Explanation:
Hey there!
Given;
Mass of the Earth (M) = 6.0*10^24kg.
Radius of Earth (R) = 6400km = 6400*1000= 6.4*10^6.
Gravitational constant (G) = 6.67*10^-11Nm^2/kg^2.
Height from surface of Earth (h) = 350km= 3.5*10^5m
Gravity (g) = ?
We have;
[tex]g = \frac{G.M}{ {(R + h)}^{2} } [/tex]
Where "G" is gravitational constant, "M" is mass of earth, "g" is acceleration due to gravity, "h" height from surface of Earth.
Keep all values.
[tex]g = \frac{6.67 \times {10}^{ - 11} \times 6.0 \times {10}^{24} }{ (6.4 \times {10}^{6} + 3.5 \times {10}^{5} )^2} [/tex]
[tex]or \: g = \frac{40.002\times {10}^{13} }{ (6.4\times {10}^{6} + 3.5*10^5)^2} [/tex]
g = 8.7m/s^2
Therefore, gravity from distance 350km above the Earth's surface is 8.7m/s^2.
Hope it helps...
Exit ticket: A lamp is plugged into a 110 Volt electrical outlet. There is a 9 Watt LED bulb in the lamp. a. What is
the current in the bulb? b. What is the resistance of the bulb?
Answer:
(a) 0.081 A (b) 1358.02 ohms
Explanation:
Voltage, V = 110 volt
Power of a LED bulb, P = 9 Watt
(a) Let the current is I. The formula for ower in terms of voltage and power is given by :
P = VI
[tex]I=\dfrac{P}{V}\\\\I=\dfrac{9}{110}\\\\=0.081\ A[/tex]
(b) Let R is the resistance of the bulb. Using Ohm's law as follows :
V = IR
[tex]R=\dfrac{V}{I}\\\\R=\dfrac{110}{0.081}\\\\=1358.02\ \Omega[/tex]
Hence, this is the required solution.
(a) The current in the bulb is 82mA
(b) The resistance of the bulb is 1340 Ω
Given information:
Supply voltage, V = 110V
The power rating of the bulb, P = 9 W
Electrical Power:(a) Current in the bulb:
The electrical power is given by:
P = VI
where V is the voltage, and I is the current
So, I = P/V
I = 9W / 110V = 0.082A
I = 82 mA
(b) Resistance of the bulb:
According to the Ohm's Law:
The relation between voltage (V), current (I), and resistance (R) is given by:
V = IR
110 = 0.082R
R = 1340 Ω
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How much power is required to lift a 2.00-kg object 5.00 meters in 4.50 seconds? (If there is a formula for this please, tell me what it is also it is about pulleys one of the simple machines)
Please help me idk what dis
What is the force needed to move a 300 kg object if you have an acceleration of 8 m/s2?
Answer: mass = 10 kg, acceleration = 3 m/s2.
Explanation: I hope that helped!!
If the astronaut from question #9 collides with a satellite and comes to a complete stop, where did his momentum go? Explain this in terms of conservation of momentum.
Answer:
m v ´- MV = (m + M) v ’
Explanation:
If the astronaut initially has a speed v the satellite has a speed V, we can define a system that is formed by the two bodies, therefore the forces during the collision are internal, so the momentum is conserved
initial instant. Before the crash
p₀ = m v - MV
final instatne. After the crash, we have two cases
1) inelastic shock
m_f = (m + M) v '
p₀ = p_f
m v ´- MV = (m + M) v ’
2) elastic collision with the astronaut's velocity, zero in this case the moment remains
m v - MV = mv ’+ Mv’
also the kinetic energy is conserved
mv'2 + M V2 = mv'2 + m v'2
with these two equations we can find the speed of the cars
Need help solving this question.
Answer:
See the answers below.
Explanation:
to solve this problem we must make a free body diagram, with the forces acting on the metal rod.
i)
The center of gravity of the rod is concentrated in half the distance, that is, from the end of the bar to the center there is 40 [cm]. This can be seen in the attached free body diagram.
We have only two equilibrium equations, a summation of forces on the Y-axis equal to zero, and a summation of moments on any point equal to zero.
For the summation of forces we will take the forces upwards as positive and the negative forces downwards.
ΣF = 0
[tex]-15+T-W=0\\T-W=15[/tex]
Now we perform a sum of moments equal to zero around the point of attachment of the string with the metal bar. Let's take as a positive the moment of the force that rotates the metal bar counterclockwise.
ii) In the free body diagram we can see that the force acts at 18 [cm] of the string.
ΣM = 0
[tex](15*9) - (18*W) = 0\\135 = 18*W\\W = 7.5 [N][/tex]
Finding volume using displacement and calculating density
Answer:
a) 0.1
b) density = mass/volume
= 0.5 /0.1
= 5 kg/[tex]m^{3}[/tex]
Find the mass if the force is 18 n and the acceleration is 2 m/s/s
Answer:
The answer is 9 kgExplanation:
The mass of an object can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{18}{2} \\ [/tex]
We have the final answer as
9 kgHope this helps you
Please help. to find these
Answer:
Velocity ratio & input work
Explanation:
If u input velocity u can work the ratio...;D ;D ;D xD
What is the power of a crane that does 5.60 kJ of work in 2.80 s?
Answer:
I don't understand what is a power cane??
Which of the following groups contain three elements with stable electron configurations?
A. xenon, neon, boron
B. helium, xenon, neon
C. argon, neon, barium
D. lithium, krypton, argon
Answer:
B. helium, xenon, neon
Explanation:
PLEASE HELP IF YOU KNOW THE ANSWER QUICK PLEASE!!!
Answer:
d
Explanation:
Lily can run 100 m in 10s. How fast was her average speed?
Answer:
The answer is 10 m/sExplanation:
The average speed can be found by using the formula
[tex]v = \frac{d}{t} \\ [/tex]
d is the distance
t is the time taken
From the question we have
[tex]v = \frac{100}{10} \\ [/tex]
We have the final answer as
10 m/sHope this helps you
40 POINTS I WILL GIVE TO BRAINLYEST.
PLEASE HELP
Just divide the d/t to get answer: 10.99
Explanation:
Consider again the objects you ranked by distance. Suppose each object emitted a burst of light right now. Rank the objects from left to right based on the amount of time it would take this light to reach Earth, from longest time to shortest time.a. star on far side of Andromeda Galaxyb. star on near side of Andromeda Galaxyc. star on far side of Milky Way Galaxyd. star near center of Milky Way Galaxy1. Orion Nebula2. Alpha Centauri3. Pluto4. The Sun
Answer:
Following are the solution to this question:
Explanation:
That light takes a very long time to hit the planet, and the object is far off the earth. The light of such an item near to the planet takes less time to enter it. The star is 2,5 million light-years from the Planet on the far side of the Andromeda Galaxy. But on the other hand, the moon is 15 crore miles from the earth, so sunlight is quickly reached on the ground as the other thing.
That milky way away from the earth is 66,500 light-years far, that distance between Earth and Orion nebula is 1,344 light-years, with such a distance of 4,367 light-years. The earth is 5.2261 trillion km apart from Pluto.
PLEASE HELP!! ITS URGENT!!!
Answer:
F = 800 [N]
Explanation:
To be able to calculate this problem we must use the principle of momentum before and after the impact of the hammer.
We must summarize that after the impact the hammer does not move, therefore its speed is zero. In this way, we can propose the following equation.
ΣPbefore = ΣPafter
[tex](m_{1}*v_{1}) - F*t = (m_{1}*v_{2})[/tex]
where:
m₁ = mass of the hammer = 0.15 [m/s]
v₁ = velocity of the hammer = 8 [m/s]
F = force [N] (units of Newtons)
t = time = 0.0015 [s]
v₂ = velocity of the hammer after the impact = 0
[tex](0.15*8)-(F*0.0015) = (0.15*0)\\F*0.0015 = 0.15*8\\F = 1.2/(0.0015)\\F = 800 [N][/tex]
Note: The force is taken as negative since it is exerted by the nail on the hammer and this force is directed in the opposite direction to the movement of the hammer.
The yoga term asanas are which of the following?
A.
The yoga breathing method.
B.
The yoga term for mediation.
C.
The yoga term for exercises or poses.
D.
The yoga term for spiritual enlightenment.
Answer:
i guss its A
Explanation:
A soccer ball takes 30 seconds to roll 15 meters. calculate the average speed ot the ball using distance and tome measurements?
Answer:
average speed = 0.5 m/s
Explanation:
average speed = (distance) / (elapsed time)
Given time elapsed = 30 seconds and distance = 15 meters
average speed = 15 meters / 30 seconds = 0.5 meters/second = 0.5 m/s
A positive charge is 1 m to the left of a negative charge. The positive charge is then moved and placed 1 m to the right of the negative charge. What happens to the electrostatic force between the charges?
The electrostatic force remains attractive, and the magnitude does not change.
The electrostatic force remains repulsive, and the magnitude does not change.
The electrostatic force remains repulsive, but the magnitude changes.
The electrostatic force remains attractive, but the magnitude changes.
Answer:
Option (a) is correct.
Explanation:
Let the magnitude of the positive charge = [tex]q_1[/tex] and the magnitude of the negative charge = [tex]q_2[/tex]
Earlier, the distance between both the charge, d = 1m
By using Coulomb's law, the magnitude of the force between two charge
[tex]F=k\frac {q_1 q_2}{d^2}[/tex], where k is a constant.
So, the magnitude of the force in the initial configuration,
[tex]F_i = k\frac {q_1 q_2}{1^2}= k q_1q_2\cdots(i)[/tex]
The nature of the force is attractive, as both the charges are opposite in nature.
On replacing the positive charge from 1m left to 1 m right side of the negative charge, the distance between the charges remains the same, i.e d=1m.
Moreover, the magnitude, and nature of each charge, [tex]q_1[/tex] as well as [tex]q_2[/tex], are remain the same.
So, the magnitude of the force in the final configuration,
[tex]F_f = k\frac {q_1 q_2}{1^2}= k q_1q_2[/tex]
From equation (i), [tex]F_f=F_i[/tex]
The nature of the force is attractive, as both the charges are opposite in nature.
So, the electrostatic force remains attractive, and the magnitude does not change.
Hence, option (a) is correct.
When the electrostatic force lies between the charges so here the force should remain attractive, also the magnitude should remain the same.
Impact on the electrostatic force:Here we assume the magnitude of the positive charge should be q1 and the magnitude of the negative charge should be q2
Also, the distance between the charge should be d = 1 m
So here we use the columb law
F = kq1q2/d2
here k should be constant
Here the nature of the force should be attractive since the both the charges should be opposite.
Hence, the first option is correct.
Learn more about force here: https://brainly.com/question/3398162
define the unit of time and unit of length
Answer:
hope you like
Explanation:
A unit of time is any particular time interval, used as a standard way of measuring or expressing duration.Its SI unit is second
A unit of length refers to any arbitrarily chosen and accepted reference standard for measurement of length. Its SI unit is meter
Monica walks from +21 m to - 46 m along a stretched-out tape measure.
What is her total DISTANCE traveled? Include units.
What is her total
DISPLACEMENT? Include units.
Answer:
67 meters (distance) +67 meters (displacement)
Explanation:
21 - (-46) meters
= 21 + 46 meters
= 67 meters
Hope this helped!
Answer:
67m
67m
both dist and displacement are the same oz it is on the same line
Which physical property is best measured using only a balance?
A. Color
B. Volume
C. Mass
D. Density
Answer:
The answer is Mass
Explanation:
I took the tests and study kinda yeahhhhhh
AHHHHHHHHHHHHHHHHHh chicks butts
Two bowling balls, each with a mass of 8.52 kg, are traveling toward each other. Find the total momentum of the system if both balls have a speed of 2.13 m/s, but are traveling opposite of one another.
a. 18.1
b. 36.3
c. 0.0
d. 17.4
b=36•3
momentum=mass×velocity
The total momentum of the given system is equal to zero. Therefore, option (C) is correct.
What is the law of conservation of momentum?The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.
According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂
where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.
The first ball, m = 8.52 g and v = 2.13 m/s
The momentum of the first ball = 18.15 g.m/s
The second ball is moving in the opposite direction w.r.t. first ball,
The second ball, m = 8.52 g and v = - 2.13 m/s
The momentum of the first ball = - 18.15 g.m/s
The total momentum of the system = 18.15 + (-18.15) = 0
Therefore, the total momentum of the given system is zero.
Learn more about the law of conservation of linear momentum, here:
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brainlists please help
on the coner opposite of 8n is 5n
Answer:
resultant force=16N→(TOWARDS THE DIRECTION OF 8N)
Explanation:
resultant force=8N+13N-5N
=16N→(TOWARDS THE DIRECTION OF 8N)
Which line represents a stationary object?
A. Line A
B. Line B
C. Line C
D. Line D
PLZ HELP
Line D represents a stationary object.
When an object is stationary, the line on the graph is horizontal.
When the object is stationary the gradient is?We know, that an object is stationary means the slope of its position-time graph is zero or its pt graph is a straight line parallel to the x-axis.
What is an example of a stationary object?The nest, or the resting place, is a stationary object, and one cannot put one's foot in front of it. A string is then tied from the head assembly to another stationary object.
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The kinetic energy of a roller coaster is 100 joules. The potential energy of the same coaster is 100 joules. What is the mechanical energy of the coaster?
Answer/Explanation:
The mechanical energy is 200 joules. Mechanical energy is determined by adding the total kinetic energy by the total potential energy.
M = kp
100 + 100 = 200
A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:
Question:
A cork floats on the surface of an incompressible liquid in a container exposed to atmospheric pressure. The container is then sealed and the air above the liquid is evacuated. The cork:
A. sinks slightly
B. rises slightly
C. floats at the same height
D. bobs up and down about its old position
Answer:
The correct answer is C) floats at the same height
Explanation:
The liquid is incompressible because its density very high and leaves no room for further compaction whether or not there is atmospheric pressure. So when you put a cork on the liquid, pressure or no pressure, there is no displacement hence it floats on the same height regardless of the absence of air.
Cheers!
A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
42000 kilometers
Explanation:
distance is velocity × time
28000 ×1.5
42000
remember to match units
thats why i wrote 1.5 hours instead of 90minutes
What are the different forms of potential energy
Answer:
Gravitational potential energy.
Chemical energy.
Nuclear energy.
Elastic potential energy
Electrical potential energy
Hope this helps :)
Calculate Vector component in Y if the hypotenuse is 32 and angle is 45
Answer:
The correct option is;
c. 22.6
Explanation:
The given parameters are;
The hypotenuse of the vector = 32
The angle of the vector = 45°
Therefore, the vector component in the y-axis is given as follows;
[tex]v_y = v \times sin(\theta)[/tex]
Substituting the values from the question gives;
[tex]v_y = 32 \times sin(45^{\circ}) \approx 22.6[/tex]
The vector component in the y-axis, [tex]v_y[/tex], is approximately 22.6.