Can someone explain how a compass and straight-edge allow us to “measure” segments and angles. This is for Geometry... Thank you!

Answer:

5/7

Step-by-step explanation:

There are 7 cards, all of which have an equal chance of being chosen.

And in this case, because there are 7 cards in total, they each have a 1/7 chance of being chosen. Because there are 5 cards greater than 4, you have a 5x1/7 chance =5/7 chance of choosing a number greater than 4.

P.S. If you need it as a percentage, then it is 71.428571%.

P.P.S. Remember if you like the answer then mark as brainliest thank you!

Answer:

c is the answer just did the quiz

The value of x in the triangle is 26.

Option D is the correct answer.

A  triangle is a 2-D figure with three sides and three angles.

The sum of the angles is 180 degrees.

We can have an obtuse triangle, an acute triangle, or a right triangle.

We have,

If two triangles are similar,

The ratio of its corresponding sides is equal.

This means,

ΔABC and ΔCDE

AB/AC = ED/CD

42/x = 8/(32 - x)

42 (32 - x) = 8x

1344 - 42x = 8x

1344 = 50x

x = 1344/50

x = 26.88

x = 26

Thus,

The value of x in the triangle is 26.

Learn more about triangles here:

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Answer:

The length of the rectangle is 6.

Step-by-step explanation:

Given: The diagonal of a rectangle is 10 and the height is 8.

Please understand, that a diagonal, divides the rectangle into two tringles.

To find the length of the rectangle, you can use Pythagoras on one of the right sided triangles, because the length of the triangle, is also the length of the rectangle!

EXTRA:

If you know the special 3 4 5 triangle, a so called Pythagorean Triple, then you can "see" the simularity between the numbers.

Instead of 5, a diagonal of 10 is given (factor of 2 bigger).

Instead of 4, the height of 8 is given (factor of 2 bigger). By scaling the Pythagorean Triple 3 4 5 by a factor of 2, you get the numbers 6 8 10. Could it be, that the number we need to find, is six?

Try to verify, by calculating the missing number (which is the length of the rectangle we are looking for).

a² + b² = c²

a = length (and is unknown)

b = height = 8

c = hypothenusa/diagonal = 10

Substitute the numbers given:

a² + 8² = 10²

Subtract 8² left and right of the = sign.

a² +8² -8² = 10² - 8²

a² + 0 = 100 - 64

a² = 36

a = + - √36

a = + - 6

EXTRA:

You can ignore the -√36 = -6 part of the solution, because a length of -6 has no meaning here.

a = 6

So, the length of the triangle is 6 and thus, the length of the rectangle is also 6.

Answer:

2

Step-by-step explanation:

Given,

6x-3y=18

or, -3y=18-6x

dividing by 3 into both sides and multiply by -1

we get,

y=2x-6

comparing above eq with linear equation y=mx+c

we get,

m=2 Ans.

Answer:

45 bricks

Step-by-step explanation:

First we need to find the volume of one brick. The bricks are rectangular prisms. The volume formula for rectangular prisms is:

V=l*w*h

The bricks are 13 inches long, 5 inches wide and 4 inches high.

l=13 inches

w=5 inches

h=4 inches

V= 13 inches * 5 inches * 4 inches

V=65 inches^2 * 4 inches

V=260 inches ^3

Each brick has a volume of 260 inches^3. We know they used a total of 11,700 inches^3 of concrete. The question asks us to find how many bricks they made. We must divide the volume of concrete used by the volume of one brick.

concrete volume / one brick volume

concrete volume= 11,700 in^3

one brick volume= 260 in^3

11,700 in^3 / 260 in^3

11,700/260

45

They made 45 bricks.

Answer:

Y = 1, E = -1, A= 1, R = -1

Step-by-step explanation:

YYYY - EEE + AA - R = 1234

First we would break down the digits in the whole numbers into their place value (thousands, hundreds, tens and units).

YYYY = 1000Y + 100Y +10Y + Y

EEE = 100E + 10E + E

-EEE = -100E - 10E - E

AA = 10A + A

R = R

-R = -R

1234 = 1000+200+30+4

Let's equate each place value for each of the numbers.

Thousands: 1000Y = 1000

Y = 1000/1000 = 1

Hundreds: 100Y - 100E = 200

100(1) - 100E = 200

-100E = 200-100

-100E= 100

E = -1

-EEE = -E(111)

Tens: 10Y - 10E + 10A = 30

10(1) - 10(-1) + 10A = 30

20+ 10A = 30

A = 10/10

A= 1

Units: Y - E + A - R = 4

1 - (-1) + 1 - R = 4

3-R = 4

R = 3-4 = -1

YYYY - EEE + AA - R = 1234

1111 - (-111) + 11 - (-1) = 1111+111+11+1 = 1234

All possible values of the digits Y, E, A, R are Y = 1, E = -1, A= 1, R = -1

Answer:

Y=2

E=9

A=1

R=0

Step-by-step explanation:

Let's check our work.

2,222 - 999 + 11 - 0

1,223 + 11 - 0

1,234 - 0

1,234

Also previous answerer how can digits be negative?

Answer:

New mean will be( 8 + 3 + 4 + 2 + 8) / 2

= 25/5 = 5 (old was 6)

New median will be 4 (old was 8)

Answer:

Mean, Mean would change the most the original mean was 28.4, after replacing 9 with 4 it changed to 23.4. With the difference of 5.

Step-by-step explanation:

Mode will stay the same with the repetition of 8, median will be a 4 difference from 8 to 4

Answer:

a) [tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [/tex]

And replacing we got:

[tex]\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730) [/tex]

b) [tex] z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739[/tex]

And using the normal standard distribution table and the complement rule we got:

[tex] P(z>2.739) =1- P(z<2.739) = 1-0.997= 0.003[/tex]

Step-by-step explanation:

From the info given if we define the random variable X as "amount of saturated fat in a daily serving of a particular brand of breakfast cereal " we know that the distribution of X is given by:

[tex] X \sim N(\mu =25, \sigma =4)[/tex]

Part a

For this case the sample size would be n =30 and then the distribution for the sample mean would be given by:

[tex]\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}}) [/tex]

And replacing we got:

[tex]\bar X \sim N(\mu=25, \frac{4}{\sqrt{30}}= 0.730) [/tex]

Part b

We want to find this probability:

[tex] P(\bar X >27)[/tex]

And we can use the z score formula given by:

[tex] z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]

And replacing we got:

[tex] z =\frac{27-25}{\frac{4}{\sqrt{30}}}= 2.739[/tex]

And using the normal standard distribution table and the complement rule we got:

[tex] P(z>2.739) =1- P(z<2.739) = 1-0.997= 0.003[/tex]

Answer:

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

Also:

The normal distribution is symmetric, which means that 50% of the data is above the mean and 50% is below.

Then:

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.7 percent are within 3 standard deviations of the mean.

In a normal distribution, 50 percent of the data are above the mean, and 50 percent of the data are below the mean. Similarly, 68 percent of all data points are within 1 standard deviation of the mean, 95 percent of all data points are within 2 standard deviations of the mean, and 99.9 percent are within 3 standard deviations of the mean.

The normal distribution is a probability distribution that is important in many areas. It is, in fact, a family of distributions of the same form, each with different location and scale parameters: the mean and standard deviation respectively. The standard normal distribution is the normal distribution with mean equal to zero, and standard deviation equal to one. The shape of its probability density function is similar to that of a bell.

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Answer:

[tex]P(x\geq 3)=0.3233[/tex]

Step-by-step explanation:

If the number of defects in poured metal follows a Poisson distribution, the probability that x defects occurs is:

[tex]P(x)=\frac{e^{-m}*(m)^{x}}{x!}[/tex]

Where x is bigger or equal to zero and m is the average. So replacing m by 2, we get that the probability is equal to:

[tex]P(x)=\frac{e^{-2}*(2)^{x}}{x!}[/tex]

Finally, the probability that there will be at least three defects in a randomly selected cubic millimeter of this metal is equal to:

[tex]P(x\geq 3)=1-p(x\leq 2)\\[/tex]

Where [tex]P(x\leq 2)=P(0)+P(1)+P(2)[/tex]

So, P(0), P(1) and P(2) are equal to:

[tex]P(0)=\frac{e^{-2}*(2)^{0}}{0!}=0.1353\\P(1)=\frac{e^{-2}*(2)^{1}}{1!}=0.2707\\P(2)=\frac{e^{-2}*(2)^{2}}{2!}=0.2707[/tex]

Finally, [tex]P(x\leq2)[/tex] and [tex]P(x\geq3)[/tex] are equal to:

[tex]P(x\leq 2)=0.1353+0.2707+0.2707=0.6767\\P(x\geq 3)=1-0.6767=0.3233[/tex]

Answer:

1/748 or about 0.0013

Step-by-step explanation:

Since there is an exactly equal probability of drawing any of the chips, the probability of drawing the one numbered 513 is:

[tex]\dfrac{1}{748}\approx 0.0013[/tex]

Hope this helps!

Answer:

Change 4020 to 4000 + 25.

Then use the distributive property.

4025 * 5 = (4000 + 25) * 5 = 4000 * 5 + 25 * 5 = 20,000 + 125 = 20,125

Answer:

The probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm is 0.97.

Step-by-step explanation:

The complete question is:

Suppose that the thickness of one typical page of a book printed by a certain publisher is a random variable with mean 0.1 mm and a standard deviation of 0.002 mm Anew book will be printed on 500 sheets of this paper. Approximate the probability that the thicknesses at the entire book (excluding the cover pages) will be between 49.9 mm and 50.1 mm. Note: total thickness of the book is the sum of the individual thicknesses of the pages Do not round your numbers until rounding up to two. Round your final answer to the nearest hundredth, or two digits after decimal point.

Solution:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e S, will be approximately normally distributed.  

Then, the mean of the distribution of the sum of values of X is given by,  

 [tex]\mu_{S}=n\mu[/tex]

And the standard deviation of the distribution of the sum of values of X is given by,  

[tex]\sigma_{S}=\sqrt{n}\sigma[/tex]

The information provided is:

[tex]n=500\\\mu=0.1\\\sigma=0.002[/tex]

As n = 500 > 30, the central limit theorem can be used to approximate the total thickness of the book.

So, the total thickness of the book (S) will follow N (50, 0.045²).

Compute the probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm as follows:

[tex]P(49.9<S<50.1)=P(\frac{49.9-50}{0.045}<\frac{S-E(S)}{SD(S)}<\frac{50.1-50}{0.045})[/tex]

                               [tex]=P(-2.22<Z<2.22)\\\\=P (Z<2.22)-P(Z<-2.22)\\\\=0.98679-0.01321\\\\=0.97358\\\\\approx 0.97[/tex]

Thus, the probability that the thicknesses at the entire book will be between 49.9 mm and 50.1 mm is 0.97.

Answer:

C. 12.3

Step-by-step explanation:

We should use Law of Cosines: c² = a² + b² -2abcosC

If that is the case, then EF is a, DF is b, and ∠F is c. We then plug the known variables in:

c² = 12² + 13² - 2(12)(13)cos59°

Plug that into the calc and you should get 12.2313, rounded to 12.3 as your final answer!

Question:

Flight 4581 travels daily from Pittsburgh to San Antonio. The flight is due into San Antonio at 5:07 p.m. The following list gives the Flight 4581 arrival time relative to 5:07 p.m. (in minutes) for a selection of 9 days. (A negative number means that the flight arrived early.) 21, 39, 37, 25, 6,-6, -4, 40, 37 Send data to Excel

(a) What is the mean of this data set? If your answer is not an integer, round your answer to one decimal place. an integer, round your answer to one decimal place.

b) How many modes does the data set have? and what are their values

Answer:

a) 21.2

b) Value of mode = 37

It contains just one mode

Step-by-step explanation:

Given:

x = 21, 39, 37, 25, 6,-6, -4, 40, 37

n = 9

a) Find the mean

Mean is the average value of a dataset.

Mean = Σx/n

Mean = [tex] \frac{21+39+37+25+6+(-6)+(-4)+40+37}{n} [/tex]

[tex] = \frac{195}{9} [/tex]

[tex] = 21.667 [/tex]

The question says one decimal place.

Therefore, mean = 21.7

b) The mode of a dataset is the value that appears most frequently.

We have the following datasets:

21, 39, 37, 25, 6,-6, -4, 40, 37

The value that appears most frequently here is 37.

37 appeared twice while the rest appeared just once.

Therefore the dataset contains just one mode

Answer:

A)

The number of weights of an organ in adult males = 374.85

B)

The percentage of organs weighs between 275 grams and 375

P(275≤x≤375) = 0.6826 = 68%

C)

The percentage of organs weighs between 275 grams and 425

P(275≤x≤375) = 0.8185 = 82%

Step-by-step explanation:

A)

Step(i):-

Given mean of the normal distribution = 325 grams

Given standard deviation of the normal distribution = 50 grams

Given Z- score = 99.7% = 0.997

[tex]Z = \frac{x-mean}{S.D} = \frac{x-325}{50}[/tex]

[tex]0.997 = \frac{x-325}{50}[/tex]

Cross multiplication , we get

[tex]0.997 X 50= x-325[/tex]

x - 325 = 49.85

x = 325 + 49.85

x = 374.85

The number of weights of an organ in adult males = 374.85

Step(ii):-

B)

Let X₁ = 275 grams

[tex]Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{275-325}{50} = -1[/tex]

Let X₂ = 375 grams

[tex]Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{375-325}{50} = 1[/tex]

The probability of organs weighs between 275 grams and 375

P(275≤x≤375) = P(-1≤Z≤1)

                       = P(Z≤1)- P(Z≤-1)

                      =  0.5 + A(1) - ( 0.5 - A(-1))

                     = A(1) + A(-1)

                    = 2 A(1)

                    = 2 × 0.3413

                    = 0.6826

The percentage of organs weighs between 275 grams and 375

P(275≤x≤375) = 0.6826 = 68%

C)

Let X₁ = 275 grams

[tex]Z_{1} = \frac{x_{1} -mean}{S.D} = \frac{275-325}{50} = -1[/tex]

Let X₂ = 425 grams

[tex]Z_{2} = \frac{x_{2} -mean}{S.D} = \frac{425-325}{50} = 2[/tex]

The probability of organs weighs between 275 grams and 425

P(275≤x≤425) = P(-1≤Z≤2)

                       = P(Z≤2)- P(Z≤-1)

                      =  0.5 + A(2) - ( 0.5 - A(-1))

                     = A(2) + A(-1)

                    = A(2) + A(1)       (∵A(-1) =A(1)

                    = 0.4772 + 0.3413

                    = 0.8185

The percentage of organs weighs between 275 grams and 425

P(275≤x≤375) = 0.8185 = 82%

Answer:

C

Step-by-step explanation:

because you need the energy of the box to lift it, as my old professor used to say " you can only push on somthing as much as it can push you back "

Answer:

D. energy(weight) is the correct answer

hope this helps

f(x)=1, 0 < x < 1 is the probability density function of the random variable x.

generally, it is f(x)=1/(b-a)  a < x < b;

where b=1 and a=0.

b) mean = integral (0 to 1) xdx  =  (0 to 1)  = 1/2

c)integral( 0.35 to 0.6) dx  =x (between 0.35 and 0.6)  = 0.6-0.35=0.25

d) integral(less than 0.82)dx = x (between 0 and 0.81) = 0.81 - 0 = 0.81

Please mark me brainliest!

Answer:

the answer is right below the picture sir ;-;

Step-by-step explanation:

Answer:

  [tex]\dfrac{1}{3}=0.\overline{3}[/tex]

Step-by-step explanation:

Since a single digit is repeated in each case, and since the repeat starts at the decimal point, the fraction corresponding to the repeated digit is that digit divided by 9.

  [tex]0.\overline{5}+0.\overline{1}-0.\overline{3}=\dfrac{5}{9}+\dfrac{1}{9}-\dfrac{3}{9}=\dfrac{5+1-3}{9}=\dfrac{3}{9}\\\\=\boxed{\dfrac{1}{3}}[/tex]

_____

Comment on equivalents to repeating decimals

The number of 9s in the denominator equals the number of repeated digits.

  0.2727(repeated) = 27/99 = 3/11 . . . . . 2 repeated digits

Answer:

The policy has an effect because the null hypothesis rejected since P-value < significance level.

Step-by-step explanation:

Since (P-value = 0.0108) < 0.1 significance level, we have sufficient evidence to show that the mean is not equal to 39.8. This means that the policy has an effect on the average number of the emails received per day.

The workings are clearly written in the file attached below. Please check.

Answer:

Step-by-step explanation:

Hello!

The variable of interest is

X: number of emails a profession employee receives per day

This variable has an average of μ= 39.8 emails/day and the standard deviation is known to be δ= 16.2 emails/day

A company considers that the large amount of emails creates distraction, reducing the employees concentration and thus their efficiency, so they established a new priority list that all employees were to use before sending an e-mail. After one month they took a random sample of employees obtaining:

n= 38

X[bar]= 33.1 emails/day

If the company's new policy worked, then the company would expect the mean number of emails an employee receives per day to decrease, symbolically: μ < 39.8

The hypotheses are:

H₀: μ ≥ 39.8

H₁: μ < 39.8

α: 0.10

To analyze the population mean you need as condition that the variable of interest is at least normal.

There is no information about the population distribution, but the sample size is big enough for it to be valid to apply the Central Limit Theorem. This states that for variables of unknown distribution, if a sample large enough is taken (normally n≥30 is considered ok) you can approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;σ²/n)

This allows you to use the standard normal as statistic for the test:

Z= (X[bar] - μ)/(σ/n) ≈ N(0;1)

[tex]Z_{H_0}= \frac{33.1-39.8}{\frac{16.2}{\sqrt{38} } }= -2.549= -2.55[/tex]

Using the critical value approach, this test is one tailed to the left, meaning that you will reject the null hypothesis to low values of Z.

The critical value is:

[tex]Z_{\alpha }= Z_{0.10}= -1.283[/tex]

The decision rule is:

If [tex]Z_{H_0}[/tex] ≤ -1.283, reject the null hypothesis.

If [tex]Z_{H_0}[/tex] > -1.283, do not reject the null hypothesis.

The calculated value is less than the critical value so the decision is to reject the null hypothesis.

At a 10% significance level, the null hypothesis was rejected. You can conclude that the new policy reduced the average number of emails a professional employee receives per day.

I hope this helps!

Answer:

A = 1.02 P

Step-by-step explanation:

A = P + 0.02P

Formula in Factorized form

(Taking P common)

A = P(1+0.02) [The required factorized from]

Then,

A = 1.02 P

Answer:

The correct answers are (1) Option d (2) option a (3) option a

Step-by-step explanation:

Solution

(1) Option (d) The statement is false. A diagonalizable matrix must have n linearly independent eigenvectors: what it implies is that a matrix is diagnostic if it has linearity independent vectors.

(2) Option (a) The statement is false. A diagonalizable matrix can have fewer than n eigenvalues and still have n linearly independent eigenvectors: what this implies is that a diagonalizable matrix  can have repeated eigenvalues.

(3) option (a) The statement is true. AP = PD implies that the columns of the product PD are eigenvalues that correspond to the eigenvectors of A : this implies that P is an invertible matrix whose column vectors are the linearity independent vectors of A.

Answer:

Step-by-step explanation:

Answer: $16

Step-by-step explanation:

1.94 * 8 = 15.52

$15.52 rounds up to $16

Answer:

A personality test may be given to assess individual behavior patterns. A personality test may be given to assess individual behavior patterns. This answer has been confirmed as correct and helpful.

Step-by-step explanation:

hopes this helps

Answer:

Interests, values, skill set and basic personality

Step-by-step explanation:

Personality tests are mostly used as an assessment tool be HR managers and employers during the interview process. They can provide a potential employer with information about your interests, values, skill set and even basic personality, which can be very useful to help an employer make a decision about whether you are the best fit for a position.

I hope this helped. I am sorry if you get this wrong.

Answer:

a)x−2=10

b) 2x=24

Two equations have have the solution

x = 12

Question:

How many of these equations have the solution x=12 ?

x−2=10

2x=24

10−x=2

2x−1=25

Step-by-step explanation:

To determine which of the above equations have x= 12, we would solve for x in each of the equations.

a) x−2=10

Collecting like terms

x = 10+2

x = 12

This equation has x= 12 as a solution

b) 2x =24

Divide through by coefficient of x which is 2

2x/2 = 24/2

x = 12

This equation has x= 12 as a solution

c) 10−x=2

Collecting like terms

10-2 - x = 0

8 - x = 0

x = 8

d) 2x−1=25

Collecting like terms

2x = 25+1

2x = 26

Divide through by coefficient of x which is 2

2x/2 = 26/2

x = 13

Note: that (b) x2 = 24 from the question isn't clear enough. I used 2x = 24.

If x2 = 24 means x² = 24

Then x = √24 = √(4×6)

x = 2√6

Then the number of equations that have the solution x = 12 would be 1. That is (a) x−2=10 only

Answer:

1/2x + 12 >10

Step-by-step explanation:

Answer:

In the case of a Type I error, the null hypothesis would be wrongly rejected and the school district will conclude that the new technology is effective when it is not.

They will start to pay for the software when in fact it does not improve Algebra 1 skills.

Step-by-step explanation:

A Type I error happens when a true null hypothesis is rejected.

The probability of a Type I error is equal to the significance level, as it is the probabilty of getting an sample result with low probability but only due to chance, as the null hypothesis is in fact true.

In this scenario, the null hypothesis would represent the claim that the new technology does not make significant improvement.

In the case of a Type I error, this null hypothesis would be wrongly rejected and the school district will conclude that the new technology is effective when it is not.

They will start to pay for the software when in fact it does not improve Algebra 1 skills.

Answer:

0

Step-by-step explanation:

The lines of symmetry of a parallelogram must either be a diagonal of the parallelogram or must be bisectors of opposite sides. There is no way to draw such lines through a general parallelogram and have it produce mirror images on either side of the line. Thus, it has no lines of symmetry.

Answer:

2.88

Step-by-step explanation:

Data provided in the question

[tex]\sigma[/tex] = Population standard deviation = 7 miles per hour

Random sample = n = 32 vehicles

Sample mean = [tex]\bar X[/tex] = 64 miles per hour

98% confidence level

Now based on the above information, the alpha is

= 1 - confidence level

= 1 - 0.98

= 0.02

For [tex]\alpha_1_2[/tex] = 0.01

[tex]Z \alpha_1_2[/tex] = 2.326

Now the margin of error is

[tex]= Z \alpha_1_2 \times \frac{\sigma}{\sqrt{n}}[/tex]

[tex]= 2.326 \times \frac{7}{\sqrt{32}}[/tex]

= 2.88

hence, the margin of error is 2.88

Answer:

2.879 (rounded 3 decimal places)

Step-by-step explanation: