calculate the pressure by sea water when diving to a depth of 100m.what is the pressure acting on the diver?​

Answer:

Approximately [tex]2.2\; \rm cm^{3}[/tex] (assuming that this gas is ideal, and that the initial volume of this gas is [tex]4.0\; \rm cm^{3}[/tex].)

Explanation:

In this question, both the pressure on the gas and the temperature of the gas have changed. However, the ideal gas laws (Boyle's Law and Charles' Law) requires that only one of the two quantity change at a time. Therefore, consider this change in two steps:

Boyle's Law states that for a fixed quantity of some ideal gas, if temperature is held constant, the volume of the gas will be inversely proportional to the pressure on the gas.

Let [tex]V_0[/tex] denote the initial volume of this gas. The question states that at [tex]P_0 = 2.0\times 10^{5}\; \rm Pa[/tex] and [tex]T_0 = 288\; \rm K[/tex], the volume of the gas is [tex]V_0 = 4.0\; \rm cm^{3}[/tex].

By Boyle's Law, if temperature is held constant ([tex]T_1 = T_0 = 288\; \rm K[/tex],) then at [tex]P_1 = 1.6 \times 10^{5}\; \rm Pa[/tex]:

[tex]\begin{aligned} V_1 &= V_0 \cdot \frac{P_0}{P_1} \\ &= 4.0\; \rm cm^3 \times \frac{2.0 \times 10^{5}\; \rm Pa}{1.6 \times 10^{5}\; \rm Pa} \approx 5.0\; \rm cm^{3} \end{aligned}[/tex].

On the other hand, Charles' Law suggests that for a fixed quantity of some ideal gas, if the pressure of the gas is held constant, the volume of the gas will be proportional to the temperature (in degree Kelvins) of the gas.

Let [tex]V_1[/tex] denote the volume of this gas before the temperature change. At [tex]P_0 = 2.0\times 10^{5}\; \rm Pa[/tex] and [tex]T_0 = 288\; \rm K[/tex], previous calculations show that [tex]V_0 = 5.0\; \rm cm^{3}[/tex].

By Charles' Law, if the pressure of this gas is held constant ([tex]P_2 = P_1 =1.6 \times 10^{5}\; \rm Pa[/tex],) then at the new temperature [tex]T_2 = 125\; \rm K[/tex]:

[tex]\begin{aligned} V_2 &= V_1 \cdot \frac{T_1}{T_0} \\ &= 5.0\; \rm cm^3 \times \frac{125\; \rm K}{288\; \rm K} \approx 2.2\; \rm cm^{3} \end{aligned}[/tex].

Therefore, at [tex]T_2 = 125\; \rm K[/tex] and [tex]P = 1.6 \times 10^{5}\; \rm Pa[/tex], the volume of this gas would be approximately [tex]2.2\; \rm cm^{3}[/tex].

Answer:

KE increases and PE decreases.

Explanation:

First, note that the formula for kinetic energy is KE = (1/2)mv^2 where m is the mass and v is the velocity and the formula for potential energy is PE = mgh where h is the height it is at. Since mass and the acceleration provided by gravity doesn’t change, we can disclude that our conclusion. We know that the height (h) and velocity (v) does change, so let’s look at that. As you continue down the slope, you accelerate due to gravity. Thus, velocity increases and KE increases. As you continue down the slope, you get closer to the ground, hence h decreases and PE decreases.

I hope this helped! :)

Answer:

V = 1000 [cm³]

Explanation:

To solve this type of problem we must apply the definition of density, which is equal to the relationship between mass and volume, in this way it can be easily found by means of the following equation.

[tex]Ro = m/V[/tex]

where:

Ro = density = 2.7 [g/cm³]

m = mass = 2700 [g]

V = volume [cm³]

Now replacing:

[tex]V = m/Ro\\V = 2700/2.7\\V = 1000 [cm^{3} ][/tex]

Answer:

stay in doors and away from the windows

Explanation:

Answer:

During a thunderstorm, you should remain indoors and have a weather radio handy. Your family should be prepared for the possibility of high winds and power failures. Have candles, emergency supplies, food, and water accessible. Some thunderstorms have been known to cause power failures for millions of people at a time. During a severe weather event, the National Weather Service will issue watches and warnings associated with the storm system. A watch means that severe weather may be possible in the near future. You should take precautions during a watch. A warning is issued when severe weather is likely to strike at any moment. All watches and warnings for severe weather should be listened to carefully.

Answer: I scored a 9/10

Explanation:

I agree with Kathy gravity must be acting the same on both balls just because one ball is heavier doesn’t mean they will hit different times if the wooden ball was drop closer to the ground then the wooden ball would hit the ground first

Answer:

5 N right

Explanation:

Fx = 9N-4N

Fx = 5N

Since we can define the x and y axis. We have x to the right as positive.

Answer:

147 newton.

Explanation:

Force is the product of mass and acceleration. The formula of force is given below: Force =  mass x acceleration, but due to height we put gravity instead of acceleration. So by putting values of mass i. e. 15 kg and gravity i. e. 9.8 meter/ second in the formula we get the net force of the ball which is 147 newton or 147 kg meter/second square.

Answer:

Mass, m = 1561.23kg

Explanation:

Given the following data;

Weight = 15300N

We know that acceleration due to gravity is equal to 9.8m/s²

To find mass;

Weight can be defined as the force acting on a body or an object as a result of gravity.

Mathematically, the weight of an object is given by the formula;

[tex] Weight, W = mg[/tex]

Where;

Substituting into the equation, we have;

[tex] 15300 = m*9.8[/tex]

[tex] m = \frac {15300}{9.8}[/tex]

Mass, m = 1561.23 Kg

Therefore, the mass of the car is 1561.23 kilograms.

The work done by the force sill be 600 joules and the increase in kinetic energy will be same as 600 joules.

Work done by a force is defined as the dot product of the force and the displacement caused by it. Mathematically -

W = F . d

W = |F| x |d| x cos Ф

Given is net Force Of 60 N that accelerates a 4 kg Mass Over A Distance of 10 meter.

We can calculate the work done by the formula discussed above. Therefore -

W = F . d

W = |F| x |d| x cos(0)

W = 60 x 10

W = 600 joules

Now, using the work - energy theorem, the change in kinetic energy is equal to work done. Therefore -

ΔE[K] = W = 600 joules

Therefore, the work done by the force sill be 600 joules and the increase in kinetic energy will be same as 600 joules.

To solve more questions on work done, visit the link below-

https://brainly.com/question/13865035

#SPJ2

Explanation:

Time=distance/speed

=600/50

=12

=600/60=10

==12-10=2 hours

Answer:

nuclear fusion

Explanation:

The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons

Answer:

Nuclear fusion

Explanation:

PICK ME AS BRAINLIEST

Answer:10

Explanation:

You have to do speed divided by time so your answers 10

Answer:

The branch of applied mathematics dealing with motion and forces producing motion is called mechanics.

Answer:

Para que la masa del proton sea 1 kg se requieren alrededor de 6x10²⁶ protones.

Explanation:

Sabiendo que la masa del proton es:

[tex]m_{p} = 1,67 \cdot 10^{-27} kg[/tex]

Entonces para que la masa sea 1 kg tenemos:

[tex] 1 kg = N*m_{p} [/tex]

En donde N es el número de protones.

[tex]N = \frac{1 kg}{1,67 \cdot 10^{-27} kg} = 6 \cdot 10^{26}[/tex]

Por lo tanto, para que la masa del proton sea 1 kg se requieren alrededor de 6x10²⁶ protones.

Espero que te sea de utilidad!  

Answer:

The dilation of time.

The falling of objects.

The changing of paths of light.

Explanation:

I have explained in the image attached below.

From the explanation, the correct ones are;

The dilation of time.

The falling of objects.

The changing of paths of light.

The answer you are looking for is approximately 9.4 m/s.

Solution/Explanation:

First, writing out the formula for the speed of an object, encompassing distance and time, in meters per second, or m/s,

S=D/T.

"S" stands for "Speed."

"D" stands for "Distance."

"T" stands for "Time."

Speed (S)=????

Distance (D)=100m.

Time (T)=10.6s.

Substituting the given values of the variables,

S=100m/10.6s.

100÷10.6=9.43396226415≈9.4.

So, therefore, the final answer is approximately 9.4 m/s.

I hope that this has helped answer your question. Good day to you.

Answer:

49m at 5 seconds, 98m at 10 seconds. the object will keep accelerating until an obstacle occurs or something blocks/stops it. (ex. the ground)

Answer:

the Noble gases

Explanation:

the Noble gases are atoms that do not easily react with or form bonds with other atoms

Explanation:

Variety in to an exercise program allows the body to adapt to many demands, from high intensity exercise to slow, steady state exercise. Variety is important in a fitness program because it allows for your body to be challenged on a consistent basis and to overcome a plateau.

Answer:DOWN a Group: Atomic radius INCREASES as you go DOWN a Group because each successive Period (row) has an additional occupied energy level. If you visualize the not 100% accurate but still useful Bohr model of the atom, you can think of it this way: each time you drop down a row, you add a "ring." ACROSS a Period: Atomic radius DECREASES as you go ACROSS a Period because the net nuclear charge increases (Huh?). Remember, it's the protons (+) in the nucleus that pull on or attract the electrons in the orbitals. Across a Period you are adding more and more protons pulling on electrons occupying the same orbitals. The overall effect is more pulling power in the same basic space. This draws the electrons in closer, making the overall atomic radius smaller at the right side of a Period.

Ionization Energy:

DOWN a Group: Ionization energy DECREASES as you go DOWN a Group because the farther the valence electrons are from the nucleus (pulling power of the protons) the less energy it costs another atom to steal them. ACROSS a Period: Ionization energy INCREASES as you go ACROSS a Period because atoms are getting ever closer to that magic "octet" rule for stability via the Noble Gas configuration. In plain speak - your frequent buyer punch card gets one step closer to the freebie each time you move closer to the right of the Periodic Table so you guard those punches more carefully. The atomic radius is getting smaller, too, so those protons do a great job of holding on tighter.

Electron Affinity:

Electron affinity is a bit outside the scope of this class so I'm not going to get into it too deeply, other than to point out the general trend.

DOWN a Group: Electron Affinity DECREASES (a tiny bit) as you go DOWN a Group because elements become slightly less attractive toward electrons. Father from the pull of those protons, remember?  ACROSS a Period: Electron Affinity INCREASES as you go ACROSS a Period because generally speaking (and remember, exclude the Noble Gases here) elements toward the right of the Periodic Table give off a great deal of energy when they gaining electrons to become more stable.

Electronegativity:

DOWN a Group: Electronegativity DECREASES as you go DOWN a Group because the valence electrons are increasingly farther away from the attraction of the protons in the nucleus. Less pull, less "desire" to grab other electrons. ACROSS a Period: Electronegativity INCREASES as you go ACROSS a Period because the number of protons (+ charges) in the nucleus increases. More protons in the nucleus means electrons are more strongly attracted to the nucleus.

Chemical Reactivity:

METALS

DOWN a Group: In METALS reactivity INCREASES as you go DOWN a Group because the farther down a Group of metals you go, the easier it is for electrons to be given or taken away, resulting in higher reactivity. ACROSS a Period: In METALS reactivity DECREASES as you go ACROSS a Period because though they still want to give away valence electrons they have more of them to get rid of, which requires more energy. Not as easy to blow off a little steam!

I can't help it, I just love this video on reactivity (however embellished the reactions) down the Alkali Metals. Top Gear (BBC) fans will recognize Richard "Hamster" Hammond as the narrator here. Enjoy!

Explanation:

Answer:

m/s is answer for your questions

more than mg

Explanation:

the pressure

Answer:

....

Explanation:

Answer:

What do you mean.

Explanation:

Answer:

a) t = 2.55s

b) [tex]v_{0x} = 9.80 m/s[/tex]

c) yes

Explanation:

In order to solve this problem, we can start by drawing a sketch of the situation so we can better visualize what the problem is about (see attached picture).

a)

For the first question. We are talking about a movement in two dimensions. So on the first question they are asking us for vertical movement. It will be uniformly accelerated, so we can use the following formula:

[tex]y_{f}=y_{0}+V_{0y}t+\frac{1}{2}at^{2}[/tex]

We know the following:

[tex]y_{f}=0[/tex]

[tex]y_{0} = 32m[/tex]

[tex]V_{0y}=0[/tex]

t=?

[tex]a=-9.81 m/s ^{2}[/tex]

With this data, we can simplify our equation, so we end up with:

[tex]y_{0}+\frac{1}{2}at^{2}=0[/tex]

so we can now substitute the data we know and solve for t:

[tex]32m-\frac{1}{2}(9.81 m/s^{2})t^{2}=0[/tex]

[tex](-4.905 m/s^{2})t^{2}=-32m[/tex]

[tex]t^{2} = \frac{-32m}{-4.905 m/s^{2}}[/tex]

[tex]t=\sqrt{6.52s^{2}}[/tex]

t = 2.55 s

b)

For part b, since we are talking about horizontal movement and we are neglecting drag, this means that his horizontal speed will be constant. So we can use the following formula:

[tex]V_{x}=\frac{x}{t}[/tex]

we know he most move a horizontal distance of 25 meters in a time of 2.55s so we get:

[tex]V_{x} = \frac{25m}{2.55s}[/tex]

[tex]V_{x}=9.80 m/s[/tex]

c) for part c, we can do the conversion between miles per hour to meters per second like this:

[tex]\frac{27mi}{1hr}*\frac{1hr}{3600s}*\frac{5280ft}{1mi}*\frac{0.3048m}{1ft}[/tex]

so the given initial speed is equivalent to:

12.07 m/s

this is greater than the minimum 9.80 m/s we need, so the skater will clear the pool at this speed.

(a) The time spent in air by the skateboarder is 2.56 s

(b) The initial speed needed by the skateboarder to clear the pool is 9.77 m/s.

(c)  The skateboarder with given initial speed of 27 mph will clear the pool since it is greater than minimum initial velocity required.

The given parameters;

The time spent in air by the skateboarder is calculated as follows;

[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 32}{9.8} } \\\\t =2.56 \ s[/tex]

The initial speed needed by the skateboarder to clear the pool is calculated as;

[tex]v = \frac{d}{t} \\\\v = \frac{25}{2.56} \\\\v = 9.77 \ m/s[/tex]

The initial speed of the skateboarder is m/s;

[tex]27 \ \frac{mile}{hour} \times \frac{1609.3 \ m}{1 \ mile} \times \frac{1 \ hr}{3600 \ s} = 12.07 \ m/s[/tex]

Thus, the skateboarder with given initial speed of 27 mph will clear the pool since it is greater than minimum initial velocity required.

Learn more here:https://brainly.com/question/14670531

Explanation:

length of pipe= 32 ft

wavelength of wave λ= 8.8 m

let f be frequency

we know velocity of wave v=λf

therefore, f=v/λ = 346/8.8 = 39.31 per second or hertz

time period = 1/f = 1/39.31 = 0.02543 seconds

The frequency of this sound will be 39.31-sec⁻¹or Hz. While the time period will be 0.02543 sec.

Frequency is defined as the number of repetitions of waves occurring in 1 second. Frequency is also defined as the number of cycles completed in 1 second. SI unit of frequency is Hz.

The given data in the problem is;

L is the length of pipe= 32 ft

λ is the  wavelength of wave= 8.8 m

f is the frequency=?

T is the time period=?

The frequency is fine as the ratio of the speed of wave and wavelength.,

[tex]\rm f= \frac{v}{\lambda} \\\\ \rm f= \frac{346}{8.8}\\\\ \rm f= 39.31 \ Hz[/tex]

The time period is guven as the inverse of the time period.

[tex]\rm T = \frac{1}{f} \\\\ \rm T = \frac{1}{39.31} \\\\ \rm T = 0.02543\ sec[/tex]

Hence the frequency of this sound will be 39.31-sec⁻¹or Hz. While the time period will be 0.02543 sec.

To learn more about the frequency reference to the link;

https://brainly.com/question/14926605