73 degrees , x degrees , angles
without knowing the value of "x" in the specific question, its not possible to answer the value of the ×.
Solve the polynomial by completing the square. Show all steps of your work.[tex]x^2+10x+14=-7[/tex]
Answer:
-3, - 7
Step-by-step explanation:
x² + 10x + 14 = -7
x² + 10 x + 21 = 0
Now let's complete the square.
(x + 5)² - 25 + 21 = 0
(x+5)² - 4 = 0
(x+5)² = 4
x + 5 = ± root 4 = ± 2
x = +2-5 or -2-5 = -3 or -7
The values of x that meet the equation x2 + 10x + 14 = -7 are x = -3 and x = -7.
The given equation is: x2 + 10x + 14 = -7.
Transfer the constant term to the opposite side of the equation:
x2 + 10x + 14 + 7 = 0.
Combine comparable terms to simplify the equation: x2 + 10x + 21 = 0.
Complete the square by rewriting the equation with a constant term. To do so, square half of the coefficient of x (which is 10):
Half of ten equals five, and five squared equals twenty-five. Insert 25 into the equation:
x^2 + 10x + 25 + 21 - 25 = 0
Rearrange the terms as follows:
(x2 + 10x + 25) + (21 - 25) = 0.
Reduce the first set of brackets to a perfect square trinomial:
[tex](x + 5)^2 + (-4) = 0[/tex]
Reduce the number of constant terms:
[tex](x + 5)^2 - 4 = 0[/tex]
To find x, take the square root of both sides:
[tex]√((x + 5)^2 - 4) = √0[/tex]
Determine x: x + 5 = 4
To simplify even further, we have: x + 5 = 2
Solve for x separately:
x = -5 + 2 = -3 x = -5 - 2 = -7
As a result, the answers to the equation x2 + 10x + 14 = -7 are x = -3 and x = -7.
Learn more about polynomial from:
https://brainly.com/question/12552477
Factor out the greatest common factor (GCF) using the distributive property (do not solve!).
8 + 12
Hint: Rewrite as __(__+__)
[tex]\begin{array}{r|l}8&2\\4&2\\2&2\\1\end{array}\\\\8=2^3\\\\\\\begin{array}{r|l}12&2\\6&2\\3&3\\1\end{array}\\\\12=2^2\cdot3[/tex]
Therefore, [tex]\text{gcf}(8,12)=2^2=4[/tex].
And so [tex]8+12=4(2+3)[/tex].
8h-4d/d+1
H=1/4 d=5
Evaluate the expression
Solve the polynomial by completing the square. Show all steps of your work.
[tex]x^2 - 11x + 24 = 0[/tex]