California college students who drink according to the centers for disease control and prevention, 60% of all american adults ages 18 to 24 currently drink alcohol. is the proportion of california college students who currently drink alcohol different from the proportion nationwide? A survey of 450 california college students indicates that 66% currently drink alcohol. the null hypothesis is ___________. The alternative hypothesis is _____________.

We can actually see here that all the true statements are:

A. The mean is the most appropriate measure of center for the 8th graders.

C. The range describes the difference between the greatest and least minutes.

We can deduce here that in Mathematics, "mean" is usually used to calculate the average value of a set of numbers. The arithmetic mean is usually known to be the most common type of mean amongst others.

The arithmetic mean is usually obtained by adding up all the numbers in the set and then dividing by the total number of numbers.

All the true statements are seen above.

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In order to show that 6x2 + 3x + 4 is O(22), we need to find suitable values for c and k in the definition of big-O.  Recall that a function f(x) is O(g(x)) if there exist positive constants c and k such that |f(x)| ≤ c|g(x)| for all x ≥ k.

Looking at the options given, we can see that the value of c must be greater than or equal to 1, since we are looking for an upper bound for the function.

Option a, where c = 100 and k = 1, is not a suitable choice because it is too large of a value for c. Similarly, option e, where c = 7 and k = 87, is not a suitable choice because it is too large of a value for k.

Option b, where c = 13 and k = 1, is a possible choice. To show this, we need to prove that there exist constants c = 13 and k = 1 such that:

[tex]|6x2 + 3x + 4| ≤ 13|22| for all x ≥ 1.[/tex]

Note that |22| = 22 and |6x2 + 3x + 4| ≤ 6x2 + 3x + 4.

Thus, we need to show that:

6x2 + 3x + 4 ≤ 13(22) for all x ≥ 1.

Simplifying the inequality, we get:

6x2 + 3x + 4 ≤ 286

This inequality holds for all x ≥ 1, since the left-hand side is a quadratic function that is increasing for x ≥ 0. Therefore, option b is a suitable choice.

Option c, where c = 1 and k = 87, is not a suitable choice because it is too small of a value for c.

Option d, where c = 10 and k = 2, is not a suitable choice because it is too small of a value for k.

Option f, where c = 7 and k = 1, is also a possible choice. To show this, we need to prove that there exist constants c = 7 and k = 1 such that:

[tex]|6x2 + 3x + 4| ≤ 7|22| for all x ≥ 1.[/tex]

Note that |22| = 22 and |6x2 + 3x + 4| ≤ 6x2 + 3x + 4.

Thus, we need to show that:

6x2 + 3x + 4 ≤ 154 for all x ≥ 1.

This inequality holds for all x ≥ 1, since the left-hand side is a quadratic function that is increasing for x ≥ 0. Therefore, option f is also a suitable choice.

In summary, options b and f are both suitable choices for c and k in the definition of big-O to show that 6x2 + 3x + 4 is O(22).

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The correct set of transformations is "Dilation by a scale factor of 2 followed by reflection about the x-axis".

Compare the corresponding side lengths to find the scale factor of the dilation.

For example, the distance between X and Y is √2 in triangle XYZ, and the distance between X'' and Y'' is 2√2 in triangle X''Y''Z''.

Therefore, the scale factor of the dilation is 2.

Now, find the direction of the reflection.

The y-coordinates of corresponding points in the two triangles have the same absolute values but opposite signs, which suggests a reflection about the x-axis.

Therefore, the correct set of transformations is:

Dilation by a scale factor of 2 followed by reflection about the x-axis.

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As per the mentioned informations and the given values, the area of the shaded region is calculated to be 52cm².

The width of the rectangular garden with an area of 120 square meters and length 15 meters is 8 meters.

To find the area of the shaded region in the diagram that shows squares of sides 8cm, 8cm, 12cm, and 18cm, we need to first determine which area is shaded. Assuming that the shaded area is the region between the 18cm square and the other squares, we can calculate its area as follows:

Area of the shaded region = Area of the 18cm square - Area of the 12cm square - 2(Area of the 8cm square)

= (18cm x 18cm) - (12cm x 12cm) - 2(8cm x 8cm)

= 324cm² - 144cm² - 128cm²

= 52cm²

Therefore, the area of the shaded region in the diagram is 52cm².

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The complete question is :

A rectangular garden has an area of 120 square meters. If the length is 15 meters, what is the width of the garden? What is the area of the shaded region in a diagram that shows squares of sides 8cm, 8cm, 12cm, and 18cm?

The second number in an ordered pair is the y-coordinate and corresponds to a number on the y-axis.

In this pair, the 1st number represents x-coordinate and corresponds to position on x-axis while 2nd number represents y-coordinate and corresponds to position on the y-axis.

The y-axis, a vertical line, runs along the graph with positive values above the origin and negative values below the origin.

The y-coordinate tells about level of high or low which the point is on y-axis. In conclusion, the second number in an ordered pair is the y-coordinate and corresponds to a number on the y-axis.

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To display this data, I advise using a box plot or a histogram.

The distribution of package weights may be shown in a histogram, which also shows how many parcels fall within the 100-125 ounce range. The histogram can be used to find any trends or outliers in the data that can point to problems with the packing methods.

An expanded description of the data, including the median, quartiles, and any outliers, would be shown in a box plot.

Also, it would demonstrate if most of the packages fall within the acceptable weight limit. It would be very helpful to use a box plot to see any severe outliers that could be distorting the data.

By giving the data a visual representation and highlighting any trends or outliers that would point to problems with the packing operations, both of these data presentations would aid in deciding if the packaging techniques needed to be updated.

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With multiple regression model on the specific data in the house sales Excel file, I am unable to provide you with a prediction for the sales price of a single-family home or townhouse with a lot cost of $30,000.

As the Excel file house sales is not available to me, I cannot provide you with the specific multiple regression model for sales price as a function of lot cost and type of home. However, I can give you the general steps to develop a multiple regression model:

Start by exploring the data with summary statistics and visualizations to get an idea of the relationship between the variables.

Create a scatterplot matrix to visualize the relationships between the variables.

Use a correlation matrix to check for multicollinearity between the predictor variables.

Fit a multiple regression model with sales price as the dependent variable and lot cost and type of home as the independent variables.

Check the model assumptions by examining the residuals and residuals plot.

Check for any outliers and influential points that may affect the model.

Test for interaction effects between lot cost and type of home using the appropriate statistical tests.

If an interaction effect is present, include an interaction term in the model.

Evaluate the model performance using metrics such as R-squared, adjusted R-squared, and root mean squared error (RMSE).

Once you have a final model, use it to predict the sales price for a single-family home or townhouse with a lot cost of $30,000.

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In Naive Bayes classification, probability calculations involve multiplying ratios of probabilities of the form P(A|B)/P(A). These ratios are called "Lift."

Lift is a measure used to assess the performance of a classification model, and it indicates the likelihood of an outcome being classified correctly by the model.

In this context, a higher Lift value signifies a better-performing model. If the Lift is greater than 0.5 (Lift > 0.5), it implies that the model's classification is more accurate than random chance. This means the model has a better ability to predict the correct outcome, improving the overall classification performance.

In conclusion, the likelihood of an outcome being classified correctly in a Naive Bayes classifier is higher if the Lift is greater than 0.5 (Lift > 0.5). This value serves as a threshold that indicates the model's ability to perform better than random chance in classifying outcomes.

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The probability of the red die showing a 5 is 1/6 since there are 6 possible outcomes on a die and only one of them is a 5. The same goes for the blue die. Therefore, the probability of both dice showing a 5 is 1/6 x 1/6 = 1/36. So the reduced fraction for this probability is 1/36.

The probability of the red die showing a 5 and the blue die showing a 5 can be calculated by finding the individual probabilities and multiplying them.

For each die, there are 6 possible outcomes (1-6), and only one of those outcomes is a 5. So, the probability of getting a 5 on a single die is 1/6.

Now, multiply the probabilities for the red die and the blue die:
(1/6) * (1/6) = 1/36

So, the probability of the red die showing a 5 and the blue die showing a 5 is 1/36 as a reduced fraction.

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The probability that the article will have no errors is approximately 0.0233.

To solve this problem, we can use the formula for the probability of an event, which is the number of favorable outcomes divided by the total number of outcomes.

Let's first find the probability that the article is typed by the first typist. Since the article is equally likely to be typed by either typist, this probability is 1/2.

Now, we need to find the probability that the article has no errors given that it is typed by the first typist. We know that the average number of errors per article typed by the first typist is 3.5, so the probability that an article typed by the first typist has no errors is given by the Poisson distribution with λ = 3.5:

P(X = 0) = e^(-λ) * λ^0 / 0! = e^(-3.5) * 3.5^0 / 1 = e^(-3.5) ≈ 0.0302

Similarly, we can find the probability that the article has no errors given that it is typed by the second typist. This probability is given by the Poisson distribution with λ = 4.1:

P(X = 0) = e^(-λ) * λ^0 / 0! = e^(-4.1) * 4.1^0 / 1 = e^(-4.1) ≈ 0.0164

Finally, we can use the law of total probability to find the probability that the article has no errors:

P(X = 0) = P(X = 0 | typed by first typist) * P(typed by first typist) + P(X = 0 | typed by second typist) * P(typed by second typist)

= 0.0302 * 1/2 + 0.0164 * 1/2

= 0.0233

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The length of x in the secant intersection is 90.0 units.

If two secant segments intersect outside a circle, then the product of the measures of one secant segment and its external secant segment is equal to the product of the measures of the other secant segment and its external secant segment.

Therefore,

a(a + x) = b(b + c)

where

Hence,

11(11 + x) = 24.2(24.2 + 21.7)

121 + 11x = 585.64 + 525.14

121 + 11x = 1110.78

11x = 1110.78 - 121

11x = 989.78

divide both sides by 11

x = 989.78 / 11

x = 89.98

Therefore,

x = 90.0 units

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The translation applied to the quadrilateral is (x, y) ---> (x + 1, y + 4)

Just look at one of the vertices of the two figures, then we can take the difference between the coordinate pairs and that will define the translation done, on the first figure we can see that we can see that:

K = (-2, -3)

And the translated vertex of the red figure is at K' = (-1, 1)

Taking the difference:

(-1, 1) - (-2, -3) = (1, 4)

So it moves 1 unit to the rigth and 4 units up, then the correct translation is.

(x, y) ---> (x + 1, y + 4)

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To design a binary counter with the repeated binary sequences (a) 0, 1, 2 and (b) 0, 1, 2, 3, 4, 5, we can use D flip-flops and logic gates as follows:

(a) Binary counter for sequence 0, 1, 2:

We need two D flip-flops to store the binary value of the counter. Let's call the flip-flops Q1 and Q0, where Q1 is the MSB (most significant bit) and Q0 is the LSB (least significant bit). We also need some logic gates to determine the next state of the counter based on the current state.

The next state of the counter can be determined by the following truth table:

Q1 Q0 next Q1 next Q0

0 0 0 1

0 1 1 0

1 0 1 1

1 1 0 0

We can implement this truth table using the following logic gates:

   The D input of flip-flop Q0 is connected to the output of an XOR gate that has inputs Q1 and Q0.

   The D input of flip-flop Q1 is connected to the output of an AND gate that has inputs Q1 and NOT(Q0).

The initial state of the counter is 0, 0. When the clock signal is applied, the counter will sequentially count through the binary values 0, 1, 2, and then repeat.

(b) Binary counter for sequence 0, 1, 2, 3, 4, 5:

We need three D flip-flops to store the binary value of the counter. Let's call the flip-flops Q2, Q1, and Q0, where Q2 is the MSB and Q0 is the LSB. We also need some logic gates to determine the next state of the counter based on the current state.

The next state of the counter can be determined by the following truth table:

Q2 Q1 Q0 next Q2 next Q1 next Q0

0 0 0 0 0 1

0 0 1 0 1 0

0 1 0 0 1 1

0 1 1 1 0 0

1 0 0 1 0 1

1 0 1 1 1 0

We can implement this truth table using the following logic gates:

   The D input of flip-flop Q0 is connected to the output of an XOR gate that has inputs Q1 and Q0.

   The D input of flip-flop Q1 is connected to the output of an XOR gate that has inputs Q2 and NOT(Q0).

   The D input of flip-flop Q2 is connected to the output of an XOR gate that has inputs Q1 and NOT(Q1) (which is equivalent to an XNOR gate).

The initial state of the counter is 0, 0, 0. When the clock signal is applied, the counter will sequentially count through the binary values 0, 1, 2, 3, 4, 5, and then repeat.

The volume of the triangular pyramid is 576 unit³.

We know the volume of a Triangular pyramid is

V = (1/3) x B x h

So, Base Area

= 1/2 x b x h

= 1/2 x 12 x 18

= 12 x 9

= 108 square unit

Now, the Triangular pyramid

= 1/3 x Base area x height

= 1/3 x 108 x 16

= 36 x16

= 576 unit³

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The moment of inertia of an object depends on its mass distribution and the distance of that distribution from the axis of rotation.

(a) For the hoop and pipe of the same mass and radius, the hoop has the larger moment of inertia because its mass is distributed farther from the axis of rotation.
(b) For the cylinder and disk of the same mass and radius, the cylinder has the larger moment of inertia because its mass is distributed farther from the axis of rotation.
(c) For the solid sphere, it has the largest moment of inertia out of the three objects because its mass is distributed uniformly at a greater distance from the axis of rotation compared to the other two objects.

So, the answer is (c) solid sphere.
Hi! Based on the given options, an object with the same mass and radius will have the largest moment of inertia if it is a hoop or pipe. The moments of inertia for the mentioned objects are:

(a) Hoop or pipe: I = MR^2
(b) Cylinder or disk: I = (1/2)MR^2
(c) Solid sphere: I = (2/5)MR^2

As you can see, the hoop or pipe has the largest moment of inertia among the given options.

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The correct matching of the above items with their descriptions is as follows:

Prescription medical abbreviations are those abbreviations that are used by medical practitioners to direct both the patient and pharmacist the dosage, route of administration and duration for the drug treatment regimen.

The typical examples of medical prescription used by doctors include the following:

BID = twice daily (think bi/bilateral or two, or Bicycle which has 2 wheels)

QID = four times daily (think quad/four or 4 quarters)

TID = three times daily (think tri/three, or tricycle which has 3 wheels)

Q or q = means 'every'

extremity= arm or leg

QOD =every other day

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Alexander can conclude that the inconstancy (spread) of the information in one dataset is twice as much as the changeability of the information within the other dataset.

The mean absolute deviation (MAD) could be a degree of inconstancy that depicts the normal separation between each information point and the cruelty of the dataset. The bigger the Frantic esteem, the more spread out the information is. The proportion of the implies to MADs of two datasets can be utilized to compare their spread.

In this case, the proportion of implies to MADs is 2.1. This implies that the cruelty of one dataset is 2.1 times bigger than the Frantic of that dataset, whereas the cruelty of the other dataset is as if it were 1 times bigger than its Frantic. Hence, the dataset with the bigger proportion (2.1) encompasses a bigger spread (inconstancy) compared to the other dataset.

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The graph of line a and line b is shown in the image attached below. The lines do not intersect each other.

To check if both lines intersect, we need to graph the system of equations. First, use the points given to write out the equations.

Line a:

Slope (m) = change in y / change in x = 6 - 4 / 8 - 0 = 2/8

m = 1/4

Find the y-intercept (b) by substituting m = 1/4, x = 0 and y = 4 into y = mx + b:

4 = 1/4(0) + b

b = 4

The equation of line a is: y = 1/4x + 4.

Line b:

Slope (m) = change in y / change in x = 1 - (-2) / 8 - 0

m = 3/8

Find the y-intercept (b) by substituting m = 3/8, x = 0 and y = -2 into y = mx + b:

-2 = 3/8(0) + b

b = -2

The equation of line b is: y = 3/8x - 2.

Both lines are graphed in the image attached below. Line a is the red line and line b is the red line. They do not intersect at any point.

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The point P that partitions the line segment AB three fourths of the way from A to B is given as follows:

P(3.75, 4.5).

The coordinates of point B are obtained applying the proportions in the context of the problem.

The point P partitions the line segment AB three fourths of the way from A to B, hence the equation is given as follows:

P - A = 3/4(B - A).

Then the x-coordinate of the point is given as follows:

x - 3 = 3/4(4 - 3)

x = 3 + 3/4

x = 15/4.

x = 3.75.

The y-coordinate of the point is given as follows:

y - 5 = 3/4(3 - 5)

y - 5 = -1.5

y = 4.5.

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The area of the polygon are:

1. 3358 square inch

2. 54 square yd

3. 54 square in

4. 384 square units

5. 18 square ft

6. 356.76 square yd

1. Rectangle

formula: length x width

= 73 * 46

= 3358 square inch

2. Parallelogram

formula: base x height

= 3 * 18

= 54 square yd

3. Parallelogram

formula:1/2 (sum of parallel lines) x height

= 1/2 (3 + 17) x 8

= 54 square in

4. Kite

formula:1/2 product of diagonals

= 1/2 (12 + 20) x (12 + 12)

= 384 square units

5. Triangle

formula: 1/2 x base x height

= 1/2 x 9 x 4

= 18 square ft

5. Regular pentagon

formula: 1/2 x perimeter x apothem

= 1/2 x (5 x 14.4) x 9.91

= 356.76 square yd

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The Mean Value Theorem (MVT) is a theorem in calculus that relates the derivative of a function to the average rate of change of the function over a given interval.

The Mean Value Theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists a number c in (a, b) such that:

f'(c) = (f(b) - f(a)) / (b - a)

To find all numbers c that satisfy the conclusion of the Mean Value Theorem, we need to check if the hypotheses of the theorem are satisfied, i.e. if the function is continuous on the closed interval and differentiable on the open interval.

Without the specific function and interval provided, we cannot determine all numbers c that satisfy the conclusion of the Mean Value Theorem. Please provide more information so we can help you better.

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Answer: The differential equation that models the weight of the baby bird is:

dR/dt = k (A - R)

where R is the weight of the bird at time t, A is the adult weight of the bird, and k is the proportionality constant.

To solve this differential equation, we can separate the variables and integrate both sides:

dR / (A - R) = k dt

ln|A - R| = -kt + C

|A - R| = e^(-kt+C)

|A - R| = Ce^(-kt)

where C is the constant of integration.

Since the initial weight of the bird is 20 grams, we have R(0) = 20. Plugging this into the above equation, we get:

|A - 20| = Ce^0

|A - 20| = C

Since C is a constant, we can use this to solve for it in terms of the adult weight A:

C = |A - 20|

Thus, the solution to the differential equation is:

|A - R| = |A - 20| e^(-kt)

To determine whether the bird is gaining weight faster when it weighs 40 grams or when it weighs 70 grams, we need to compare the rates of change of the weight at these two points.

When the weight of the bird is 40 grams, we have:

|A - R| = |A - 20| e^(-kt)

|A - 40| = |A - 20| e^(-kt)

Dividing both sides by |A - 20|, we get:

|A - 40| / |A - 20| = e^(-kt)

Taking the natural logarithm of both sides, we get:

ln(|A - 40| / |A - 20|) = -kt

Similarly, when the weight of the bird is 70 grams, we have:

ln(|A - 70| / |A - 20|) = -kt

To compare the rates of change of the weight at these two points, we need to compare the absolute values of the slopes, which are given by the absolute values of the coefficients of t in the above equations:

|ln(|A - 40| / |A - 20|)| = k

|ln(|A - 70| / |A - 20|)| = k

Since k is positive, we can compare the absolute values of the logarithms to determine which weight corresponds to a faster rate of weight gain.

If ln(|A - 40| / |A - 20|) > ln(|A - 70| / |A - 20|), then the bird is gaining weight faster when it weighs 40 grams. If ln(|A - 40| / |A - 20|) < ln(|A - 70| / |A - 20|), then the bird is gaining weight faster when it weighs 70 grams.

Simplifying these expressions, we get:

ln(|A - 40| / |A - 20|) - ln(|A - 70| / |A - 20|) > 0

ln[(A - 40) / (A - 20)] - ln[(A - 70) / (A - 20)] > 0

ln[(A - 40) / (A - 70)] > 0

(A - 40) / (A - 70) > 1

A - 40 > A - 70

70 > 40

This inequality is true, so we can conclude that the bird is gaining weight faster when it weighs.

According to the given differential equation, the rate at which a baby bird gains weight is proportional to the difference between its adult weight and its current weight. Therefore, the rate of weight gain is higher when the bird weighs closer to its adult weight.

Assuming that the adult weight of the bird is greater than 70 grams, the bird is gaining weight faster when it weighs 70 grams as compared to when it weighs 40 grams. This is because the difference between the bird's current weight and its adult weight is greater when it weighs 70 grams as compared to when it weighs 40 grams. Thus, the rate of weight gain is higher when the bird weighs 70 grams.

To further clarify, let's consider the proportional constant k in the differential equation. We know that the rate of weight gain is given by dR/dt = k*(Adult weight - Current weight). As the adult weight is constant, k*(Adult weight - Current weight) is directly proportional to the difference between adult weight and current weight. When the bird weighs 40 grams, this difference is smaller as compared to when it weighs 70 grams, which means the rate of weight gain is slower. Therefore, the bird is gaining weight faster when it weighs 70 grams.

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The number of jars that the raspberry jam fill will be 2/9.

Vijay created raspberry and strawberry jam. He made 2/3 of a jar's worth of strawberry jam. If he produced just a third as much strawberry jam as raspberry jam.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The number of jars that the raspberry jam fill is calculated as,

⇒ (2/3) x (1/3)

⇒ 2/9

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On average each year in the United States, approximately 100,000 people are shot, making option C the correct choice.

The number of gunshot victims includes various circumstances such as  unintentional shootings, law enforcement-related incidents, etc. Gun violence is a significant issue in the U.S., and public opinion varies on the most effective methods to address it, such as through gun control legislation, mental health support, or community-based interventions.

Efforts to reduce gun violence require a comprehensive approach, including understanding its root causes, studying the effectiveness of interventions, and promoting responsible gun ownership. Despite the challenges in addressing this complex issue, many organizations and individuals continue to work towards solutions to prevent gun-related injuries and deaths.

In the United States, approximately 100,000 (Option C) people are shot on average each year.

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As per the given data, the true proportion of nearsighted children is equal to 8%.

When an experiment is employed as the technique of examination, the two variations of the hypothesis the null hypothesis and the alternative hypothesis that is frequently utilised in research are referred to as the experimental hypothesis. The null hypothesis (H0) states that 8% of children are truly nearsighted. The alternative hypothesis (H1) states that the actual percentage of children who are nearsighted is lower than 8%.

The alternative hypothesis contends that the real proportion of nearsighted youngsters is different from 8%, whereas the null hypothesis argues that the 8% estimate is accurate. These hypotheses can be used in a hypothesis test to see if the sample data have enough support for the alternative hypothesis, which states that the 8% number is incorrect, to be accepted instead of the null hypothesis.

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The value of fraction which is equal to 2/-7 are,

⇒ - 4/14, - 6/21, - 8/28, ..

We know that;

A fraction is a part of whole number, and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called fraction. It can be written as the form of p : q, which is equivalent to p / q.

Given that;

The fraction is,

⇒ 2/- 7

Now, We can find all the fractions which is equal to 2/-7 as,

⇒ 2/- 7 = - 2/7

           =  - 4/14,

⇒ - 2/7 = - 6/21,

⇒ - 2/7 =  - 8/28,

Thus, the value of fraction which is equal to 2/-7 are,

⇒ - 4/14, - 6/21, - 8/28, ..

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Answer:D: 75.36 in

Step-by-step explanation: A= 3.14 x 12(2)

The 99% confidence interval for the mean mathematics SAT score for the entering freshman class is between 450 and 452.

 Based on the information provided, we can use the formula for a confidence interval for the population mean with a known standard deviation:

[tex]Confidence interval = sample mean +/- z*(standard deviation/square root of sample size)[/tex]

where z is the z-score corresponding to the desired confidence level (99% in this case).

Using a z-score table, we can find that the z-score for a 99% confidence level is 2.576.

Plugging in the values from the question, we get:

Confidence interval = 451 +/- 2.576*(0.115/sqrt(100))
Confidence interval = 451 +/- 0.029
Confidence interval = (450, 452)

Therefore, the 99% confidence interval for the mean mathematics SAT score for the entering freshman class is between 450 and 452 (rounded to the nearest whole number).

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The vectors has a magnitude of square root of 40 and a direction of θ = 251.565° is u = {-2, -6}. Option C

To find the vectors that has the stated magnitude, we check each vectors;

1. √(-7)² + (-2)² = √49 + 4 = √53 ≠ √40

Θ = arctan (-2/-7) = 15. 945 ≠ 251.565

Therefore {-7, -2} and {-2, -7} do not fit.

2. √(-6)² + (-2)²  = √36 + 4  = √40

tan Θ = -2/-6 = 1/3

Θ = arctan (1/3) + 180° = 18.43° ≠ 198.43°. Not it

3. √(-2)² + (-6)²  = √4 + 36  = √40

tan Θ = -6/-2 = 3

Θ = arctan (3) + 180° = 71.565° ≠ 251. 565°

The above answer is based on the question below as seen in the picture;

Which of the following vectors has a magnitude of square root of 40 and a direction of θ = 251.565°

a. u = (-7, -2)

b. u = (-6, -2)

c. u = (-2, -6)

d. u = (-2, -7)

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[tex]\begin{array}{|c|ll} \cline{1-1} \textit{\textit{\LARGE a}\% of \textit{\LARGE b}}\\ \cline{1-1} \\ \left( \cfrac{\textit{\LARGE a}}{100} \right)\cdot \textit{\LARGE b} \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{68\% of 32}}{\left( \cfrac{68}{100} \right)32}\implies 21.76[/tex]

Answer: 21.76 or 0.22

Step-by-step explanation: You put in 68% and 32 then you'll get 21.76

32=100

and .68%

32=100%(1)

68%(2)

.68/100

Then 0.22 or 21.76