Brainliest if right.

Someone fires a 0.04 kg bullet at a block of wood that has a mass of 0.5 kg. (The block of wood is sitting on a frictionless surface, so it moves freely when the bullet hits it). The wood block is initially at rest. The bullet is traveling 300 m/s when it hits the wood block and sticks inside it. Now the bullet and the wood block move together as one object. How fast are they traveling?

Answers

Answer 1

Answer:

Explanation:

Remark

This is a conservation problem.

The momentum before impact = momentum after impact

momentum before

m = 0.04 kg

v = 300 m/s

momentum after

m = 0.5 kg + 0.04kg    That's the mass of the block and bullet

v = ?

Solution

0.04 * 300 = 0.54 * x

12 kg m/s   = 0.54 kg * x

12 / 0.54 = x

x = 22.22 m/s


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