Calculate the magnetic field at point P in the image below.

Calculate The Magnetic Field At Point P In The Image Below.

Answers

Answer 1

Answer:

B. 10.08

C.2448

Explanation:


Related Questions

A soccer player with a mass of 80.0 kg kicks a ball by applying a 20.0 N force. What force does the ball exert on the player?
A. 160. N
C. 2.50 N
B. 0.400 N
D. 20.0N

Answers

Answer:

F = 160.0 N

Explanation:

Given: Soccer payer with a mass = 80 kg, force = 20 N

To find: force

Formula: [tex]F=ma[/tex]

Solution: It is summarized by the equation: Force (N) = mass (kg) × acceleration (m/s²). Thus, an object of constant mass accelerates in proportion to the force applied.

F = m × a

F = 20 kg - 10 = 2  

F = 80 × 2 = 160

F = 160.0 N

Newtons are derived units, equal to 1 kg-m/s². In other words, a single Newton is equal to the force needed to accelerate one kilogram one meter per second squared.

A +26.3 uC charge qy is repelled by a force
of 0.615 N from a second charge 92 that is
0.750 m away. What is the value of 92?
Include the sign of the charge (+ or -).
(u stands for micro.)
[?] x 10-6 C

Answers

Answer:

+1.46×10¯⁶ C

Explanation:

From the question given above, the following data were obtained:

Charge 1 (q₁) = +26.3 μC = +26.3×10¯⁶ C

Force (F) = 0.615 N

Distance apart (r) = 0.750 m

Electrical constant (K) = 9×10⁹ Nm²/C²

Charge 2 (q₂) =?

The value of the second charge can be obtained as follow:

F = Kq₁q₂ / r²

0.615 = 9×10⁹ × 26.3×10¯⁶ × q₂ / 0.750²

0.615 = 236700 × q₂ / 0.5625

Cross multiply

236700 × q₂ = 0.615 × 0.5625

Divide both side by 236700

q₂ = (0.615 × 0.5625) / 236700

q₂ = +1.46×10¯⁶ C

NOTE: The force between them is repulsive as stated from the question. This means that both charge has the same sign. Since the first charge has a positive sign, the second charge also has a positive sign. Thus, the value of the second charge is +1.46×10¯⁶ C

Answer:

+1.46

Explanation:

acellus

A hydraulic system is lifting a 11760 N car using a cylinder with an area of 0.25 m
squared. What force is applied to the small cylinder if it has an area of 0.0125 m
squared?

Answers

Answer: 588 N

Explanation: pressure = force/area, or p = F/A. Then p1=p2

And F1//A1 = F2/A2 . F2 = F1·A2/A1 = 11760 N·0.0125 m²/ 0.25 m²

The left end of a long glass rod 9.00 cmcm in diameter, with an index of refraction 1.55, is ground and polished to a convex hemispherical surface with a radius of 4.50 cmcm. An object in the form of an arrow 1.52 mmmm tall, at right angles to the axis of the rod, is located on the axis 25.0 cmcm to the left of the vertex of the convex surface.
A) Find the position of the image of the arrow formed by paraxial rays incident on the convex surface. (answer is s1 in units cm)
B) Find the height of the image formed by paraxial rays incident on the convex surface. (answer is y1 in units mm)
C) Is the image erect or inverted?
I have tried solving this problem multiple ways and even referred to previous answers, but nothing seems to work. I will rate lifesaver for anyone who shows a correct explanation of how to solve and approach this problem. I greatly appreciate any help you can provide!

Answers

Answer:

A) s' = 18.85 cm

B) Height is 0.739 mm

C) the image is inverted.

Explanation:

We are given;

Diameter; D = 9 cm

Radius; R = d/2 = 9/2 = 4.5 cm = 0.045 m

Refractive Index of glass; n₂= 1.55

Height of object; y = 1.52 mm = 0.00152 m

Object distance s = 25 cm = 0.25 m

Now, Refractive index of air is 1 from online values.

Thus; n_1 = 1

A) To find the position of the image of the arrow formed by paraxial rays incident on the convex surface which is denoted by s', we will use the formula;

((n_1)/s) + n₂/s' = (n₂ - n_1)/R

Plugging in the relevant values, we have;

(1/0.25) + 1.55/s' = (1.55 - 1)/0.045

(1/0.25) + 1.55/s' = 12.222

1.55/s' = 12.222 - (1/0.25)

1.55/s' = 12.222 - 4

1.55/s' = 8.222

s' = 1.55/8.222

s' = 0.1885 m

s' = 18.85 cm

B) We will use the magnification formula to calculate the height of the image formed by paraxial rays incident on the convex surface denoted by y';

m = y'/y = -n_1•s'/n_2•s

Thus;

y' = -(y × n_1 × s')/(n_2•s)

y' = -(0.1885 × 1 × 0.00152)/(1.55 × 0.25)

y' = -0.739 mm

Height is 0.739 mm inverted.

C) Since the height of y' is negative, then it means the image is inverted.

20/05/2021
BP102T
- Which one of the following statements about reaction rate is false?
3253505030
Reaction rates are not sensitive to temperature.
Reaction rate is governed by the energy barrier between reactants and products.
Reaction rate is the speed at which the reaction proceeds.
Enzymes can accelerate the rate of a reaction.​

Answers

Answer:

Reaction rate are not sensitive to temperature.

applications of infrared wave​

Answers

Optical fibres, short range communication, electric cookers and infrared cameras/ security systems

Four point masses are connected by rods of negligible mass and form a square with sides of length 32.2 cm. Three of the masses are 1.5 kg and one is 3.0 kg. How far from the 3.0 kg mass is the center of mass of the system

Answers

Solution :

Placing the[tex]$3 \ kg$[/tex] mass at the [tex]$\text{origin}$[/tex] and line up the square up with the axes.

[tex]$x_{cm} = \frac{\sum_i x_i m_i}{\sum_i m_i }$[/tex]

     [tex]$=\frac{1.5 a + 1.5a +0 +0}{7.5}$[/tex]

     [tex]$=\frac{3a}{7.5}$[/tex]

    [tex]$=\frac{2a}{5}$[/tex]

[tex]$y_{cm} = \frac{\sum_i y_i m_i}{\sum_i m_i }$[/tex]

     [tex]$=\frac{1.5 a + 1.5a +0 +0}{7.5}$[/tex]

     [tex]$=\frac{3a}{7.5}$[/tex]

    [tex]$=\frac{2a}{5}$[/tex]

Therefore,  r = [tex]$\sqrt2 \left(\frac{2a}{5}\right)$[/tex]

                           [tex]$=\frac{2 \sqrt2}{5}a$[/tex]

It s given that the side of the square is a = 32.2 cm

So, r [tex]$=\frac{2 \sqrt2}{5}a$[/tex]

       [tex]$=\frac{2 \sqrt2}{5}\times 32.2$[/tex]

       = 18.21 cm

So the distance of the 3 kg mass from the center of mass, r= 18.21 cm


State the
the properties of magnets.

Answers

Answer:

All magnets have two poles: the North Pole and the South Pole.

Magnets attract ferromagnetic materials such as iron, nickel, and cobalt.

The magnetic force of a magnet is stronger at its poles than in the middle.

A freely suspended magnet always points in North-South direction.

Hope this helps

If the centripetal force is of the form m^a v^b r^c, find the values of a, b and c.

Answers

Answer with explanation:

what is a period in physics?

Answers

Answer:

The period of a wave is the time for a particle on a medium to make one complete vibrational cycle. Period, being a time, is measured in units of time such as seconds, hours, days or years. The period of orbit for the Earth around the Sun is approximately 365 days; it takes 365 days for the Earth to complete a cycle.

A clarinetist, setting out for a performance, grabs his 3.070 kg clarinet case (including the clarinet) from the top of the piano and carries it through the air with an upward force of 25.60 N. Find the case's vertical acceleration. Indicate an upward acceleration as positive and a downward one as negative. Use for =9.810 m/s2 for the acceleration due to gravity.

Answers

Answer:

the vertical acceleration of the case is 1.46 m/s

Explanation:

Given;

mass of the clarinet case, m = 3.07 kg

upward force applied by the man, F = 25.60 N

Apply Newton's second law of motion;

the upward force on the clarinet case = its weight acting downwards + downward force due to its downward accelaration

F = mg + m(-a)

the acceleration is negative due to downward motion from the top of the piano.

F = mg - ma

ma = mg - F

[tex]a = \frac{mg - F}{m} \\\\a = \frac{(3.07 \times 9.8) \ - \ 25.6}{3.07} \\\\a = 1.46 \ m/s^2[/tex]

Therefore, the vertical acceleration of the case is 1.46 m/s²

A boat of mass 650kg float on water, what volume of water does it displace?

Answers

Answer:

The weight of water displace is equal to the weight of boat i.e, 200kg.

Explanation:

oscillating spring mass systems can be used to experimentally determine an unknown mass without using a mass balance. a student observes that a particular spring-mass system has a frequency of oscillation of 10 Hz. the spring constant of the spring is 250 N/m. what is the mass?​

Answers

Answer:

Mass, m = 6.18 kg

Explanation:

Given the following data;

Frequency, F = 10 Hz

Spring constant, k = 250 N/m

We know that pie, π = 22/7

To find the mass, we would use the following formula;

F = 1/2π√(k/m)

Where;

F is the frequency of oscillation.

k is the spring constant.

m is the mass of the spring.

Substituting into the formula, we have;

10 = 1/2 * 22/7 * √250/m

10 = 22/14 * √250/m

Cross-multiplying, we have;

140 = 22 * √250/m

Dividing both sides by 22, we have;

140/22 = √250/m

6.36 = √250/m

Taking the square of both sides, we have;

6.36² = (√250/m)²

40.45 = 250/m

Cross-multiplying, we have;

40.45m = 250

Mass, m = 250/40.45

Mass, m = 6.18 kg

name the basic principle on which generators work.​

Answers

electromagnetic induction?

A car with a mass of 800 g and velocity of 15 m/s collided with a truck of a velocity of 20 m/s, if the momentum is conserved what is the mass of the truck?

Answers

Question: A car with a mass of 800 g and velocity of 15 m/s collided with a truck moving in opposite direction with a velocity of 20 m/s, if the momentum is conserved and they both move with a common velocity of 10 m/s, what is the mass of the truck?

Answer:

0.133 kg

Explanation:

Applying the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m')................... Equation 1

Where m = mass of the car, m' = mass of the truck, u = initial velocity of the car, u' = initial velocity of the truck, V = common velocity.

From the question,

Given: m = 800 g = 0.8 kg, u = 15 m/s, u' = -20 m/s, V = 10 m/s

Substitute these values into equation 2

(0.8*15)+(m'*20) = 10(0.8+m')

Solve for m'

12-20m' = 8+10m'

-20m'-10m' = 8-12

-30m' = -4

m' = -4/-30

m' = 0.133 kg

what is the kinetic energy of a bike with a mass of 16 kg traveling at 4m/s

Answers

Explanation:

answer is that i think???

We know that the frequency and wavelength of an oscillation are related by the velocity of the wave . In standing waves, the wave velocities of the different harmonics are the same.Think about why this may be and explain that in your notebook. (Hint: The wave velocity is dependent on the static properties of the oscillating object like mass per unit length and tension)

Answers

Answer

the medium does not change the speed of the on they should change.

Explanation:

The speed of the waves is constant for a given medium, depending on the physical properties of the medium,

When a wave is strapped on a wall of a medium it does not change the properties of the medium, the wave changes direction, but since the medium does not change the speed of the on they should change.

A wave has a frequency of 6 Hz and a speed of 30 m/s. What is the wavelength of the wave?
a) 180 m

b) 0.2 m

c) 36 m

d) 5 m

Answers

Answer:

D. 5m

Explanation:

fλ = c, where f is frequency, λ is wavelength and c is speed.

6λ=30

λ=30/6=5

which term describes the process of transferring charge without the direct contact

Answers

induction............

Solid pressure depends on?​

Answers

Answer:

The pressure of the solid on the surface depends on the area of contact. The area of contact between the two surfaces. The greater the force or the smaller the area the greater the pressure.

(credits to the rightful owner for these answers :)

One way to provide artificial gravity (i.e., a feeling of weight) on long space voyages is to separate a spacecraft into two parts at the ends of a long cable, and set them rotating around each other. A craft has been separated into two parts with a mass of 70600 kg each, at the ends of a cable with their centers of mass 155 m apart, rotating around the center point of the cable with a period of 385.3 seconds.
1) If the cable is reeled in so that the the centers of the two pieces are now only 119.35 m apart, what will the new period be?
2) What happens to the angular momentum L and kinetic energy K of the system consisting of both pieces of the space ship when the two pieces are pulled closer to the center?

Answers

Answer:

1)  T = 649.86 s, 2)   L₀ = L_f,   [tex]\frac{K_o}{K_f}[/tex] = 4.8

Explanation:

1) As the system of the two bodies is isolated, its angular momentum is conserved

             

initial instant.  r₀ = 155 m, T₀= 385.3 s

      L₀ = I₀ w₀

final instant. r = 119.35 m

      L_f = I w

      L₀ = L_f

      I₀ w₀ = I w

      w = [tex]\frac{I_o}{I} \ w_o[/tex]

let's consider each object as punctual

      I = m r²

at angle velocity and period are related

         w = 2pi / T

     

we substitute

      [tex]\frac{2\pi }{T} = \frac{m r^2}{m _o^2 } \ \frac{2\pi }{T_o}[/tex]

      [tex]\frac{1}{T} = ( \frac{r}{r_o} )^2 \ \frac{1}{T_o}[/tex]

       T = [tex](\frac{r_o}{r} )^2 \ T_o[/tex]

let's calculate

       T = [tex]( \frac{155}{119.35} )^2 \ 385.3[/tex]

        T = 649.86 s    

2) The angular momentum is conserved because the system is isolated.

Let's look for kinetic energy

        K_total = 2 K = 2 (½ I w²)

        K_total = I 4π² / T²

        K_total = 2m r² 4 π² / T²

 

for r = 155 m

         K₀ = 8π² m r₀² / T₀²

for r = 119.35 m

          K_f = 8π² m r² / T²

the relationship is

        [tex]\frac{K_o}{K_f} = ( \frac{r_o \ T}{ r \ \ T_o} )^2[/tex]

        [tex]\frac{K_o}{K} = ( \frac{ 155 \ \ \ 649.86}{ 119.35 \ 385.3})^2[/tex]

       [tex]\frac{K_o}{K_f}[/tex] = 4.8



The world record for the women's 100 m dash was set by Flo Jo (Florence Griffiths-Joyner) in
1988. During the race she generated 2,590 J of energy and ran a velocity of 9.53 m/s. What
was her mass?

Answers

florence Griffith-Joyner recorded a time 10.61 seconds (wind reading +1.2) in the final at the 1988 U.S. Olympic Trials the wind reading for this race is not in doubt, and the performance should be the official IAAF women's 100-m world record

When a massive star greater than 8 solar masses has its core filled with iron, the core can no longer continue fusion, and it becomes supported by electron degeneracy pressure for a while. When the mass of the accumulating iron becomes greater than 1.4 solar masses, what happens

Answers

I know if honest at this point right

If the hairdryer was put on full power, what would happen? Why?

Answers

Most hair dryers are in the 1800 watt range and lets assume you turned it to the highest speed and heat setting.

PLEASE MARK AS A BRAINLIST

It will heat up the air in the box, failry quickly. Rules of thermodynamics says that the heat will increase the temperature according to the rate of heat input minus the rate of heat loss from the box… due to conduction, radiation and convection (in this case none of the latter because the box is sealed).

HOPE IT WILL HELP YOU

The loss rate depends in the temperature difference and the thermal resistance. THicker and better insulation increases the resistance; larger area decreases the resistance. Eventually the heat (temperature) will rise and the difference between inside and outside will be so large that the temperature will rise no more. But in the case of a 1800 W hairdryer the temperature will exceed the melting point of plastics and wire insulation and if allowed to come to heat equilibrium will probably short out and catch fire or blow an external fuse.

Most modern hair dryers have a internal thermal fuse that cuts out at temperatures below the melting point and probably this will cut off the dryer before catastrophic meltdown. Its a one time fuse and not readily available, mostly you toss the dryer when the fuse goes

You are standing outside with two speakers. The temperature is 0 degrees C. The two speakers are playing sound of the same frequency: a pure sinusoidal sound of the same frequency at the same phase. The speakers are playing at different amplitudes. One speaker is 1.230 meters from you and one is 1.425 meters from you. You hear no sound. Which of the following is a possible frequency of the sound being played?

a. 993 Hz
b. 331 Hz
c. 4965 Hz
d. 1655 Hz
e. 662 Hz

Answers

Answer:

Explanation:

No sound is heard , that means there is destructive interference at the place where sound is heard .

Path difference of the source of sound = 1.425 m - 1.230 m

= 0.195 m

Let frequency of sound be n .

wave length = velocity of sound at 0°C / n

λ = 330 / n

for destructive interference ,

path difference = ( 2m+1) λ /2 , where λ is wave length of sound.

0.195 m = ( 2m+1) λ /2

0.195 m = ( 2m+1)330 / 2n

2n = 1692.3 (2m+1)

If m = 0

n = 846 . which is nearest to given frequency of 993 Hz

So 993 Hz is the answer.

Which has a greater momentum: a 0.0010 kg bullet going
250 m/s OR a 80 kg student walking at 4 m/s? Which has
more inertia? Which has more kinetic energy?

Answers

Answer:

Momentum is Mass x Velocity.

Its pretty obvious that the 80kg student Moving at 4ms-¹ has more momentum.

80x4 = 320kgms-1

0.001x250= 0.25kgms-¹

The Second student also Has More Inertia. Inertia is the resistance to motion offered by a Body. An Object with greater mass has more tendency to resist Motion .

So

The 80Kg student wins all.

Answer:

i think it is 80 kg

Explanation:

how many moles in 3.4x10^24 atoms calcium chloride

Answers

rounded to the tenth is 5.6 moles

What can be said about the reactants in an endothermic reaction? (1 point)
- They have more energy than the products because they absorb energy during the reaction.
- They have less energy than the products because they absorb energy during the reaction.
- They have less energy than the products because they release energy during the reaction.
- They have more energy than the products because they
release energy during the reaction.

If anyone has full physics b semester exam helpp

Answers

Answer:

in endothermic reactions, more energy is absorbed when the bonds in the reactants are broken than is released when new bonds are formed in the products! Endothermic reactions are accompanied by a decrease in temperature of the reaction mixture.

Answer:  They have less energy than the products because they absorb energy during the reaction.

Explanation: In an endothermic reaction, the products are higher in energy than the reactants. Therefore, the change in enthalpy is positive, and heat is absorbed from the surroundings by the reaction.

An endothermic process is any process with an increase in the enthalpy H of the system. In such a process, a closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system.

 

Pre-laboratory Assignment: Experiment 20 Reflection and Refraction of Light 1. When light is incident on a reflective surface, what can be said about the angle and speed at which the light is reflected? (Information is in your ‘General Physics Laboratory Manual’ Chapt. 20) 2. At what angle is the normal drawn to the reflective surface or air-medium interface? 3. How are angles of incidence, angles of reflection and of refraction measured? 4. Describe what happens to a light ray as it enters from a medium of greater refractive index to a medium of lesser refractive index

Answers

Answer:

1) ngle of incidence and reflection are equal,  light carries does not change

2) the angle of this line with respect to the surface is 90º

3) protractor

4)    n₂  sin θ₂ = n_1 sin θ₁,  light ray must have a greater angle than the incident ray ,

Explanation:

1) When light falls on a reflective surface, the angle of incidence and reflection are equal and as it travels in the same medium, the speed that the light carries does not change

2) The normal is a line perpendicular to the point of incidence of light, so the angle of this line with respect to the surface is 90º

3) Angles are measured with a protractor

4) When light passes from one medium to another, the speed of the ray changes due to the difference in the refractive index in each medium, due to this change in speed the transmitted light ray must have a greater angle than the incident ray , since the speed increases as the density of the medium decreases

           [tex]\frac{sin \theta _2}{ sin \theta_1} = \frac{v_2}{v_1}[/tex]

          [tex]\frac{c}{v_2} \ sin \theta_2 = \frac{c}{v_1} \ sin \theta_1[/tex]

          n₂  sin θ₂ = n_1 sin θ₁

Which of the following rays is NOT possible for a converging lens?

Answers

Ray B. isn't possible for a converging lens, because after passing through focus ot would go parallel to the principal axis,

So, Correct option is :

=》Option B.)

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