Answer:
[H⁺] = 6.17×10¯⁶ M
Explanation:
From the question given above, the following data were obtained:
pH = 5.21
Concentration of Hydrogen ion [H⁺] =?
The pH of a solution is defined by the following equation:
pH = –Log [H⁺]
With the above formula, we can obtain the concentration of Hydrogen ion [H⁺] in the solution as follow:
pH = –Log [H⁺]
5.21 = –Log [H⁺]
Divide both side by –1
–5.21 = Log [H⁺]
Take the antilog of –5.21
[H⁺] = Antilog (–5.21)
[H⁺] = 6.17×10¯⁶ M
Therefore, the concentration of Hydrogen ion [H⁺] in the solution is 6.17×10¯⁶ M
What is the oxidation state of nitrogen in Nz?
Answer:
the oxidation state of nitrogen is +5
10 ml of a 0.25M solution is diluted to make exactly 250 ml of solution. What's the concentration of the diluted solution?
Answer:
0.01 M
Explanation:
As this problem deals with a dilution process, we can solve it by using the following formula:
C₁V₁=C₂V₂Where subscript 1 stands for the initial concentration and volume, while 2 stands for the final conditions.
That means that in this case:
C₁ = 0.25 MV₁ = 10 mLC₂ = ?V₂ = 250 mLWe input the given data:
0.25 M * 10 mL = C₂ * 250 mLC₂ = 0.01 MHow many molecules are present in 4.5
moles of H2O?
Answer:
Mole of the H2O = 4.5
Number of molecules =4.5 multipled by avogadro's number.
Is it dangerous to remove gunpowder from firecracker
200.0g of a 3.0% NaF solution, how much distilled water do we weigh out?
197g of distilled water
194g of distilled water
140g of distilled water
170g of distilled water
Answer:
194g of distilled water.
Explanation:
Hello there!
In this case, according to the given information for this problem, it turns out possible for us to use the given mass of the solution and the percent by mass of NaF to firstly calculate the grams of this solute as shown below:
[tex]\%m=\frac{m_{solute}}{m_{solution}} *100\%\\\\m_{solute}=\frac{\%m*m_{solution}}{100\%} \\\\m_{solute}=\frac{3.0\%*200.0g}{100\%} \\\\m_{solute}=6g[/tex]
And finally, since the mass of solution is calculated by adding mass of solute and mass of solvent we obtain the mass of water (solvent) as follows:
[tex]m_w=200g-6g=194g[/tex]
Therefore, the answer is 194g of distilled water
Regards!
Use the equations below to calculate the enthalpy of formation for propane gas, C3H8, from its elements, hydrogen gas and solid carbon. Please hurry!!
Answer: I got -4542.9kg/mol
Explanation:
Using the enthalpy relation, the enthalpy of formation of propane gas in the given equation is 4542.9 kJ/mol
[tex] △H_{f} = Product [/tex]Using the enthalpy value of [tex] CO_{2} [/tex] and[tex] H_{2}0[/tex] given :
Product = [tex] 3CO_{2} + 4H_{2}0[/tex] Product = 3(-393.5) + 4(-285.8) = - 2323.70Reactant = [tex] C_{3}H_{8} + 5H_{2}0[/tex] Water, H20 has △H = 0Reactant = [tex] C_{3}H_{8} + 0[/tex]
Enthalpy of formation = product - Reactant
2219.2 = -2323.70 - (propane + 0)
2219.2 = - 2323.70 - propane
Propane = - 2323.70 - 2219.2
[tex] C_{3}H_{8} = - 4542.9 [/tex]
Therefore, the entalphy of formation of propane gas is - 4542.9 kJ/mol.
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What type of chemical reaction is represented by this balanced equation? S8(s)+802(g)-->8SO2(g)
Answer: I think it could be Decomposition
Explanation: I think is composition because decomposition starts by being together and ends up as two
What are the missing coefficients for H3PO4 + HCl = PCl5 + H2o
Answer:
H3PO4 + 5 HCl → PCl5 + 4 H2O
Explanation:
The given equation is
H3PO4 + HCl = PCl5 + H2O
The above chemical equation has one P atom on both the sides, hence phosphorus is balanced
There are 5 Cl on the RHS but only one Cl on the LHS. On balancing the chlorine, we get -
H3PO4 + 5HCl = PCl5 + H2O
Now, there are 8 hydrogen atom on the LHS but only two on the RHS. On balancing the hydrogen on both the sides, the new equation become
H3PO4 + 5HCl = PCl5 + 4H2O
Let us check for oxygen
Oxygen on LHS = 4 and oxygen on RHS = 4
Thus, the balanced equation is H3PO4 + 5HCl = PCl5 + 4H2O
For a reaction that has reactant A in its rate law, select which factor(s) affect the reaction rate of reactant A. Choose one or more: A. temperature B. change in concentration of a reactant C. catalyst D. change in concentration of a product E. physical state of the reactants
Answer:
Option B
Explanation:
The rate law is represented as
Rate of the reaction = [tex]k [A^x][B^y][/tex]
Here K is the rate constant
A is the concentration of substance A
B is the concentration of substance B
Hence, If reactant A is in the rate law equation, then if its concentration varies then it will impact the rate of the reaction
Hence, option B is correct
Why is a wire used to connect the electrodes in an electrochemical cell?
O A. To provide the metal that is the oxidizing agent
B. To prevent the flow of protons from electrodes
C. So ions can flow from one electrode to another
D. So electrons can flow from one electrode to another
Answer:
D. So electrons can flow from one electrode to another
Explanation:
An electrochemical cell is any cell in which electricity is produced by reason of a chemical change.
An electrochemical cell consists of two electrodes, these two electrodes are connected using a wire.
Usually, electrons flow from one electrode to another via this wire thereby enabling the electrochemical processes of oxidation and reduction in the cell to proceed effectively.
A sample of gas at 90 degrees Celsius occupies 15.5 L. This gas is heated to occupy a new volume of 20.3L. What is the new temperature of the gas?
Answer:
202 °C
Explanation:
From the question given above, the following data were obtained:
Initial temperature (T₁) = 90 °C
Initial volume (V₁) = 15.5 L
Final volume (V₂) = 20.3 L
Final temperature (T₂) =?
Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T₁) = 90 °C
Initial temperature (T₁) = 90 °C + 273
Initial temperature (T₁) = 363 K
Next, we shall determine the final temperature.
Initial temperature (T₁) = 363 K
Initial volume (V₁) = 15.5 L
Final volume (V₂) = 20.3 L
Final temperature (T₂) =?
V₁ / T₁ = V₂ / T₂
15.5 / 363 = 20.3 / T₂
Cross multiply
15.5 × T₂ = 363 × 20.3
15.5 × T₂ = 7368.9
Divide both side by 15.5
T₂ = 7368.9 / 15.5
T₂ ≈ 475 K
Finally, we shall convert 475 K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T₂ = 475 – 273
T₂ = 202 °C
Thus, the new temperature of the gas is 202 °C
Hl Weakly dissociates in water according to the chemical equation below. H20+ Hl <-> H3O^+ + l- What is a conjugate acid-base pair in this reaction?
Answer:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
Explanation:
https://www.clutchprep.com/chemistry/practice-problems/70217/hi-aq-h2o-l-h3o-aq-i-aq-identify-each-as-either-a-bronsted-lowry-acid-bronsted-l
Spread your smarts while you wait.
Answer:
lol ok 1+1=2 2 x 2=4
have a good day :)
Explanation:
Answer: oke
Explanation: have a goood day!
Which of the following would result in being able to dissolve a greater amount of gas in a solution?
Answer:
Lower the temperature of the solution
For each of the following compounds, decide whether the compound's solubility in aqueous solution changes with pH. If the solubility does change, pick the pH at which you'd expect the highest solubility. You'll find Ksp data in the ALEKS Data tab. compound Does solubility change with pH
Answer: Hello attached below is the complete question and using data from ALEKS data tab
answer:
PbCl₂ : Yes , PH = 3
CaC0₃ : Yes, PH = 3
AgCn : Yes , PH = 3 .
Explanation:
For PbCl₂
PbCl₂ solubility will change ( decrease ) with increase in PH, and the PH at which PbCl₂ will be most soluble is at PH = 3
For CaC0₃
Addition of -ions which increases the PH level will cause a decrease in the solubility of CaC0₃ hence the PH at which it will be most soluble in an aqueous solution is PH = 3
For AgCn
Increase in the PH level there would be a decrease in the solubility of AgCn hence the PH at which AgCn is most soluble ( highest solubility ) = 3
The ability of a solute to be able to dissolve is called solubility. Yes, at pH 3, the solubility of lead chloride, calcium carbonate, and silver cyanide.
What is solubility?The ability of the solute to get dissolved in a solvent to form a saturated solution is called solubility.
For lead chloride, the solubility will decrease as the pH will increase and is most soluble at a pH of 3.
For calcium carbonate, the addition of ions increases the pH will result in a decreased solubility, and will be most soluble at pH 3.
For silver cyanide increased pH decreases the solubility and is most soluble at a pH of three.
Therefore, solubility decrease with an increase in pH due to the concentration factor.
Learn more about solubility here:
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How many moles are in 3.87 x 10 ^24 molecules of carbon?
Answer:
1 mole contains 6.02⋅1023 particles
Explanation:
Explanation:
X×6.02⋅1023=3.75⋅1024→
X=3.75⋅10246.02⋅1023=0.623⋅101=6.23 moles
in an expirement a scientist should
Which substance is the best oxidizing agent?
A. NaOH
B. H2O
C. Xe
D. HCI
E. O3
Answer:
the answer is A.
Explanation:
Elemental fluorine, for example, is the strongest common oxidizing agent.
What is one movement that liquid water CANNOT do while on or at the Earth's surface? (GIVE RIGHT ANSWER OR I DELETE 100 POINTS)
Answer:
One movement that i can't do is float in mid air
Explanation:
Solve (2 x 10^3) + (7 x 10^5) *
Answer:
702000
Explanation:
(2 x 10^3) + (7 x 10^5)
=> 2 x 1000 + 7 x 100000
=> 2000 + 700000
=> 702000
The enthalpy of formation of water is -285.8 kJ/mol. What can be inferred from this statement? O The enthalpy of the products is equal to the enthalpy of the reactants. O Heat is absorbed during the process. O Heat is released during the process. The enthalpy of the products is more than the enthalpy of the reactants.
Answer:
the answer is c
Explanation:
i did the test
The enthalpy of the formation of water is -285.8 kJ/mol. The information that can be made by the statement is heat is released during the process. The correct option is C.
What is enthalpy?Enthalpy is the volume times the pressure times the internal energy of the system. It is an entity of thermodynamics. It is the measurement of the energy in a thermodynamic system. The enthalpy totals the internal energy plus pressure and volume.
The statement that is given here is given that enthalpy is -285.8 kJ/mol. The value is negative, so the energy is released here. When energy is gained the energy will be positive and when the energy is released it is negative.
Thus, the correct option is C, heat is released during the process regarding the given statement of enthalpy.
To learn more about enthalpy, refer to the link:
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#SPJ6
12. An electrolysis reaction is
A. hydrophobic.
B. spontaneous.
C. exothermic.
D. non-spontaneous.
Answer: D.) non-spontaneous.
Explanation:
By what factor does [OH- ] change when the pH increases by 1.7?
The heat of combustion per mole for acetylene, C2H2(g), is -1299.5 kJ/mol. Assuming that the combustion products are CO2(g) and H2O(l), and given that the enthalpy of formation is -393.5 kJ/mol for CO2(g) and -285.8 kJ/mol for H2O(l), find the enthalpy of formation of C2H2(g).
Answer: The heat of combustion per mole for acetylene is 227.7 kJ/mol.
Explanation:
The combustion equation of acetylene is as follows.
[tex]C_{2}H_{2} + \frac{5}{2}O_{2} \rightarrow 2CO_{2} + H_{2}O[/tex]
Formula to calculate enthalpy of formation for a reaction is as follows.
[tex]\Delta H^{o}_{rxn} = \sum \Delta H_{products} - \sum \Delta H_{reactants}\\\Delta H^{o}_{rxn} = [2\Delta H^{o}_{f}(CO_{2}) + \Delta H^{o}_{f} (H_{2}O)] - [\Delta H^{o}_{f}(C_{2}H_{2}) + \frac{5}{2} \Delta H^{o}_{f} O_{2}]\\-1299.5 = 2(-393.5) + (-285.8) - \Delta H^{o}_{f} (C_{2}H_{2})\\\Delta H^{o}_{f} (C_{2}H_{2}) = 227.7 kJ/mol[/tex]
Thus, we can conclude that heat of combustion per mole for acetylene is 227.7 kJ/mol.
A 0.150-kg sample of a metal alloy is heated at 540 Celsius an then plunged into a 0.400-kg of water at 10.0 Celsius, which is contained in a 0.200-kg aluminum calorimeter cup. The final temperature of the system is 30.5 Celsius. What is the specific heat of the metal alloy in J/Kg.Celsius
Answer:
[tex]C_{alloy}=0.497\frac{J}{g\°C}[/tex]
Explanation:
Hello there!
In this case, according to this calorimetry problem on equilibrium temperature, it is possible for us to infer that the heat released by the metal allow is absorbed by the water for us to write:
[tex]Q_{allow}=-(Q_{water}+Q_{Al})[/tex]
Thus, by writing the aforementioned in terms of mass, specific heat and temperature, we have:
[tex]m_{alloy}C_{alloy}(T_{eq}-T_{alloy})=-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})[/tex]
Then, we solve for specific heat of the metallic alloy to obtain:
[tex]C_{alloy}=\frac{-(m_{water}C_{water}(T_{eq}-T_{water})+m_{Al}C_{Al}(T_{eq}-T_{Al})}{m_{alloy}(T_{eq}-T_{alloy})}[/tex]
Thereby, we plug in the given data to obtain:
[tex]C_{alloy}=\frac{-(400g*4.184\frac{J}{g\°C} (30.5\°C-10.0\°C)+200g*0.900\frac{J}{g\°C}(30.5\°C-10.0\°C)}{150g(30.5\°C-540\°C)} \\\\C_{alloy}=0.497\frac{J}{g\°C}[/tex]
Regards!
What would the products be for the reaction between Na3PO4 + MgSO4?
MgSO4 + Na3PO4 = Na2SO4 + Mg3(PO4)2
Answer: The products of Na3PO4 + MgSO4 are Na2SO4 + Mg3(PO4)2
Explanation:
If the fan and power source are not connected to anything else, the amount of electrical energy is the same as the amount of mechanical energy. What is this rule known as?
1. transference of energy
2. conversion of energy
3. adaptation of energy
4. conservation of energy
Answer:
not B
Explanation:
my friend got it wrong
1. Which individuals are most likely to die before reproducing, those with adaptive traits or
nonadaptive traits? Why? (Hint: You may use the newt population as an example in your
explanation.)
A 0.125 g sample of unknown hydrocarbon is prepared for combustion analysis. After the hydrocarbon undergoes complete combustion, 0.4225 g of CO2 and 0.0865 g of H2O are produced. What is the empirical formula of the unknown
Answer:
Empirical formula is CH
Explanation:
A hydrocarbon, CₐHₓ reacts with oxygen in the combustion reaction as follows:
CₐHₓ + O₂ → a CO₂ + x/2 H₂O
That means we can find the moles of C and H from the moles of CO2 and H2O. As empirical formula is defined as the simplest whole-number ratio of atoms in a molecule, we can determine it as follows:
Moles CO2 = Moles C -Molar mass: 44.01g/mol:
0.4225g * (1mol / 44.01g) = 0.0096 moles C
Moles H2O -Molar mass: 18.01g/mol:
0.0865g H2O * (1mol / 18.01g) = 0.0048moles H2O * (2mol H / 1mol H2O) =
0.0096 moles H
The ratio of atoms of C:H is:
0.0096moles C / 0.0096moles H = 1
That means empirical formula is CH
1) For the following molecules: - Draw the Lewis structures/dots - Determine the polarity (polar or non-polar). - List all intermolecular forces. a) CF4 b) CH2Br2 c) H2CO3 d) N2 e) PCl3 f) XeF2 g) NH4
Answer:
ed
Explanation:
ed