brick falls from a height of 10 m. Calculate the time taken for the brick to reach the ground.​

Answer:

I'm not sure but, this video's pretty cool: gestyy.com/eyRkH2

Explanation:

pretty scary gameplay

Answer:

After five monthly payments, Quiana’s loan amount changes by $1,237.15.

Explanation:

Answer:

It is negativity charged

Answer:

positively charged

Explanation:

a wool has neutral charges hence when rubbed against a balloon it will generate positive charges

Answer:

Its a wave

Explanation:

THis is one

Answer: a light wave

Explanation: a pex

Answer:

convection

Explanation:

I hope this helps

Answer:

Centrifugal force = 1230.77 Newton.

Explanation:

The force associated with the car is generally referred to as centrifugal force and it can be calculated using the formula;

Centrifugal force = mv²/r

Given the following data;

Mass = 800kg

Radius = 65m

Velocity = 10m/s

To find the force;

Centrifugal force = (800*10²)/65

Centrifugal force = (800*100)/65

Centrifugal force = 80000/65

Centrifugal force = 1230.77 Newton.

Answer:

Here u go

Explanation:

Mass of air in the room m= volume of room×density of air

=(5m×4m×3m)(1.20kgm3)=72kg

Weight of air, W=mg=(72kg)(9.8ms2)=706N.

Answer:

person above is correct, i did the work and got the smae answer

Answer:

If a coil of wire is placed in a changing magnetic field, a current will be induced in the wire. This current flows because something is producing an electric field that forces the charges around the wire. (It cannot be the magnetic force since the charges are not initially moving). ... that determines the induced current.

Answer:

H-Hydrogen

B-Boron

O-Oxygen

Au-Gold

Co-Cobolt

He-Helium

Na-Sodium

S-Sulfur

K-Potassium

Ag-Silver

Explanation:

Normally, chemical symbols are either the first letter or the first two letters of the element.

However, there are some exceptions where they use the Latin names e.g:

Aurum-Au-Gold

Natrium-Na-Sodium

Kalium-K-Potassium

Argentum-Ag-Silver

Hope this helps :)

Answer: 0.15 m/s

Explanation:

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Answer:

The relation between velocity and time is a simple one during uniformly accelerated, straight-line motion. The longer the acceleration, the greater the change in velocity. Change in velocity is directly proportional to time when acceleration is constant.

~Hoped this helped~

~Brainiliest?~

Answer:

We describe motion in terms of velocity and acceleration. Velocity: The rate of change of displacement of an object (displacement over elapsed time) is velocity. Velocity is a vector since it has both magnitude (called speed) and direction. ... Acceleration: The rate of change of velocity is acceleration.

Explanation:

Displacement is a vector which points from the initial position of an object to its final position. ... Instantaneous velocity, on the other hand, describes the motion of a body at one particular moment in time. Acceleration is a vector which shows the direction and magnitude of changes in velocity.

Displacement is the vector difference between the ending and starting positions of an object. Velocity is the rate at which displacement changes with time. ... The average velocity over some interval is the total displacement during that interval, divided by the time.

Hope this helps      :)

i think this is the incomplete page that you are showing but the answer is

:-

Answer:

953.5 J/kg.°C

Explanation:

From the question,

Heat lost by the metal = heat gained by the glass.

cm(t₁-t₃) = c'm'(t₃-t₂)................. Equation 1

Where c = specific heat capacity of the metal, m = mass of the metal, c' = specific heat capacity of the glass, m' = mass of the glass, t₁ = initial temperature of  metal, t₂ = initial temperature of glass, t₃ = Equilibrium temperature

Make c' the subject of the equation

c' = cm(t₁-t₃)/m'(t₃-t₂)................ Equation 2

Given: m = 5 kg, c = 650 J/kg.°C, m' = 1.25 kg, t₁ = 80 °C, t₂ = 20 °C, t₃ = 63.9 °C

Substitute these values into equation 2

c' = 5×650(80-63.9)/1.25(63.9-20)

c' = (5×650×16.1)/(1.25×43.9)

c' = 52325/54.875

c' = 953.5 J/kg.°C

Answer:

960 J/(kg*C)

Explanation:

i got this right in acellus  trust me :D

Answer:

l

Explanation:

Answer:

true I believe

Explanation:

Inner Planets:

- Rocky

- Small

- Only 3 moons total

- Very close to each other (for space)

- Underweight

Outer Planets:

- Gassy oop-

- GIANT

- Over 200 moons total

- VERY far from each other

- Obese

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Good luck foe.

Lb.

A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.

Answer:

A switched-mode power supply (switching-mode power supply, switch-mode power supply, switched power supply, SMPS, or switcher) is an electronic power supply that incorporates a switching regulator to convert electrical power efficiently.

Explanation:

Answer: The answer is A

Explanation:

Answer:

The third charge needs to be placed at [tex]x \approx 0.57\; \rm m[/tex].

Explanation:

Both [tex]q_1[/tex] and [tex]q_2[/tex] would attract [tex]q_3[/tex].

These two electrostatic attractions need to balance one another. Hence, they need to be opposite to one another. Therefore, [tex]q_1[/tex] and [tex]q_2[/tex] need to be on opposite sides of [tex]q_3[/tex]. That is possible only if [tex]q_3 \![/tex] is on the line segment between [tex]q_1 \![/tex] and [tex]q_2 \![/tex].

Assume that [tex]q_3[/tex] is at [tex]x\; \rm m[/tex], where [tex]0 < x < 3.72[/tex] (in other words, [tex]q_3 \![/tex] is on the line segment between [tex]q_1[/tex] and [tex]q_2[/tex], and is [tex]x\; \rm m \![/tex] away from [tex]q_2 \![/tex].)

Let [tex]k[/tex] denote Coulomb's constant.

The magnitude of the electrostatic attraction between [tex]q_1[/tex] and [tex]q_3[/tex] would be:

[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}}[/tex].

Similarly, the magnitude of the electrostatic attraction between [tex]q_2[/tex] and [tex]q_3[/tex] would be:

[tex]\displaystyle \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].

The magnitudes of these two electrostatic attractions need to be equal to one another for the resultant electrostatic force on [tex]q_3[/tex] to be [tex]0[/tex]. Equate these two expressions and solve for [tex]x[/tex]:

[tex]\displaystyle \frac{k\cdot q_1 \cdot q_3}{(3.72 - x)^{2}} = \frac{k\cdot q_2 \cdot q_3}{x^{2}}[/tex].

[tex]\displaystyle \frac{q_1}{(3.72 - x)^{2}} = \frac{q_2}{x^{2}}[/tex].

[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1}[/tex].

[tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{q_2}{q_1} = \frac{1}{30}[/tex].

By the assumption that [tex](0 < x < 3.72)[/tex], it should be true that [tex](x > 0)[/tex] and [tex](3.72 - x > 0)[/tex]. Therefore, [tex]\displaystyle \frac{x}{(3.72 - x)} > 0[/tex].

Take the square root of both sides of the equation [tex]\displaystyle \frac{x^2}{(3.72 - x)^{2}} = \frac{1}{30}[/tex].

[tex]\displaystyle \sqrt{\frac{x^2}{(3.72 - x)^{2}}} = \sqrt{\frac{1}{30}}[/tex].

[tex]\displaystyle \frac{x}{3.72 - x} = \frac{1}{\sqrt{30}}[/tex].

[tex]\sqrt{30}\, x = 3.72 - x[/tex].

Therefore:

[tex]\left(1 + \sqrt{30}\right)\, x = 3.72[/tex].

[tex]\displaystyle x = \frac{3.72}{1 + \sqrt{30}} \approx 0.57[/tex].

Hence, [tex]q_3[/tex] should be placed at [tex]x \approx 0.57\; \rm m[/tex].

Answer:

friction as friend

friction as foe

hope it helps

Answer:

Wear and tear of soles of our shoes is due to friction.

When a tyre deflates, it is difficult to move the vehicle because of increased friction between the tyre and the road surface.

Machines get heated up and produce noise because of friction.