Calculate the amount of heat required to convert 10.0 grams of ice at –20.°C to steam at 120.°C. (Sp. heat of H2O(s) = 2.09 J/g•°C, Sp. heat of H2O(l) = 4.18 J/g•°C, Sp. heat of H2O(gas) = 2.03 J/g•°C; heat of fusion of H2O(solid) = 333 J/g, heat of vaporization of H2O(liquid) = 2260 J/g).

Answers

Answer 1

Answer:

THE AMOUNT OF HEAT REQUIRED TO CONVERT ICE FROM -20 C TO STEAM AT 120 C IS 30 946 J OR 30.946 KJ OF HEAT.

Explanation:

Mass = 10 g

To convert 10 g of ice at -20°C to steam at 120°C, the heat involved is:

1. Heat involved in converting the ice from -20 °c to ice at 0 °C:

Heat = mass * specific heat of water solid * change in temperature

heat = 10g * 2.09 J/g°C * ( 0- (-20))

Heat = 10 * 2.09 * 20

heat = 418 J

2. Heat required to convert the ice from 0°C to water at 0°C:

Heat = mass * specific heat of fusion of water solid

Heat = 10 * 333

Heat = 3330 J

3. Heat required to convert water at 0 C to water at 100 C:

Heat = mass * specific heat of water * change in teperature

Heat = 10 * 4.18 * (100 -0)

Heat = 4180 J

4. Heat required to convert water at 100 C to steam at 100 C:

Heat = mass * specific heat of vaporization

Heat = 10 * 2260

Heat = 22600 J

5. Heat required to convert steam from 100 C to steam at 120 C:

Heat = mass * specific heat of water * change in temperature

Heat = 10 * 2.09 * (120 -100)

Heat = 10 * 2.09 * 20

Heat = 418 J

T

he heat required to convert 10 g of ice at -20 C to steam at 120 C is therefore the total of the individual heat of reactions

Total amount of heat = ( 418 J + 3330 J + 4180 J + 22600 J + 418 J)

Total heat =  30946 J


Related Questions

For the reaction 2 A - Products, the concentration of A is monitored over time. A graph of [A] versus time was found to be linear, with a negative slope. Select the true statement regarding this reaction.
A) The reaction is first order with respect to A.
B) The reaction is second order with respect to A.
C) The rate constant has a negative value.
D) In 2 The reaction has a half-life equal to k.
E) None of these statements is true.

Answers

Answer:

none of these statements is true

according to the question E) None of these statements is true.

What is a concentration in chemistry?

The concentration of a chemical substance expresses the amount of a substance present in a mixture. There are many different ways to express concentration. Chemists use the term solute to describe the substance of interest and the term solvent to describe the material in which the solute is dissolved

What is concentration in chemistry units?

Quantitative units of concentration include molarity, molality, mass percentage, parts per thousand, parts per million, and parts per billion.

Learn more about concentration here

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4. What are the potential sources of error that might cause disagreement between the activity series' prediction of reactions and your observations of reactions

Answers

Answer:

1. Not to have enough salt water on the foil

2.not cleaning the foil well to remove interfering materials

g The "Coulomb barrier" is defined to be the electric potential energy of a system of two nuclei when their surfaces barely touch. The probability of a nuclear reaction greatly increases if the energy of the system is above this barrier. What is the Coloumb barrier (in MeV) for the absorption of an alpha particle by a lead-208 nucleus

Answers

Answer:

The Coulomb Barrier U is 25.91 MeV

Explanation:

Given that:

Atomic Mass of lead nucleus A = 208

atomic mass of an alpha particle A = 4

Radius of an alpha particle [tex]R_\alpha = R_o A^{^{\dfrac{1}{3}}[/tex]

where;

[tex]R_\alpha = 1.2 \times 10 ^{-15} \ m[/tex]

[tex]R_\alpha = R_o A^{^{\dfrac{1}{3}}[/tex]

[tex]R_\alpha = 1.2 \times 10 ^{-15} \ m \times (4) ^{^{\dfrac{1}{3}}[/tex]

[tex]R_\alpha = 1.905 \times 10^{-15} \ m[/tex]

Radius of the Gold nucleus

[tex]R_{Au}= R_o A^{^{\dfrac{1}{3}}[/tex]

[tex]R_{Au}= 1.2 \times 10 ^{-15} \ m \times (208) ^{^{\dfrac{1}{3}}[/tex]

[tex]R_{Au} = 7.11 \times 10^{-15} \ m[/tex]

[tex]R = R_\alpha + R_{Au}[/tex]

[tex]R = 1.905 \times 10^{-15} \ m + 7.11 \times 10^{-15} \ m[/tex]

[tex]R = 9.105 \times 10 ^{-15} \ m[/tex]

The electric potential energy of the Coulomb barrier [tex]U = \dfrac{Ke \ q_{\alpha} q_{Au}}{R}[/tex]

[tex]U = \dfrac{8.99 \times 10^9 \ N.m \ ^2/C ^2 \ \times 2 ( 82) \times \(1.60 \times 10^{-19} C \ \ e } {9.105 \times 10^{-15} \ m }[/tex]

U = 25908577.7eV

U = 25.908577 × 10⁶ eV

U =  25.91 MeV

The Coulomb Barrier U is 25.91 MeV

Calculate the volume of 0.500 M C2H3O2H and 0.500 M C2H3O2Na required to prepare 0.100 L of pH 5.00 buffer with a buffer strength of 0.100 M. The pKa of C2H3O2H is 4.75.

Answers

Answer:

You require 12.8mL of the 0.500M C₂H₃O₂Na and 7.2mL of the 0.500M C₂H₃O₂H

Explanation:

It is possible to obtain pH of a weak acid using H-H equation:

pH = pKa + log₁₀ [A⁻] / [HA]

For the buffer of acetic acid/acetate, the equation is:

pH = pKa + log₁₀ [C₂H₃O₂Na] / [C₂H₃O₂H]

Replacing:

5.00 = 4.75 + log₁₀ [C₂H₃O₂Na] / [C₂H₃O₂H]

1.7783 =  [C₂H₃O₂Na] / [C₂H₃O₂H] (1)

Buffer strength is the concentration of the buffer, that means:

0.1M = [C₂H₃O₂Na] + [C₂H₃O₂H] (2)

Replacing (2) in (1):

1.7783 =  0.1M - [C₂H₃O₂H] / [C₂H₃O₂H]

1.7783 [C₂H₃O₂H] = 0.1M -  [C₂H₃O₂H]

2.7783 [C₂H₃O₂H] = 0.1M

[C₂H₃O₂H] = 0.036M

Also:

[C₂H₃O₂Na] = 0.1M - 0.036M

[C₂H₃O₂Na] = 0.064M

The moles of both compounds you require is:

[C₂H₃O₂Na] = 0.1L × (0.064mol / L) = 0.0064moles

[C₂H₃O₂H] = 0.1L × (0.036mol / L) = 0.0036moles

Your stock solutions are 0.500M, thus, volume of both solutions you require is:

[C₂H₃O₂Na] = 0.0064moles × (1L / 0.500M) = 0.0128L = 12.8mL

[C₂H₃O₂H] = 0.0036moles × (1L / 0.500M) = 0.0072mL = 7.2mL

You require 12.8mL of the 0.500M C₂H₃O₂Na and 7.2mL of the 0.500M C₂H₃O₂H

The Ksp of calcium sulfate, CaSO4, is 9.0 × 10-6. What is the concentration of CaSO4 in a saturated solution? A. 3.0 × 10-3 Molar B. 9.0 × 10-3 Molar C. 3.0 × 10-6 Molar D. 9.0 × 10-6 Molar

Answers

Answer: The concentration of [tex]CaSO_4[/tex]  in a saturated solution is [tex]3.0\times 10^{-3}M[/tex]

Explanation:

Solubility product is defined as the equilibrium constant in which a solid ionic compound is dissolved to produce its ions in solution. It is represented as [tex]K_{sp}[/tex]

The equation for the ionization of [tex]CaSO_4[/tex]  is given as:

[tex]K_{sp}[/tex] of [tex]CaSO_4[/tex]  = [tex]9.0\times 10^{-6}[/tex]

By stoichiometry of the reaction:

1 mole of  [tex]CaSO_4[/tex] gives 1 mole of [tex]Ca^{2+}[/tex] and 1 mole of [tex]SO_4^{2-}[/tex]

When the solubility of [tex]CaSO_4[/tex] is S moles/liter, then the solubility of [tex]Ca^{2+}[/tex] will be S moles\liter and solubility of [tex]SO_4^{2-}[/tex] will be S moles/liter.

[tex]K_{sp}=[Ca^{2+}][SO_4^{2-}][/tex]

[tex]9.0\times 10^{-6}=[s][s][/tex]

[tex]9.0\times 10^{-6}=s^2[/tex]

[tex]s=3.0\times 10^{-3}M[/tex]

Thus concentration of [tex]CaSO_4[/tex]  in a saturated solution is [tex]3.0\times 10^{-3}M[/tex]

Using the volumes of EDTA solution you just entered and the corresponding dry unknown sample masses entered earlier, calculate the percent mass of calcium carbonate in the unknown sample mixture.
Enter the calculated percent mass of calcium carbonate in the dry unknown sample for each of the 3 acceptable trials.
Be sure to enter your mass percentages to the correct number of significant digits and in the corresponding order that you entered your masses of your dry unknown samples and volumes of your EDTA previously. The dry unknown sample mass you entered for entry #1 below should correspond to the percent mass of calcium carbonate you enter for entry #1 here.

Trial #: Mass (Grams):

#1: 0.015

#2: 0.015

#3: 0.015

Volume (mL)

#1: 16.4

#2: 15.00

#3: 18.70

Molarity of EDTA Solution: 0.0675

Answers

Answer:

#1

Explanation:

molarity of EDTA solution 0.0675

no1

PLEASE ANSWER AS SOON AS POSSIBLE REALLY WOULD APPRECIATE IT

Answers

Answer:

The answer is option D.

Hope this helps you

How much heat is absorbed when 52.39 H2O(l) at 100°C and 101.3 kPa is converted to steam at 100°C? (The molar heat of vaporization of water is
40.7 k/mol.)
2.09 x 1020
O 2.31% 10110
O 1.18 x 102 103
O 1.11% 1021)

Answers

2.09 x 1020 that’s the answer

What is a heterogeneous mixture?

Answers

Answer:

The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.

for eg, mixture of sand and sugar.

hope it helps..

Given the information about each pair of acids fill in the correct answer.
a. Acid A has a lower % ionization than B:_______ is a stronger acid.
b. Acid B has a larger K_a than acid A._______ will have a larger percent ionization.
c. A is a stronger acid than B. Acid B will have________ percent ionization than A.

Answers

Answer:

a. Acid B

b. Acid B

c. lower

Hope this helps you

Organic chemistry too eazy but why 90% students avoid ?

Answers

Answer:

because it covers a large area as there are more then 1 lakh compounds of organic chemistry.

How many grams of CO are produced when 41.0 g of C reacts?

Answers

Answer:

95.7 g CO to the nearest tenth.

Explanation:

2C + O2 ---> 2CO

Using relative atomic masses:

24 g C produces  2*12 + 2*16 g CO.

So 41 g produces  ( (2*12 + 2*16) * 41  ) / 24

= 95.7 g CO,

Five mol of calcium carbide are combined with 10 mol of water in a closed, rigid, high-pressure vessel of 1800 cm3 internal empty volume. Acetylene gas is produced by the reaction:

Answers

Answer:

CaC₂  +  2H₂O  →  C₂H₂  + Ca(OH)₂

Explanation:

In order to find out the reaction, we must know the reactants.

For this situation, we make acetylene gas from carbide calcium CaC₂ and H₂O (water); therefore the reactants are:

- CaC₂  and  H₂O

Acetylene is one of the products made  →  C₂H₂

So the reaction can be formed as this:  CaC₂  +  H₂O  →  C₂H₂

We missed the calcium, and this reaction also makes, Calcium Hydroxide, so the complete equation must be:

CaC₂  +  H₂O  →  C₂H₂  + Ca(OH)₂

This is unbalanced, because we have 1 O in left side and 2 in right side so we add 2 in water so now, we get the complete reaction:

1 mol of calcium carbide reacts to 2 mol of water in order to produce 1 mol of acetylene and 1 mol of calcium hydroxide.

Determine the [OH⁻] concentration in a 0.344 M Ca(OH)₂ solution.

Answers

Answer:

[tex]0.688M[/tex]

Explanation:

Hello,

In this case, it is widely acknowledged that strong bases usually correspond to those formed with metals in groups IA and IIA which have relatively high activity and reactivity, therefore, when they are dissolved in water the following dissociation reaction occurs (for calcium hydroxide):

[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]

In such a way, for the same volume, we can compute the concentration of hydroxyl ions by simple stoichiometry (1:2 molar ratio):

[tex]0.344\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\0.688\frac{mol OH^-}{L}[/tex]

Or simply:

[tex]0.688M[/tex]

Regards.

Using the determined equivalence point from question 2 and the balanced reaction of acetic acid and sodium hydroxide, calculate the molarity of the acetic acid in your hot sauce packet.
Equivalance point is 3.0 mL NaOH, 0.6 g hot sauce, 0.1 M NaoH.

Answers

Answer:

Molarity of the packet is 0.5M

Explanation:

In the reaction of acetic acid with NaOH:

CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺

1 mole of acetic acid reacts with 1 mole of NaOH.

When you are titrating the acid with NaOH, you reach equivalence point when moles of acid = moles of NaOH.

Moles of NaOH are:

3.0mL = 3.0x10⁻³L ₓ (0.1 mol / L) = 3.0x10⁻⁴ moles of NaOH = moles of CH₃COOH.

Now, you find the moles of acetic acid in the hot sauce packet. But molarity is the ratio between moles of the acid and liters of solution.

As you don't know the volume of your packet, you can assume its density as 1g/mL. Thus, volume of 0.6g of hot sauce is 0.6mL = 6x10⁻⁴L.

And molarity of the packet is:

3.0x10⁻⁴ moles acetic acid / 6x10⁻⁴L =

0.5M

Gallium chloride is formed by the reaction of 2.25 L of a 1.50 M solution of HCl according to the following equation: 2Ga 6HCl --> 2GaCl3 3H2 Determine the mass of gallium chloride, in grams, produced. Group of answer choices

Answers

Answer:

198.56g of GaCl3

Explanation:

We'll begin by calculating the number of mole HCl in 2.25 L of a 1.50 M solution of HCl. This is illustrated below:

Molarity of HCl = 1.50 M

Volume = 2.25 L

Mole of HCl =..?

Molarity = mole /Volume

1.5 = mole /2.25

Cross multiply

Mole = 1.5 x 2.25

Mole of HCl = 3.375 mole

Next, we shall determine the number of mole Gallium chloride, GaCl3 produced from the reaction. This is shown below:

2Ga + 6HCl —> 2GaCl3 + 3H2

From the balanced equation above,

6 moles of HCl reacted to produce 2 moles of GaCl3.

Therefore, 3.375 mole of HCl will react to produce = (3.375 x 2)/6 = 1.125 mole of GaCl3.

Therefore, 1.125 moles of GaCl3 were produced from the reaction.

Next, we shall convert 1.125 mole of GaCl3 to grams. This is illustrated below:

Molar mass of GaCl3 = 70 + (35.5x3) = 176.5g/mol

Mole of GaCl3 = 1.125 mole

Mass of GaCl3 =..?

Mole = mass /Molar mass

1.125 = mass of GaCl3 /176.5

Cross multiply

Mass of GaCl3 = 1.125 x 176.5

Mass of GaCl3 = 198.56g

Therefore, 198.56g of GaCl3 were produced from the reaction.

g what would happen to the solubility of a gas in a solution if the pressure above the solution is increased

Answers

Answer: The solubility of gas increases in a solution if the pressure above the solution is increased

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

[tex]C=K_H\times p[/tex]

where,

C = solubility

[tex]K_H[/tex] = Henry's constant

p = partial pressure

As the solubility is directly proportional to the pressure, thus increasing the pressure increases the solubility.

The element nitrogen would be expected to form covalent bond(s) in order to obey the octet rule. Use the octet rule to predict the formula of the compound that would form between nitrogen and hydrogen , if the molecule contains only one nitrogen atom and only single bonds are formed. Formula:

Answers

Answer:

The compound formula will be "NF₃". The further explanation is given below.

Explanation:

Nitrogen seems to have an electrical structure consisting of 1S², 2S² as well as 3S² and it requires three electrons to fulfill or conclude the octet. This will, therefore, form three bonds (covalent). Even though only single nitrogen has been present, that can only represent a single bond including fluorine. Therefore the methodology for something like the compound would be NF₃.

So that the above would be the right answer.

Which of the following cannot have hydrogen bonds? Select one: A. NH3 B. H2O C. HF D. CH3NH2 E. Which of the following cannot have hydrogen bonds? Select one: A. NH3 B. H2O C. HF D. CH3NH2 E. HCl

Answers

Answer:

E. HCl

Explanation:

Cl atom does not have enough electronegativity to make enough positive charge on H.

HCl is the compound which doesn't have hydrogen bonds. This is because of

the higher size of the chlorine atom.

There is no hydrogen bond because of the high size of the chlorine.

Chlorine have electrons with a very low density. It is also very

electronegative which explains why the formation of hydrogen bonds in the

compound HCl is not possible.

Instead, HCl has covalent bonds in which electron is shared between the

hydrogen and  chlorine to achieve a stable configuration.

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➔ Which compound has both ionic and covalent bonds? A. Ammonium chloride B. Carbon dioxide C. Ethyl ethanoate D. Sodium chloride

Answers

Answer:

Choice A. Ammonium chloride.

Explanation:

Consider the bonds in each of the four compounds.

Ammonium chloride

Ammonium chloride [tex]\rm NH_4Cl[/tex] is an ionic compound. Each

The [tex]\rm {NH_4}^{+}[/tex] and [tex]\rm Cl^{-}[/tex] ions in [tex]\rm NH_4Cl[/tex] are connected with ionic bonds.

What make [tex]\rm NH_4Cl[/tex] special is that its cation [tex]\rm {NH_4}^{+}[/tex] is polyatomic. In other words, each [tex]\rm {NH_4}^{+}[/tex] ion contains more than one atoms. These atoms (one [tex]\rm N[/tex] atom and four [tex]\rm H[/tex] atoms) are connected with covalent bonds. Therefore, [tex]\rm NH_4Cl[/tex] has both ionic and covalent bonds.

Carbon dioxide

Carbon dioxide [tex]\rm CO_2[/tex] is a covalent compound. Each [tex]\rm CO_2[/tex] molecule contains two [tex]\rm C=O[/tex] double bonds in total. [tex]\rm CO_2[/tex] molecules have no ionic bond.

Ethyl ethanoate

The name "ethyl ethanoate" might sound like the name of a salt (think about sodium ethanoate.) However, in reality, ethyl ethanoate [tex]\rm CH_3COOCH_2CH3[/tex] is an ester. The "ethyl" here refers to the [tex]\rm -OCH_2CH3[/tex] part, originating from ethanol. On the other hand, "ethanoate" refers to the [tex]\rm CH_3C(O)-[/tex] part, which can be obtained from ethanoic acid.

These two parts are connected with a covalent [tex]\rm C-O[/tex] single bond. (The [tex]\rm C[/tex] in ethanoic acid is connected to the [tex]\rm O[/tex] in ethanol.) As a result, there's no ionic bond in ethyl ethanoate, either.

Sodium chloride

Sodium chloride [tex]\rm NaCl[/tex] is an ionic compound. Both the [tex]\rm Na^{+}[/tex] ion and the [tex]\rm Cl^{-}[/tex] are monoatomic. While the [tex]\rm Na^{+}[/tex] and [tex]\rm Cl^{-}[/tex] in sodium chloride are connected with ionic bonds, neither [tex]\rm Na^{+}[/tex] nor [tex]\rm Cl^{-}[/tex] contains covalent bond.

The complete combustion of ethanol, C2H5OH(l), to form H2O(g) and CO2(g) at constant pressure releases 1235 kJ of heat per mole of C2H5OH.
Write a balanced equation for this reaction.
Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

Complete combustion means the substance is burnt in unlimited supply of Oxygen therefore carbon dioxide and not carbon monoxide is produced.

Balanced Equation

C2H5OH(l) + 3O2(g) —> 3H2O(g) + 2CO2(g)

For the reaction Ca(s)+Cl2(g)→CaCl2(s) calculate how many grams of the product form when 14.4 g of Ca completely reacts. Assume that there is more than enough of the other reactant.

Answers

Answer:

[tex]m_{CaCl_2}=39.96gCaCl_2[/tex]

Explanation:

Hello,

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

[tex]m_{CaCl_2}=14.4gCa*\frac{1molCa}{40gCa} *\frac{1molCaCl_2}{1molCa} *\frac{111gCaCl_2}{1molCaCl_2}\\ \\m_{CaCl_2}=39.96gCaCl_2[/tex]

Clearly, chlorine is not used since it is said there is enough for the reaction to go to completion.

Best regards.

Which products are formed when aluminum is added to a silver chlorine solution?

Answers

Answer:

Alcl3 and Cl2

Explanation:

the product above will be formed

Answer:

silver (Ag) and aluminum chloride (AlCl₃)

Explanation:

The reaction between aluminum and silver chloride is a single replacement reaction. A single replacement reaction is when one element switches places with another.

Al + 3AgCl ➔︎ 3Ag + AlCl₃

In the reaction, the cations (positively charged ions) switch places. Aluminum (Al) switches places with Silver (Ag). So, the products of the reaction are silver and aluminum chloride.

Hope this helps.

Carbon dioxide gas reacts with liquid water to produce aqueous carbonic acid.” Which chemical equation correctly translates this description? CO2 (s) + H2O (g) → H2CO3 (s) CO2 (l) + H2O (l) → H2CO3 (l) CO2 (g) + H2O (g) → H2CO3 (aq) CO2 (g) + H2O (l) → H2CO3 (aq)

Answers

Last option:
CO2 (g) + H2O (l) -> H2CO3 (aq)

In the brackets:
g = gas,
l = liquid,
s = solid,
aq = aqueous.

So,
CO2 (g) = carbon dioxide gas
H2O (l) = liquid water
H2CO3 (aq) = aqueous carbonic acid

Answer: CO2(g)+H2O(I) > H2CO3(Aq)

Explanation:

Got it right?

A sample of an unknown substance has a mass of 0.158kg. If 2,520.0 j of heat is required to heat the substance from 32.0C to 61.0C what is the specific heat of the substance

Answers

Q= mc0
2520= 0.158 kg x c x ( 61°c - 32° c )
you can find c, specific heat capacity
= 549.98

Write a balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product.

Answers

Answer:

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

Explanation:

Methanol is CH₃OH.  Oxygen is O₂.  A combustion produces CO₂ and H₂O.  Create an equation using this information and balance.

CH₃OH  +  O₂  ⇒  CO₂  +  H₂O

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

The balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is

CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

From the question,

We are to write a balanced equation for the combustion of liquid methanol in air.

The combustion of liquid methanol in air is the reaction between methanol (CH₃OH) and oxygen (O₂). The reaction yields carbon(IV) oxide and water.

Now, for the balanced equation for the combustion of liquid methanol in air

The balanced chemical equation is

CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

Hence, the balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product is CH₃OH(l) + O₂(g) → CO₂(g) + H₂O(g)

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Convert 120 degrees F to K.
[?]K

Answers

120 Fahrenheit -32 x 5/9 +273.15 = 322

Answer:

322

Explanation:

This is easy

Lead can be prepared from galena [lead(II) sulfide] by first heating with oxygen to form lead(II) oxide and sulfur dioxide. Heating the metal oxide with more galena forms the metal and more sulfur dioxide. Write a balanced equation for the overall reaction by adding the balanced equations for the two steps.

Answers

Answer:

2 PbS(s) + 1.5 O₂(g) + PbO(s) ⇒ 2 SO₂(g) + 3 Pb(s)

Explanation:

Lead can be prepared from galena [lead(II) sulfide] by first heating with oxygen to form lead(II) oxide and sulfur dioxide. The corresponding chemical equation is:

PbS(s) + 1.5 O₂(g) ⇒ PbO(s) + SO₂(g)

Heating the metal oxide with more galena forms the metal and more sulfur dioxide. The corresponding chemical equation is:

2 PbO(s) + PbS(s) ⇒ 3 Pb(s) + SO₂(g)

We can get the overall reaction by adding both steps and canceling what is repeated on both sides.

2 PbS(s) + 1.5 O₂(g) + 2 PbO(s) ⇒ PbO(s) + 2 SO₂(g) + 3 Pb(s)

2 PbS(s) + 1.5 O₂(g) + PbO(s) ⇒ 2 SO₂(g) + 3 Pb(s)

Which of the following is an alkali metal?
A. Lithium (LI)
B. Boron (B)
c. Calcium (Ca)
D. Krypton (Kr)

Answers

Answer:

lithium is akali metal

Answer:

lithium is an alkali metal as it lies in group 1st in modern perodic table.

Sort the resources into the correct categories.
are replaced by natural processes
Renewable Resources
Nonrenewable Resources
cannot be replaced in a short time
are used more quickly than replaced
have fixed amounts
are considered unlimited
are replaced faster than used
Intro
✓ Done

Answers

Answer:

Renewable Resources: are considered unlimited, are replaced faster than used.

Nonrenewable Resources: are used more quickly than replaced, have fixed amounts, cannot be replaced in a short time.

Explanation:

Renewable resources are natural resources that are able to naturally regenerate themselves, hence, they are considered to be unlimited. They are usually replaced faster than they are used because they have a short regeneration time. A good example is the solar energy.

Nonrenewable resources are those natural resources that cannot naturally regenerate and when they do, it takes a very long time (usually millions of years). They are therefore used at a much faster rate than they are being replaced and their natural deposits are more or less fixed due to the long regeneration time. A good example is the crude oil deposit.

Hence:

Renewable Resources: are considered unlimited, are replaced faster than used.

Nonrenewable Resources: are used more quickly than replaced, have fixed amounts, cannot be replaced in a short time.

Answer: !

Explanation:

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