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How does the Half-life setting affect how quickly the simulated substance decays?


The greater the half-life is, the faster the rate of decay will be.

The greater the half-life is, the slower the rate of decay will be.

The smaller the half-life is, the slower the rate of decay will be.

The half-life does not affect rate of decay.

Answers

Answer 1

Answer:

the greater the half life is the slower the rate of decay will be.

Explanation:

half life of a radioactive substance is inversely proportional to the radioactive decay.

Answer 2

Answer:

B. The greater the half life is, the slower the rate of decay will be

Explanation: Most living things contain carbon-14, an unstable isotope of carbon that has a half-life of around 5,000 years. That means that when scientists dig up fossil bones, they can figure out how old they are by measuring the amount of carbon-14 remaining in the bones.


Related Questions

How do you determine the height of a wave?

Answers

Answer:

Wave height is the vertical distance between the crest (peak) and the trough of a wave. Some other definitions: Still-Water Line is the level of the lake surface if it were perfectly calm and flat. Crest is the highest point on the wave above the still-water line.

Explanation:

Wave height is the vertical distance between the crest (peak) and the trough of a wave. Some other definitions: Still-Water Line is the level of the lake surface if it were perfectly calm and flat. Crest is the highest point on the wave above the still-water line.

Pls help
The Q : Look at your recorded results and models for both the man and the boy. How close are the coefficients of friction for the sled on ice for two runs? How confident would you feel about specifying a coefficient of kinetic friction for this sled on this ice surface, based on these results? What other variables might impact this coefficient result?

Answers

Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:

The friction coefficients are man is0.8 and for the boy is0.98, the relationship between them is 0.82 The results are very accurate after the graphical analysis. The wind is a very important factor in the calculations that is not taken into account.

Second law of Newton.

Newton's second law establishes a relationship between the net force, the mass and the acceleration of the body. In the attachment we can see a free body diagram which is a schematic of the forces without the details of the bodies.

               N-W = 0

               fr = ma

where N is the normal, W the weight of the body, fr the friction force, m the mass and a the acceleration

The friction force is a macroscopic representation of the interactions between the two surfaces, it is given by the expression

             fr = μ N

where μ is the coefficient of friction between the two surfaces.

We substitute

             μ mg = m a

             a = μ g

Kinematics and graphic analysis.

Kinematics study the movement of bodies, looking for relationships between position, speed and acceleration.

             v= v₀ – at t

In this case they give tables and graphs with the values ​​of time and speed, where we can see that the relationship is a straight line that has as equation

            y = ax +b

Where y is the dependent variable, x is the independent variable, a is the slope, and b is the cutoff point.

If we relate the two equations:

The independent variable x → time. The dependent variable y → speed. The cutoff point b → the initial velocity. The slope (a) is:

          a = mug

          μ = [tex]\frac{a}{g}[/tex]

Using linear regression the slope and cutoff point is:

The man.

The slope is a = -0.8 m/s² and the cut-off point b= 4.86 m/s.

Let's calculate the coefficient of friction.

          μ =  [tex]\frac{0.8}{9.8}[/tex]  

          μ  = 0.082

The child.

The slope is a = -0.98 m/s² and the cut-off point b= 4.72 m/s.

We calculate the coefficient of friction.

          μ  = [tex]\frac{0.98}{9.8}[/tex]  

          μ  = 0.1

The relationship between the two coefficients of friction is

        [tex]\frac{\mu_{man} }{\mu_{boy}} = \frac{0.082}{0.1}[/tex]  

         [tex]\frac{\mu_{man}}{\mu_{boy}} = 0.82[/tex]

The results are very exact since there are values ​​of several points in the route and the graphical analysis gives the best possible value for all the points.

There are some variables not taken into account, one of the most important is friction with the wind and wind speed.

In conclusion using Newton's second law, kinematics and graphic analysis we can find the results for the questions about the movement of the trine are:

The friction coefficients are man is0.8 and for the boy is0.98, the relationship between them is 0.82 The results are very accurate after the graphical analysis. The wind is a very important factor in the calculations that is not taken into account.

Learn more about kinematics and graphical analysis here: brainly.com/question/11579754

An artillery shell is fired with an initial speed of 300m/s at 55 deegry about the horizontal,it explodes on a mountain side 42s after firing,what are the x and y coordinate of the shell where it explodes relative to its firing point?

Answers

Answer:

x = 7226.94 m

y = 1677.4 m

Explanation:

This is a classic problem of a parabolic move. Let's analyze the given data.

The speed is 300 m/s but it's fired at 55°, so the x and y component of the speed would be:

Vx = 300 cos55 = 172.07 m/s

Vy = 300 sin55 = 245.75 m/s

Now, to get the x and y components of the shell, we need to apply the following expressions:

X = Xo + Vx*t    (1)

Y = Yo + Vy*t - 1/2 gt²   (2)

Xo and Yo is 0, and we already have the speed in x and y, so the components are:

X = 0 + (172.07)(42)

X = 7226.94 m

For the y component:

Y = 0 + (245.75)(42) - 1/2 (9.8)(42)²

Y = 10321.5 - 8643.6

Y = 1677.4 m

Hope this helps

20 points + Brainliest. Help please!

In an adiabatic process, the pressure on an ideal gas is increased to 14 times its initial value. The initial volume is 78 L. What is the final volume? Let γ = 1.67.
A. 16 L
B. 22 L
C. 8.1 L
D. 10 L

Answers

Answer:

i belive it should be C

Explanation:

How do the offspring produced by asexual reproduction differ from those produced by sexual reproduction?
А.
Offspring produced by asexual reproduction are bigger.
В.
Offspring produced by asexual reproduction use more energy.
С.
Offspring produced by asexual reproduction are more uniform.
D
Offspring produced by asexual reproduction are produced more slowly.

Answers

Answer:

Asexual reproduction produces offspring that are genetically identical to the parent because the offspring are all clones of the original parent. During sexual reproduction the genetic material of two individuals is combined to produce genetically diverse offspring that differ from their parents.

Explanation:

On Mars, which has 0.38 the gravity of Earth, the acceleration of
a dropped ball will be _ m/s2 and the weight of a 50 kg
basketball player would be
_N.

Answers

Answer:

if g on Earth= 9.8m/s²

then g on moon will be 0.38 *9.8=3.7m/s²

Mass of a basketball player is 50kg then the weight will be 50*3.7=186.2N

Question 2 10 points)
Blueprints were used in the year

Answers

Answer:

1842.

Explanation: Blueprints were invented a generation before the Civil War by John Herschel, a chemist, astronomer, and photographer, in 1842.

Urgent! Pls help
A bug and windshield of a fast-moving vehicle collide. Which of the following statements does NOT describe this situation?

A) The change in momentum of the bug and the vehicle is the same.

B) The force felt by the bug and the vehicle is the same.

C) The impulse felt by the bug and the vehicle is the same.

D) The acceleration of the bug and the vehicle is the same.

Answers

Answer:

The force felt is the same

Explanation:

how the relationship between photosynthesis and cellular respiration prove that the Laws of Conservation of Mass and Energy exists in living systems?

Answers

Answer:

The AMOUNT of oxygen and carbon atoms released by photosynthesis are EXACTLY EQUAL to the atoms of these material contained in carbon-dioxide converted. In this way photosynthesis has conserved the mass or material, and in this way followed the law of conservation of mass.

What type of reaction feels cold to the touch? A. Endothermic, because energy is being released into the surroundings B. Endothermic, because energy is being absorbed from the surroundings C. Exothermic, because energy is being released into the surroundings D. Exothermic, because energy is being absorbed from the surroundings

Answers

Answer:

D. Exothermic, because energy is being absorbed from the surroundings

Explanation:

This is true about the Exothemic reaction due to the fact that, the reaction occurs outside the body. During this reaction, the energy being absorbed from the surrounding environment will hit the body surface thereby creating the coldness due to the heat given out from the body  being minimal.

Answer:

Endothermic, because energy is being absorbed from the surroundings.

Explanation:

A bullet of mass 50 g travelling with a speed of 15ms penetrates into a
bag of sand and is uniformly brought to rest in 0.05s.

Find
(a) How for the bullet will penetrate into the bag of sand?
(b) The Average force exerted by the sand ?

Answers

Answer:

a) The bullet will penetrate 0.375 meters into the bag of sand.

b) The average force exerted by the sand is 15 newtons.

Explanation:

The statement is incorrectly written. The correct form is presented below:

A bullet of mass 50 grams travelling with a speed of 15 meters per second penetrates into a bag of sand and is uniformly brought to rest in 0.05 second.

a) How far the bullet will penetrate into the bag of sand?

b) The average force exerted by the sand?

b) The average force exerted by the sand on the bullet ([tex]F[/tex]), measured in newtons, is determined by Principle of Linear Momentum Conservation and Impulse Theorem:

[tex]F = \frac{m\cdot (v_{f}-v_{o})}{\Delta t}[/tex] (1)

Where:

[tex]m[/tex] - Mass of the bullet, measured in kilograms.

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Initial and final speeds of the bullet, measured in meter per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]\Delta t = 0.05\,s[/tex], then the average force exerted by the sand is:

[tex]F = \frac{(0.05\,kg)\cdot \left(0\,\frac{m}{s}-15\,\frac{m}{s} \right)}{0.05\,s}[/tex]

[tex]F = -15\,N[/tex]

The average force exerted by the sand is 15 newtons.

a) The distance travelled by the bullet ([tex]\Delta s[/tex]), measured in meters, is determined by application of Principle of Energy Conservation and Work-Energy Theorem:

[tex]\Delta s = \frac{m\cdot (v_{f}^{2}-v_{o}^{2})}{2\cdot F }[/tex] (2)

If we know that [tex]m = 0.05\,kg[/tex], [tex]v_{o} = 15\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex] and [tex]F = -15\,N[/tex], then the distance travelled by the bullet is:

[tex]\Delta s = \frac{(0.05\,kg)\cdot \left[\left(0\,\frac{m}{s} \right)^{2}-\left(15\,\frac{m}{s} \right)^{2}\right]}{2\cdot (-15\,N)}[/tex]

[tex]\Delta s = 0.375\,m[/tex]

The bullet will penetrate 0.375 meters into the bag of sand.

A football player is tackled by another player and lands with the combined weight of both players on his knee. If the combined weight of the players is 2400 N and the player's knee measures 0.1 m by 0.1 m, how much pressure is exerted on the turf when the player lands on his knee?

Answers

Answer:

the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².

Explanation:

Given;

combined weight of the players, F = 2400 N

measurement of the player's knee = 0.1 m by 0.1 m

The area of the player's knee is calculated as;

A = 0.1 m x 0.1 m = 0.01 m²

The pressure exerted on the turf when the player lands on his knee is calculated as;

P = F / A

P = (2400 N) / (0.01 m²)

P = 240,000 N/m²

Therefore, the pressure exerted on the turf when the player lands on his knee is 240,000 N/m².

What is the force on a 1000 kg elevator that is falling freely at 9.8 m/ sec²? ​

Answers

Answer:

f=m.a 1000*9.8=9800newton

A phonograph record 0.15 m in its radius rotates 18 times per 90 seconds what is the frequency?

Answers

Answer:

The frequency of the phonograph record is 0.2 Hz

Explanation:

The frequency of an object moving in uniform circular motion is the number of completed cycles the object makes in a specified time period

The given parameters of the phonograph record are;

The radius of the record = 0.15 m

The number of times the phonograph record rotates, n = 18 times

The time it takes the phonograph record to rotate the 18 times, t = 90 seconds

The frequency of the phonograph record, f = (The number of times the phonograph record rotates) ÷ (The time it takes the phonograph record to rotate the 18 times)

∴ The frequency of the phonograph record, f = n/t = 18/(90 s) = 0.2 Hz

The frequency of the phonograph record = 0.2 Hz.

HELPPPPP!

which of the following is a human action that could lead to decreased amounts of greenhouse gases found in the atmosphere, such as carbon dioxide?

A ) Generating energy by burning coal
B ) Deforestation
C ) Driving automobiles
D ) Planting trees

Answers

I believe the answer is C

According to Newton’s second law of motion, what is force equal to?

Answers

Answer:

Force is equal to Mass Multiplied by Acceleration

F = M x A

Answer:

Newton's second law of motion is F = ma, or force is equal to mass times acceleration.

An aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m drops a package of supplies. a) Express the initial velocity of the package as a vector

Answers

Answer:

Explanation:

If unit vector towards east is represented by i in the present case ,

initial horizontal velocity of aircraft towards east is 70 m /s . The package dropped by the aircraft will also have same velocity while getting separated from the aircraft . Hence its velocity is represented by the vector ,

v = 70 i .

Its vertical velocity of package at that time will be zero so

v = 70 i + 0 j

= 70 i

Initial Velocity can be defined as the velocity at which the motion starts.

Initial Velocity for the package is [tex]70i[/tex].

Given that an aircraft flying at a steady velocity of 70 m/s eastwards at a height of 800 m.

Here we express the steady velocity as [tex]u\;\rm m/s[/tex]. Distance is expressed by [tex]d\;\rm meter[/tex]. Initial Velocity can be expressed as [tex]v\;\rm m/s[/tex].

Initial velocity can be calculated by the formula given below.

[tex]v\;=\;u\;+\;at[/tex]

In the above formula, [tex]a[/tex] is expressed the acceleration and [tex]t[/tex] is expressed the time of the motion.

For the initial velocity, time [tex]t\;=\;0[/tex] because motion starts in the vertical direction. Let us assume that unit vector can be expressed by [tex]i[/tex] and [tex]j[/tex].

Initial velocity formula in vector form is given below.

[tex]v\;=\;ui\;+\;atj[/tex]

By substituting all the values in the above formula, initial velocity is

[tex]v\;=\;ui\;+\;a\times0j\\v\;=\;ui\\v\;=\;70i[/tex]

So the initial velocity of the package is 70[tex]i[/tex].

For more details about the velocity, follow the link given below.

https://brainly.com/question/862972.

NEED HELP ASAP
thanks + BRAINLIST only for correct answer

Answers

Answer:

I. They come from sources across space

II. They travel in a straight line from their source.

III. They can be reflected by some types of material.

Explanation:

Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.

The following statements about light waves are true;

I. They come from sources across space.

II. They travel in a straight line from their source.

III. They can be reflected by some types of material. reflection occurs when a ray of light or wavefronts bounces off a smooth surface. Thus, when light hit a surface, it bounces back to the medium from which it was originally propagated with.

However, light waves cannot travel through all type of material except materials that are transparent or translucent but not opaque.

A 2011 Porsche 911 Turbo S goes from 0-27 m/s in 2.5 seconds. What is the car's acceleration?

Answers

Answer:

-10.8m/s^2

Explanation:

a=change in velocity/change in time

-27 m/s/2.5=10.8m/s^2

or if its not negative

27m/s/2.5=10.8m/s^2

When more energy is released when new bonds are formed. Which bonds are stronger. Please add why

1. The bonds that are formed
2. The bonds that are broken

Answers

Answer:

the bonds that are formed

Explanation:

Energy is absorbed in order to break bonds.  Energy is released when new bonds are formed. Bond-making is a process of exothermic. Whether the reaction is endothermic or exothermic refers to the difference between the energy needed to break bonds and the energy released when new bonds are formed.

5. If an object has an acceleration of 0 m/s2, then one can be sure that the object is not ____.

a. moving

b. changing position

c. changing velocity


6. If car A passes car B, then car A must be ____.

a. accelerating.

b. accelerating at a greater rate than car B.

c. moving faster than car B and accelerating more than car B.

d. moving faster than car B, but not necessarily accelerating.

7. Which one of the following is NOT consistent with a car which is accelerating?

a. A car is moving with an increasing speed.

b. A car is moving with a decreasing speed.

c. A car is moving at a high speed.

d. A car is changing direction.

8. A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that

a. he is accelerating

b. he is covering a greater distance in each consecutive second.

c. he is moving with a constant speed (on average).

Answers

Answer: c

Explanation: for #5 it can still be moving, just at a constant speed; therefore, it will be c.

If an object has an acceleration of 0 m/s2, then one can be sure that the object is not changing velocity.

If car A passes car B, then car A must be moving faster than car B, but not necessarily accelerating.

The not consistent with a car that is accelerating is a car is moving at a high speed.

A fullback is running down the football field in a straight line. He starts at the 0-yard line at 0 seconds. At 1 second, he is on the 10-yard line; at 2 seconds, he is on the 20-yard line; at 3 seconds, he is on the 30-yard line; and at 4 seconds, he is on the 40-yard line. This is evidence that he is moving with a constant speed (on average).

What is Acceleration?Acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities (in that they have magnitude and direction). Speed is the distance covered in a unit of time while acceleration is the rate of change in speed. The unit of speed in the metric system is meters per second (m/s) while that of acceleration is meters per second squared (m/s2). Speed is a scalar quantity while acceleration is a vector quantity.

To learn more about acceleration and speed, refer to: https://brainly.com/question/25086037

#SPJ2

dont mind this question

Answers

lol there’s no question

ASNWER THIS OR ILL KIDNAPP YOUR DOG AND REVEAL YOUR SEARCH HISTORY!!
Name 3 different forces that act on objects on the Earth

Answers

Answer:

Applied Force.

Gravitational Force.

Normal Force.

Frictional Force.

Air Resistance Force.

Tension Force.

Spring Force.

Explanation:

:)

Please help with this?!?!?!?!?!?!

Answers

Answer: c because our solar system is called the milky way

Explanation:

How does a balanced Chemical Equation Satisfy the Law of Conservation of Mass?
A. During a chemical reaction, the total amount of matter stays the same.
b. During a chemical reaction, matter is destroyed.
c. During a Chemical reaction, one ore more new substances formed.
d. During a chemical reaction, the total number of atoms increases.

Answers

During a chemical reaction,one ore more new substances forwed

Which statement best describes the relationship between mass and gravitational attraction (pull)?

Answer choices:

The more mass an object has, the greater the gravitational pull.

The less mass an object has, the greater the gravitational pull.

All objects have the same gravitational pull on other objects.

Mass has no effect on gravitational pull.

Answers

Answer:

The first option, "The more mass an object has, the greater the gravitational pull. "

Explanation:

Newton's Law of Gravity states that [tex]F_G=\frac{Gm_1m_2}{r^{2}}[/tex], where G is the gravitational constant, [tex]m_1[/tex] and [tex]m_2[/tex] are the masses of the two objects, and r is the distance between the objects' centers. Because the objects' masses are in the fraction's numerator, they are directly proportional to [tex]F_G[/tex], and increasing the mass of one or both objects increases the gravitational pull.

Please have a great day! I hope this helps you understand the question!

What is the kinetic energy of a 25kg object moving at a velocity of 2.5 m/s

Answers

Answer:

78j

Explanation:

78.125J to be exact

An automobile moves on a level horizontal road in a circle of radius 30 m. The coefficient of
friction between tires and road is 0.50. The maximum speed with which this car can round
this curve is????/

Answers

Answer:

v = 12.12 m/s      

Explanation:

It is given that,

Radius of circle, r = 30 m

The coefficient friction between tires and road is 0.5,

The centripetal force is balanced by the force of friction such that,

v = 12.12 m/s

So, the maximum speed with which this car can round this curve is 12.12 m/s. Hence, this is the required solution.

Is this right? I think i am but i wanna make sure

Answers

yea your answer is corrext

8. Calculate the total resistance in a series circuit with a fan (3 ohms) and 3 lights (1 ohms each). 9 ohms O 12 ohms 15 ohms 06 ohms​

Answers

Answer:

 R_eq = 6 Ω

Explanation:

In a series circuit the current is constant throughout the circuit and the resistance is the sum of all the resistances in it.

         R_eq = ∑

in this case we have

         R_eq = R₁1 + 3 R₂

where R₁ is the resistance of the fan and R₂ the resistance of each light, we must clarify that we will assume that the resistance of the lights does not change with temperature

let's calculate

          R_eq = 3 + 3 1

           R_eq = 6 Ω

Answer:

6 ohms

Explanation:

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