Answers
Answer:
a 0.50m
0.50
L=0.50m
w=0.50m
A=L.w
0.50*0.50=25
Related Questions
A 1.0 kg block is pushed 3.0 m at a constant velocity up a vertical wall by a constant force applied at an angle of 26.0 ◦ with the horizontal, as shown in the figure. The acceleration of gravity is 9.81 m/s 2 . If the coefficient of kinetic friction between the block and the wall is 0.40, find a) the work done by the force on the block. Answer in units of J.
Answers
Explanation:
a) 8.2 J
The work done by the force on the block is equal to the force multiplied by the distance moved in the direction of the force. Since the force is applied at an angle of 26.0° with the horizontal, only a component of the force is acting in the direction of motion. The component of the force in the direction of motion is equal to the magnitude of the force multiplied by the cosine of the angle between the force and the direction of motion. Therefore, the work done by the force on the block is equal to:
Work = Force x Distance x cos(26.0°)
= (1.0 kg)(9.81 m/s2)(3.0 m) x cos(26.0°)
= 8.2 J
Answer
Given:
The thermal energy added to the system is Q = 90 J
The work done by the system on the surroundings is
W = 30 J
To find the change in internal energy.
Explanation:
According to the first law of thermodynamics, the
change in internal energy can be calculated by the
formula
AU = Q-W
On substituting the values, the change in internal en...
AU -90-30
= 60 J
Final Answer: The chage in internal energy is 60 J
(option D)
EdemT260579. Beginner
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Q
Answers
Answer:
Explanation:
Given:
Q = 90 J
W = 60 J
________
ΔU - ?
1 law of thermodynamics:
Q = ΔU + W
Change in internal energy:
ΔU = Q - W = 90 - 30 = 60 J
Two stars orbit near each other in a galaxy far far away.... If the masses
of both stars is doubled and the distance between them is doubled, what
is the new gravitational force going to be?
Answers
If the mass of both of the objects is doubled, then the force of gravity between them is quadrupled and decreased when distance between two objects is doubled.
What is gravity?All of the matter in the universe is drawn to all of the other bits of matter in the universe by the attractive force of gravity. It is a very significant force on the scale of moons, planets, stars, and galaxies, and it controls a much of the behavior of these objects. Our feet remain firmly planted on the ground thanks to gravity, which also keeps the Moon in orbit around the Earth, the Earth in orbit around the Sun, the Sun in orbit around the center of our Milky Way galaxy, the Milky Way and Andromeda galaxies orbiting their shared center of mass, and so on. Gravity is important to matter.We gravitate toward things that are closest to us and that are the most massive. The Earth's close proximity to the Sun prevents us from zooming off toward the Sun even though the Sun is much more massive than the Earth.Learn more about Gravitational force refer to :
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In an experiment, a jewel is placed in
water. A laser beam is passed from the
water through the jewel. The angle of
incidence is 50.0°, and the angle of
refraction is 28.0°. What is the index of
refraction, and what type of jewel is it?
Pls help
Answers
Answer:
dimond and 21
Explanation:
An average person with good physical condition can work at the rate of 1 hp for a short period (1 min). Calculate the time needed to run up two flights of stairs with a total H of 8 meters
Answers
The time needed to run up two flights of stairs is 8.41 Second.
What is power?Power can be defined as the amount of work completed in a given amount of time. Watt (W), which is derived from joules per second (J/s), is the SI unit of power. Horsepower (hp), which is roughly equivalent to 745.7 watts, is a unit of measurement sometimes used to describe the power of motor vehicles and other devices.
The power of an average person with good physical condition: P = 1 hp = 745.7 watts.
The work done to run up two flights of stairs with a total height of 8 meters = mgh = 80×9.8×8 Joule = 6272 joule.
So the time needed to run up two flights of stairs is= 6272/745.7 second = 8.41 Second.
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(Figure 1) shows a container with a cross-section area of 15 cm^2 in which a layer of water floats on top of a layer of mercury. A 1.0 kg wood block with a cross-section area of 10 cm^2 floats on the water. The water depth, measured from the bottom of the block, is 25 cm. A pressure gauge at the bottom of the container reads 26 kPa.
A container with vertical walls is filled with a layer of mercury of height h at the bottom and a layer of water above it. A rectangular block of 1.0 kilogram floats on the water. The distance from the mercury layer to the bottom side of the block is 25 centimeters. The area of the horizontal cross section of the block is 10 square centimeters. The area of the bottom of the container is 15 square centimeters. A pressure gauge is located at the bottom of the container.
Part A
What is the depth dm of the mercury? Use ρw = 1000 kg/m3 as the density of water and ρm = 13,600 kg/m3 as the density of mercury.
Answers
Pressure gauge is located at the bottom of the container thus, the depth of the mercury = 11.05 cm
What is pressure?Pressure refers to the force applied on a unit area of a surface. It works parallel to the pressure-applied surface. Pressure = force multiplied by the area on which it operates. The stronger the power, the smaller the area.
Given that,
pressure exerted by block ([tex]P_{B}[/tex])= weight / cross-section area of block
[tex]P_{B}[/tex] = (1 ×9.81) ÷ (10 × 10⁻⁴)
= 9810 Pa
Now, pressure at bottom of container is given as:
[tex]P_{Bottom}[/tex] = [tex]P_{B}[/tex] + ρ × g × h + ρ₁ × g × h₁
[ ρ = density of water,
ρ₁ = density of Hg,
h = height of water and
h₁ = height of Hg ]
Thus, 27000 = 9810 + (1000 × 9.81 × 0.25) + (13600 × 9.81 × h₁)
h₁ = 14737.5 ÷ 133416
h₁ = 0.1105 m
h₁ = 11.05 cm
Thus, depth of the mercury = 11.05 cm.
So, the depth of the mercury = 11.05 cm
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The air of an average sneeze travels around 100 miles an hour. Rebecca believes a sneeze induced by a stimulant will produce air that travels at a faster speed than the typical 100 miles per hour. She designs an experiment to induce sneezing. She subjects four participants to different stimulants: pepper, bright light, pollen, and fizzy soda. Once a sneeze is induced, Rebecca measures how fast the air traveled through the nasal passage.
Which statement WOULD NOT be an appropriate hypothesis for Rebecca's experiment?
A Induced sneezes move air at a faster speed than naturally occurring sneezes.
B There is no difference in air speed of induced versus naturally occurring sneezes.
C Using pepper as a stimulant induces more sneezing than any other stimulants.
D All sneezes move air at the same rate of speed.
Answers
Based on the study conducted by Rebecca, the statement that would not be an appropriate hypothesis for Rebecca's experiment is:
Using pepper as a stimulant induces more sneezing than any other stimulant; option CWhat is a hypothesis?A hypothesis is an explanation that is given in the form of a statement to explain an observation based on limited evidence and which serves as a starting point for further investigation.
A hypothesis may or may not be true and must be investigated to prove or disprove it.
Experiments are conducted to prove or disprove a given hypothesis.
A hypothesis is divided into a null and an alternate hypothesis.
A null hypothesis is a hypothesis that state that the treatment given to the subjects of the experiment does not produce any significant effect.
An alternate hypothesis states that the treatment given to the subjects of the experiment produces significant effects on the subjects.
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An airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, how many degrees east of north does the airplane travel relative to the ground?
a. 66°
b. 63°
c. 27°
d. 24°
please help me
Answers
With the knowledge of bearing, the airplane will be 24 degrees east of north relative to the ground. The correct answer is option d
What is Relative Motion ?Relative motion can be defined as a change of position of an object with a point or frame of reference which we may assumed to be at rest.
Given that an airplane whose airspeed is 190 km/h heads due north. If there is a wind blowing at 86 km/h from west to east, the magnitude of degrees Ф east of north in which the airplane will travel relative to the ground can be known by using a trigonometry ratio.
The Y component is 190 km/h heads due north.
The X component is 86 km/h from west to east.
TanФ = Y/X
Ф = [tex]Tan^{-1} (\frac{Y}{X})[/tex]
Ф = [tex]Tan^{-1} (\frac{190}{86})[/tex]
Ф = [tex]Tan^{-1} (2.209)[/tex]
Ф = 65.65°
The degrees east of north = 90 - 65.65
The degree east of north = 24.4°
Therefore, the magnitude of degrees east of north in which the airplane will travel relative to the ground is 24° approximately.
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A 7.50 kg bowling ball moving directly east at 6.42 m/s strikes a 1.60 kg bowling pin at rest. After, the pin moves 14.8 m/s at a -47.0° angle. What is the x and y component of the ball’s final velocity?
Answers
The x component of the ball's final velocity is 7.35 m/s.
The y component of the ball's final velocity is 4.90 m/s.
What is velocity?The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Mass of the ball: M = 6.35 kg.
Initial velocity of ball along x axis: U = 8.49 m/s.
Mass of the pin at rest: m = 1.59 kg.
Final velocity of pin at a -77.0° angle.: v = 20.1 m/s
Let the x component of the ball's final velocity is V₁ m/s.
The y component of the ball's final velocity is V₂ m/s.
Appling conservation of momentum along x axis:
MU + m.0 = MV₁ + mvcos(-77.0°)
⇒ V₁ = u - (m/M) v cos(-77.0°)
After putting the values we get:
V₁ = 7.35 m/s.
Appling conservation of momentum along y-axis:
M.0 + m.0 = MV₂ + mvsin(-77.0°)
⇒ V₂ = - (m/M) vsin(-77.0°)
After putting the values we get:
V₂ = 4.90 m/s.
Hence, The x component of the ball's final velocity is 7.35 m/s.
The y component of the ball's final velocity is 4.90 m/s.
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Carl notices that his window air conditioner takes thermal energy from the room and transfers it to the air outside. He thinks he has found an exception to the rules of physics. Which is the most likely reason he is incorrect?
A. Heat does not flow outside naturally. It requires an input of work by the air conditioner.
B. Heat always flows naturally from inside to outside.
C. The room air is actually warmer than the outside air.
D. The air conditioner is actually taking cold from the outside and transferring it into the room.
Answers
The heat of the room does not flow outside naturally actually it requires an input of work by the air conditioner. Therefore, option (A) is correct.
How does the air conditioner work?The air conditioner work on the principles of heat sinks. It functions to cool the temperature of a closed space while transferring the heat from a closed space to another place known as a sink. This process consists of four thermodynamic stages that result in the transformation of electrical energy into a thermal heat absorption system.
Air Conditioners are cooling devices that are used to cool large spaces. The capacity of the air conditioner depends on how much space it needs to cool. An air conditioner takes the thermal energy away to make the air cooler.
Therefore, the heat flow outside the room due to work done by the air conditioner.
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(Figure 1) shows a thin liquid film bounded on the right side by a sliding wire that is attached to a spring with spring constant 0.50 N/m. The spring is stretched by 1.3 cm. What is the liquid's surface tension in mN/m?
Answers
The liquid's surface tension in N/m is determined as 0.25 N/m.
What is surface tension?
Surface tension is defined as the property of the surface of a liquid that allows it to resist an external force, due to the cohesive nature of its molecules.
Mathematically, the formula for surface tension of a liquid is given as;
γ = F/L
γ = F/2x
where;
F is the applied forcex is the extension of the springγ is the surface tensionFrom Hooke's law, the force applied on an elastic material is directly proportional to the extension of the material.
F = kx
where;
k is the spring constantx is the extension of the springThe final equation for the surface tension of the liquid film becomes;
γ = F/2x
γ = kx/2x
γ = k/2
γ = (0.5 N/m) / 2
γ = 0.25 N/m
Thus, the surface tension of a liquid depends on the applied force and length of the liquid surface.
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A radioisotope, tritium (1^3H) has half life of 12.3 years. If the initial amount of tritium is 32 mg , how many milligrams of tritium would remain after 49.2 years?
Answers
Hope this answer helps you
We all know the trick of pretending to lose a cell phone connection, but the receiving person (in reality) can usually tell you have a good connection. This time, you are in luck- you are using a cell phone at 850 MHz, on one side of you is the cell phone tower, and on the other side, a tall building.
1) what is the wavelength of your cell phone transmission?
2) How far from the building should you stand to lose reception?
3) Since the phone companies employ good engineers, that trick won't actually work. However, you happen to see a chain-link fence nearby, and (out of desperation) try to use that as a diffraction grating to scatter the radiation. Estimating the link spacing as 5 cm, will this work?
Answers
The transmission waves from a smartphone, which range in frequency from 800 to 2400 MHz and belong within the category of the electromagnetic spectrum, have a wavelength of around one foot.
define frequency ?
The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. The unit of frequency is (Hz), or one occurrence per second. The time lapsed between occurrences is measured by the time, which is the reciprocal of the frequency.
For instance, if a bets 120 times per minute , the period, T—the space between bets—is half a second. The frequency of oscillatory and vibrtory phenomena, such as mechanical vibrions, sound, and radio waves, is a crucial characteristic in science and engineering.
The transmission waves from a smartphone, which range in frequency from 800 to 2400 MHz and belong within the RF category of the electromagnetic spectrum, have a wavelength of around one feet.
Standing 8 feet away is advised, according to FEMA.
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Question 2 A object of mass 50kg is placed on a horizontal floor with a smooth surface. If the velocity of the object changes from stationary to 25.0 m/s in 5 seconds when is acted by a force, find the magnitude of the force that is acting?
Answers
The force acting on the box is 250N if the object's velocity changes from being stationary to 25.0 m/s in 5 seconds when it is subjected to a force.
We are aware that the formula F = ma could be used to determine a force's magnitude.
where F = force
m = mass
a = acceleration
Although the question already contains the mass m, it does not directly state the acceleration.
In this case, the acceleration is equal to the change in velocity divided by the time interval,
From the formula, we can determine acceleration.
[tex]a = \frac{v- u}{t}[/tex][tex]a = \frac{25 - 0}{5}[/tex]
[tex]a = 5ms^{-2}[/tex]
Using the equation,
F = ma
F = 50 * 5
F = 250N
Therefore, The force acting on the box is 250N if the object's velocity changes from being stationary to 25.0 m/s in 5 seconds when it is subjected to a force.
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The driver of a car slams on the brakes, causing the car to slow down at a rate of 19.0ft/s2 as the car skids 195ft to a stop.
How long does the car take to stop?
What was the car's initial speed?
Answers
The time taken by the car to stop will be 4.53 seconds. The final velocity is zero and the initial velocity will be 86.08 ft./s.
What is velocity?Velocity is a vector quantity which measures distance covered per unit time. It is given that the acceleration of the car a is 19 ft/s². The distance it covered is 195 ft.
We have the expression for final velocity v initial velocity u and the time t with acceleration a as follows where the final velocity v for the car is zero.
0 = U - at
u = at.
The relation between time, acceleration and initial velocity with distance d is written as:
d = u t - 1/2 at²
= at² -1/2 at²
= 1/2 at²
Thus, t = √(2d/a)
= √(2×195 ft / 19 ft/s²)
= 4.53 s.
Initial velocity u = a t
= 4.53 s ×19 ft/s²
= 86.08 ft./s
Therefore, the initial velocity will be 86.08 ft./s.
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The figure shows a 23 cm -long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.3 m/s . The rails have negligible resistance, but the rod has a resistance of 0.75 Ω .(Figure 1)
A) What is current in the rod?
B) What is magnitude of force required to keep the rod moving at a constant speed?
C) Direction of the force?
Answers
a. The induced current is i = 1.42 A
b. The force is F = 0.46 N
c. The force is in the positive z - direction along the rod
What is current?Current is the flow of electric charge ina circuit.
What is force?Force is that thing which causes a change in motion of an object.
A) What is current in the rod?Since the figure shows a 23 cm -long metal rod pulled along two frictionless, conducting rails at a constant speed of 3.3 m/s . The rails have negligible resistance, but the rod has a resistance of 0.75 Ω, the current in the rod is the induced current given by
i = BLv/R where
B = magnetic field = 1.4 TL = length of rod = 23 cm = 0.23 mv = speed of rod = 3.3 m/s and R = resistance of rod = 0.75 ΩSubstituting the values of the variables into the equation, we have
i = BLv/R
i = 1.4 T × 0.23 m × 3.3 m/s/0.75 Ω
i = 1.0626 Tm²/s/0.75 Ω
i = 1.4168 A
i ≅ 1.42 A
The current is i = 1.42 A
B) What is magnitude of force requiredThe magnitude of the force the force on a metallic conductor is given by
F = B²L²v/R where
B = magnetic field = 1.4 TL = length of rod = 23 cm = 0.23 mv = speed of rod = 3.3 m/s and R = resistance of rod = 0.75 ΩSubstituting the values of the variables into the equation, we have
F = B²L²v/R
F = (1.4 T)² × (0.23 m)² × 3.3 m/s/0.75 Ω
F = 1.96 T² × 0.0529 m² × 3.3 m/s/0.75 Ω
F = 0.3422 T²m³/s ÷ 0.75 Ω
F = 0.456 N
F ≅ 0.46 N
The force is F = 0.46 N
C) Direction of the force?We know that the force F = q(v × B) where
v = speed of rod = -vi and B = magnetic field = -BjSo, F =q(v × B)
= q(-vi × Bj)
= q(vB (i × j)
= (qvB)k
Since F is in the positive k direction, the force is in the positive z - direction along the rod
The force is in the positive z - direction along the rod
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Assume that one object collides with a second object that is at rest. In which of the following scenarios would you expect that momentum would not be conserved?
a) When both objects move in the direction of initial motion after colliding.
b) When the objects move in opposite directions after colliding (the second object moves in the direction of initial motion, the first object moves in the reverse direction).
c) When the objects stick together after colliding.
d) When there is an external force (like friction) acting on the objects in the system.
Answers
The momemtum is not conserved in scenario d.
What is momentum?Momentum of an object is the product of its mass and velocity.
How to determine In which of the following scenarios would you expect that momentum would not be conserved?To determine in which of the conditions in which momentum is not conserved, we need to know the law of conservation of momentum.
What is the law of conservation of momentum?The law of conservation of momentum states that as long as no external force acts on a system, the total momentum of the system of two colliding objects is conserved.
If we consider scenarios a, b and c, we see that no external force acts on the system of two objects in the three instances so, the total momentum is conserved.
In scenario d, an external force acts on the system, so total momentum is not conserved since according to the law of conservation of momentum, total momentum is only conserved when there is no external force acting on a system.
So, the momemtum is not conserved in scenario d.
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4. You are pushing a 100 kg block across a flat wood floor with a coefficient of friction of
0.25. You can push the block with a force of 300 N.
a) Draw the free body diagram for the scenario below.
Answers
Answer:
The free body diagram for this scenario is shown below. The force of 300 N is the applied force, pushing the block across the floor. The force of friction is opposing the applied force, and is equal to the coefficient of friction (0.25) multiplied by the weight of the block (100 kg). This gives a force of friction of 25 N.
b) Calculate the acceleration of the block
The acceleration of the block can be calculated using Newton's Second
In a study conducted by a University of Illinois researcher, the football team at Unity High School in Tolono, IL was equipped for an entire season with helmets containing accelerometers. Information about every impact in practice and in games was sent to a computer present on the sidelines. The study found that the average force on a top of the head impact was 1770 N. If the initial velocity of the head was 2.09 m/s and the collision brings the head to a stop, and assuming the head has a mass of 4.12 kg, determine the duration of the impact.
(Note: we are treating the head as a free body which is a bit of an approximation).
Answers
The duration (i.e time) of the impact, given that the head impact was 1770 N is 0.005 s
How do I determine the duration (i.e time)?Impulse is defined as the change in momentum of an object. It is expressed as:
Impulse = change in momentum
Impulse = final momentum – Initial momentum
Impule = m(v - u)
Impulse = force × time
Impulse = Ft
Thus,
Ft = m(v - u)
Where
F is the force t is the timem is the massu is the initial velocityv is the final velocityNow, we can obtain the duration (i.e time) of the impact. Details below:
Force (F) = 1770 NInitial velocity = 2.09 m/sMass (m) = 4.12 KgFinal velocity = 0 m/sDuration (t) =?Ft = m(v + u) since the collision came to a stop
1770 × t = 4.12 × (0 + 2.09)
1770 × t = 4.12 × 2.09
Divide both sides by 1770
t = (4.12 × 2.09) / 1770
t = 0.005 s
Thus, the duration is 0.005 s
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Were is the computer located
Answers
Answer:
where u put it last time or retrace ur steps to where u last put it
A building with a wall 50m long by 4m high with sixty percent (60%) of the wall area occupied by 10 mm thick plate glass and the remainder is of 20 cm thick concrete blocks with solid concrete cores is being designed. If expected condition for site of the building has average dally air temperatures of 35°C and the interior temperature of the building will be kept at 25 °C by designed air conditioning syster, calculate the rate of heat transfer from outside to inside (heat load) due to this wall.
Answers
Answer: If you have "A, B, C" as answers chose the answer: "A".
Explanation:
Trust me.
When a train's velocity is 12.0 m/s eastward, raindrops that are falling vertically with respect to the earth make traces that are inclined 30.0∘ to the vertical on the windows of the train.
a.What is the horizontal component of a drop's velocity with respect to the earth?
b.What is the horizontal component of a drop's velocity with respect to the train?
c.What is the magnitude of the velocity of the raindrop with respect to the earth?
d.
What is the magnitude of the velocity of the raindrop with respect to the train?
Answers
Answer:
a. Horizontal component v = 12 m/s
b. Magnitude of velocity v = 20.78 m / s
Explanation:
Vₓ = 12.0 m / s eastward
β = 30.0 °
So
a.
Vt = Vₐ - Vₓ
Vₐ = 0 i
Vt = 0i - 12.0 = - 12 m/s
b.
Vₙ = 12 / sin (30 °)
Vₙ = 24 m / s
Vₙ = 24 * con (30 °)
Vₙ = 20.78 m / s
A satellite with a mass of 9.3 x 1012 kg is orbiting a planet at a distance R from the center of the planet. The gravitational field strength of the planet at distance R from its center is 0.03 m/s2. What is the magnitude of the gravitational force between the satellite and the planet?
Answers
The gravitational force that is acting on the satellite can be obtained as 2.79 * 10^11 N.
What is the gravitational force?We know that the gravitational force has to do with the force of attraction that does act between any two objects that are around each other in the earth's gravitation force. We have to state it quite clearly again that the gravitational force is known to be an attractive force that acts between any two masses as the case may be.
We have the following pieces of information about the satellite that we need to use so as to obtain the gravitational force as follows;
Mass of the satellite = 9.3 x 1012 kg
Acceleration due to gravity = 0.03 m/s2
Force on the satellite = ??
We then have;
F/m = g
F = gravitational force
m = mass
g = acceleration due to gravity
Thus;
F = mg
F = 9.3 x 10^12 kg * 0.03 m/s2
F = 2.79 * 10^11 N
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compare the wind speed within the eye and the eyewall. What can you say?
Answers
Answer:
I can say words like cheese and balls
50PTS!!!!
A golf ball is hit at a velocity of 42.0 m/s at an angle of 42.2° on Earth and on the Moon where the acceleration due to gravity is 1.62 m/s². How much higher will the maximum height be on the Moon compared to the maximum height on Earth?
Answers
Answer:
Approximately [tex]205\; {\rm m}[/tex] (assuming that [tex]g = 9.81\; {\rm m\cdot s^{-2}}[/tex] on Earth and that air resistance is negligible.)
Explanation:
Initial vertical velocity of the golf ball:
[tex]\begin{aligned} & (\text{initial vertical velocity}) \\ =\; & (\text{initial velocity})\, \sin(\text{angle of elevation}) \\ =\; & (42.0\; {\rm m\cdot s^{-1}}})\, \sin(42.2^{\circ}) \\ \approx\; & 28.212\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
Let [tex]u_{y}[/tex] denote the initial vertical of the ball. When the ball is at maximum height, the vertical velocity [tex]v_{y}[/tex] of the ball will be [tex]0[/tex]. Let [tex]x_{y}[/tex] denote the vertical displacement of the ball (height of the ball.)
Let [tex]a_{y}[/tex] denote the vertical acceleration of the ball. Under the assumptions, the vertical acceleration of the ball during the flight will be constantly [tex](-g)[/tex].
The SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] relates these quantities. Rearrange this equation to find the maximum vertical displacement of the ball (value of [tex]x_{y}[/tex] when [tex]v_{y} = 0\; {\rm m\cdot s^{-1}}[/tex].)
[tex]{v_{y}}^{2} - {u_{y}^{2} = 2\, a_{y}\, x_{y}[/tex].
[tex]\begin{aligned}x_{y} &= \frac{{v_{y}}^{2} - {u_{y}}^{2}}{2\, a_{y}} \end{aligned}[/tex].
On the Earth, [tex]a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex]. Therefore:
[tex]\begin{aligned}x_{y} &= \frac{{v_{y}}^{2} - {u_{y}}^{2}}{2\, a_{y}} \\ &\approx \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (28.212\; {\rm m\cdot s^{-1}})^{2}}{2\, ((-9.81)\; {\rm m\cdot s^{-2}})} \\ &\approx 40.57\; {\rm m}\end{aligned}[/tex].
On the Moon, it is given that [tex]g = 1.62\; {\rm m\cdot s^{-2}}[/tex], such that [tex]a_{y} = (-g) = (-1.62)\; {\rm m\cdot s^{-2}}[/tex]. Therefore:
[tex]\begin{aligned}x_{y} &= \frac{{v_{y}}^{2} - {u_{y}}^{2}}{2\, a_{y}} \\ &\approx \frac{(0\; {\rm m\cdot s^{-1}})^{2} - (28.212\; {\rm m\cdot s^{-1}})^{2}}{2\, ((-1.62)\; {\rm m\cdot s^{-2}})} \\ &\approx 245.65\; {\rm m}\end{aligned}[/tex].
The difference between the maximum heights will be approximately:
[tex](245.65\; {\rm m}) - (40.57\; {\rm m}) \approx 205\; {\rm m}[/tex].
A 6.35 kg bowling ball moving 8.49 m/s strikes
a 1.59 kg bowling pin at rest. After, the pin moves 20.1 m/s at a -77.0° angle. What is
the x and y component of the ball's final velocity?
Answers
The x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
What is velocity?
The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.
Given that:
Mass of the ball: M = 6.35 kg.
Initial velocity of ball: U = 8.49 m/s.
Mass of the pin at rest: m = 1.59 kg.
Final velocity of pin: v = 20.1 m/s at a -77.0° angle.
Let the x and y component of the ball's final velocity are respectively V₁ m/s and V₂ m/s.
Appling conservation of momentum along x axis:
MU + m.0 = MV₁ + mvcos(-77.0°)
⇒ V₁ = u - (m/M) v cos(-77.0°)
After putting the values we get:
V₁ = 7.35 m/s.
Appling conservation of momentum along y-axis:
M.0 + m.0 = MV₂ + mvsin(-77.0°)
⇒ V₂ = - (m/M) vsin(-77.0°)
After putting the values we get:
V₂ = 4.90 m/s.
Hence, the x and y component of the ball's final velocity are respectively 7.35 m/s and 4.90 m/s.
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if a thermometer indicates a temperature of 86F what's the equivalent temperature in Celsius scale
Answers
The equivalent temperature in Celsius scale is (86°F − 32) × 5/9 = 30°C
Take the °F temperature and subtract 32
Multiply this number by 5.
Divide this number by 9 to obtain your answer in °C.
The formula to convert °F to °C is:
T(°C) = (T(°F) - 32) × 5/9
converting 86 degrees Fahrenheit into degrees Celsius:
T(°C) = (86°F - 32) × 5/9
T(°C) = 30 °C
(86°F − 32) × 5/9 = 30°C
When doing the temperature conversion, one quick way to make certain you did the conversion right is to remember Fahrenheit temperatures are higher than the corresponding Celsius scale until you get down to -40°, which is where the Celsius and Fahrenheit scales meet. Below this temperature, degrees Fahrenheit are lower than degrees Celsius.
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what is the acceleration of a 38 kg crate being pushed horizontally by an 83 N force?
Answers
The magnitude of acceleration of the crate be 7.14 m/s².
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Mass of the create be: m = 38kg.
Force applied on the create : F = 83N.
From Newton's second law of motion, we can write:
force = mass × acceleration
⇒ acceleration = force/mass = 38/83m/s² = 0.45 m/s².
Hence, acceleration of the create be 0.45 m/s².
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To drill or not to drill? That is the big question as Americans face climbing gas prices. Mobil Oil is considering drilling for oil off the coast of California and concerned citizens have protested their attempts to set up drilling sites off-shore. As a result of the controversy, a group of research scientists have been employed by the State of California to study the possible impacts of oil drilling on near-by ecosystems and investigate the likelihood of future oil spills.
The most appropriate method to study the potential impacts of oil drilling on coastal California would be which of these options?
Responses
A research other areas where unsuccessful oil drilling has occurredresearch other areas where unsuccessful oil drilling has occurred
B check historical data in drilling areas to see the likelihood of an oil spillcheck historical data in drilling areas to see the likelihood of an oil spill
C design a computer simulation of an oil spill in the area to determine the environmental impactdesign a computer simulation of an oil spill in the area to determine the environmental impact
D perform a mark and recapture population study on the wildlife in the area prior to drilling
Answers
The most appropriate method to study the potential impacts of oil drilling on coastal California would be design a computer simulation of an oil spill in the area to determine the environmental impact design a computer simulation of an oil spill in the area to determine the environmental impact. The correct option to this question is C.
Drilling There are a number of preliminary surveys that must be completed before drilling may be confirmed in the off-coast area, includingTo learn more about the subsurface structures that may make drilling difficult, seismic surveys are conducted in the area.To produce a thorough study, a facias analysis is performed. It aids in identifying the type of facies present, the time the rocks were deposited, and their lithological properties.Additionally, it selects the most promising locations for oil and gas prospecting.So, following a thorough analysis of this criteria and after meeting all requirements, the scientists report these findings and then start digging.For more information on drilling kindly visit to
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Using the right hand rule, what do the three numbered vectors represent in the diagram below?
Answers
A) Magnetic field
B) Electric current
C) Force
The equation corresponding to this graphical representation is
F = IBL
where I is the current, B the magnetic field, L the length of the wire and F the magnetic force.