Can I have some help please :)

Answer:

Solids expand when they are heated.

Explanation:

It is possible to loosen caps on the screw  top bottles by dipping the cap briefly in hot water due to the fact that whenever a solid is heated, it expands. This means that the size of the solid Screw cap (in this our case) increases as the temperature does.

This increase in size causes it to slide off easily from the mouth of the bottle when a little twisting effort is applied.

Answer:

credits to the real owner of the answer I just found it here

Answer:

When two substances are mixed together, a color change is observed. This observation is not enough evidence that there is a chemical reaction happening because color changes are not indicators of chemical reaction:

Answer:

....

Explanation:

During the "U" part of the turn, the car would follow an approximately circular path, and if it's moving at a constant speed, it would have to accelerate toward the center of the circle in order to change its direction.

Answer:

We kindly invite you to read carefully the explanation and check the image attached below.

Explanation:

According to this problem, the rocket is accelerated uniformly due to thrust during 30 seconds and after that is decelerated due to gravity. The velocity as function of initial velocity, acceleration and time is:

[tex]v_{f} = v_{o}+a\cdot (t-t_{o})[/tex] (1)

Where:

[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.

[tex]v_{f}[/tex] - Final velocity, measured in meters per second.

[tex]a[/tex] - Acceleration, measured in meters per square second.

[tex]t_{o}[/tex] - Initial time, measured in seconds.

[tex]t[/tex] - Final time, measured in seconds.

Now we obtain the kinematic equations for thrust and free fall stages:

Thrust ([tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 30\,\frac{m}{s^{2}}[/tex], [tex]t_{o} = 0\,s[/tex], [tex]0\,s\le t< 30\,s[/tex])

[tex]v = 30\cdot t[/tex] (2)

Free fall ([tex]v_{o} = 900\,\frac{m}{s}[/tex], [tex]a = -9.807\,\frac{m}{s}[/tex], [tex]t_{o} = 30\,s[/tex], [tex]30\,s \le t \le 120\,s[/tex])

[tex]v = 900-9.81\cdot (t-30)[/tex] (3)

Now we created the graph speed-time, which can be seen below.

Answer:

1mph

Explanation:

Answer:

the answer is A. acceleration mom

Explanation:

:)

Answer:

I need points thank you

Answer:

The answer is D

Explanation:

The number of  algebra problems did he have for homework is 15.

Here we assume x represent the number of algebra problems. So,  the number of geometry problems was 27-x and the total working time was ...

 2x +5(27 -x) = 90

 -3x = 90 -135

-3x = -45

x = 15

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sorry

Explanation:

Sorry

Answer:

Difference is given below.

Explanation:

The main difference between beneficial and harmful friction is that beneficial friction is necessary for performing different activities while on the other hand, harmful effect of friction is destroy different parts of products and machines. examples of beneficial friction are walking, holding things, rubbing hands to produce heat, running etc whereas examples of harmful friction are destruction of sole, slipping, tearing of machine's part, Wet roads and Mudslides etc.

Answer:

100 g

Explanation:

Or 0.1 kilograms, just count

If the density of water is 1 g/cm³, the mass of 100cm³ of water should be 100g.

DENSITY:

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Answer:

b

Explanation:

Answer:

5400

Explanation:

i calculated it

Big  brain

Hello!

[tex]\large\boxed{KE = 360 J}[/tex]

Use the equation KE = 1/2mv² to solve for the kinetic energy of the man.

We are given the mass and velocity, so plug these values into the equation:

KE = 1/2(80)(3²)

KE = 1/2(720)

KE = 360 J

Answer:

No

Explanation:

The statement is implying that if you do a certain amount of work, you're entitled to do a certain amount of work. Sometimes, work doesn't entitle you a reward.  

Answer:

yo so if nobody helps ill gladly take the brainliest

Explanation:

Answer:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

Explanation:

Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself.

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A  box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

[tex]v^2-u^2=2as[/tex]

Put u = 0 and a = g

[tex]v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s[/tex]

So, when it hits the ground its velocity is 556.59 m/s.

Explanation:

The velocity of an object can be found by using the formula

[tex]v = \frac{d}{t} \\ [/tex]

d is the distance

t is the time taken

From the question we have

[tex] v = \frac{10}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

[sə′plī ‚vōl·tij] (electricity) The voltage obtained from a power source for operation of a circuit or device.

Explanation:

hope this helps :)

Answer:

When the string of a bow and arrow is pulled from equilibrium, the elastic potential energy in the bow is converted to kinetic energy of the arrow when the string is released.

Kinetic energy of an arrow can be found by using the formula KE=(mv²)/450,240 where m = mass of the arrow in grains and v = velocity of the arrow in fps.

Two factors determine the amount of energy a bow can hold. Its draw weight is the amount of force required to draw the bow. A bow's draw weight increases the farther back you pull the string.

Does a stretched bow and arrow have energy?

An arrow held in a stretched bow also contains this stored energy. Specifically, the bow has elastic potential energy. When the bow is released, the arrow will move. ... When work is done on an object, the work may be converted into either kinetic or potential energy.

Explanation:

Answer:

v = 14.7m/s

Explanation:

When the rock was at the top of cliff it had only Potential Energy and no Kinetic Energy but soon as the rock hit the ground all the Potential Energy converted into Kinetic Energy so by the Law of Conservation of Energy

[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]

because all of that potential energy got converted into kinetic energy so we use the following formula as we need to calculate the velocity (v)

[tex]Potential\ Energy = Kinetic\ Energy\\mgh=\frac{1}{2}mv^2\\\\v^2=\frac{2mgh}{m} \\\\v^2=2gh[/tex]

here we know  [tex]g = 9.8m/s^2[/tex] because the rock was under free fall motion so it had acceleration of 9.8 but we do not the height which is h but we do know the formula:

[tex]Velocity=\frac{Displacement}{Time}[/tex]

the height h is the displacement so we replace height with the following:

[tex]Velocity=\frac{Displacement}{Time}\\\\Displacement=Velocity*Time\\h=vt[/tex]

now, insert h = vt in the above equation

[tex]v^2=2gh\\\\v^2=2g(vt)\\v^2=2vgt\\\\\frac{v^2}{v} =2gt\\\\v=2gt\\v=2(9.8)(0.75)\\v=14.7m/s[/tex]

Answer:

3N

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 3.2 × 3.1

We have the final answer as

Hope this helps you

Answer:

9.92

Hope I helped

Answer:

v₀ = 16.55 m/s

Explanation:

This motion of the ball can be modeled as a projectile motion with following data:

R = Range of Projectile = 27.5 m

θ = Launch Angle = 50°

g = acceleration due to gravity = 9.81 m/s²

v₀ = Initial Speed of Ball = ?

Therefore, using formula for range of projectile, we have:

[tex]R = \frac{v_{0}^2\ Sin2\theta}{g}\\\\v_{0}^2 = \frac{Rg}{Sin2\theta}\\\\v_{0}^2 = \frac{(27.5\ m)(9.81\ m/s^2)}{Sin100^o}\\\\v_{0} = \sqrt{273.93\ m^2/s^2}[/tex]

v₀ = 16.55 m/s

Positive Work.

Negative Work.

Case of zero work done.

Displacement at an angle to the force.

Energy.

Kinetic Energy.

work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement.