Calculate the approximate temperature of a 0.50 mol sample of gas at 2.7 atm and a volume of 1.20L

Answer:

I believe is A

Explanation:

Enthalpy change is the name given to the amount of heat evolved or absorbed in a reaction carried out at constant pressure.

Answer:

A person's skin color, hair color, dimples, freckles, and blood type are all examples of genetic variations that can occur in a human population.

Explanation:

Answer:

Citric Acid is a weak acid with a chemical formula C6H8O7.

...

Properties of Citric Acid – C6H8O7.

C6H8O7 Citric Acid

Molecular Weight/ Molar Mass 192.124 g/mol

Density 1.66 g/cm³

Boiling Point 310 °C

Melting Point 153 °C

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Answer:

a. The resonance effect of the hydroxyl group stabilizes the anionic intermediate

Explanation:

The resonance effect stabilizes the the charge through the delocalization of the pi bonds. The resonance stabilization mainly occurs in the conjugated pi systems.

For example, phenol forms a strong hydrogen bonds than the nonaromatic alcohols as the [tex]$O_2-H_2$[/tex] dipole present in the hydroxyl group is being stabilized by the presence of the aromatic ring of phenol.

Thus the resonance effect of the hydroxyl group stabilizes the anionic intermediate.

Answer:

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]ph = - log(6.2 \times {10}^{ - 5} ) \\ = 4.207608[/tex]

We have the final answer as

Hope this helps you

Solution :

A complex ion may be defined as a metal ion that is located at the center with other molecules or ions surrounding the center ion.

In the context, the number of the unpaired electrons for the following complex ions are :

1. [tex]$Ru(NH_3)62+$[/tex]  (low spin)

  [tex]$Ru^{2+} = [Kr] \ 4d^6 \ 5s^0$[/tex]

   Here all the d-electrons are paired. Therefore, there are no unpaired electrons.

2. [tex]$Ni(H_2O)62+$[/tex]  (high spin)

   [tex]$Ni^{2+} = [Ar] \ 4s^0 \ 3d^8$[/tex]

   Therefore, it has two unpaired electrons.

3. [tex]$V(en)33+$[/tex]  (high spin)

    [tex]$V=[Ar] \ 3d^2 \ 4s^0$[/tex]

   It has 2 unpaired electrons

Answer: The new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

Explanation:

Given: [tex]V_{1}[/tex] = 61 L,      [tex]T_{1}[/tex] = 183 K,      [tex]P_{1}[/tex] = 0.60 atm

At STP, the value of pressure is 1 atm and temperature is 273.15 K.

Now, formula used to calculate the new volume is as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{0.60 atm \times 61 L}{183 K} = \frac{1 atm \times V_{2}}{273.15 K}\\V_{2} = 54.63 L[/tex]

Thus, we can conclude that the new volume of a 61 L sample at STP that is moved to 183 K and 0.60 atm is 54.63 L.

[tex]\huge\bf\red{\underline{\underline{Answer:-}}}[/tex]

Here, 16 L = 0.80 Mole

_____________________________

Answer:

si.mple fe

Explanation:

ghhsshzhzbbzhh

Answer:

Explanation:

The reaction is given as:

[tex]N_{2(g)} + 3H_{2(g)} \to 2NH_{3(g)}[/tex]

The reaction quotient is:

[tex]Q_C = \dfrac{[NH_3]^2}{[N_2][H_2]^3}[/tex]

From the given information:

TO find each entity in the reaction quotient, we have:

[tex][NH_3] = \dfrac{6.42 \times 10^{-4}}{3.5}\\ \\ NH_3 = 1.834 \times 10^{-4}[/tex]

[tex][N_2] = \dfrac{0.024 }{3.5}[/tex]

[tex][N_2] = 0.006857[/tex]

[tex][H_2] =\dfrac{3.21 \times 10^{-2}}{3.5}[/tex]

[tex][H_2] = 9.17 \times 10^{-3}[/tex]

∴

[tex]Q_c= \dfrac{(1.834 \times 10^{-4})^2}{(0.0711)\times (9.17\times 10^{-3})^3} \\ \\ Q_c = 0.6135[/tex]

However; given that:

[tex]K_c = 1.2[/tex]

By relating [tex]Q_c \ \ and \ \ K_c[/tex], we will realize that [tex]Q_c \ \ < \ \ K_c[/tex]

The reaction is said that it is not at equilibrium and for it to be at equilibrium, then the reaction needs to proceed in the forward direction.

Balanced Equation is

4H2SiCl2+4H2O → H8Si4O4 + 8HCl

Answer:

its called molding

Explanation:

Answer: almost 7g

Explanation: 25 grams of carbon dioxide contains 6.818 grams of carbon.

Answer:

D. C triple bond C.

Explanation:

The absorption frequency value is highest for carbon-carbon triple bond. The stretching frequencies are much higher than the bending frequency. It mainly depends upon the strength of the bonds as well as masses of the bonded atoms.

The triple bonds have higher stretching strength than the double bonds and double bonds have higher strength than single carbon to carbon bonds.

The triple bonds has a higher bond order, i.e. 3. So it has maximum stretching bonds.

Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.

Explanation:

Given: [tex]T_{1}[/tex] = 178 K,      [tex]P_{1}[/tex] = 0.3 atm

[tex]T_{2}[/tex] = 278 K,           [tex]P_{2}[/tex] = ?

According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.

Formula used to calculate the pressure is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\[/tex]

Substitute the values into above formula is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{0.3 atm}{178 K} = \frac{P_{2}}{278 K}\\P_{2} = 0.468 atm[/tex]

Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.

Answer:

The correct answer is - 46.60 mL.

Explanation:

To find the volume of the gas at its new increased temperature we need to use Charl Law that shows the direct relationship between Volume and Temperature while Pressure remains constant.

V1 = 40 ml

T1  = 30 degree C + 273 = 303 K

V2  = ?

T2  = 80 degree C + 273 = 353 K

Charl Equation is:

V 1/T 1  =  V 2/ T 2

(V1) * (T2)/ T1= V2

placing value:

40*353/303 = V2

= 14120/303

Vf = 46.60 mL

Answer:

Explanation:

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₅(g) --------> PCl₃(g)+ Cl₂(g)

1 mole               1 mole      1 mole

Amount of phosphorus pentachloride reacted = 0.75 M - 0.65 M = 0.10 M

PCl₃(g) and  Cl₂(g) formed are .10 M and .10 M

Keq = [ PCl₃] x [ Cl₂ ] / [ PCl₅ ]

= .10 M x .10 M / .65 M

= .0154

B ) is the correct choice .

Answer:

39.57 °C

Explanation:

Applying,

Heat gain = Heat lost.

cm'(t₃-t₁) = cm(t₂-t₃)................. Equation 1

Where c = specific heat capacity of water, m = mass of the hotter water, m' = mass of the colder water, t₁ = initial temperature of the colder water, t₂ = initial temperature of the hotter water, t₃ = Final Temperature.

Equation 1 above can futher be simplified to

m'(t₃-t₁) = m(t₂-t₃)................. Equation 2

From the question,

Given: m' = 155 g, m' = 75 g, t₁ = 20 °C, t₂ = 80 °C

Substitute these values into equation 2

155(t₃-20) = 75(80-t₃)

Solve for t₃

155t₃- 3100 = 6000-75t₃

155t₃+75t₃ = 6000+3100

230t₃ = 9100

t₃ = 9100/230

t₃ = 39.57 °C

Assuming no heat is lost to the surrounding, the final temperature of the water is 39.57°C.

Given the following data:

To determine the final temperature of the water, assuming no heat is lost to the surrounding:

The quantity of heat lost by the water 1 = The quantity of heat gained by the water 2.

[tex]Q_{lost} = Q_{gained}\\\\m_1c\theta = m_2c\theta\\\\m_1\theta = m_2\theta\\\\m_1(T_2 - T_1) = m_2(T_3 - T_2)[/tex]

Substituting the given parameters into the formula, we have;

[tex]155(T_2 -20)=75(80-T_2 )\\\\155T_2 -3100=6000-75T_2\\\\155T_2 +75T_2=6000+3100\\\\230T_2=9100\\\\T_2=\frac{9100}{230}[/tex]

Final temperature = 39.57°C

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Answer:

Bathypelagic

54% of the ocean lies in the Bathypelagic (aphotic) zone into which no light penetrates. This is also called the midnight zone and the deep ocean. Due to the complete lack of sunlight, photosynthesis cannot occur and the only light source is bioluminescence.

Explanation:

The small surface zone that has light is the photic zone. The entire rest of the ocean does not have light and is the aphotic zone.

Permanent darkness below 1000 meters with bioluminescent bacteria, bottom feeders, and angler fish is where no light reaches.

This is referred to the state of being dark as a result of absence of light in the area.

The light ray penetration decreases with increase in depth thereby making areas below 1000 meters dark with bioluminescent bacteria, bottom feeders, and angler fish which is why option C was chosen.

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Answer:

oficialismo hemostasia Jalisco

Answer:

K

Explanation:

Potassium is atomic no 19 and it is k because is from kalium, the Meldiaeval Latin for potash, which may have derived from an arabic word quality, meaning alkali.

Atomic mass, 39.098amu

Oxidation status, +1

Year discovered, 1807

Melting point, 63.28 degrees Celsius(145.90degrees Fahrenheit )

Boiling point, 760 degrees Celsius (1400 degrees Fahrenheit )

Answer:

a. 2.44 nm

b. 15.33 nm²

Explanation:

a. Calculate the thickness (in nm) of the surface film

Since the volume of a teaspoon equals V = 4.93 cm³ and the area of the oil film is half an acre = 1/2 × 4046.86 m² = 2023.43 m²

The volume of the oil film, V' equals the volume of the oil in the teaspoon, V

V' = Ah where A = cross-sectional area of oil film = 2023.43 m² = 2023.43 × 10⁴ cm² and h = height of oil film

So, V' = V

Ah = V

h = V/A

= 4.93 cm³/2023.43 × 10⁴ cm²

= 0.00244 × 10⁻⁴ cm

= 2.44 × 10⁻⁷ cm

=  2.44 × 10⁻⁷ cm × 1m/100 cm

= 2.44 × 10⁻⁹ m

= 2.44 nm

b. The surface area (in nm2) occupied by an oleic acid molecule on water.

Since the height of the oil film equals the diameter of the oil molecule, and the molecule is assumed to be a sphere of radius, r. Its surface area is thus A = 4πr²

r = h/2 = 2.44 nm/2 = 1.22 nm

A = 4πr²

A = 4π(1.22 nm)²

A = 4.88π nm²

A = 15.33 nm²

Answer:

I'm so sorry if this is wrong but I think its B

Answer:

2731.875 J

Explanation:

Applying

Q = cm(t₂-t₁)................ Equation 1

Where Q = amount of heat, c = specific heat capacity of silver, m = mass of silver, t₂ = Final temperature of silver, t₁ = Initial temperature of silver

From the question,

Given: c = 0.235 J/g°C, m = 250 g, t₁ = 22.0°C, t₂ = 68.5°C

Substitute these values into equation 1

Q = 0.235×250(68.5-22.0)

Q = 58.75(46.5)

Q = 2731.875 J

Answer:

[tex]1 \: mole \: = 6.02 \times {10}^{23} \: molecules \\ 3.05 \: moles \: = (3.05 \times 6.02 \times {10}^{23} ) \: molecules \\ = 1.8361 \times {10}^{24} \: molecules[/tex]

Answer:

C₃H₈O

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 1.031 g

Mass of CO₂ = 2.265 g

Mass of H₂O = 1.236 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen in the compound. This can be obtained as follow:

For carbon, C:

Mass of CO₂ = 2.265 g

Molar mass of CO₂ = 44.01 g/mol

Molar mass of C = 12.01 g/mol

Mass of C =?

Mass of C = molar mass of C / molar mass of CO₂ × mass of CO₂

Mass of C = 12.01/44.01 × 2.265

Mass of C = 0.618 g

For hydrogen, H:

Mass of H₂O = 1.236 g

Molar mass of H₂O = 18.02 g/mol

Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol

Mass of H =?

Mass of H = Molar mass of H₂ / Molar mass of H₂O × Mass of H₂O

Mass of H = 2.02/18.02 × 1.236

Mass of H = 0.139 g

For oxygen, O:

Mass of compound = 1.031 g

Mass of C = 0.618 g

Mass of H = 0.139 g

Mass of O =?

Mass of O = Mass of compound – (mass of C + mass of H)

Mass of O = 1.031 – ( 0.618 + 0.139)

Mass of O = 1.031 – 0.757

Mass of O = 0.274 g

Finally, we shall determine the empirical formula. This can be obtained as follow:

C = 0.618 g

H = 0.139 g

O = 0.274 g

Divide by their molar mass

C = 0.618 / 12.01 = 0.051

H = 0.139 / 1.01 = 0.138

O = 0.274 / 16 = 0.017

Divide by the smallest

C = 0.051 / 0.017 = 3

H = 0.138 / 0.017 = 8

O = 0.017 / 0.017 = 1

Therefore, the empirical formula of the compound is C₃H₈O

Based on the data provided, the empirical formula of the compound is C₃H₈O

The empirical formula of compound is its simplest formula showing the mole ratio of the elements in the compound.

First, the mass of carbon, hydrogen and oxygen in the compound is determined first as follows:

For carbon, C:

Mass of CO₂ = 2.265 g

Molar mass of CO₂ = 44.01 g/mol

Molar mass of C = 12.01 g/mol

Mass of C = 12.01/44.01 × 2.265

Mass of C = 0.618 g

For hydrogen, H:

Mass of H₂O = 1.236 g

Molar mass of H₂O = 18.02 g/mol

Molar mass of H₂ = 2 × 1.01 = 2.02 g/mol

Mass of H = 2.02/18.02 × 1.236

Mass of H = 0.139 g

For oxygen, O:

Mass of compound = 1.031 g

Mass of C = 0.618 g

Mass of H = 0.139 g

Mass of O = Mass of compound – (mass of C + mass of H)

Mass of O = 1.031 – ( 0.618 + 0.139)

Mass of O = 0.274 g

To determine the empirical formula of a compound, the mole ratio of the elements are determined as follows:

Mole ratio of the elements:

Carbon                Hydrogen         Oxygen

0.618 g/12.01    0.139 / 1.01         0.274 / 16

0.051                   0.138              0.017

Divide by the smallest ratio to convert to whole numbers

0.051 / 0.017     0.138 / 0.017  0.017 / 0.017

3           :            8           :               1

Therefore, the empirical formula of the compound is C₃H₈O

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Answer:

x² = mutiphy by them self

Explanation: