Answer: CD and FH
Step-by-step explanation:
Skew lines are lines that have NO intersections and are also not parallel, all the other ones are either parallel or have intersections. This one does not. Hope this helps!
Answer:
CD and FH
Step-by-step explanation:
I did it and this was the answer
A company plan to manufacture closed rectangular boxes that have a volume of 8m3
. If the
material for the top and bottom costs twice as much as the material for the sides. Find the
dimensions that will minimize the cost.
Answer:
Base Side Length =1.59m
Height = 3.16 m
Step-by-step explanation:
Volume of the box = [tex]8$ m^3[/tex]
Let the base dimensions = x and y
Let the height of the box =h
However, for any optimal configuration, Width = Length as varying the length and width to be other than equal reduces the volume for the same total(w+l)
Volume, V=xyh=8
Since x=y
[tex]h=\dfrac{8}{x^2}[/tex]
Surface Area of the box
[tex]= 2(x^2+xh+xh)\\=2x^2+4xh[/tex]
The material for the top and bottom costs twice as much as the material for the sides.
Let the cost of the sides =$1 per square meter
Cost of the material for the sides = 4xh
Cost of the material for the top and bottom = [tex]=2*2x^2=4x^2[/tex]
Therefore:
Total Cost, [tex]C= 4xh+4x^2[/tex]
Substitution of [tex]h=\frac{8}{x^2}[/tex] into C
[tex]C= 4x(\frac{8}{x^2})+4x^2\\=\frac{32}{x}+4x^2\\C(x)=\dfrac{4x^3+32}{x}[/tex]
To minimize C(x), we find its derivative and solve for the critical points.
[tex]C'(x)=\dfrac{8x^3-32}{x^2}\\$Setting C'(x) to zero\\8x^3-32=0\\8x^3=32\\x^3=4\\x=\sqrt[3]{4}\\ x=1.59$ m[/tex]
To verify if it is a minimum, we use the second derivative test
[tex]C''(x)=8+\frac{64}{x^3}\\C''(1.59)=23.92[/tex]
Since C''(x) is greater than zero, it is a minimum point.
Recall:
[tex]h=\frac{8}{x^2}\\h=\frac{8}{1.59^2}=3.16$ m[/tex]
Therefore, the dimensions that minimizes the cost are:
Base Side Lengths of 1.59m; and
Height of 3.16 m
One driver drives 25 mph faster than another driver does. They start at the same time and after a certain amount of time, one driver has driven 90 miles, and the other driver has driven 165 miles. What are the speeds of the two drivers?
Answer:
speed of slower driver 30 mph
speed of faster driver = 55 mph
Step-by-step explanation:
let the speed of slower driver b x mph
given
One driver drives 25 mph faster than another driver does
Speed of faster driver = (x+25) mph
we know time = speed / distance
also in same time faster will travel more distance than the slower one.
thus
driver with speed (x+25) mph would have traveled 165 miles
driver with speed x mph would have traveled 90 miles
time for driver with speed (x+25) mph = 165/(x+25)
time for driver with speed x mph = 90/x
Given that
They start at the same time and after a certain amount of time, one driver has driven 90 miles, and the other driver has driven 165 miles.
\time for driver with speed (x+25) mph =time for driver with speed x mph
165/(x+25) = 90/x
165x = 90(x+25)
=> 165x = 90x + 2250
=> 165x -90x = 2250
=> 75x = 2250
=> x = 2250/75= 30
Thus, speed of slower driver 30 mph
speed of faster driver = 30+25 = 55 mph
Please help me with this problem thank you✨
Answer:
x ≈ 8.37819064728
Step-by-step explanation:
Maybe you want to solve for x.
[tex]\dfrac{x-4}{x-3}=\dfrac{2x^2-6}{x^2+2x-3}-\dfrac{x-1}{x+1}=\dfrac{2(x^2-3)}{(x-1)(x+3)}-\dfrac{x-1}{x+1}\\\\\dfrac{x-4}{x-3}=\dfrac{2(x^2-3)(x+1)}{(x-1)(x+3)(x+1)}-\dfrac{(x-1)(x-1)(x+3)}{(x+1)(x-1)(x+3)}\\\\\dfrac{x-4}{x-3}=\dfrac{(2x^3+2x^2-6x-6)-(x^3+x^2-5x+3)}{(x^2-1)(x+3)}\\\\\dfrac{(x^2-1)(x+3)(x-4)}{(x^2-1)(x+3)(x-3)}=\dfrac{(x^3+x^2-x-9)(x-3)}{(x^2-1)(x+3)(x-3)}\\\\\dfrac{x^4-x^3-13x^2+x+12}{(x^2-1)(x^2-9)}=\dfrac{x^4-2x^3-4x^2-6x+27}{(x^2-1)(x^2-9)}\\\\\dfrac{x^3-9x^2+7x-15}{(x^2-1)(x^2-9)}=0[/tex]
A graphing calculator shows the numerator cubic to have one real irrational zero near x ≈ 8.37819064728.
How many ways can you order your favorite 3 different desserts from a menu of 10 desserts?
Answer:
Only 1 because you can only have 3 favourite desserts.
Answer:
Only 1 desert :)
Step-by-step explanation:
g True or False: A sample of size 25 provides a sample variance of 400. The standard error in this case, equal to 4, is best described as the estimate of the standard deviation of means calculated from sample of size 25.
Answer:
True.
Step-by-step explanation:
If we have for a sample of size n=25 a sample variance of 400, the standard error can be written as:
[tex]\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{\sqrt{400}}{\sqrt{25}}=\dfrac{20}{5}=4[/tex]
This way of calculating the standard error is the same used for estimating the standard deviation of the sample means for samples of size n=25.
What is the numerator of the simplified sum?
StartFraction x Over x squared + 3 x + 2 EndFraction + StartFraction 3 Over x + 1 EndFraction
Answer:
4x + 6
Step-by-step explanation:
[tex] \frac{x}{x² + 3x + 2} + \frac{3}{x + 1} [/tex]
To determine what the numerator would be, after simplifying both fractions, take the following steps:
Step 1: Factorise the denominator of the first fraction, x² + 3x + 2.
Thus,
x² + 2x + x + 2
(x² + 2x) + (x + 2)
x(x + 2) +1(x + 2)
(x + 1)(x + 2)
We would now have the following as our new fractions to add together and simplify:
[tex] \frac{x}{(x + 1)(x + 2)} + \frac{3}{x + 1} [/tex]
Step 2: find the highest common factor of the denominator of both fractions.
Highest common factor of (x + 1)(x + 2) and (x + 1) = (x + 1)(x + 2)
Step 3: To add both fractions, divide the highest common factor gotten in step 2 by each denominator, and then multiply the result by the numerator of each fraction.
Thus,
[tex] \frac{x}{(x + 1)(x + 2)} + \frac{3}{x + 1} [/tex]
[tex] \frac{x + 3(x + 2)}{(x + 1)(x + 2)} [/tex]
[tex] \frac{x + 3x + 6)}{(x + 1)(x + 2)} [/tex]
[tex] \frac{4x + 6)}{(x + 1)(x + 2)} [/tex]
Therefore, the numerator of the simplified form sum of both fractions = 4x + 6
Answer:
C - 4x+6
Explanation:
Edg2020
Help???????????????????????????????????
Answer:
2Explanation:
F(2) means, value of function at x=2.
Here,you can see from the graph,from 0 to 4, it's a straight line and value of y is 2.
Hope this helps...
Good luck on your assignment....
Find the x- and y-intercepts of the function f(x) = log(2x + 1) − 1.
The x-intercept of the function f(x) = log(2x + 1) − 1 is
. Its y-intercept is
.
Answer:
The y-intercept is -1
The x-intercept is 4.5
Step-by-step explanation:
We have the following equation:
f(x) = log(2x+1) - 1
The y intercept is the value of f(x) when x is equal to 0, so replacing x by 0 and solving for f(x), we get:
f(0) = log(2*0 + 1 ) -1
f(0) = log(1) - 1
f(0) = 0 - 1 = -1
Additionally, the x-intercept is the value of x when f(x) is equal to 0. So, replacing f(x) by 0 and solving for x, we get:
[tex]0 = log(2x + 1) - 1\\1 = log(2x + 1)\\10^1=10^{log(2x + 1)}\\10 = 2x + 1\\10 - 1 = 2x\\4.5 = x[/tex]
Simplify -4 • -4 • -4
Answer: -64
Step-by-step explanation: Since we know that -4 x -4 is a positive, it equals 16, then a positive plus a negative equals a negative, so 16 x -4 equals -64
Answer:
-64
Step-by-step explanation:
-4 • -4 • -4
-4*-4 = 16
16*-4
-64
A genetic experiment with peas resulted in one sample of offspring that consisted of 435 green peas and 163 yellow peas.Given that the percentage of offspring yellow peas is not 25%, do the results contradict expectations
Answer:
a
The estimate for the percentage of yellow peas lie within the confidence interval 23.66% and 30.83 %
b
Since the expected value for the estimate of the yellow peas lies between the confidence interval it means that the given estimate of yellow peas does not contradict the expectation
Step-by-step explanation:
From the question we are told that
The number of green peas is [tex]g = 453[/tex]
The number of yellow peas is [tex]y = 163[/tex]
The sample size is [tex]n = y + g = 435 + 163 = 598[/tex]
The sample proportion of the yellow peas is [tex]\r p_y = \frac{y}{n}[/tex]
substituting values
[tex]\r p_y = \frac{163}{598}[/tex]
[tex]\r p_y = 0.2726[/tex]
Given that the confidence level is [tex]c = 95[/tex]%
The level of significance is [tex]\alpha = 100 - 95 = 5[/tex]%
The critical values at this level of significance is obtained from the table of critical values as
[tex]t_{\alpha } = 1.960[/tex]
Now the confidence interval is mathematically evaluated as
[tex]k = \r p _y \pm t_{\alpha } \sqrt{\frac{\r p (1 - \r p) }{n} }[/tex]
substituting values
[tex]k =0.2726 \pm 1.96 \sqrt{\frac{0.2726 (1 - 0.2726) }{598} }[/tex]
[tex]k =0.2726 \pm 0.036[/tex]
So the 95% confidence interval is
k = ( 0.2366, 0.3083)
This mean that the estimate of the yellow peas(25%) lies between
23.66% and 30.83 %
Given that the expected value for the estimate of the yellow peas lies between the confidence interval it means that the given estimate of yellow peas does not contradict the expectation
At a high school, 9th and 10th graders were asked whether they would prefer
robotics or art as an elective. The results are shown in the relative frequency
table.
To the nearest percent, what percentage of 10th graders surveyed preferred robotics?
Using the percentage concept, it is found that 51% of 10th graders surveyed preferred robotics, hence option B is correct.
What is a percentage?The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:
[tex]P = \frac{a}{b} \times 100\%[/tex]
In this problem, we have that 33% out of 65% of the students are 7th graders who preferred robotics, hence the percentage is given by:
[tex]P = \frac{33}{65} \times 100\% = 51%[/tex]
Which means that option B is correct.
More can be learned about percentages at https://brainly.com/question/14398287
#SPJ1
Answer:
It's A. 61% The dude above me is wrong.
Step-by-step explanation:
I just took the test
Which of the following represents the set of possible rational roots for the
polynomial shown below?
2^2+ 5^2 – 8x– 10 = 0
if a to the power x by y is equal to 1 then the value of x is
Answer:
a^x/y=1 x: 0
Step-by-step explanation: w.k.t, a^0=1( any variable raised to 0 is 1)
so, here the exponent is x/y which should have been 0 so that answer was 1.
Will mark as brainliess and thanks for awnsering this simple question
Answer:
x=-2
Step-by-step explanation:
2 times -2=-4+3=-1
Make a matrix A whose action is described as follows: The hit by A rotates everything Pi/4 counterclockwise radians, then stretches by a factor of 1.8 along the x-axis and a factor of 0.7 along the y-axis and then rotates the result by Pi/3 clockwise radians.
Answer:
The required matrix is[tex]A = \left[\begin{array}{ccc}1.07&-0.21\\-0.86&1.35\end{array}\right][/tex]
Step-by-step explanation:
Matrix of rotation:
[tex]P = \left[\begin{array}{ccc}cos\pi/4&-sin\pi/4\\sin\pi/4&cos\pi/4\end{array}\right][/tex]
[tex]P = \left[\begin{array}{ccc}1/\sqrt{2} &-1/\sqrt{2} \\1/\sqrt{2} &1/\sqrt{2}\end{array}\right][/tex]
x' + iy' = (x + iy)(cosθ + isinθ)
x' = x cosθ - ysinθ
y' = x sinθ + ycosθ
In matrix form:
[tex]\left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}cos\theta&-sin\theta\\sin \theta&cos\theta\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right][/tex]
The matrix stretches by 1.8 on the x axis and 0.7 on the y axis
i.e. x' = 1.8x
y' = 0.7y
[tex]\left[\begin{array}{ccc}x'\\y'\end{array}\right] = \left[\begin{array}{ccc}1.8&0\\0&0.7\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right][/tex]
[tex]Q = \left[\begin{array}{ccc}1.8&0\\0&0.7\end{array}\right][/tex]
According to the question, the result is rotated by pi/3 clockwise radians
[tex]R = \left[\begin{array}{ccc}cos(-\pi/3)& -sin(-\pi/3)\\-sin(\pi/3)&cos(\pi/3)\end{array}\right][/tex]
[tex]R = \left[\begin{array}{ccc}1/2&\sqrt{3}/2 \\-\sqrt{3}/2 &1/2\end{array}\right][/tex]
To get the matrix A, we would multiply matrices R, Q and P together.
[tex]A = RQP = \left[\begin{array}{ccc}1/2&\sqrt{3}/2 \\-\sqrt{3}/2 &1/2\end{array}\right] \left[\begin{array}{ccc}1.8&0\\0&0.7\end{array}\right] \left[\begin{array}{ccc}1/\sqrt{2} &-1/\sqrt{2} \\1/\sqrt{2} &1/\sqrt{2}\end{array}\right][/tex]
[tex]A = \left[\begin{array}{ccc}1.07&-0.21\\-0.86&1.35\end{array}\right][/tex]
6.1.3
What requirements are necessary for a normal probability distribution to be a standard normal probability distribution?
Answer:
μ = 0σ = 1Step-by-step explanation:
A standard normal probability distribution is a normal distribution that has a mean of zero and a standard deviation of 1.
pleaseeeeeeeeeeeeee helpppppp meeeeeeeeee
Answer:
3 is the answer
Step-by-step explanation:
They are 8 blocks the ones shaded is the denominator and the amount un-shaded are the numerator.
The polynomial-7.5x^2 + 103 + 2142 models the yearly number of visitors (in thousands) x years after 2007 to a park. Use this polynomial to estimate the number of visitors to the park in 2021.
Answer:
In that year approximately 2114 thousand people visited the park.
Step-by-step explanation:
Since the expression [tex]y(x) = -7.5*x^2 + 103*x + 2142[/tex] models the number of visitors in the park, where x represents the number of years after 2007 and 2021 is 14 years after that, then we need to find "y" for that as shown below.
[tex]y(14) = -7.5*(14)^2 + 103*14 + 2142\\y(14) = -7.5*196 + 1442 + 2142\\y(14) = -1470 + 3584\\y(14) = 2114[/tex]
In that year approximately 2114 thousand people visited the park.
Combine these radicals.
3 square root 2 -5 square root 2
Answer:
-2√2.
Step-by-step explanation:
Treat the radical as if it were a variable.
3x - 5x = -2x
3√2 - 5√2 = -2√2.
Answer:
The guy above me is right, it is A
Step-by-step explanation:
I got that answer right on the Quiz... In total I got an 80% But this was one of the right answers.
What is 6 1/2 - 2 2/3 =
Answer
3 5/6 or 3.83
Step-by-step explanation:
A team of four boys and five girls is to be chosen from a group of six boys and eight girls. How many different teams are possible?
Answer:
There are a total of 840 possible different teams
Step-by-step explanation:
Given
Number of boys = 6
Number of girls = 8
Required
How many ways can 4 boys and 5 girls be chosen
The keyword in the question is chosen;
This implies that, we're dealing with combination
And since there's no condition attached to the selection;
The boys can be chosen in [tex]^6C_4[/tex] ways
The girls can be chosen in [tex]^8C_5[/tex] ways
Hence;
[tex]Total\ Selection = ^6C_4 * ^8C_5[/tex]
Using the combination formula;
[tex]^nCr = \frac{n!}{(n-r)!r!}[/tex]
The expression becomes
[tex]Total\ Selection = \frac{6!}{(6-4)!4!} * \frac{8!}{(8-5)!5!}[/tex]
[tex]Total\ Selection = \frac{6!}{2!4!} * \frac{8!}{3!5!}[/tex]
[tex]Total\ Selection = \frac{6 * 5* 4!}{2!4!} * \frac{8 * 7 * 6 * 5!}{3!5!}[/tex]
[tex]Total\ Selection = \frac{6 * 5}{2!} * \frac{8 * 7 * 6}{3!}[/tex]
[tex]Total\ Selection = \frac{6 * 5}{2*1} * \frac{8 * 7 * 6}{3*2*1}[/tex]
[tex]Total\ Selection = \frac{30}{2} * \frac{336}{6}[/tex]
[tex]Total\ Selection =15 * 56[/tex]
[tex]Total\ Selection =840[/tex]
Hence, there are a total of 840 possible different teams
There are 9 numbers written, beginning with: 8, 5, 4, 9, 1, ... Finish the sequence.
Answer:
14 -50 -29 -541
Step-by-step explanation:
8-3=5-1=4+5=9-8=1+13=14-64=-50+21=-29-512=-541
i got this by looking up sequence pattern finder in google and clicking on the second option then inserting the numbers you gave hope this helps
A production line operation is designed to fill cartons with laundry detergent to a mean weight of ounces. A sample of cartons is periodically selected and weighed to determine whether underfilling or overfilling is occurring. If the sample data lead to a conclusion of underfilling or overfilling, the production line will be shut down and adjusted to obtain proper filling.a. Formulate the null and alternative hypotheses that will help in deciding whether to shut down and adjust the production line.: - Select your answer -: - Select your answer -b. Comment on the conclusion and the decision when cannot be rejected. Is there evidence that the production line is not operating properly
Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
A production line operation is designed to fill cartons with laundry detergent to a mean weight of 32 ounces. A sample of cartons is periodically selected and weighed to determine whether under filling or overfilling is occurring. If the sample data lead to a conclusion of under filling or overfilling, the production line will be shut down and adjusted to obtain proper filling.
A. Formulate the null and alternative hypotheses that will help in deciding whether to shut down and adjust the production line.
B. Comment on the conclusion and the decision when H0 cannot be rejected.
C. Comment on the conclusion and the decision when H0 can be rejected.
Solution:
A) We would set up the hypothesis. Under filling or over filling means two ways. Thus, it is a two tailed test
For null hypothesis,
H0: μ = 32
For alternative hypothesis,
H1: μ ≠ 32
B) if H0 cannot be rejected, it means that there was insufficient evidence to reject it. Thus, it would be concluded that the production line operation filled the cartons with laundry detergent to a mean weight of 32 ounces.
C) There was sufficient evidence to reject the null hypothesis. Thus, it can be concluded that there was under filling or over filling.
pls help me on this question
Answer:
h < 2
Step-by-step explanation:
Step 1: Distribute
10h + 40 < 60
Step 2: Subtract 40 on both sides
10h < 20
Step 3: Divide both sides by 10
h < 2
A triangle in the xy-coordinate plane is formed by the points (3, 5), (− 1, 5) , and (3,− 6) . What is the perimeter and area of this triangle?
Answer:
Therefore, the perimeter of the triangle is 26.7 units and the area is 22 square units.
Step-by-step explanation:
Given the vertices of a triangle as: A(3, 5), B(− 1, 5), and C(3,− 6)
Since A and B are on the same y-coordinate, we have that:
AB = 3-(-1)=4 Units
Since A and C are on the same x-coordinate, we have that:
AC=5-(-6)=11 Units
Next, we determine the distance BC using the distance formula.
Given: B(− 1, 5), and C(3,− 6)
[tex]BC=\sqrt{(3-(-1))^2+(-6-5)^2}\\= \sqrt{(4)^2+(-11)^2}=\sqrt{137}$ Units[/tex]
Therefore:
Perimeter of the Triangle
[tex]= 4+11+\sqrt{137}\\ =15+\sqrt{137}$ Units\\=26.7 Units[/tex]
On plotting the triangle, it forms a right triangle such that the:
Base = 4 Units
Height = 11 Units
Therefore:
Area of a triangle [tex]=\dfrac12 *Base*Height[/tex]
Therefore:
Area of the Triangle = 0.5 X 4 X 11
=22 Square Units.
Therefore, the perimeter of the triangle is 26.7 units and the area is 22 square units.
BIG Corporation advertises that its light bulbs have a mean lifetime, μ, of 2800 hours. Suppose that we have reason to doubt this claim and decide to do a statistical test of the claim. We choose a random sample of light bulbs manufactured by BIG and find that the mean lifetime for this sample is 2620 hours and that the sample standard deviation of the lifetimes is 650 hours.
In the context of this test, what is a Type II error?
A type II error is (rejecting/failing to reject) the hypothesis that μ is (less than/less than or equal to/greater than/greater than or equal to/not equal to/equal to) ____ when in fact, μ is (less than/less than or equal to/greater than/greater than or equal to/not equal to/equal to) ______.
Answer:
A type II error is failing to reject the hypothesis that μ is equal to 2800 when in fact, μ is less than 2800.
Step-by-step explanation:
A Type II error happens when a false null hypothesis is failed to be rejected.
The outcome (the sample) probability is still above the level of significance, so it is consider that the result can be due to chance (given that the null hypothesis is true) and there is no enough evidence to claim that the null hypothesis is false.
In this contest, a Type II error would be not rejecting the hypothesis that the mean lifetime of the light bulbs is 2800 hours, when in fact this is false: the mean lifetime is significantly lower than 2800 hours.
Which of the following are possible values for x?
Answer:
The answer is only c) x=5
Step-by-step explanation:
|x| means that this is an absolute value. If the number is a negative, removing the value bars will make it a positive again. Positives stay positives. So the only answer greater than value of 2 is 5.
Give the coordinates of two points that lie on the hyperbola y=2/x
Answer:
(1, 2), (-2, -1)
Step-by-step explanation:
We can choose x = 1 and find y:
y = 2/1 = 2
(x, y) = (1, 2)
We can choose x = -2 and find y:
y = 2/(-2) = -1
(x, y) = (-2, -1)
Write a division problem with these types of numbers: • The dividend and divisor are both mixed numbers. • The quotient is a whole number. Explain how to solve your division problem. Make sure to describe each step. (comments that do not meet the criteria will be reported)
Answer:
1 2/1 ÷1 1/2 = 2
Step-by-step explanation:
dividend ÷ divisor = quotient
1 2/1 ÷1 1/2 = 2
In order to solve this you need to make the mixed numbers into an improper fraction:
3/1 ÷ 3/2
use the KFC method (Keep Change Flip)
When you got to fractions you wanna divide flip the right and multiply
3/1 (2/3)= 2
A chemist needs 120 milliliters of a 33% solution but has only 13% and 73% solutions available. Find how many milliliters of each that should be mixed to get the desired solution.
Answer:
40 ml of 73% solution required and 80 ml of 13% solution
Step-by-step explanation:
Let x = amt of 58% solution
It say's the amt of the resulting mixture is to be 120 ml, therefore
(120-x) = amt of 13% solution
A typical mixture equation
0.73x + 0.13(120-x) = 0.33(120)
0.73x + 15.6 - 0.13x = 39.6
0.6x=24
x=40 ml of 73% solution required
and
120 - 40 =80 ml of 13% solution