Answers

it increases and gets louder

and it amplifies the noise

How much Work is done when a 5 kg object is picked up a distance of 8 m.

Answers

Answer:

392J?

Explanation:

An old mining tunnel disappears into a hillside. You would like to know how long the tunnel is, but it's too dangerous to go inside. Recalling your recent physics class, you decide to try setting up standing-wave resonances inside the tunnel. Using your subsonic amplifier and loudspeaker, you find resonances at 5.0 Hz and 6.4 Hz , and at no frequencies between these. It's rather chilly inside the tunnel, so you estimate the sound speed to be 333 m/s .

Answers

Answer:

 L = 116.6 m

Explanation:

For this exercise we approximate the tunnel as a tube with one end open and the other closed, at the open end there is a belly and at the closed end a node, therefore the resonances occur at

               λ = 4L         1st harmonic

               λ = 4L / 3    third harmonic

               λ = 4L / 5    fifth harmonic

General term

               λ = 4L / n      n = 1, 3, 5,...    odd

                                    n = (2n + 1)      n are all integers

They indicate that two consecutive resonant frequencies were found, the speed of the wave is related to the wavelength and its frequency

            v = λ f

            λ = v / f

we substitute

            [tex]\frac{v}{f} = \frac{4L}{n}[/tex]

             L = [tex]n \frac{ v}{4f}[/tex]

for the first resonance n = n

             L = (2n + 1) [tex]\frac{v}{4f_1}[/tex]

for the second resonance n = n + 1

             L = (2n + 3) [tex]\frac{v}{4f_2}[/tex]

we have two equations with two unknowns, let's solve by equating

             (2n + 1) \frac{v}{4f_1}= (2n + 3) \frac{v}{4f_2}

             (2n + 1) f₂ = (2n +3) f₁

              2n + 1 = (2n + 3) [tex]\frac{f_1}{f_2}[/tex]

              2n (1 - \frac{f_1}{f_2}) = 3 \frac{f_1}{f_2} -1

we substitute the values

              2n (1- [tex]\frac{5}{6.4}[/tex]) = 3 [tex]\frac{5}{6.4}[/tex] -1

              2n 0.21875 = 1.34375

              n = 1.34375 / 2 0.21875

              n = 3

remember that n must be an integer.

We use one of the equations to find the length of the Tunal

                  L = (2n + 1) \frac{v}{4f_1}

                  L = (2 3 + 1) [tex]\frac{333}{4 \ 5.0}[/tex]

                  L = 116.55 m

What is the wavelength of microwaves with a frequency of 3x10^10 Hz?​

Answers

Answer:

0.01 m

Explanation:

Since the speed of light is 3.0×10^8 m/s

Use the equation,

Wavelength = speed ÷ frequency

Wavelength = 3.0×10^8 ÷ 3×10^10

Wavelength = 0.01m

Can someone please help

Answers

ummmmmmmmmmm thats confusing

A 5kg object accelerates from 3m/s to 7m/s in 5 seconds. Calculate the force required
to provide this acceleration.

Answers

Answer:

4N

Explanation:

a = (7-3)/5 = 0.8m/s^2

F = ma = (5)(0.8) = 4 Newtons

Which type of land usage would increase as the population increases?

Answers

Answer:

If the population were to INCREASE land use would also INCREASE, if the human population DECREASED so would land use because there wouldn’t be as many people to using it. hope i helped

Answer:

D. Urban use

Explanation:

It shows here on this graph that overtime urban use is rising as the population is increasing! The other answers that are on this graph does not show it increasing!

Which molecules are in put in photosynthesis

Answers

Answer:

During the process of photosynthesis, cells use carbon dioxide and energy from the Sun to make sugar molecules and oxygen. These sugar molecules are the basis for more complex molecules made by the photosynthetic cell, such as glucose.

Explanation:

yes.

Answer:

Sunlight, Carbon Dioxide, and Water

Explanation:

Technically minerals are in there too but when I learned this it was just Sunlight, Carbon Dioxide, and Water

a ford explorer traveled 100 miles the next day for 5 hours. What was the average speed of this vehicle?

Answers

Answer:

25 miles per hour

Explanation:

It was 20 miles per hour the next day.  We don't have enough information to calculate the average speed for the whole trip.

Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward. You have a compass that is free to swivel in any direction. Which way does your compass point? Suppose you are standing at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward. You have a compass that is free to swivel in any direction. Which way does your compass point? It would point up. It would point east. It would point down. It would point west.

Answers

Answer:

It would point up.

Explanation:

Since I am at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward, the north pole of the compass would also point towards the earth's geographic north magnetic pole, since all other compasses point toward there.

Since the compass is free to swivel in any direction, the compass would point up, since it is at the earth's geographic north magnetic pole, the place on the earth's surface that compasses point toward.

So, the compass would point up.

3. The car's mass is 400 kg. It moves at a velocity of 20 m/s. Calculate the car's momentum. *
(10 Points)
0.05 kg.m/s
8000 kg.m/s
80,000 kg.m/s
20 kg.m/s

Answers

Answer:

momentum=mass×velocity

momentum =400kg×20m/s=8000kg.m/s

Suppose that you'd like to find out if a distant star is moving relative to the earth. The star is much too far away to detect any change in its brightness as it moves toward or away from the earth. Instead we can use the Doppler effect to determine its relative speed. For this problem we are going to look at the spectral lines from hydrogen, specifically the one with a wavelength of 656.46 nm.
The hydrogen atoms in a star are also moving at high velocity because of the random motions caused by their high temperature. As a result, each atom is Doppler shifted a little bit differently, leading to a finite width of each spectral line, such as the 656.46-nm line we were just discussing. For a star like our sun, this leads to a finite width of the spectral lines of roughly Δλ=0.04nm.
If our instruments can only resolve to this accuracy, what is the lowest speed V, greater than 0, that we can measure a star to be moving?

Answers

Answer:

The answer is "[tex]\bold{18 \ \frac{km}{s}}[/tex]"

Explanation:

Its concern is not whether star speed is significantly lower than the light speed. Taking into consideration the relativistic tempo (small speed star)

[tex]\to \frac{\Delta \lambda}{\lambda} = \frac{v}{c}\\\\\to v = \frac{\Delta \lambda}{\lambda} \left (c \right ) \\\\[/tex]

       [tex]= \left ( \frac{0.04}{656.46} \right ) (3 \times 10^8)\\\\ = 18280 \ \frac{m}{s} \approx 18 \ \frac{km}{s}[/tex]

. An object 8.5 cm high is placed 28 cm from a converging lens. The focal length of the lens is 12 cm. Calculate the image distance, di. Calculate the image height, hi.

Answers

The converging lens is also called a concave lens. The height of the image formed by the lens is 2.55 cm.

Using the lens formula;

1/f = 1/u + 1/v

f = focal length of the lens

u = object distance

v = image distance

Note that the focal length of a converging lens is positive

Substituting values;

1/12 = 1/28 + 1/v

1/v = 1/12 -  1/28

v = 8.4 cm

Magnification= image height/object height = image distance/object distance

image height = ?

object height = 8.5 cm

image distance = 8.4 cm

object distance =  28 cm

So

image height/8.5 = 8.4/28

image height = 8.5 × 8.4/28

image height = 2.55 cm

Learn more: https://brainly.com/question/11969651

Which type of biological molecule would contain fats?
A) Amino Acids.
C) Nucleic Acids.
B) Lipids.
D) Carbohydrates.

Answers

B

Explanation:

lipids contains fat

hope it helps

Consider identical spherical conducting space ships in deep space where gravitational fields from other bodies are negligible compared to the gravitational attraction between the ships. Construct a problem in which you place identical excess charges on the space ships to exactly counter their gravitational attraction. Calculate the amount of excess charge needed. Examine whether that charge depends on the distance between the centers of the ships, the masses of the ships, or any other factors. Discuss whether this would be an easy, difficult, or even impossible thing to do in practice.

Answers

Answer:

 q = 8.61 10⁻¹¹ m

charge does not depend on the distance between the two ships.

it is a very small charge value so it should be easy to create in each one

Explanation:

In this exercise we have two forces in balance: the electric force and the gravitational force

          F_e -F_g = 0

          F_e = F_g

Since the gravitational force is always attractive, the electric force must be repulsive, which implies that the electric charge in the two ships must be of the same sign.

Let's write Coulomb's law and gravitational attraction

         [tex]k \frac{q_1q_2}{r^2} = G \frac{m_1m_2}{r^2}[/tex]

In the exercise, indicate that the two ships are identical, therefore the masses of the ships are the same and we will place the same charge on each one.

          k q² = G m²

          q = [tex]\sqrt{ \frac{G}{k} }[/tex]    m

we substitute

           q = [tex]\sqrt{ \frac{ 6.67 \ 10^{-11}}{8.99 \ 10^{9}} }[/tex]   m

            q = [tex]\sqrt{0.7419 \ 10^{-20}}[/tex]   m

           q = 0.861 10⁻¹⁰ m

           q = 8.61 10⁻¹¹ m

This amount of charge does not depend on the distance between the two ships.

It is also proportional to the mass of the ships with the proportionality factor found.

Suppose the ships have a mass of m = 1000 kg, let's find the cargo

            q = 8.61 10⁻¹¹ 10³

            q = 8.61 10⁻⁸ C

             

this is a very small charge value so it should be easy to create in each one

You use 350 W of power to move a 7.0 N object 5 m.
How long did it take?

Answers

Answer:

0.1 second

Explanation:

We are given;

Power; P = 350 W

Force; F = 7 N

Distance; d = 5 m

Formula for power is;

P = workdone/time taken

Workdone = F × d

Thus;

350 = (7 × 5)/t

t = 35/350

t = 0.1 second

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