Calculate the number of moles of aluminum, sulfur, and oxygen atoms in 3.00 molesmoles of aluminum sulfate, Al2(SO4)3Al2(SO4)3. Express the number of moles of AlAl, SS, and OO atoms numerically, separated by commas.

Answers

Answer 1

Answer:

[tex]n_{Al}=6.00molAl\\\\n_{S}=9.00molS\\\\n_{O}=36.0molO[/tex]

Explanation:

Hello!

In this case, when analyzing the moles of an element inside a compound, we need to keep in mind that a mole ratio should be set up; thus, for aluminum sulfate, we have the following ones:

[tex]\frac{2molAl}{1molAl_2(SO_4)_3} \\\\\frac{3molS}{1molAl_2(SO_4)_3} \\\\\frac{12molO}{1mol1molAl_2(SO_4)_3}[/tex]

Thus, starting by 3.00 moles of aluminum sulfate, the moles of each element turn out:

[tex]n_{Al}=3.00molAl_2(SO_4)_3*\frac{2molAl}{1molAl_2(SO_4)_3} =6.00molAl\\\\n_{S}=3.00molAl_2(SO_4)_3*\frac{3molS}{1molAl_2(SO_4)_3} =9.00molS\\\\n_{O}=3.00molAl_2(SO_4)_3*\frac{12molO}{1molAl_2(SO_4)_3}=36.0molO[/tex]

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Related Questions

The density of gold is 19.3 g/cm³. Which of the following shows the mass of a gold bar that is 4.50 cm × 8.00 cm × 20.00 cm?

Answers

Answer:

13896g

Explanation:

volume = 4.50×8.00×20.00 = 720 cm³

mass = density × volume

mass= 19.3 × 720 = 13896g

Please help me ASAP I’ll mark Brainly

Answers

Answer:

Batteries hold chemical energy

Explanation:

The battery acid in a battery leads to chemical energy.

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