Answer:
Hi, there your answer is A. As the frequency of a wave increases, the shorter its wavelength is.
Explanation:
When frequency increases, wavelength decreases.
Hope this Helps :)
Look at the reaction below. Upper H subscript 2 upper S upper O subscript 4 (a q) plus upper C a (upper O upper H) subscript 2 (a q) right arrow upper C a upper S upper O subscript 4 (a q) plus 2 upper H subscript 2 upper O (l). Which substance is the base in the reaction? A. 2H2O (l) B. H2SO4 (aq) C. CaSO4 (aq) D. Ca(OH)2 (aq)
Answer:
Its D
Explanation:
Did it on edge
According to the reaction: H₂S0₄ + Ca(OH)₂ → CaSO₄+ 2H₂O, the base is Ca(OH)₂.
What is a base?Base is defined as a substance which can accept protons or any chemical compound that yields hydroxide ions (OH-) in solution.
Generally, base are substances that produces hydroxide ion when dissolve in water.
Base are substances that reacts with acid to produce salt and water. Example of base includes sodium hydroxide, potassium hydroxide, magnesium hydroxide, calcium hydroxide etc.
Therefore, according to the reaction:
H₂S0₄ + Ca(OH)₂ → CaSO₄+ 2H₂O
The base is Ca(OH)₂.
learn more on chemical reaction here: https://brainly.com/question/14575718
When water and alcohol are mixed, the final volume is less than the total of volume of alcohol plus water added due to .......
Answer:
molecules take up more space
In the following reaction, C5H12(1) + 8 O2 (g) - 6 H2O (g) + 5 CO2 (g), how many
moles of water (H20) are produced by 14.2 moles of O2?
Answer:
10.65 moles
Explanation:
O2:H2O
8:6
14.2:x
x= 10.65 moles
Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
Answer: There are [tex]16.14 \times 10^{23}[/tex] atoms of hydrogen are present in 40g of urea, [tex](NH_{2})_{2}CO[/tex].
Explanation:
Given: Mass of urea = 40 g
Number of moles is the mass of substance divided by its molar mass.
First, moles of urea (molar mass = 60 g/mol) are calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol[/tex]
According to the mole concept, 1 mole of every substance contains [tex]6.022 \times 10^{23}[/tex] atoms.
So, the number of atoms present in 0.67 moles are as follows.
[tex]0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms[/tex]
In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.
[tex]4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms[/tex]
Thus, we can conclude that there are [tex]16.14 \times 10^{23}[/tex] atoms of hydrogen are present in 40g of urea, [tex](NH_{2})_{2}CO[/tex].
A chemical bond formed when two atoms share three pairs of electrons is a ________ bond; it is best described as ________.
Answer:
Explanation:
A chemical bond formed when two atoms share three pairs of electrons is a triple bond; it is best described as covalent.
scenario Juan and Maria Lopez wish to invest in a no-risk savings account. They currently have 530,000 in an account bearing 5.25 % annual interest, compounded continuously. The following options are available to them.
Answer:
The amount after three year is 617934.1302
Explanation:
Complete question
A person places $530,000 in an investment account earning an annual rate of 5.25%, compounded continuously. Using the formula V = Pe^{rt}V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 3 years
Solution
The formula for calculating compound interest is
[tex]A = p (1 + \frac{r}{n})^{nt}[/tex]
Substituting the given values we get -
[tex]A = 530,000 (1 + \frac{5.25}{100})^3\\A = 530,000 * ( 1+ 0.0525)^3\\A = 530,000 * ( 1.0525)^3\\A = 617934.1302[/tex]
The amount after three year is 617934.1302
PLEASE HELP ME!!!!
TRUE or FALSE: When sperm and egg cells combine in fertilization, the
offspring ends up with the same number of chromosomes as their
parents.
Answer: False
Explanation:
Hope this help
Answer:
True.
Explanation:
Every child will contain the same number of chromosomes as the parents (otherwise they wouldn't be considered the same species). Additionally, animals can only mate with a species containing the same number of chromosomes as themselves. This means if the offspring of the parents had a different number fo chromosomes the offspring would be unable to mate with animals of it's own species.
PLEASE HELP ME!!!!!!!
Answer:
The heat capacity of the metal underneath the gold is 0.431 J/g°C
Explanation:
Using the formula as outlined in the image:
Q = m × c × ∆T
Where;
Q = amount of heat energy (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to the information in this question;
Q = 503.9J
m = 23.02g
c = ?
∆T = 74°C - 23.2°C = 50.8°C
Using Q = m × c × ∆T
c = Q ÷ m∆T
c = 503.9 ÷ (23.02 × 50.8)
c = 503.9 ÷ 1169.42
c = 0.431 J/g°C
From the above heat capacity of the metal underneath the gold, it is obvious that the metal is not pure gold (c = 0.129J/g°C)
How do isotopes of the same atom react chemically? How do isotopes of the same atom compare in size?
Atoms of the same elements differing in the number of neutrons in their nuclei are known as isotopes. Thus, isotopes of an element have the same atomic number but different atomic mass number. Isotopes of an element have similar chemical properties but different physical properties.
The mass of 1.63×10^21 silicon atoms
Answer:
I think it is 7.60 X 1
but if it's not srry
PbO2 + 4HCl --- PbCl2 + Cl2 + 2H2O who buys electrons and who loses electrons?
Answer: Electrons are taken up by [tex]PbO_2[/tex] and they are lost by [tex]HCl[/tex]
Explanation:
Redox reaction is defined as the reaction in which oxidation and reduction take place simultaneously. It is also called the reaction where the exchange of electrons takes place.
An oxidation reaction is defined as the reaction in which a chemical species loses electrons takes place. In this reaction, the oxidation state of a substance gets increased.
A reduction reaction is defined as the reaction in which a chemical species gains electrons takes place. In this reaction, the oxidation state of a substance gets reduced.
For the given chemical reaction:
[tex]PbO_2+4HCl\rightarrow PbCl_2+Cl_2+2H_2O[/tex]
The half-reactions for this redox rection follows:
Oxidation half-reaction: [tex]2HCl\rightarrow ClO_2 + 2e^-[/tex]
Reduction half-reaction: [tex]PbO_2+2e^-\rightarrow PbCl_2[/tex]
Hence, electrons are taken up by [tex]PbO_2[/tex] and they are lost by [tex]HCl[/tex]
About how long did it take for this population to reach the carrying capacity of this habitat
Answer:100
Explanation:
Determine the molarity and mole fraction of a 1.09 m solution of acetone (CH3COCH3) dissolved in ethanol (C2H5OH). (Density of acetone
Answer:
Molarity = 0.809 M
mole fraction = 0.047
Explanation:
The complete question is
Calculate the molarity and mole fraction of acetone in a 1.09-molal solution of acetone (CH3COCH3) in ethanol (C2H5OH). (Density of acetone = 0.788 g/cm3; density of ethanol = 0.789 g/cm3.) Assume that the volumes of acetone and ethanol add.
Solution -
Solution for molarity:
1.09-molal means 1.09 moles of acetone in 1.00 kilogram of ethanol.
1)
Mass of 1.09 mole of acetone
= 1.09 mol x 58.0794 g/mol = 63.306 g
Density of acetone = 0.788 g/cm3
Thus, volume of 1.09 moles of acetone = 63.306 g/0.788 g/cm3 = 80.34 cm3
For ethanol
1000 g divided by 0.789 g/cm3 = 1267.427 cm3
Total volume of the solution = Volume of acetone + Volume of ethanol = 80.34 cm3 + 1267.427 cm3 = 1347.765 cm3 = 1.347 L
a) Molarity:
1.09 mol / 1.347 L = 0.809 M
Mole Fraction
a) moles of ethanol:
1000 g / 46.0684 g/mol = 21.71 mol
b) moles of acetone:
1.09 / (1.09 + 21.71) = 0.047
In which substance are molecules moving the fastest? The options are, a. Solid water (ice) b. Liquid water c. Water vapor (gas)
Answer:
The answer is C
Explanation:
The more space the molecules have the faster they will move, solid doesn't allow movement at all, when it gets to liquid they are free to move around because it's more space, when a gas they can move all around in the air.
If a gas is at a pressure of 46 mm Hg and temperature of 640 K, what would be the temperature if the pressure was raised to 760 mm Hg?
Answer:
10573.9K
Explanation:
Using pressure law equation;
P1/T1 = P2/T2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
T1 = initial temperature (K)
T2 = final temperature (K)
According to the information provided in this question,
P1 = 46mmHg
P2 = 760mmHg
T1 = 640K
T2 = ?
Using P1/T1 = P2/T2
46/640 = 760/T2
Cross multiply
640 × 760 = 46 × T2
486400 = 46T2
T2 = 486400 ÷ 46
T2 = 10573.9K
A 50.00 g sample of a compound containing only carbon, hydrogen, and oxygen was partially analyzed. The sample contained 24.66 g carbon, and 3.43g of hydrogen. The molecular weight of the compound was determined to be 146.0 amu. Determine emperical the molecular formula of the compound
Answer:
1. Empirical formula => C₂H₃O
2. Molecular formula => C₆H₉O₃
Explanation:
From the question given above, the following data were obtained:
Mass of compound = 50 g
Mass of Carbon = 24.66 g
Mass of Hydrogen = 3.43 g
Molecular weight of compound = 146.0 amu
Empirical formula =?
Molecular formula =?
Next, we shall determine the mass of oxygen in the compound. This can be obtained as follow:
Mass of compound = 50 g
Mass of C = 24.66 g
Mass of H = 3.43 g
Mass of O =?
Mass of O = mass of compound – ( mass of C + mass of H)
= 50 – (24.66 + 3.43)
= 50 – 28.09
= 21.91 g
1. Determination of the empirical formula.
Mass of C = 24.66 g
Mass of H = 3.43 g
Mass of O = 21.91 g
Divide by their molar mass
C = 24.66 / 12 = 2.055
H = 3.43 / 1 = 3.43
O = 21.91 / 16 = 1.369
Divide by the smallest
C = 2.055 / 1.369 = 2
H = 3.43 / 1.369 = 3
O = 1.369 / 1.369 = 1
Therefore, the empirical formula of the compound is C₂H₃O
2. Determination of the molecular formula.
Molecular weight of compound = 146.0 amu
Empirical formula => C₂H₃O
Molecular formula =?
Molecular formula = [C₂H₃O]ₙ = molecular weight
Thus,
[C₂H₃O]ₙ = 146
[(12×2) + (3×1) + 16]n = 146
[24 + 3 + 16]n = 146
43n = 146
Divide both side by 43
n = 146 / 43
n = 3
Molecular formula = [C₂H₃O]ₙ
Molecular formula = [C₂H₃O]₃
Molecular formula = C₆H₉O₃
The student kicks the soccer ball three times and I shouldn’t record the distance the amount of time the ball travels and the average speed in the table shown below soccer ball girl how many seconds did it take for the ball to travel 30 m during kick three
Answer: D it’s is 2.0 s
i think..
Explanation:
Which waves are blocked by the atmosphere? A. gamma rays B. visible light C. radio waves D. infrared waves
Answer: look at the explanation and try to work it
Explanation: in contrast, our atmosphere blocks most ultraviolet light (UV) and all X-rays and gamma-rays from reaching the surface of Earth. Because of this, astronomers can only study these kinds of light using detectors mounted on weather balloons, in rockets, or in Earth-orbiting satellites.
how many moles of Carbon are in 3.06 g of Carbon
Answer:
[tex]\boxed {\boxed {\sf 0.255 \ mol \ C }}[/tex]
Explanation:
If we want to convert from grams to moles, the molar mass is used. This is the mass of 1 mole. They are found on the Periodic Table as the atomic masses, but the units are grams per mole (g/mol) instead of atomic mass units (amu).
Look up the molar mass of carbon.
Carbon (C): 12.011 g/molSet up a ratio using the molar mass.
[tex]\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Since we are converting 3.06 grams to moles, we multiply by that value.
[tex]3.06 \ g \ C*\frac {12.011 \ g \ C}{ 1 \ mol \ C}[/tex]
Flip the ratio. This way, the ratio is still equivalent, but the units of grams of carbon cancel.
[tex]3.06 \ g \ C* \frac{1 \ mol \ C}{12.011 \ g\ C}[/tex]
[tex]3.06 * \frac{1 \ mol \ C}{12.011 }[/tex]
[tex]\frac {3.06}{12.011 } \ mol \ C[/tex]
[tex]0.25476646 \ mol \ C[/tex]
The original measurement of grams (3.06) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place.
0.25476646The 7 in the ten-thousandth place tells us to round the 4 up to a 5.
[tex]0.255 \ mol \ C[/tex]
3.06 grams of carbon is approximately 0.255 moles of carbon.
The solubility of an ionic compound can be expressed as the number of moles of the compound that will dissolve per liter of solution (molarity). The saturated solution has approximately____(a) sodium ions dissolved in it (give an estimate of the average value.) The solution (not the solid) contains approximately_____(b) moles of sodium ions.
Answer:
Number of moles of sodium dissolved = 6.0 *10^23
Explanation:
The image for the question is attached
Solution
a) Total 181 ions of Na are dissolved
b)
The number of moles of sodium dissolved = 181/6.023 *10^23
Number of moles of sodium dissolved = 5.987 * 10^23
Number of moles of sodium dissolved = 6.0 *10^23
A potted plant is placed under a grow lamp, which provides 6,400 J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0.840 J/g°C and the temperature goes up by 9.25°C of soil. How many grams of soil are there?
Answer:
823.7g
Explanation:
Using the formula as follows:
Q = m × c × ∆T
Where;
Q = amount of heat (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
Using the information given in this question as follows:
Q = 6,400 J
m = ?
c of soil = 0.840 J/g°C
∆T = 9.25°C
Using Q = mc∆T
m = Q ÷ c∆T
m = 6,400 ÷ (0.840 × 9.25)
m = 6400 ÷ 7.77
m = 823.7g
Answer:
There are 823.68 grams.
Explanation:
Calorimetry is responsible for measuring the amount of heat generated or lost in certain physical or chemical processes.
Between heat and temperature there is a relationship of direct proportionality. The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body. In summary, the amount of heat Q that receives or transmits a mass m of a substance with specific heat C to raise its temperature from T1 to T2 is given by the formula:
Q= C*m* (T2- T1) = C*m* ΔT
In this case:
Q= 6400 JC= 0.840 [tex]\frac{J}{g*C}[/tex]m= ?ΔT= 9.25 CReplacing:
6400J= 0.840 [tex]\frac{J}{g*C}[/tex] *m* 9.25 C
Solving:
[tex]m=\frac{6400 J}{0.840 \frac{J}{g*C} *9.25 C}[/tex]
m=823.68 grams
There are 823.68 grams.
A 136 g sample of an unknown substance was heated from 20.0 °C to 40.0 °C. In the process the substance absorbed 2440 J of energy. What is the specific heat of the substance? Identify the substance among those listed in Table 2.
A. the specific heat is 0.897 J/g.C, The Substance is aluminum
B. the specific heat is -0.897 J/g.C, The Substance is aluminum
C. the specific heat is 4.184 J/g.C, The Substance is water
D. there's not enough information to determine which is the substance.
Answer:
Option A. The specific heat is 0.897 J/gºC, The Substance is aluminum.
Explanation:
We'll begin by calculating the change in temperature of the substance. This can be obtained as follow:
Initial temperature (T₁) = 20.0 °C
Final temperature (T₂) = 40.0 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 40 – 20
ΔT = 20 °C
Finally, we shall determine the specific heat capacity of the substance. This can be obtained as follow:
Mass (M) = 136 g
Change in temperature (ΔT) = 20 °C
Heat (Q) absorbed = 2440 J
Specific heat capacity (C) =?
Q = MCΔT
2440 = 136 × C × 20
2440 = 2720 × C
Divide both side by 2720
C = 2440 / 2720
C = 0.897 J/gºC
Comparing the specific heat capacity (i.e 0.897 J/gºC) of the substance with those in the table above, the substance is Aluminum.
Thus, option A gives the correct answer to the question.
The MO diagram of CN is similar to N2. Based on the molecular orbital energy-level diagram of CN, which of the following statements are correct?
i. The CN bond order is 2.
ii. CN is diamagnetic.
iii. The bond enthalpy in CN- ion is higher than CN.
iv. CN has longer bond length than CN-
answer choices:
a. ii, iv
b. iii, iv
c. i, iii
d. i, ii
e. i, iv
Answer:
Nitrogen molecule (N2)
The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.
The total number of electrons present in the nitrogen molecule (N2) is 14.
In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.
N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2
Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.
The bond order of N2can be calculated as follows:
Here, Nb = 10 and Na = 4
Bond order = (Nb−Na) /2
B.O = (10−4)/2
B.O = 3
So your answer should be C3.
Give two examples of each of the following:
1.) Physical systems designed by people.
2.) Naturally occurring physical systems.
3.) Social systems that you are a part of.
4.) Naturally occurring social system.
How many moles of O2 did you produce the 8.31 moles of H2O
the equation is not present.
THIS NOT MY WORK. its for my sister. HELP HER
Answer:
Your answer will be b(molten material from the outer core makes its way to the surface of earth)
Explanation:
Answer:
C
Explanation:
I'm pretty sure molten material comes from the inner core. I think you can search up this though, try to find where molten material comes from. Goodluck!
Congratulations you have worked hard and now you are done with the year! I am so proud of you!
Answer:
lololol
Explanation:
Calculate the mass of 100.0 mL of a substance whose density is 19.32 kg/L. Express your answer in kilograms using the correct number of significant figures. Do not enter your answer using scientific notation.
Answer:
1.932 kg
Explanation:
First we convert 100.0 mL to L:
100.0 mL / 1000 = 0.1000 LThen we calculate the mass of the substance, using the definition of density:
Density = mass / volumemass = density * volume19.32 kg/L * 0.1000 L = 1.932 kgAs the multiplication involves two numbers of 4 significant figures each, the answer needs to have 4 significants figures as well.
The table below shows some characteristics of three different types of muscles
Answer: Type A are cardiac muscles Type B are skeletal muscles, and Type C are smooth muscles.
Explanation: sub to technoblade :P
A chemist must dilute of aqueous silver perchlorate solution until the concentration falls to . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Round your answer to significant digits
The given question is incomplete, the complete question is:
A chemist must dilute 54.1 mL of 20.2 M aqueous silver perchlorate (AgC102) solution until the concentration falls to 3.00 M. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Round your answer to 3 significant digits.
Answer:
The correct answer is 0.364 L.
Explanation:
A solution is made less concentrated by diluting it with a solvent. There is no change in the number of moles when more solvent is added to the solution. In case, if the solution is diluted from V1 to V2, a change is noticed in the molarity of the solution based on the given equation,
M1V1 = M2V2
In the given case, the V1 or the volume of the original solution is 54.1 ml, M1 or the molarity of the original solution is 20.2 M.
The M2 or the molarity of the diluted solution is 3.00 M, there is a need to find the V2 or the volume of the diluted solution.
Now by putting the values in the equation we get,
= 20.2M * 54.1 ml = 3.0 M * V2
V2 = 364.27 ml
It is known that 1000 ml is equivalent to 1L, therefore, 1 ml = 0.001 L
Now, the value of V2 will be,
= 364.27 * 0.001 L = 0.36427 L or 0.364 L