Calculate the percent composition of muscovite mica. Its chemical

formula is (KF)2(Al2O3)3(SiO2)6(H2O)

Answer:

Bothersome pollutants are pollutants that persist in water.

Explanation:

Bothersome pollutants are those pollutants that have deleterious effects on human health which are consistently lodged into water bodies. Bothersome pollutants include petroleum products, heavy metals, and toxic chemicals etc.

Many of these bothersome pollutants are non biodegradable. They accumulate at the bottom of the ocean thereby causing problems for aquatic organisms and disrupting the aquatic ecosystems in the ocean.

These bothersome pollutants are not soluble in water hence we can not just destroy them by dissolving them in water. They persist in the aquatic ecosystem and can even migrate from place to place thereby spreading pollution.

Answer:

Sorry for the lack of precision, if you have any questions you can consult me again.

Explanation:

Glycine is an amino acid, forms proteins and is also called in its molecular chemical formula as C2H5NO2

Answer:

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

[tex]Q_1=-Q_2[/tex]

Mass of steel= [tex]m_1[/tex]

Specific heat capacity of steel = [tex]c_1=0.452 J/g^oC[/tex]

Initial temperature of the steel = [tex]T_1=2.00^oC[/tex]

Final temperature of the steel = [tex]T_2=T=21.50^oC[/tex]

[tex]Q_1=m_1c_1\times (T-T_1)[/tex]

Mass of water= [tex]m_2= 105 g[/tex]

Specific heat capacity of water=[tex]c_2=4.18 J/g^oC[/tex]

Initial temperature of the water = [tex]T_3=22.00^oC[/tex]

Final temperature of water = [tex]T_2=T=21.50^oC[/tex]

[tex]Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))[/tex]

On substituting all values:

[tex](m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}[/tex]

Answer:

[tex]m_{steel}=24.9g[/tex]

Explanation:

Hello,

In this case, since the water is initially hot, the released heat by it is gained by the steel rod since it is initially cold which in energetic terms is illustrated by:

[tex]\Delta H_{water}=-\Delta H_{steel}[/tex]

That in terms of mass, specific heat and temperature change is:

[tex]m_{water}Cp_{water}(T_f-T_{water})=-m_{steel}Cp_{steel}(T_f-T_{steel})[/tex]

Thus, we simply solve for the mass of the steel rod:

[tex]m_{steel}=\frac{m_{water}Cp_{water}(T_f-T_{water})}{-Cp_{steel}(T_f-T_{steel})} \\\\m_{steel}=\frac{105mL*\frac{1g}{1mL}*4.18\frac{J}{g\°C}*(21.50-22.00)\°C}{-0.452\frac{J}{g\°C}*(21.50-2.00)\°C} \\\\m_{steel}=24.9g[/tex]

Best regards.

Answer: The theoretical mass of [tex]Na_2SO_4[/tex] is, 514 grams.

Explanation : Given,

Mass of [tex]H_2SO_4[/tex] = 355 g

Molar mass of [tex]H_2SO_4[/tex] = 98 g/mol

First we have to calculate the moles of [tex]H_2SO_4[/tex].

[tex]\text{Moles of }H_2SO_4=\frac{\text{Given mass }H_2SO_4}{\text{Molar mass }H_2SO_4}[/tex]

[tex]\text{Moles of }H_2SO_4=\frac{355g}{98g/mol}=3.62mol[/tex]

Now we have to calculate the moles of [tex]Na_2SO_4[/tex]

The balanced chemical equation is:

[tex]2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O[/tex]

From the reaction, we conclude that

As, 1 mole of [tex]H_2SO_4[/tex] react to give 1 mole of [tex]Na_2SO_4[/tex]

So, 3.62 mole of [tex]H_2SO_4[/tex] react to give 3.62 mole of [tex]Na_2SO_4[/tex]

Now we have to calculate the mass of [tex]Na_2SO_4[/tex]

[tex]\text{ Mass of }Na_2SO_4=\text{ Moles of }Na_2SO_4\times \text{ Molar mass of }Na_2SO_4[/tex]

Molar mass of [tex]Na_2SO_4[/tex] = 142 g/mole

[tex]\text{ Mass of }Na_2SO_4=(3.62moles)\times (142g/mole)=514g[/tex]

Therefore, the theoretical mass of [tex]Na_2SO_4[/tex] is, 514 grams.

Answer:

HSCN (aq) + H₂O(l)  ⇄  SCN⁻(aq)  +  H₃O⁺(aq)    Ka

SCN⁻ (aq) +  H₂O(l)  ⇄  HSCN (aq)  +  OH⁻(aq)    Kb

Explanation:

We identify the formula:

HSCN → hydrogen thiocyanate which is also known as Thiocyanic acid

HSCN (aq) + H₂O(l)  ⇄  SCN⁻(aq)  +  H₃O⁺(aq)    Ka

As an acid, it gives proton to the solution. It is a weak acid, because the Ka

Ka = [SCN⁻] . [H₃O⁺] / [HSCN]

As a weak acid, the thiocyanate ion, will be the conjugate strong base. In water It can make hydrolisis:

SCN⁻ (aq) +  H₂O(l)  ⇄  HSCN (aq)  +  OH⁻(aq)    Kb

As a base, it takes a proton from water.

Kb = [HSCN] . [OH⁻] / [SCN⁻]

H-S-C-N is the structure of hydro-thi-ocyanate.

1. combines with water, it produces the ion thiocyanate and the ion hydronium.

2. When thiocyanate combines with water, it produces the ion hydrogen thiocyanate and the ion hydroxy.

Find out more information about 'Thiocyanate'.

https://brainly.com/question/4948909?referrer=searchResults

Answer:

HCL, H2SO4 and HNO3 are strong acids.

NaOH, KOH and LiOH are strong bases.

H3PO4, CH3COOH and HF are weak acids.

NH4OH, N2H4 and Zn(OH)2 are weak bases.

Explanation:

HCL, H2SO4 and HNO3 are strong acids because they completely converted into ions and gives H ion in the solution while H3PO4, CH3COOH and HF are weak acids due to their half ionization in the solution. NaOH, KOH and LiOH are strong bases completely dissociate in the solution and give OH ion while NH4OH, N2H4 and Zn(OH)2 are weak bases which cannot dissociate completely and yield less amount of OH ions. when acid and base combine together, they exchange their partners produces salt and water.

Answer:

A) -4 for C in CH4

B) +4 for C in CO2

D) +1 for H in both CH4 and H2O

Hope this helped! :D

Covalent compounds are held together with an intra molecular attraction which is weaker than metallic bond

hence covalent compounds exist as liquids, gases and soft solids

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

Answer:

The correct answer is option c, that is, being neither precise nor accurate.

Explanation:

Obtaining the experimental values that come almost close to the true value is termed as accuracy. On the other hand, precision is obtaining experimental values continuously, which may come either far away or near to the true value.  

Based on the given information, it is clear that 0.554 grams, that is, the third value obtained from the experiment is showing some closeness to the true value, which is 0.567 grams. While, neither any of the other values are close or is coming near to the true value. This shows that the measurements are an illustration of being neither precise nor accurate.  

Answer:

B. ΔHreaction = ΔH°f reactants- ΔH°f products

Explanation:

Using Hess's law, it is possible to sum ΔH of several related reactions to find ΔH of a particular reaction.

Having in mind Hess's law, ΔH°f is defined as the change in enthalpy during the formation of 1 mole of substance from its constituent elements (That is, pure elements, mono or diatomics, that have a ΔH° = 0).

For example, in ΔH°f of H₂O, the equation is:

H₂(g) + 1/2O₂(g) → H₂O(g)

The constituent elements with ΔH°f = 0 are H₂(g) and O₂(g).

Now, using Hess's law, you can sum the ΔH°f of substance in a reaction as, for example:

NaOH + HCl → H₂O + NaCl. ΔHr

The ΔH°f for each substance in the reaction is:

NaOH: Na + 1/2H₂ + 1/2O₂ → NaOH (1)

HCl: 1/2H₂ + 1/2Cl₂ → HCl (2)

H₂O: H₂ + 1/2O₂ → H₂O (3)

NaCl: Na + 1/2Cl₂ → NaCl (4)

The algebraic sum of (3) + (4) is -(ΔH°f reactants):

H₂ + 1/2O₂ + Na + 1/2Cl₂ → NaCl + H₂O ΔH°f reactants

This reaction - {(1)+(2)} ΔH°f products

NaOH + HCl → H₂O + NaCl.

ΔHr = ΔH°f reactants- ΔH°f products

In the example, we obtain this relationship that can be expanded for all reactions. Thus, right answer is:

Answer:

Dear user,

Answer to your query is provided below

When small amount of acid was added to buffered solution, pH will change very less.

Explanation:

Buffer solution resists change in ph on adding small amount of acid or base but when we calculate the value of buffer capacity we take the change in ph when we add acid or base to 1 lit solution of buffer.This contradicts the definition of buffer solution.

Answer:

[tex]M_{CO_2}=0.01665M[/tex]

Explanation:

Hello,

In this case, the Henry's law allows us to relate the molar concentration and partial pressure of a solute (carbon dioxide) in a solution (solvent is water) by:

[tex]M_{CO_2}=H_{CO_2}p_{CO_2}[/tex]

Whereas we introduce the Henry constant, therefore, we can easily compute the molar solubility by:

[tex]M_{CO_2}=p_{CO_2}*H_{CO_2} =0.45atm*3.7x10^{-2}\frac{M}{atm}\\\\M_{CO_2}=0.01665M[/tex]

Regards.

Answer:

- 61.2°C = Initial T°

Explanation:

This is a calorimetry problem, where the heat from the water was gained by the marble.

Q = m . C . ΔT

where ΔT is final T° - initial T°, C is the specific heat and m, mass.

By the volume of water, we realize the mass (we apply density):

1 g/mL = mass / 38.7 mL

38.7 g = mass of water

Now, we need to find out the specific heat for the marble and we have Heat Capacity data

Heat Capacity = C . m

3.52 J/°C / 4 g = C → specific heat → 0.88 J/g °C

We make the equations for both heats:

m . C . ΔT from water = m . C . ΔT from the marble

38.7 g . 4.18 J/g°C ( 26.1°C - 28°C) = 4 g .  0.88 J/g °C . (26.1°C - Initial T°)

307.35 J = 4 g .  0.88 J/g °C . (26.1°C - Initial T°)

- 307.35 is a negative value, because the was has decreased the temperature, is a loss of heat, but we have to work with the positive number.

307.35 J / (4 . 0.88 °C/J) = 26.1°C - Initial T°

87.32°C = 26.1°C - Initial T°

- 61.2°C = Initial T°

Answer:

a. pH = 2.52

b. pH = 8.67

c. pH = 12.83

Explanation:

The equation of the titration between the benzoic acid and NaOH is:

C₆H₅CO₂H + OH⁻ ⇄ C₆H₅CO₂⁻ + H₂O    (1)

a. To find the pH after the addition of 20.0 mL of NaOH we need to find the number of moles of C₆H₅CO₂H and NaOH:

[tex] \eta_{NaOH} = C*V = 0.250 M*0.020 L = 5.00 \cdot 10^{-3} moles [/tex]

[tex] \eta_{C_{6}H_{5}CO_{2}H}i = C*V = 0.300 M*0.050 L = 0.015 moles [/tex]  

From the reaction between the benzoic acid and NaOH we have the following number of moles of benzoic acid remaining:

[tex]\eta_{C_{6}H_{5}CO_{2}H} = \eta_{C_{6}H_{5}CO_{2}H}i - \eta_{NaOH} = 0.015 moles - 5.00 \cdot 10^{-3} moles = 0.01 moles[/tex]

The concentration of benzoic acid is:

[tex] C = \frac{\eta}{V} = \frac{0.01 moles}{(0.020 + 0.050) L} = 0.14 M [/tex]

Now, from the dissociation equilibrium of benzoic acid we have:

C₆H₅CO₂H + H₂O ⇄ C₆H₅CO₂⁻ + H₃O⁺  

0.14 - x                            x                x

[tex] Ka = \frac{[C_{6}H_{5}CO_{2}^{-}][H_{3}O^{+}]}{[C_{6}H_{5}CO_{2}H]} [/tex]

[tex] Ka = \frac{x*x}{0.14 - x} [/tex]

[tex] 6.5 \cdot 10^{-5}*(0.14 - x) - x^{2} = 0 [/tex]   (2)  

By solving equation (2) for x we have:          

x = 0.0030 = [C₆H₅CO₂⁻] = [H₃O⁺]

Finally, the pH is:

[tex] pH = -log([H_{3}O^{+}]) = -log (0.0030) = 2.52 [/tex]

b. At the equivalence point, the benzoic acid has been converted to its conjugate base for the reaction with NaOH so, the equilibrium equation is:

C₆H₅CO₂⁻ + H₂O  ⇄  C₆H₅CO₂H + OH⁻     (3)

The number of moles of C₆H₅CO₂⁻ is:

[tex] \eta_{C_{6}H_{5}CO_{2}^{-}} = \eta_{C_{6}H_{5}CO_{2}H}i = 0.015 moles [/tex]

The volume of NaOH added is:

[tex] V = \frac{\eta}{C} = \frac{0.015 moles}{0.250 M} = 0.060 L [/tex]

The concentration of C₆H₅CO₂⁻ is:

[tex] C = \frac{\eta}{V} = \frac{0.015 moles}{(0.060 L + 0.050 L)} = 0.14 M [/tex]

From the equilibrium of equation (3) we have:

C₆H₅CO₂⁻ + H₂O  ⇄  C₆H₅CO₂H + OH⁻  

0.14 - x                              x               x

[tex]Kb = \frac{[C_{6}H_{5}CO_{2}H][OH^{-}]}{[C_{6}H_{5}CO_{2}^{-}]}[/tex]

[tex] (\frac{Kw}{Ka})*(0.14 - x) - x^{2} = 0 [/tex]

[tex] (\frac{1.00 \cdot 10^{-14}}{6.5 \cdot 10^{-5}})*(0.14 - x) - x^{2} = 0 [/tex]

By solving the equation above for x, we have:

x = 4.64x10⁻⁶ = [C₆H₅CO₂H] = [OH⁻]

The pH is:

[tex] pOH = -log[OH^{-}] = -log(4.64 \cdot 10^{-6}) = 5.33 [/tex]

[tex] pH = 14 - pOH = 14 - 5.33 = 8.67 [/tex]

c. To find the pH after the addition of 100 mL of NaOH we need to find the number of moles of NaOH:

[tex] \eta_{NaOH}i = C*V = 0.250 M*0.100 L = 0.025 moles [/tex]

From the reaction between the benzoic acid and NaOH we have the following number of moles remaining:                              

[tex] \eta_{NaOH} = \eta_{NaOH}i - \eta_{C_{6}H_{5}CO_{2}H} = 0.025 moles - 0.015 moles = 0.010 moles [/tex]                          

The concentration of NaOH is:

[tex] C = \frac{\eta}{V} = \frac{0.010 moles}{0.100 L + 0.050 L} = 0.067 M [/tex]

Therefore, the pH is given by this excess of NaOH:         

[tex] pOH = -log([OH^{-}]) = -log(0.067) = 1.17 [/tex]

[tex] pH = 14 - pOH = 12.83 [/tex]

I hope it helps you!    

Answer: The hydroxide ion concentration in a solution is [tex]1\times 10^{10}M[/tex]

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

[tex]pH=-\log [H^+][/tex]

[tex]HCl\rightarrow H^++Cl^{-}[/tex]

According to stoichiometry,

1 mole of [tex]HCl[/tex] gives = 1 mole of [tex]H^+[/tex]

Thus [tex]1\times 10^{-4}[/tex] moles of [tex]HCl[/tex] gives =[tex]\frac{1}{1}\times 1\times 10^{-4}=1\times 10^{-4}[/tex] moles of [tex]H^+[/tex]

[tex]K_w=[H^+][OH^-][/tex]

[tex]10^{-14}=[1\times 10^{-4}][OH^-][/tex]

[tex][OH^-]=1\times 10^{10}M[/tex]

Thus the  hydroxide ion concentration in a solution is [tex]1\times 10^{10}M[/tex]

Answer:

The reaction moves to the left. To the reactants side

Explanation:

The reaction given by the problem is:

[tex]N_2_(_g_)~+~3H_2_(_g_)~<=>~2NH_3_(_g_)[/tex]

Therefore the equilibrium constant expression would be:

[tex]K_e_q=\frac{[NH_3]^2}{[N_2][H_2]^3}[/tex]

With the values equilibrium concentration values we can calculate the quotient "Qc", so:

[tex]Q_c=\frac{[5.27X10^-^4]^2}{[1.97X10^-^2][3.82X10^-^2]^3}=0.251[/tex]

In this case Qc>Kc we will have more amount of product. Therefore, the reaction will go to the left to reach the equilibrium.

I hope it helps!

Answer:

The translational rms speed of the sulfur dioxide molecules. vrms = 52.8 m/s

Explanation:

The root-mean-square speed is the measure of the speed of particles in a gas.  It is given by the formula below;

vrms=√3RT/M

where vrms is the root-mean-square of the velocity, M is the molar mass of the gas in kilograms per mole, R is the molar gas constant, and T is the temperature in Kelvin.

Molar mass of SO₂ in Kg/ mole = (64/1000) Kg/mol = 0.064 kg/mol

R = 8.314 m³.Pa/K*mol

T = ?

Using PV = nRT to find T

T = PV/nR

Substituting for T in the rms formula

vrms = √(3R*PV/nR)/M

vrms = √3PV/nM

vrms = √3 * 2.27 * 10⁴ * 57.9)/418 * 0.064

vrms = 52.8 m/s

Answer:

[tex]\% O=27.6\%[/tex]

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

[tex]n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC[/tex]

- Moles of hydrogen are contained in the 3.922 grams of water:

[tex]n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH[/tex]

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

[tex]m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO[/tex]

Finally, we compute the percent by mass of oxygen:

[tex]\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%[/tex]

Regards.

Answer:

-224ºC

Explanation:

Answer:

-224c

Explanation:

Answer:

All matter is in continual random motion.

Explanation:

Because Kinetic Molecular theory is based on a principle idea that tiny particles such as gas particles are always in motion.

Answer:

All matter is in continual random motion.

Explanation:

Explanation:

a. Adding a catalyst

no effect .( Catalyst can only change the activation energy but not the free energy).

b. increasing [C] and [D]

Increase the free energy .

c. Coupling with ATP hydrolysis

decrease the free energy value .

d.Increasing [A] and [B]

decrease the free energy.

Answer:

Butter  

Explanation:

Assume you have a table like the one below.

It tells you the mass of each type of fat in a 14 g sample of food.

Start at the top of the Monounsaturated Fat column.

Go straight down until you reach the smallest number in the column (3.7).

Then, move horizontally left until you reach the Food column.

The food with the least amount of monounsaturated fat is butter.

Answer:

Water, air, and food.

Explanation:

All living things need air water and food to live.

Answer:

the first the Question is what do you need to live then that your answer

food,water,air ;]

Answer:

Explanation:

1 ST METHOD

GIVEN DATA:

number of molecules=6.022×10²²molecules

Avogodro's number Na=6.022×10²²

TO FIND:

number of moles

SOLUTION:

As we knom that number of moles=number of molecules/Na

number of moles=6.022×10²²/6.022×10²²

number of moles=1 moles

2ND METHOD:

AS WE KNOW THAT A MOLE OF A SUBSTANCE CONTAINS 6.022×10²² PARTICLES OF THAT SUBATANCE SO

1MOLE OF CO2=6.022×10²²MOLECULES OF CO2

Answer:

The least whole number coefficient for HNO₃ is 6

Explanation:

The chemical equation above is the reaction between calcium orthophosphate and nitric acid.

To balance a chemical equation, we have to consider law of conservation of matter which states that matter can neither be created nor destroyed.

What this law implies is that, whatever we have at the reactant side must be equal to whatever is obtainable at the product side.

The above equation is

Ca₃(PO₄)₂ + HNO₃ → Ca(NO₃)₂ + H₃PO₄

To balance the equation, we'll have to check the number of atoms at each side and possibly balance the equation with the number of moles.

The balanced equation is

Ca₃(PO₄)₂ + 6HNO₃ → 3Ca(NO₃)₂ + 2H₃PO₄

From the balanced equation above, we can see that the number of calcium (Ca), Phosphorus (P), Oxygen(O), Nitrogen(N) and hydrogen (H) are balanced at both sides of the equation.

The least number coefficient for HNO₃ is 6

Answer:

6 electrons

Explanation:

:)

hope this helps :))))))))

Answer:

each p shell can hold max. 6 electorns

i dont know what a q shell is