calculate the number of moles equivalent to 12.7 gram of iodine molecule ​

Answer:

Scientists use  models to represent data/evidence. However, all models have limitations. However, models are simplified versions of reality, and can't be totally accurate in representation.

Hope this helps :)

Answer:

Since models are simpler than real objects or systems, they have limitations. ... It may not predict the behavior of the real system very accurately. But the more computing power that goes into the model and the care with which the scientists construct the model can increase the chances that a model will be accurate.

Answer:

d.molecules.its the answer.

Answer: B. molecules

Explanation:

it is the answer

Answer:

3 bonds

Explanation:

solve this by doing the lewis structure for CIO3

Answer:

3 bonds.

Explanation:

2 double bonds and one single bond.

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☃️ Chemical formulae ➝ [tex]\sf{CaCO_3}[/tex]

How to find?

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

[tex] \boxed{ \sf{No. \: of \: moles = \frac{given \: weight}{molecular \: weight} }}[/tex]

And, Then we need to find the number of molecules which can be found by:

[tex] \large{ \boxed{ \sf{no. \: of \: molecules = N_A \times no. \: of \: moles}}}[/tex]

Here, Na = Avagadro Number (6.022 × 10²³)

☀️ As it is a compund, We considered molecules. Then, we can predict the no. of atoms of elements in one molecule of compound and get the answer.

Solution:

Atomic weight of elements:

❍ Molecular weight of [tex]\sf{CaCO_3}[/tex]

= 40 + 12 + 3 × 16

= 52 + 48

= 100 g/mol

❍ Given weight: 10 g

Then, no. of moles,

⇛ No. of moles = 10 g / 100 g mol‐¹

⇛ No. of moles = 0.1 moles

☄ No. of moles of Calcium carbonate in the given weight = 0.1 moles

Finding no. of molecules,

⇛ No. of molecules of CaCO3 = 0.1 × 6.022 × 10²³

⇛ No. of molecules of CaCO3 = 6.022 × 10²²

Now,

Then, 6.022 × 10²² molecules will have,

= 3 × 6.022 × 10²² atoms of oxygen

= 18.022 × 10²² atoms of oxygen

In more scientific form,

= 1.8022 × 10²³ atoms of oxygen

☄ Hence, Final answer - 1.8022 × 10²³ atoms

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Answer: C.

whether it can be separated into simpler substances through physical separation techniques

Explanation:

A heterogeneous mixture is colloidal if

A heterogeneous mixture is suspension if

So, the criteria are responsible for deciding whether a heterogeneous mixture is a colloid or a suspension is "whether it can be separated into simpler substances through physical separation techniques".

So, the correct answer is "c".

The strength of the bond is based on electronegativity difference between atoms ,larger the difference stronger is the bond.The strongest bond is that of HF.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms combine as per their electronegativity which gives bond different strengths.The electronegativity is largest between hydrogen and fluorine .Thus, HF has the strongest bond.

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Answer:

Galileo Galilei

What launched the era of modern science in the 17th century? Modern science began in the 17th century, when the Italian physicist Galileo Galilei revived the Copernican view.

hope this helps

Explanation:

Answer:

Explanation:

What launched the era of modern science in the 17th century? Modern science began in the 17th century, when the Italian physicist Galileo Galilei revived the Copernican view.

Answer:

1. Define the problem

2. Conduct a literature search

3. Propose a hypothesis

4. Devise an experiment to prove or disprove

5. State conclusions

Explanation: In order to begin an experiment, you must first define a problem or question that you will be answering. Then you must research the problem in order to form a hypothesis, or an educated guess. Then you should devise and execute an experiment to answer your question. The conclusions that you draw will either prove or disprove your hypothesis. Hope this helps!

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☃️ Chemical formulae ➝ [tex]\sf{Ca_3(PO_4)_2}[/tex]

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

[tex] \boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}[/tex]

Atomic weight of elements:

❍ Molecular weight of [tex]\sf{Ca_3(PO_4)_2}[/tex]

= 3 × 40 + 2 × 31 + 8 × 16

= 120 + 62 + 128

= 310 g/mol

❍ Given weight: 20 g

Then, no. of moles,

⇛ No. of moles = 20 g / 310 g mol‐¹

⇛ No. of moles = 0.0645 moles

⚘ No. of moles of Calcium phospate in the given weight = 0.0645 moles.

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Answer:

Explanation:

To find the number of moles in calcium phosphate we use the formula

[tex]n \: = \frac{m}{M} [/tex]

where

n is the number of moles

M is the molar mass

m is the mass of the substance

To find the number of moles we must first find the molar mass

Chemical formula for calcium phosphate is

Ca3( PO4)2

Ca = 40 , P = 31 , O = 16

So the Molar mass of calcium phosphate is

M( Ca3( PO4)2 ) = (20×3) + 2( 31 + (16×4)

= 60 + 2( 31 + 64)

= 60 + 2(95)

= 60 + 190

Molar mass of calcium phosphate =

250g/mol

Mass = 20 g

So we have

[tex]n = \frac{20g}{250g/mol} [/tex]

We have the final answer as

Hope this helps you

Answer:

acquired/harmful

Explanation:

This type of mutation and exposure will cause indefinite problems.

Answer:D. Is the correct answer

Explanation:

Following are the calculation of the lead (Pb) atoms:

Balanced reaction:  

[tex]\bold{3PbO+2NH_3\longrightarrow 3Pb+N2+3H2O}\\\\[/tex]

[tex]\bold{mol\ NH_3 \longrightarrow mol \ Pb \longrightarrow atoms \ Pb}[/tex]

Calculating the number of atoms in Pb that will be generated:

[tex]=5.38 \ mol \ NH_3 \times \frac{3\ mol\ Pb}{2 \ mol NH_3} \times \frac{6.022 \times 10^{23} \times pb}{1 \ mol \ pb}\\\\ = 4.86 \times 10^{24} \ atoms\ in \ Pb\\\\= 4.86 \times 10^{24} \ atoms \\[/tex]

Therefore, the answer is "Option D"

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Answer:

A precipitate is formed

Explanation:

Answer:

It also helps them understand how life works. It even helps them predict how new materials will behave. In 1869, Dmitri Mendeleev, a Russian chemist, proposed the periodic law and his first periodic table. He published this periodic table two years later in a textbook, The Principles of Chemistry.

Explanation:

Answer:

Dmitri Mendeleev, To summarize, the periodic table is important because it is organized to provide a great deal of information about elements and how they relate to one another in one easy-to-use reference. The table can be used to predict the properties of elements, even those that have not yet been discovered

Explanation:I have already done this

Answer:

D) Ether

Explanation:

Ethers are oxygen atoms bonded between two carbon atoms. Also, I just took the test :)

CH2OCH2 is an organic compound with an oxygen atom bonded between the two carbon atoms, and it is not very soluble in water is an ether compound.

So, option D is correct one.

An ether is the functional group of organic compound in which one oxygen atom bonded by two alkyl group or aryl group is called an ether.

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Answer:

Explanation:

Physical hazard means a chemical for which there is scientifically valid evidence that it is a combustible liquid, a compressed gas, explosive, flammable, an organic peroxide, an oxidizer, pyrophoric, unstable (reactive) or water-reactive.

EXPLODE:  

to expand with force and noise because of rapid chemical change or decomposition, as gunpowder or nitroglycerine (opposed to implode).

to burst, fly into pieces, or break up violently with a loud report, as a boiler from excessive pressure of steam.

Answer:

pseudocience consists of statements, belief or practices that are claimed to be both scientific and factual but are incompatible with the scientific method.

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