Explanation:
speeds = distance/time
=100/16
=6.25m/s
second speed is;
400/44 =9.09
av. speed = total speed /n
= (6.25+9.09)/2
=7.67 m/s
Convert 400 mm to m using the method of dimensional analysis
Answer:
To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4
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whats suface tension
Answer: "Surface tension is a film of a liquid caused by the attraction of the particles in the surface layer by the bulk of the liquid, which tends to minimize surface area."
Hope this helps!
Answer:
Explanation:
Surface tension is the property of a liquid surface. It is an effect where the surface of the liquid is strong.
example - small insects can walk on water as they do not have enough weight to penetrate it.
This image might help you
Hope it helps
plz mark as brainliest!!!!!!!
If 5 complete oscillations of a sound wave pass through a point in 0.5 s and the speed of sound was recorded to be 10 m/s, then find the wavelength of the sound.
Answer:
Wavelength = 1 meters
Explanation:
Given that,
Number of oscillations is 5
It passes through a point in 0.5 s
The speed of sound was recorded to be 10 m/s.
We need to find the wavelength of the sound.
Firstly, we will find frequency of this wave. Total no of oscillations per unit time is called frequency. So,
[tex]f=\dfrac{5}{0.5}\\\\f=10\ Hz[/tex]
Now the speed of wave in terms of wavelength and frequency is given by :
[tex]v=f\lambda[/tex]
Here, [tex]\lambda[/tex] = wavelength
[tex]\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{10\ m/s}{10\ Hz}\\\\\lambda=1\ m[/tex]
So, the wavelength of the sound is 1 meters.
a car is stationary at first.it moves off with.acceleration of 2m.s-2.Calculate how far it will move in 10s
Answer:
100 m.
Explanation:
At first the car was stationary, so its inicial velocity is zero. Considering its inicial position 0 m and using the Equation of motion for the position:
X(t) = Xo + vo.t +a[tex]t^{2}[/tex]/2 , vo=0, Xo=0, a=2m/[tex]s^{2}[/tex]
X(10) = (2 x [tex]10^{2}[/tex])/2 = 100 m.
what is acceleration produced by a force of 12 newton exerted on an object of mass 3kg
Answer:
a=F/m
a=12N/3kg (here newton can be written as kgm/s^2 so kg will be cancelled)
a=4m/s^2
Explanation:
Calculate the intensity of current flowing through a computer that consumes 180W and operates at 120 V.
A.)0,66 A
B.)12600 A
C.)1,5 A
D.)60 A
Answer:
C) 1.5 A
Explanation:
P = IV
180 W = I (120 V)
I = 1.5 A
The image formed is 0.25 times the size of the object and 10 cm behind the pinhole. If the height of image on screen is 6 cm what is the distance of the object from the screen?
Answer:
40 cm
Explanation:
Magnification of a pinhole camera is given by;
M= height of image/ height of object
Since;
M= 0.25
Height of image = 6cm
Height of object = height of image / M
Height of object = 6/0.25 = 24 cm
Height of image/ height of object = distance of image from pinhole/ distance of object from pinhole
Since the distance of image from pinhole = 10cm
Let the distance of object from pinhole be x
6/24 = 10/x
6x = 240
x= 240/6
x = 40 cm
Mass stays the for an object even when or gravitational forces change the of the object.
Answer:
For some reason it doesn't let me type it in here so the answer is in the comment box!
I hope this will help you!:)
Microwaves operate at a frequency of 2.40 GHz. Find the minimum thickness for a plastic tray with a refractive
index of 1.45 that will cause enhanced reflection of microwaves incident normal to the tray.
Answer:
y (lambda) = c / f incident wavelength
y = 3 * E8 / 2.4 * E9 = .125 m incident wavelength
y' = .125 / 1.45 = .0862 m wavelength inside of tray
T = y' / 4 thickness required for phase change at bottom
T = .0862 m / 4 = .0261 m = 2.61 cm
why audiotape, credit cards and videotape not placed closed to a strong magnet
Answer:
There are many possible causes of magnetic defects in credit cards. But there are two direct causes: 1. Close to a strong magnet 2. Damage from scratches or wear Even if used properly it can cause magnetic defects. But if used incorrectly, it can cause an immediate relapse. If you have never used a credit card due to magnetic defects, check what will cause magnetic defects and for example credit cardMagnetic stripe cards, such as credit cards and cash cards, are more likely to cause magnetic field defects if brought near magnetically generating objects such as magnets. Although exposure to strong magnets does not necessarily lead to failure. However, it should be kept away from objects that may cause magnetic field defects.
Explanation:
Magnetic fields can erase or distort the data stored on these items. The correct option is A.
Magnetic media are used to store information in a magnetic format on audiotapes, credit cards, and videotapes. They may have their magnetic patterns and particle alignment disturbed if they are placed close to a powerful magnet.
The stored data may be lost or damaged as a result. For instance, credit cards' magnetic stripes may become illegible, audiotapes may lose their sound quality or possibly be completely erased, and videotapes may have distorted or scrambled imagery and audio.
To preserve the accuracy and utility of the data they contain, it is crucial to keep these things away from strong magnetic fields.
Thus, the correct option is A.
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Your question seems incomplete, the probable complete question is:
Why audiotape, credit cards and videotape not placed closed to a strong magnet
A. Magnetic fields can erase or distort the data stored on these items.
B. Magnetic fields can cause these items to become permanently demagnetized.
C. Magnetic fields can cause these items to generate excess heat and potentially catch fire.
D. Magnetic fields can cause these items to emit harmful radiation.
Each corner of a right-angled triangle is occupied by identical point charges "A", "B", and "C" respectively. Draw a sketch of this arrangement. "A" exerts force F on "B". An equal force F is exerted by "C" on "B" (/_ ABC= 90 degrees). Determine an expression for the net force on "B".
Answer:
Fnet = F√2
Fnet = kq²/r² √2
Explanation:
A exerts a force F on B, and C exerts an equal force F on B perpendicular to that. The net force can be found with Pythagorean theorem:
Fnet = √(F² + F²)
Fnet = F√2
The force between two charges particles is:
F = k q₁ q₂ / r²
where
k is Coulomb's constant, q₁ and q₂ are the charges, and r is the distance between the charges.
If we say the charge of each particle is q, then:
F = kq²/r²
Substituting:
Fnet = kq²/r² √2
A 63 kg kg person starts traveling from rest down a waterslide 6.0 mm above the ground. At the bottom of the waterslide, it then curves upwards by 1.0 mm above the ground such that the person is consequently launched into the air. Ignoring friction, how fast is the person moving upon leaving the waterslide
Answer:
change waterslide according to question. and you are good to go. check photo for solve
The person moving with speed upon leaving the waterslide is equal to 0.313 m/s while ignoring the friction.
What is the law of conservation of energy?If there is a loss of energy in any part of the system, there must be the same amount of a gain of energy in some other part of the isolated system.
Kinetic energy + Potential energy = constant
Therefore, the initial kinetic and potential energy of the person must be equal to the final kinetic and potential energy.
mgh₁ + mv₁²/2 = mgh₂ + mv₂²/2
gh₁ + v₁²/2 = gh₂ + v₂²/2
2gh₁ + v₁² = 2gh₂ + v₂²
2g(h₁ - h₂) = v₂² - v₁²
[tex]v_2=\sqrt{2g(h_2-h_1) + v^2_1}[/tex] .................(1)
Given, the mass of the person, m = 63 Kg
The initial speed of the person as at rest, v₁ = 0
Consider that the speed of the person while leaving the waterslide is v₂
The initial height of the person above the ground, h₁ = 6.0 mm
The height of the person leaving the waterslide, h₂= 1.0 mm
Substitute, the value of m, v₁, h₁ and h₂ in equation (1):
[tex]v_2 = \sqrt{2(9.8m/s^2)(6mm-1mm) + (0)^2}[/tex]
[tex]v_2 =\sqrt{2(9.8)\times 5 \times 10^{-3}} \;m/s[/tex]
[tex]v_2 =\sqrt{0.098}\; m/s[/tex]
v₂ = 0.313 m/s
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The speed of light in space is 3.00 x 10^8 m/s. The time for light from the sun to reach earth is 8mins and 20 seconds. Therefore, the distance from the Sun to Earth is
Select one:
A. 2.40 x 10^9 m
B. 8.64 x 10^12 m
C. 1.50 x 10^11
D. 2.25 x 10^9
Answer:
C. 1.50×10¹¹ m
Explanation:
First, convert the time to seconds.
8 min × (60 s/min) + 20 s = 500 s
Distance = speed × time
d = (3×10⁸ m/s) (500 s)
d = 1.50×10¹¹ m
The distance from the Sun to the Earth is 1.50 × 10¹¹. Speed is the distance travelled by an object in a particular time period. Thus, the correct option is C.
What is the Speed of light?
The speed of light in vacuum is commonly denoted by c. It is a universal physical constant. The speed of light (c) is exactly equal to 3.00 x 10⁸m/s (meter per second).
The speed of an object is the rate of change of position with respect to time. It is also defined as the distance covered by an object with respect to time. It can be calculated by dividing the distance travelled by an object by the time taken. It is a scalar quantity as it has only magnitude and no direction.
Speed = Distance / time
Distance = Speed × Time
Distance = 3.00 × 10⁸ × 500
Distance = 1500 × 10⁸
Distance = 1.50 × 10¹¹
Therefore, the correct option is C.
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is iron and copper brittle
Answer:
no
Explanation:
they are metal and there property is strong and hard
El salto con garrocha es practicado por:
A. Solo hombres
B. Solo mujeres
C. N.A
D. Solo a y b
A square is cut out of a copper sheet. Two straight scratches on the surface of the square intersect forming an angle theta. The square is heated uniformly. As a result, the angle between the scratches?a) increasesb) decreasesc) stays the samed) depends on whether theta is obtuse or acute
Answer:
a) increases
Explanation:
Almost all substance or material undergoes expansion due to heating. Heat gives thermal energy to the molecules of a substance increasing their body temperature. The temperature of a substance is the measure of the average kinetic energy of the molecules of that substance. When the temperature of a substance increases, the molecules begin to agitate and try to move far from each other, leading to either a linear, area, or cubic expansion, or all three of them. Metals like copper expand very well on heating, and their expansion is relatively minute, but very observable. When the face of such a copper is scratched to give and angle, heating the copper uniformly will cause the copper to expand, leading to an increase in the angle formed.
A baseball weights 1429 (0.142kg) were striked with force of 120N. Calculate its acceleration at
that time. Include the correct unit with your answer. Include one decimal place.
Answer:
a=845.07 m/s2
Explanation:
m=0.142kg
F=120N
a=?
F=m*a /:m
a=F/m
a=120N/0.142kg
a=845,07m/s2
Answer:
a = 845.07 m/s²
Explanation:
As we know ,
as per newton's 2nd law:-
F = ma
therefore
a = F/m
given:
a = ?
F = 120N
m = 0.142 kg
procedure:-
a = 120/0.142
therefore :
a = 845.07 m/s²
Một bóng đèn có hiệu điện thế định mức là 110V. Đặt vào hai đầu bóng đèn các hiệu điện thế sau đây, hỏi trường hợp nào dây tóc của đèn sẽ đứt?
Answer:
fhaiisjrbekxkrkebxnsiiwj4bnds
Define measurement and write its importance.
Answer:
Measurement is the way humans define certain amounts of matter, and is expressed in various types of units respective to the type of matter or object being defined.
Explanation:
Measurement is extremely important because it helps one another understand how much of something is needed to accomplish something. If no method existed to define the specific amount needed, we would simply mess delicate operations up and machines, even simple recipes, would fail.
A 2-kg cart, traveling on a horizontal air track with a speed of 3m/s, collides with a stationary 4-kg cart. The carts stick together. The impulse exerted by one cart on the other has a magnitude of
Answer:
The impulse exerted by one cart on the other has a magnitude of 4 N.s.
Explanation:
Given;
mass of the first cart, m₁ = 2 kg
initial speed of the first car, u₁ = 3 m/s
mass of the second cart, m₂ = 4 kg
initial speed of the second cart, u₂ = 0
Let the final speed of both carts = v, since they stick together after collision.
Apply the principle of conservation of momentum to determine v
m₁u₁ + m₂u₂ = v(m₁ + m₂)
2 x 3 + 0 = v(2 + 4)
6 = 6v
v = 1 m/s
Impulse is given by;
I = ft = mΔv = m(
The impulse exerted by the first cart on the second cart is given;
I = 2 (3 -1 )
I = 4 N.s
The impulse exerted by the second cart on the first cart is given;
I = 4(0-1)
I = - 4 N.s (equal in magnitude but opposite in direction to the impulse exerted by the first).
Therefore, the impulse exerted by one cart on the other has a magnitude of 4 N.s.
You have a cup with 50cm filled with water. How much pressure will the water act on the bottom of the cup? The density of water is 1000kg/m^3 and g = 10N/kg
Answer:
5000 N/m².
Explanation:
The following data were obtained from the question:
Density (d) = 1000 kg/m³
Acceleration due to gravity (g) = 10 N/kg
Height (h) = 50 cm = 50/100 = 0.5 m
Pressure (P) =.?
Pressure is related to density and height by the following equation:
P = dgh
Where
P is the pressure.
d is the density.
g is the acceleration due to gravity.
h is the height.
With the above formula, we can obtain the pressure at the bottom of the cup as follow:
P = dgh
P = 1000 x 10 x 0.5
P = 5000 N/m²
Therefore, the pressure at bottom of the cup is 5000 N/m².
Your help will really be great plz help me
5 N
Archimedes' Principle
25 N
calculate the force exerted by a mental ball having a mass of 70kg moving with speed of 20m/s>2
Answer:
F = 1400 N
Explanation:
It is given that,
Mass of the ball, m = 70 kg
It is moving with an acceleration of 20 m/s². We need to find the force exerted by the ball.
Force is given by the product of mass and acceleration. So,
F = ma
[tex]F=70\ kg\times \ 20m/s^2\\\\F=1400\ N[/tex]
So, the force of 1400 N is exerted by a metal ball.
Kgms-1-= Ns ...solution
Answer:
units of impact or impulse or momnetum are same
These are
Kg m s-1 or N s
An 8.0g bullet, moving at 400 m/s, goes through a stationary block of wood in 4.0 x 10^-4s, emerging at a speed of 100 m/s. (a) what average force did the wood exert on the bullet? (b) how thick is the wood?
Answer:
Explanation:
Initial velocity (u) of the Bullet = 400 m/sec
Final velocity (v) of the Bullet = 100 m/sec
Bullet passed through the block in (t) = 0.0004 sec
Using 1st Equation of motion :
400 m/s = 100 m/s - a (0.0004)
Deceleration of Bullet = 750,000 m/sec^2
(a) F (force exerted by the wooden block on the bullet) = F (force exerted by the bullet on the wooden block)
F = m * a = 0.008 * 750,000 = 6000 N
(b) Using 3rd Equation of motion :
[tex]v^{2} = u^{2} - 2aS[/tex]
10000 = 160000 - 2 * 750,000 * S
Thickness of wood (S) = 0.1 m
The graph below shows the number of sunspots observed between 1750 and 2000.
Based on the graph, which of these periods most likely witnessed the greatest increase in solar radiation
Answer:
1950 cause it's clearly shown in graph that it has the highest sunspot number .
An object accelerates to a velocity of 230 m/s over a time of 2.5 s. The acceleration it experienced was 42 m/s2. What was its initial velocity?
Answer:
230 = x + 105
x= 125
Explanation:
v = v0 + at
Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. If there is no air resistance, when they hit the ground A) both will have the same kinetic energy. B) the heavier one will have twice the kinetic energy of the lighter one. C) the heavier one will have four times the kinetic energy of the lighter one. D) the heavier one will have half the kinetic energy of the lighter one. E) the heavier one will have one-fourth the kinetic energy of the lighter one.
Answer:
option b
Explanation:
the heavier one will have twice the kinetic energy of the lighter one
The heavier one will have twice the kinetic energy of the lighter one. Hence, option (B) is correct.
Given data:
The mass of object 1 is, m.
The mass of object 2 is, 2m.
Here, the concept of kinetic energy is used. The kinetic energy of an object is the energy possessed by the object by virtue of its motion. Motion means something related with the speed.
And the mathematical expression for the kinetic energy is given as,
[tex]KE =\dfrac{1}{2}mv^{2}[/tex]
Here,
m is the mass of body.
v is the speed of body.
Now considering the kinetic energy for the two given objects as,
[tex]KE=\dfrac{1}{2}mv^{2}\\\\KE'=\dfrac{1}{2}(2m)v^{2}[/tex]
Comparing both the values of kinetic energies, we find that,
KE' = 2KE
Thus, we can conclude that the heavier one will have twice the kinetic energy of the lighter one. Hence, option (B) is correct.
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A rifle bullet with mass 8.00 g and initial horizontal velocity 280 m/s strikes and embeds itself in a block with mass 0.992 kg that rests on a frictionless surface and is attached to one end of an ideal spring. The other end of the spring is attached to the wall. The impact compresses the spring a maximum distance of 15.0 cm. After the impact, the block moves in SHM. Calculate the period of this motion.
Answer:
0.4113772 s
Explanation:
Given the following :
Mass of bullet (m1) = 8g = 0.008kg
Initial horizontal Velocity (u1) = 280m/s
Mass of block (m2) = 0.992kg
Maxumum distance (x) = 15cm = 0.15m
Recall;
Period (T) = 2π√(m/k)
According to the law of conservation of momentum : (inelastic Collison)
m1 * u1 = (m1 + m2) * v
Where v is the final Velocity of the colliding bodies
0.008 * 280 = (0.008 + 0.992) * v
2.24 = 1 * v
v = 2.24m/s
K. E = P. E
K. E = 0.5mv^2
P.E = 0.5kx^2
0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2
0.5*1*5.0176 = 0.5*k*0.0225
2.5088 = 0.01125k
k = 2.5088 / 0.01125
k = 223.00444 N/m
Therefore,
Period (T) = 2π√(m/k)
T = 2π√(0.992+0.008) / 233.0444
T = 2π√0.0042910
T = 2π * 0.0655059
T = 0.4113772 s
The period of the simple harmonic motion (SHM) is 0.42 s.
The given parameters;
mass of the bullet, m₁ = 8 g = 0.008 kginitial horizontal velocity of the bullet, u = 280 m/smass of the block, m₂ = 0.992 kginitial velocity of block, u₂ = 0extension of the spring, x = 15 cm = 0.15 mThe final velocity of the system after the impact is calculated as follows;
[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.008(280) \ + \ 0.992(0) = v(0.008 \ + \ 0.992)\\\\2.24 = v(1) \\\\v = 2.24 \ m/s[/tex]
The spring constant is calculated as follows;
[tex]\frac{1}{2} kx^2 = \frac{1}{2} mv^2\\\\k = \frac{mv^2}{x^2} \\\\k = \frac{(0.008 + 0.992))\times 2.24^2}{(0.15)^2} \\\\k = 223 \ N/m[/tex]
The angular speed of the simple harmonic motion (SHM) is calculated as follows;
[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{223}{(0.008 + 0.992)} }\\\\\omega = 14.933 \ rad/s[/tex]
The period of the oscillation is calculated as follows;
[tex]T = \frac{2\pi }{\omega} \\\\T = \frac{2\pi }{14.933} \\\\T = 0.42 \ s[/tex]
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Light travels at a speed of 2.998*108 m/s. Light takes approximately 3.25 minutes to travel from the Sun to reach a planet. Calculate the distance from the Sun to this planet in meters. Give your answer to 0 decimal places.
Answer:
585×10⁸ m
Explanation:
Distance = rate × time
d = (2.998×10⁸ m/s) (3.25 min) (60 s/min)
d = 585×10⁸ m