Answer:
The probability that the child will have red hair color is 0.75.
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Explanation:
It is provided that each parent has the genotype red / blond which consists of the pair of alleles that determine hair color, and each parent contributes one of those alleles to a child.
The possible outcomes for the hair color of the child are:
S = {R/R, R B, B/R and B/B}
There are four possible outcomes.
Compute the probability that the child will have red hair color as follows:
[tex]P(\text{R})=P(\text{R/R})+P(\text{R/B})+P(\text{B/R})[/tex]
[tex]=\frac{1}{4}+\frac{1}{4}+\frac{1}{4}\\\\=\frac{3}{4}\\\\=0.75[/tex]
Thus, the probability that the child will have red hair color is 0.75.
Compute the probability that a child of these parents will have the blond / blond genotype as follows:
[tex]P(\text{B/B})=\frac{1}{4}=0.25[/tex]
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Answer:
The probability that the child will have red hair color is 0.75.
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Explanation:
It is provided that each parent has the genotype red / blond which consists of the pair of alleles that determine hair color, and each parent contributes one of those alleles to a child.
The possible outcomes for the hair color of the child are:
S = {R/R, R B, B/R and B/B}
There are four possible outcomes.
Compute the probability that the child will have red hair color as follows:
Thus, the probability that the child will have red hair color is 0.75.
Compute the probability that a child of these parents will have the blond / blond genotype as follows:
Thus, the probability that a child of these parents will have the blond / blond genotype is 0.25.
Suppose that 80% of books are classified as fiction. Two books are chosen at random. What is the probability that both books ara fiction?
Answer:
64% or 16/25
Explanation:
To calculate probability, we first find the fraction for the number of books that are fiction.
[tex]80= \frac{4}{5}[/tex]
To find out what the probability of choosing a fiction book twice, we multiply 4/5 with 4/5 to get our probability if we selected a book twice.
[tex]\frac{4}{5} *\frac{4}{5} = \frac{16}{25} \\0.64[/tex]
The probability of choosing two fiction books is a 16/25, or 64% chance.
(SAT Prep) Find y in equilateral △ABC. A. 90° B. 70° C. 60° D. 45°
Answer:
[tex]\boxed{60}[/tex]
Explanation:
Equilateral means that all three sides of a triangle are equal to the same value. When an equilateral triangle is identified, we can also know that the angles will be equal to each other.
ΔABC will have angles that all add up to 180° because it is a triangle. Therefore ⇒ [tex]\frac{180}{3} = \boxed{60}[/tex].
Answer:
60
Explanation:
An equilateral triangle has equal sides and equal angles
The sum of the angles in a triangle is 180
There are 3 angles in a triangle
180/3 = 60
Find the volume, in cubic inches, of the composite solid below, which consists of a 4 -inch square solid rectangular bar that is 16 inches in length. The bar has a 2 -inch diameter cylinder hole cut out of the center of the bar from the top of the bar through the entire length of the bar. Use 3.14 to find the volume. Enter only the number.
Answer:
10 in³
Explanation:
given:
square box = 4 in², length = 16 in
bar diameter = 2 in, length = 16 in
box volume (in solid) = 4 in² * 16 in = 64 in³
bar volume = pi * d² / 4 = 3.14 * 2² / 4 * 16 in = 50.24 in³
Volume of slotted box = 64 - 50 = 10 in³
I NEED HELP PLEASE ANSWER QUICK (SAT Prep) In the given figure, a ∥ b. Find the value of z. A. 50° B. 90° C. 45° D. 75°
Answer:
C
Explanation:
The two z angles form a 90° angle so one z angle would be 45°
Answer:
C. 45°
Explanation:
half of 90° to a perpendicular is equal to 45°