Chang wants to build a circuit that will light up the bulb from a flashlight. Which component could Chang leave out and still light up the bulb? the switch the battery the wire the light bulb
We could choose to leave out the switch and simply join the wires together and the bulb will still light up.
What is a circuit?A circuit is defined as pathway that has been designed for the flow of current. Now we know that a circuit must have a battery, connecting wires and the bulb itself.
However, we could choose to leave out the switch and simply join the wires together and the bulb will still light up.
Learn more about circuit: https://brainly.com/question/365923
A car moving with a speed of 20 m/s
applies brakes. What is the acceleration
of the car?
Explanation:
[tex]speed : U = 20 \: m {s}^{ - 1} \\ {V}^{2} = {U}^{2} + 2aS \\ 0 = {20}^{2} + (2 \times a \times S) \\ a = \frac{200}{S} \: m {s}^{ - 1} [/tex]
Please help ..........................
Answer:
it's 10 you can see it goes by 2 and the others fo by 1 pretty simple
The distance covered by a car moving with a speed of 36 km/h in 20 minutes is
Answer:
D=12000m
Explanation:
Distance
Speed=distance/time
Where, speed is given in m/s
Time is given in s
Distance is given in m
Data
S=36km/h
T=20minutes
D=?
D=S*T
D=(36*1000m)/3600s*(20*60s)
D=36000m/3600s*1200s
D=10m/s*1200s
D=12000m
If a running system has a total change in the heat of 315 joules, and it is running at a temperature of 350 K, what is the entropy? Α.1.54 joules/kelvin B.0.847 joules/kelvin C.1.22 joules/kelvin D. 0.900 joules/kelvin E. 0.762 joules/kelvin
Answer:
0.900
Explanation:
joules" (and any subsequent words) was ignored because we limit queries to 32 words.
Answer:
See image
Explanation:
Plato
The _____is a measure of the number of waves that pass a point in a given amount of time
Can some one help me with this question its hard :( down below ill give brainliest
Which of the following describes the moon’s motion around Earth?
A) The moon is in free fall around the Earth.
B)The acceleration of the moon is toward the center of Earth.
C)The moon is falling toward the center of Earth and away from the straight line path it would travel without gravity.
D)All are correct.
Answer:
i think B?
Explanation:
how can a sound of a different note be produced in a guitar without changing the length of wire?
Answer:
how tightly strung the wire is
-- Make the string tighter or looser.
-- Keep the same length, but make the string thicker or thinner.
-- Touch the string at a point exactly 1/2, 1/3, 1/4, or 1/5 of its length from one end.
1.) A ball is thrown horizontally from the top of a building. What is the vertical velocity of the ball after 1 second?
A. 0 m/s
B. 9.8 m/s
C. 4.9 m/s
D. 19.6 m/s
2.) This is a required question
What is the horizontal acceleration of a projectile?
A. 0 m/s2
B. 8.9 m/s2
C. 4.9 m/s2
D. 9.8 m/s2
3.) If air resistance is neglected, at what angle a projectile must be projected to attain the maximum range?
A. 40
B. 75
C. 45
D. 90
4.) Neglecting air resistance, the range of a projectile projected at an angle of 20 degrees is the same as that of _______ if they were released with the same velocity.
A. 50
B. 70
C. 60
D. 80
5.) What do you call the motion of an object with constant acceleration?
A. circular motion
B. uniform motion
C. constant motion
D. uniformly accelerated motion
CAN SOMEONE PLEASE HELP ASAP. THANK U
Q.1 - V = u + at
u = 0, a = g = 9.8, t = 1
V = 0+9.8*1 = 9.8 m/s
Q 2- In horizontal position the velocity remains same hence a= dv/t, since change in velocity is zero the acceleration also equal to zero
Q.3- After neglecting the air resistance at 45° angle the maximum range is obtained.
let's prove, consider the range have maximum angle at θ, now range is given by
R = u²Sin2θ/g where sin2θ can we written as 2sinθ.cosθ.
Now the range value is directly proportional to the product of sin & cos of firing angle & this maximum value is obtained at 45°
Q.4 The range of two angle will be same if and only if they give 90° on addition.
20+x = 90,
x = 90-20 = 70°
Q.5 The motion with constant acceleration is known as uniformly accelerated motion.
Thanks for joining brainly community!
Answer:
B. 9.8 m/sA. 0 m/s²C. 45°B. 70°D. uniformly accelerated motionExplanation:
1.
u=0m/s
v=?
a=9.8m/s²
t=1sec
now
we have
v=u+at
v=0+9.8*1
v=9.8m/s
3.
angle is measured in sin and cos angle where maximum angle's value is gained by 45°
4.
we have
range
R=[tex]\frac{u²sin2\theta}{g}[/tex]
For
angle =20°
R1=[tex]\frac{u²sin2*20}{g}[/tex].......[1]
another angle be [tex]\theta[/tex]
R2=[tex]\frac{u²sin2\theta}{g}[/tex].......[2]
since R1=R2
By comparing we get
Sin40=Sin([tex]2\theta[/tex])
Sin(180-40)=Sin([tex]2\theta[/tex])
we
140=[tex]2\theta[/tex]
[tex]\theta[/tex]=70°
What information is represented by the slope of a graph of displacement versus time (displacement-time graph)?
Determine the mass of fuel required for the expected energy consumption in the United States for the next 10 years:
Provide the energy use per person per year in the United States = 3.5 × 1011 joules.
Base your calculations on a current population of 310,000,000.
Answer:
(This will depend on the type of fuel, I will assume that the fuel is petrol)
First, let's find the expected energy consumption in the US for the next 10 years.
We know that in one year, a person consumes 3.5*10^11 joules.
There are 310,000,00 people on the US
Then the total consumption in one year is:
310,000,000*3.5*10^11 joules = 1.085*10^20 J
In 10 years the consumption is 10 times the consumption of a single year, then the expected energy consumption in the US for the next 10 years is:
10*1.085*10^20 J = 1.085*10^21 J
Now let's find the mass of fuel required.
We know that a liter of petrol has 31,536,000 joules of energy,
And a liter of petrol weights 0.75 kg
To find the number of liters of petrol that we need, we need to find the quotient between the expected energy consumption in the next 10 years and the energy of a single liter of petrol, this is:
N = (1.085*10^20 J)/(31,536,000 j) = 3.44*10^13
We will need 3.44*10^13 liters of petrol.
And the total mass of petrol will be:
M = 3.44*10^13*0.75 kg = 2.58*10^13 kg of fuel.
is there a "real" simple machine that has an efficiency of 100%?
Answer:
NO
Explanation:
No, a machine cannot be 100% efficient. This is due to the movement of the moving parts siding against each other and causing friction. This friction is the one that creates heat and causes wear and tear between moving ports f the machine hence making the machine to decrease in efficiency with time
What charge does an object have if it has an excess of electrons?
Answer:
negative charge
Explanation:
On an atomic scale, those are called "ions", and negatively charged ions are called anions.
What process is represented by this redox equation ? 6H 2 O+6CO 2 C 6 H 12 O 6 +6O 2
Answer:
C. Photosynthesis
Explanation:
Photosynthesis is a process by which plants and photosynthetic bacteria obtain their food in presence of sunlight from water and carbon dioxide. They produce glucose as the food and oxygen is emitted as the byproduct. The equation for photosynthesis is - 6H2O+6CO2 → C6H12O6 + 6O2
Thus, the correct answer is 'C.Photosynthesis.'
According to the law of conservation of momentum, in a(n) _______ system, the initial total momentum before a collision equals the final total momentum.
Answer:
rhastuutse5r says he n and happiness of
Explanation:
UKDIAMOND is a great place to live and live and live in the world best friend tum jio hjaro and happiness of the day and the day of the day of the day of the day of the day of the day of 2nd century and the day of the day of
Answer:
Isolated
Explanation:
According to the law of conservation of momentum, in a(n) isolated system, the initial total momentum before a collision equals the final total momentum. I just did it on A p e x.
over due by alot please help
Answer:
i would say the third one
Explanation:
may i be brainliest?
Question 7 of 10
What is kinetic friction?
A. Friction that acts when an object is not moving
B. Friction that opposes air resistance
C. Friction that exerts no force
D. Friction that acts on a sliding object
SUBMIT
Answer: Friction that acts on a sliding object
Explanation:
help please, it’s on my physics paper!
Answer:
15.4
Explanation:
770x14% = 107.8
rearrange f =kx to get k (constant)
k = f/x
x is the distance stretched , so 42 - 35 =7
so 107.8/7 =15.4
can someone double check
Answer:
k = 44000 N/m is the answer.
Explanation:
Gravitational Potential Energy = 770J
Elastic Potential Energy = 14% of 770J
= 14/100 × 770
= 107.8J
Extension (x) = 42 - 35 = 7cm = 7 × 10⁻²m
To find the spring constant (k)
Elastic Potential Energy Formula:
[tex]U = \frac{1}{2}kx^2[/tex]
107.8 = 1/2 × k × (7 × 10⁻²)²
215.6 = 0.0049 × k
k = 215.6/0.0049
k = 44000 N/m
When the net force acts at right angles to an object’s motion, what does it do to the object’s motion?
a. it changes the object’s speed
b. it changes the object’s direction
c. it changes both the speed and direction of the object’s motion.
Answer:
B. It changes the objects direction
a microwave with a frequency of 5.0 x 10^10 hertz has a period of
Answer:
A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.
Explanation:
Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass a reference point. The period (T) is simply the inverse of the frequency (f):
[tex]T=\frac{1}{f}[/tex]
In this case, f=5*10¹⁰ Hz. So, replacing in the definition of period T:
[tex]T=\frac{1}{5*10^{10} Hz }[/tex]
Solving:
T= 2*10⁻¹¹ seconds
A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.
A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.
What is fequency?The fequency is defined as the number of cycles achieved by the any wave it is expressed in hertz.
Frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).
The period is the time that elapses between the emission of two consecutive waves. In other words, it is the time it takes for a complete wave to pass a reference point. The period (T) is simply the inverse of the frequency (f):
[tex]T=\dfrac{1}{f}[/tex]
In this case, f=5*10¹⁰ Hz. So, replacing in the definition of period T:
[tex]T=\dfrac{1}{5\times 10^{10}}=2\times 10^{-11}\ Sec[/tex]
A microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.
Thus a microwave with a frequency of 5*10¹⁰ hertz has a period of 2*10⁻¹¹ seconds.
To know more about Frequency follow
https://brainly.com/question/25699025
What is the frequency of a wave with a speed of 45 m/s and
a wavelength of 2.5 m?
Answer:
f=s/w
f=45/2.5=18
s means speed which is in m/s while w is wavelength which is Lamda
Use the image above to answer the following for 2 points each:
1. Identify a point in the diagram where a divergent boundary is occurring and explain how it is interacting with the rock cycle.
2. Identify a point in the diagram where a divergent boundary is occurring and explain how it is interacting with the rock cycle.
3. Identify a point in the diagram where the rock cycle is occurring without a plate boundary and how it is interacting with the rock cycle.
Answer: the divergent one goes where it looks like there a crack because when you think about divergent it means dividing like seperating.(igneous rock) is where the divegent one goes.
the one that is no plate boundary is sedimentary rock and it occurs by because there is nothing there for it todo there
Explanation:
What is the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m? No links
72 m/s
Explanation:
Given,
Frequency ( f ) = 6 Hz
Wavelength ( λ ) = 12 m
To find : -
Speed ( v ) = ?
Formula : -
v = f x λ
v
= 6 x 12
= 72 m/s
Therefore,
the speed of a wave with a frequency of 6 Hz and a wavelength of 12 m is 72 m/s.
transparent materials allow electromagnetic waves to be while trapping thermal energy
1. transmitted
2. reflected
3. absorbed
Answer:
2. reflected
hope it is helpful to you
I would assume its A. or B.
Answer:
B
Explanation:
remember that you are looking for the value of the graph
to take into account or value a lot: prize, estimate to value your opinion. 2nd: estimate or assign the monetary value of: appraise a necklace. b: qualify or scale in utility, importance or general value: evaluate. value.
c) Explain the following.
Keftles, cooking pans and iron boxes have polished surfaces
Answer:
Polished surfaces reduce heat loss
An object with a mass of 1.5 kg accelerates 10.0 m/s^2? when an unknown force is applied to it. What is the amount of the force?
Answer:
15 N
Explanation:
f=ma
f=1.5*10
f=15 N
Two resistors, R 1 and R 2 , are connected in parallel. R 2 =221.0 ohms, and the equivalent resistance of the combination is 120.7 ohms. What is the value of R 1 ? (Unit = ohm)
Answer:
Explanation:
When resistors are connected in parallel combination, then equivalent resistance is given by,
[tex] \to \quad \bf{ \dfrac{1}{R_1} + \dfrac{1}{R_2} =\dfrac{1}{R_p}}[/tex]
Inserting values,
[tex] \to \quad \bf { \dfrac{1}{R_1} + \dfrac{1}{R_2} =\dfrac{1}{R_p} } \\ \\ \to \quad \bf { \dfrac{1}{R_1} + \dfrac{1}{221} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { \dfrac{221+R_1}{(R_1)(221)} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { \dfrac{221+R_1}{221R_1} =\dfrac{1}{120.7} } \\ \\ \to \quad \bf { 120.7(221+R_1) = 221R_1(1)} \\ \\ \to \quad \bf { 26674.7 + 120.7R_1= 221R_1} \\ \\ \to \quad \bf { 26674.7= 221R_1- 120.7R_1} \\ \\ \to \quad \bf { 26674.7 = 100.3R_1} \\ \\ \to \quad \bf { \dfrac{26674.7 }{100.3} =R_1} \\ \\ \to \quad\underline{\boxed{ \bf { 265.9 \; \Omega=R_1}}} \\ [/tex]
1. A 110.0 g sample of metal is warmed 10.0 °C when 70.0 calories is added. What is the specific heat of this metal?
2. How much heat must be supplied to a 550.0 g aluminum pan to raise the temperature of the pan from 14.0°C to 108.0 °C?
Answer:
1. The specific heat of the meatal is approximately 0.266 J/(g·°C)
2. 46.6334 kJ
Explanation:
1. The given mass of the sample of metal, m = 110.0 g
The temperature change of the metal when heat is added, ΔT = 10.0°C
The amount of head that was added, ΔH = 70.0 Calories = 292.88 Joules
The formula for heat heat capacity of a material is given as follows
Q = m × c × ΔT
Where;
Q = The quantity of heat added = 292.88 Joules
m = The mass of the material = 110.0 g
ΔT = The temperature change = 10.0°C
c = The specific heat capacity of the material
We get;
c = ΔH/(m × ΔT)
Which gives;
c = 292.88 J/(110.0 g × 10.0°C) ≈ 0.266 J/(g·°C)
2. The given mass of aluminum, m = 550.0 g
The initial temperature of the aluminum, T₁ = 14.0°C
The final temperature of the aluminum, T₂ = 108.0°C
The specific heat of aluminum, c = 0.902 J/(g·°C)
We get;
Q = m × c × (T₂ - T₁)
Q = 550.0 g × 0.902 J/(g·°C) × (108.0°C - 14.0°C) = 46,633.4 joules = 46.6334 kJ
The heat that must be supplied to 550.0 g of aluminum pan to raise the temperature of the pan from 14.0°C to 108.0°C, Q = 46.6334 kJ.