Calculate the mass percent composition of iron for the third one of these iron ores.
Iron is mined from the earth as iron ore. Common ores include Fe2O3 (hematite), Fe3O4 (magnetite), and FeCO3 (siderite).

Answers

Answer 1

Answer:

[tex]\% Fe=48.2\%[/tex]

Explanation:

Hello!

In this case, since the percent composition of an element in a compound is given by:

[tex]\% i =\frac{z_i*m_i}{MM}*100\%[/tex]

Whereas i represent the element in the compound for which we want compute the mass percent. As required for siderite, FeCO3 whose molar mass is 115.854 g/mol, and knowing there is one iron atom there with an atomic mass od 55.85 g/mol, the mass percent of iron there is:

[tex]\% Fe=\frac{1*55.85}{115.854}*100\%\\\\\% Fe=48.2\%[/tex]

Best regards!


Related Questions

Which of these lead (II) salts will dissolve to the greatest extent in water?

a. PbSO4, Ksp = 1.7x10^-8
b. PbI2, Ksp = 6.5x10^-9
c. PbCrO4, Ksp = 1.8x10^-14
d. PbS, Ksp = 2.5x10^-27
e. Pb3(AsO4)2, Ksp = 4.0x10^-36

Answers

Answer:

a. PbSO4, Ksp = 1.7x10^-8.

Explanation:

Hello!

In this case, since the solubility product indicates how likely a solid is able to ionize and consequently dissolve in water, we can infer that the larger the solubility product Ksp, the more ions are able dissolve in water; therefore the proper answer goes with the largest Ksp, which is a. PbSO4, Ksp = 1.7x10^-8 since the power goes closer to 1 than the other options.

Best regards!

What are three ways that we can identify when a chemical reaction is occurring?

Answers

Three ways (out of the many) are:

Change of temperature
Color change
Formation of gas

Hope this helps!! (:

1. 2Al(s) + 3H2SO4(aq) → Al2(SO4)3(aq) + 3H2(g) a. Determine the volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum to produce aluminum sulfate. b. Determine the % yield if 112 g of aluminum sulfate is produced under the above conditions.

Answers

Answer:

a. 167 mL b. 39.27 %

Explanation:

a. From the chemical equation. 2 mole of Al reacts with 3 mole H₂SO₄ to produce 1 mol  Al₂(SO₄)₃.

Now, we calculate the number of moles of Al in 45.0 g Al.

We know number of moles, n = m/M where m = mass of Al = 45.0 g and M = molar mass of Al = 26.98 g/mol.

So n = 45.0 g/26.98 g/mol = 1.668 mol

Since 2 mole of Al reacts with 3 mole H₂SO₄, then 1.668 mole of Al reacts with x mole H₂SO₄. So, x = 3 × 1.668/2 mol = 2.5 mol

So, we have 2.5 mol H₂SO₄.

Now number of moles of H₂SO₄, n = CV where C = concentration of H₂SO₄ = 15.0 M = 15.0 mol/L and V = volume of H₂SO₄.

V = n/C

= 2.5 mol/15.0 mol/L

= 0.167 L

= 167 mL of 15.0 M H₂SO₄ reacts with 45.0 g Al to produce aluminum sulfate.

b. From the chemical reaction, 2 mol Al produces 1 mol Al₂(SO₄)₃

Therefore 1.668 mol Al will produce x mol  Al₂(SO₄)₃. So, x = 1 mol × 1.668 mol/2 mol = 0.834 mol

So, we need to find the mass of 0.834 mol  Al₂(SO₄)₃. Now molar mass  Al₂(SO₄)₃ = 2 × 26.98 g/mol + 3 × 32 g/mol + 4 × 3 × 16 g/mol = 53.96 g/mol + 96 g/mol + 192 g/mol = 341.96 g/mol.

Also number of moles of  Al₂(SO₄)₃, n = mass of  Al₂(SO₄)₃,m/molar mass  Al₂(SO₄)₃, M

n =m/M

So, m = nM = 0.834 mol × 341.96 g/mol = 285.2 g

% yield = Actual yield/theoretical yield × 100 %

Actual yield = 112 g, /theoretical yield = 285.2 g

So, % yield = 112 g/285.2 g × 100 %

= 0.3927 × 100 %

=  39.27 %

The volume (mL) of 15.0 M sulfuric acid needed to react with 45.0 g of aluminum is 166mL and % yield of the reaction is 39.46%.

How do we calculate moles?

Moles of any substance will be calculated by using the below formula as:
n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is :

2Al(s) + 3H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3H₂(g)

Moles of 45g of Al will be calculated as:

n = 45g / 27g/mol = 1.66 mole

From the stoichiometry of the reaction, it is clear that:

1.66 moles of Al = react with 3/2×1.66=2.49 moles of H₂SO₄

By using the formula of molarity we can calculate the volume of H₂SO₄ as:

M = n/V

V = (2.49) / (15) = 0.166L = 166mL

Again from the stoichiometry it is clear that:
1.66 moles of Al = produces 1/2×1.66= 0.83 moles of Al₂(SO₄)₃

Mass of 0.83 moles of Al₂(SO₄)₃ = (0.83mol)(341.96g/mol) = 283.82 g

Given actual yield of Al₂(SO₄)₃ = 112g

% yield will be calculated as:

Percent yield = (Actual yield/Theoretical yield) × 100

% yield = (112/283.82) × 100 = 39.46%

Hence required values are discussed above.

To know more about percent yield, visit the below link:

https://brainly.com/question/8638404


Mr. Juan is husband of Maria, before they get married Maria knows that her husband cannot make a baby since he cant produce sperm. But during their 2 years in marriage, Maria got pregnant. Is Juan can file a case to Maria? What it is? Support your answer?​

Answers

Answer:

yes but first he need to check himself

Explanation:

bcoz if he cannot produce a sperm than she might have cheated him and the baby might be of someone other.

Every element in group one has ______________ electron in its outer shell. Every element in group two has _______________ electrons in its outer shell.

need help

Answers

Every element in group one has 1 electron in its outer shell. Every element in group 2 has 2 electrons in its outer shell

A student pipets 5.00 mL of a 5.103 M aqueous NaOH solution into a 250.00 mL volumetric flask and dilutes up to the mark with distilled water. What is the final molarity of the dilute solution?

Answers

Answer:

0.102 M.

Explanation:

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 5 mL

Molarity of stock solution (M1) = 5.103 M

Volume of diluted solution (V2) = 250 mL

Molarity of diluted solution (V2) =?

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

M1V1 = M2V2

5.103 × 5 = M2 × 250

25.515 = M2 × 250

Divide both side by 250

M2 = 25.515 / 250

M2 = 0.102 M

Thus, the molarity of the diluted solution is 0.102 M.

The dilution of the NaOH results in the dilution of the molarity of the solution. The molarity of the final NaOH solution is 0.102 M.

What is molarity?

Molarity is the concentration unit that defines the amount of solute present in a liter of solution.

The dilution of the solution results in a change in the molarity. It can be accessed as:

[tex]\rm M_1V_1=M_2V_2[/tex]

The initial molarity of the solution is, [tex]\rm M_1=5.103\;M[/tex]

The initial volume of the NaOH is, [tex]\rm V_1=5\;mL[/tex]

The final volume of the NaOH is, [tex]\rm V_2=250\;mL[/tex]

Substituting the values for the calculation of final molarity, [tex]\rm M_2[/tex]:

[tex]\rm 5.103\;\M\;\times\;5.0\;mL=M_2\;\times\;250\;mL\\\\M_2=\dfrac{5.103\;\M\;\times\;5.0\;mL}{250\;mL} \\\\M_2=0.102\;M[/tex]

The molarity of the NaOH solution after dilution is 0.102 M.

Learn more about molarity, here:

https://brainly.com/question/12127540

Elements in the same period have _____ in common?


-

Answers

Answer:

The elements that have the same number of energy levels or the orbitals.

Explanation:

They have he same number -- energy levels

A solid substance was tested in the laboratory. The test results are listed below: 1.) dissolves in water 2.) is an electrolyte 3.) melts at a high temperature. Based on these results, the solid substance could be

Answers

Answer:

NaCl may be i guess so....

A solution is made by adding 5.01 g of iron sulfate to 75.3 g of water. What is the mass percentage of iron sulfate in this solution?

Answers

Answer:

6.24 % of FeSO₄

Explanation:

Solute mass: 5.01 g of FeSO₄

Solvent mass: 75.3 g of water

Solution mass = solute mass + solvent mass

5.01 g + 75.3 g = 80.31 g

We can apply a rule of three. Mass percentage means the mass of solute which is contained in 100 g of solution. Then,

In 80.31 g of solution we have 5.01 g of solute

In 100 g solution, we may have (5.01  . 100)/ 80.31 = 6.24 g of solute.

This is the mass percentage: 6.24%

Calculate the mass of zinc that reacts with 16.23 g of hydrochloric acid to form 15.2 g of zinc chloride and 18.97 g of hydrogen gas

Answers

Answer:

17.94 g

Explanation:

3. Theoretically how many grams of magnesium is required to produce to 5.0 g of

Magnesium oxide?

Answers

Answer:

3grams

Explanation:

The reaction for the production of Magnesium dioxide will be

Mg + O2  → MgO

we have 5g of MgO (molar mass 40g)

no of moles of MgO = 5/40 = 0.125

Using unitary method we have

1 mole of Mg require 1 mole of MgO

0.125 Mole of MgO = 0.125mole of Mg

n = given mass /molar mass

0.125 = mass / molar mass

mass = 0.125* 24 = 3grams

The properties of compund are different from the properties of their constituenr​

Answers

Answer: Atoms of carbon and hydrogen

Explanation:

Many materials, such as rocks, expand (get larger) when they are heated and contract (shrink) when they are cooled. This change
in size can cause cracks to form and break large rocks into smaller pieces.
In this example, what is caused by heating and cooling?
OA. decay
ОВ.
weathering
OC.
erosion
OD
earthquakes

Answers

Answer:

OB: weathering

Explanation:

the cycle of heating and cooling causes stresses called thermal fatigue, this causes the material to break down. In hand, weathering is a physical and chemical process that causes rocks and minerals on the Earth's surface to break down and decompose. Therefore, this matches the process you have described.

Answer:

weathering fun way to imagen it: just imagen u saw ur worst enemie and pretende it is the rock and the wind and ice and water are ur best friends THEN BAM wind and ice and water(ur best friends) make the rock(worst enemie) to dust :D

Which of the following belong to a category called the main group of elements
A halogens
B nonmetals
C alkaline metal
D transition elements

Answers

Answer:

C. Alkaline Metal ok thanks

C I hope it helps rkjnjjrnbejjje

how many atoms does sodium hypochlorite have?

Answers

Answer:

NaClO; the contained elements ae Na, Cl, O.

in which beakers are the particles moving the most slowly

Answers

Answer:

A and D

Explanation:

If 75J of heat are applied to 8.4 L of a gas at 732 mmHg and 298K, what is the final temperature, in K, of the gas? Cp for an ideal gas is 20.79 J/mol*K.

Answers

Answer:

309 K

Explanation:

Step 1: Convert the pressure to atm

We will use the conversion factor 1 atm = 760 mmHg.

732 mmHg × 1 atm/760 mmHg = 0.963 atm

Step 2: Calculate the moles (n) of the ideal gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 0.963 atm × 8.4 L/0.0821 atm.L/mol.K × 298 K

n = 0.33 mol

Step 3: Calculate the temperature change

We will use the following expression.

Q = n × Cp × ΔT

ΔT = Q/n × Cp

ΔT = 75 J/0.33 mol × 20.79 J/mol.K

ΔT = 11 K

Step 4: Calculate the final temperature

T = 298 K + 11 K = 309 K

DO NOT TROLL AND ANSWER WITHOUT THE CORRECT ANSWER! I EXPECT THE CORRECT ANSWER NOT A TROLL SO IF YOU DONT HAVE THE ANSWER DO NOT WRITE ANYTHING. IF YOU TROLL I WILL REPORT YOU

A weather balloon with a volume of 3.40774 L

is released from Earth’s surface at sea level.

What volume will the balloon occupy at an

altitude of 20.0 km, where the air pressure is

10 kPa?

Answer in units of L.

Answers

Answer:  The volume occupied at an altitude of 20.0 km is 34.5289 L

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

[tex]P\propto \frac{1}{V}[/tex]     (At constant temperature and number of moles)

where,

[tex]P_1[/tex] = initial pressure of gas = 101.325 kPa ( sea level)

[tex]P_2[/tex] = final pressure of gas = 10 kPa

[tex]V_1[/tex] = initial volume of gas = 3.40774 L

[tex]V_2[/tex] = final volume of gas = ?

Now put all the given values in the above equation, we get the final pressure of gas.

[tex]101.325\times 3.40774=10\times V_2[/tex]

[tex]V_2=34.5289L[/tex]

Therefore, the volume occupied at an altitude of 20.0 km is 34.5289 L

If the net force acting on an object is 0 N, the forces are

Answers

There won’t be any force since if the net force acting on an object is 0 N, inertia causes it to stay still, having no motion

Since the forces equal to 0, it's balanced because the object isn't moving.

if you a boy answer this question because............. idk

Answers

Answer:

no

Explanation:

What is the answer? Please

Answers

Answer:

Cell

Explanation:

I just passed this unit a month ago.

Answer:

It is 6. Cell

Explanation:

Cells make up the smallest level of a living organism such as yourself and other living things. The cellular level of an organism is where the metabolic processes occur that keep the organism alive. That is why the cell is called the fundamental unit of life.

I really hope this helped. God bless you and have a great day! :-)

Balance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)

Answers

Explanation:

C3H8+5O2----->3CO2+4H2O

Answer:

C3H8+5O2----->3CO2+4H2O

Explanation:

ONLY ANSWER IF YOU PLAY ADOPT ME ON ROB.LOX!!! tell me your best pet and user name in your answer plz.
READ!!!!! p.s. i have a fly ride T rex and more! also, STAY ON THE PAGE SO I COULD RESPOND AND WE COULD PLAY! yay!! :) :)

Answers

Answer:

I play!!!!!!!!

Explanation:

Which cannot be chemically broken down into simpler substances?
O compound
O element
O solution
O mixture

Answers

Answer:

an element.

Explanation:

it is the purest form

Answer:

b

Explanation:

A 50.0 mL solution of Ba(OH)2 is combined with a 150 mL solution of 0.20 M HCl. If the resulting solution has a hydroxide ion concentration of 0.12 M, what was the concentration of Ba(OH)2 in the original solution?

Answers

Answer:

0.54M of Ba(OH)2

Explanation:

When Ba(OH)2 reacts with HCl, BaCl2 and H2O are produced as follows:

Ba(OH)2 + 2HCl → BaCl2 + 2H2O

The remanent hydroxide ion is because not all Ba(OH)2 reacts. Thus, we need to find moles of Ba(OH)2 that doesn't react and moles of Ba(OH)2 that reacts. The ratio between total moles and volume of the Ba(OH)2 solution = 0.050L is the molarity of the original solution

Moles of Ba(OH)2 that doesn't react:

50mL + 150mL = 0.200L * (0.12 mol OH- / L) = 0.024 moles OH-

2 moles of OH- are in 1 mole of Ba(OH)2:

0.024 moles OH- * (1mol Ba(OH)2 / 2 mol OH-) = 0.012 moles Ba(OH)2

Moles of Ba(OH)2 that react:

0.150L * (0.20mol / L) = 0.030 moles HCl

2 moles of HCl react per mole of Ba(OH)2:

0.030 moles HCl * (1mol Ba(OH)2 / 2 mol HCl) = 0.015 moles Ba(OH)2

Total moles:

0.012mol + 0.015mol = 0.027mol Ba(OH)2 in 50mL

0.027mol Ba(OH)2 / 0.0500L =

0.54M of Ba(OH)2

why does 3-methylcyclohexene elute before
1-methylcyclohexene in gas chromatography?

Answers

Answer: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%. This is because 1-methylcyclohexene is the major product with the more stable carbocation intermediate and 3-methylcyclohexene is the minor product with the less stable carbocation intermediate.

Explanation: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%

How many atoms of phosphorus are in 5.70 mol of copper(II) phosphate?​

Answers

Answer:

Cu3 (PO4)2 contains a total of 2 atoms of phosphorus in just one molecule. (2.10 mol)(6.02214 x 10^23 atoms / mol)(2 phosphorous) = 2.53 x 10^24 atoms of phosphorous per molecule of copper i

Explanation:

Three isotopes of argon occur in nature. Calculate the average atomic mass of argon given the following relative atomic masses and abundances of each of the isotopes.

Isotope Relative Atomic Mass Abundance
Ar-36 35.97 amu 0.337%
Ar-38 37.96 amu 0.063%
Ar-40 39.96 amu 99.600%
a
35.97 amu
b
37.95 amu
c
39.95 amu
d
38.96 amu

Answers

Answer:

whats the question

Explanation:

Answer:

Calculate the average atomic mass of argon to two decimal places, given the following relative masses and abundances of each of the isotopes: argon-36 (35.97 amu; 0.337%), argon-38 (37.96 amu; 0.063%), and argon-40 (39.96 amu; 99.600%). ... So the atomic mass of Ar is 0.99639. 96 + 0.0006337. 96 + 0.00337*35.97 = 39.957.

Explanation:

hope this help

What is the difference between Mega and Milli symbols?

Answers

Gg
B o)))!hb. I I am Gn I’m ok
Lolkk lol h o
Look?ioooookonjj kk kkkkkkkkk has has always always always have s$$&&9999

Noooo I Ik ion ddxd
O
O
Sw n nun. Kkj

Answer:

Mega = 10^6

Milli = 10^-3

Explanation:

Mega is whatever times 10 to 6th power.

Milli is whatever times 10 to the -3rd power.

How many atoms are in 1.4 mol of phosphorus trifluoride (PF3)?

Answers

Number of atoms in 1.4 mol of Phosphorus trifluoride (PF₃) : 8.428 x 10²³

Further explanation  

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

1.4 mol of Phosphorus trifluoride (PF₃), number of atoms :

[tex]\tt N=1.4\times 6.02\times 10^{23}\\\\N=8.428\times 10^{23}[/tex]

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