what is the area of triangle EDF?

Answer:

Taking 45 degree as reference angle

Then using sine rule

sin 45=

p/h

replacing the value of sin 45 degree by 1/root 2.so

1/root 2=9/c

doing cross multiplication

9*root 2=1*c

9 root 2 =c

therefore the value of c is 9 root 2

Step-by-step explanation:

Answer:

C)

Step-by-step explanation:

Answer:

c≈5.2

Step-by-step explanation:

c=a2+b2=1.412+52≈5.19501

[tex]\huge\mathcal\pink{Answer}[/tex]

radius r = 10 m

volume V = 4188.7902 m3

surface area A = 1256.63706 m2

circumference C = 62.8318531 m

In Terms of Pi π

volume V = 1333.33333 π m3

surface area A = 400 π m2

circumference C = 20 π m

Answer:

There is a 1/3 chance it lands on each section

Step-by-step explanation:

Answer: Angles ∠4 and∠2 are not alternate interior angles and neither are ∠1 and ∠5

Step-by-step explanation: Khan Academy

Joe made the mistake by guessing Angles ∠4 and∠2 are not alternate interior angles and neither are ∠1 and ∠5.

The correct option is (b).

The fundamental characteristics listed below make it simple to recognise parallel lines.

Given:

WE have to  prove that the sum of a triangle's interior angle measures is 180°

According to the figure <1 and <4 are the alternate interior angle and <2 and <5 are  alternate interior angle.

So, Joe made the mistake by guessing Angles ∠4 and∠2  and ∠1 and ∠5 are alternate interior angles.

Learn more about parallel lines here:

https://brainly.com/question/16701300

#SPJ2

Answer:

1. D. Teorema.

2. A. Axioma.

Step-by-step explanation:

En matemáticas, un conjunto de proposiciones que deben estar respaldadas por una prueba adecuada basada en el razonamiento se denomina teorema. Se puede demostrar plenamente que todos los teoremas matemáticos son verdaderos mediante el razonamiento.

Sin embargo, un axión es evidente por sí mismo y no necesita ser probado. Es un hecho ya establecido.

Answer:

1. D. Teorema.

2. A. Axioma.

Step-by-step explanation:

Espero que esto ayude

Answer:

What?

Step-by-step explanation:

G8ve me more info and Ill answer again

Answer:

i its 3 or 4

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

==========================================================

Explanation:

Let's solve 6x = 3y + 5 for y

6x = 3y + 5

6x-5 = 3y

3y = 6x-5

y = (6x-5)/3

y = (6x)/3 - (5/3)

y = 2x - (5/3)

This final equation is in the form y = mx+b with m = 2 as the slope and b = -5/3 as the y intercept.

With the equation y = 2x, aka y = 2x+0, the m and b values are m = 2 and b = 0 respectively.

We see that both equations have the same slope (m = 2), but different y intercepts. Therefore, the two lines are parallel. If both y intercepts were the same as well, then we'd be talking about the same identical line.

If the slopes multiplied to -1, then the lines are perpendicular. In any other case, the two lines are neither parallel nor perpendicular.

Answer:

hope this helps

Step-by-step explanation:

31 divided by 2 = 15.5 then do 15.5 x 15.5= 240.25 then you do 240.25 x 3.14 = 754.385

Answer:

The polar bear weighs 525kg

Step-by-step explanation:

C = Polar Bear

D = Baby Elephant

____________________________

(1)  C + D = 700 kg

(2)  C = 3D

________________________________

C = 700 - D

700 - D = 3D

700 = 4D

________________________________

525 + 175 = 700

Then we get our answer, the polar bear weighs 525kg, and the baby elephant weighs 175kg.

Hope this helps you :)

9514 1404 393

Answer:

  (a)  Interest = Principal x Rate x Time

Step-by-step explanation:

The letters in the simple interest formula ...

  I = Prt

stand for ...

  Interest = Principal x Rate x Time

Answer:

I searched it up and took a screenshot

Step-by-step explanation:

Here they are:

Btw the 1st one is for 6x + 2y = 12 and the second one is for 5x + 2y = 8​.

Hope this helps! : )

Answer:

89^2π

Step-by-step explanation:

Using the formulas

A=4πR2

D=2r

Solving for A

A=πD2=π·89^2≈24884.55541

Answer:

[tex] \frac{4}{5} [/tex]

Step-by-step explanation:

[tex] ( \cos \theta) ^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \therefore \: { \bigg( \frac{{6} }{10} \bigg)}^{2} + ( \sin \theta) ^{2} = 1 \\ \\ \frac{36}{100} + ( \sin \theta) ^{2} = 1 \\ \\ ( \sin \theta) ^{2} = 1 - \frac{36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{100 - 36}{100} \\ \\ ( \sin \theta) ^{2} = \frac{64}{100} \\ \\ \sin \theta = \sqrt{\frac{64}{100} } \\ \\ \sin \theta = \frac{8}{10} \\ \\ \sin \theta = \frac{4}{5} [/tex]

Answer:

x=28

Step-by-step explanation:

4(x-5)=92

4x-20=92

add 20 to both sides

4x=112

divide 4 on both sides

x=28

Answer:

The value of x is 28

Step-by-step explanation:

4(x - 5) = 92

4x - 20 = 92

4x = 92 + 20

4x = 112

x = 112 ÷ 4

x = 28

Thus, The value of x is 28

-TheUnknownScientist

Answer: 5 is your answer hope this helped

plz make brainly

Step-by-step explanation:

Step-by-step explanation:

I hope you understand what I wrote

Answer:

91,858

Step-by-step explanation:

This is the right answer

Answer: the answer is B hope it helps

Step-by-step explanation:

16,468 plus 75,390 = 91858

Step-by-step explanation:

In a cylinder

We know that

[tex] \boxed { \sf \: volume = \pi {r}^{2} h} \\ \rm \rightharpoonup \: \frac{22}{7} \times {5}^{2} \times 12 \\ \rm \rightharpoonup \: \frac{22}{7} \times 25 \times 12 \\ \rm \rightharpoonup \: \frac{6600}{7} \\ \rm \rightharpoonup \: 942.8cm {}^{3} [/tex]

Answer:

approx. 943 cm^3

Step-by-step explanation:

π × 5^2 x 12 = approx. 943 cm^3

Answer:

1.870828693387

Step-by-step explanation:

Standard Deviation, σ: 1.870828693387

Count, N:4

Sum, Σx: 12

Mean, μ: 3

Variance, σ2:  3.5

Steps

σ2 = Σ(xi - μ)2

N  =   (6 - 3)2 + ... + (1 - 3)2

4 = 14

4  = 3.5

σ = √3.5

= 1.870828693387

Answer:

33

Step-by-step explanation:

Answer:

{x,y} = {-5,-2}

Step-by-step explanation:

Answer:

21.908

Step-by-step explanation:

Answer:

y=1/3x+2

Step-by-step explanation:

Answer:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1, \frac{\sqrt{3}}{2} - 1[/tex]

Step-by-step explanation:

we are given two coincident points

[tex] \displaystyle P( \sin(θ)+2, \tan(θ)-2) \: \text{and } \\ \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

since they are coincident points

[tex] \rm \displaystyle P( \sin(θ)+2, \tan(θ)-2) = \displaystyle Q(4 \sin ^{2} (θ)+4 \sin(θ )\cos(θ)+2a \cos(θ), 3 \sin(θ)-2 \cos(θ)+a)[/tex]

By order pair we obtain:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2a \cos(θ) = \sin( \theta) + 2 \\ \\ \displaystyle 3 \sin( \theta) - 2 \cos( \theta) + a = \tan( \theta) - 2\end{cases}[/tex]

now we end up with a simultaneous equation as we have two variables

to figure out the simultaneous equation we can consider using substitution method

to do so, make a the subject of the equation.therefore from the second equation we acquire:

[tex] \begin{cases} \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sinθ \cos(θ)+2a \cos(θ )= \sin( \theta) + 2 \\ \\ \boxed{\displaystyle a = \tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) } \end{cases}[/tex]

now substitute:

[tex] \rm\displaystyle \displaystyle 4 \sin ^{2} (θ)+4 \sin(θ) \cos(θ)+2 \cos(θ) \{\tan( \theta) - 2 - 3 \sin( \theta) + 2 \cos( \theta) \}= \sin( \theta) + 2 [/tex]

distribute:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ)+4 \sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) - 6 \sin( \theta) \cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

collect like terms:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + 4 \cos ^{2} ( \theta) = \sin( \theta) + 2 [/tex]

rearrange:

[tex]\rm\displaystyle \displaystyle 4 \sin ^{2}( θ) + 4 \cos ^{2} ( \theta) - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) + = \sin( \theta) + 2 [/tex]

by Pythagorean theorem we obtain:

[tex]\rm\displaystyle \displaystyle 4 - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) + 2 [/tex]

cancel 4 from both sides:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+2 \sin(θ ) - 4\cos( \theta) = \sin( \theta) - 2[/tex]

move right hand side expression to left hand side and change its sign:

[tex]\rm\displaystyle \displaystyle - 2\sin(θ) \cos(θ)+\sin(θ ) - 4\cos( \theta) + 2 = 0[/tex]

factor out sin:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) - 4\cos( \theta) + 2 = 0[/tex]

factor out 2:

[tex]\rm\displaystyle \displaystyle \sin (θ) (- 2 \cos(θ)+1) + 2(- 2\cos( \theta) + 1 ) = 0[/tex]

group:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(- 2 \cos(θ)+1) = 0[/tex]

factor out -1:

[tex]\rm\displaystyle \displaystyle - ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

divide both sides by -1:

[tex]\rm\displaystyle \displaystyle ( \sin (θ) + 2)(2 \cos(θ) - 1) = 0[/tex]

by Zero product property we acquire:

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) + 2 = 0 \\ \displaystyle2 \cos(θ) - 1= 0 \end{cases}[/tex]

cancel 2 from the first equation and add 1 to the second equation since -1≤sinθ≤1 the first equation is false for any value of theta

[tex] \begin{cases}\rm\displaystyle \displaystyle \sin (θ) \neq - 2 \\ \displaystyle2 \cos(θ) = 1\end{cases}[/tex]

divide both sides by 2:

[tex] \rm\displaystyle \displaystyle \displaystyle \cos(θ) = \frac{1}{2}[/tex]

by unit circle we get:

[tex] \rm\displaystyle \displaystyle \displaystyle θ= {60}^{ \circ} , {300}^{ \circ} [/tex]

so when θ is 60° a is:

[tex] \rm \displaystyle a = \tan( {60}^{ \circ} ) - 2 - 3 \sin( {60}^{ \circ} ) + 2 \cos( {60}^{ \circ} ) [/tex]

recall unit circle:

[tex] \rm \displaystyle a = \sqrt{3} - 2 - \frac{ 3\sqrt{3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = - \frac{ \sqrt{3} }{2} - 1[/tex]

when θ is 300°

[tex] \rm \displaystyle a = \tan( {300}^{ \circ} ) - 2 - 3 \sin( {300}^{ \circ} ) + 2 \cos( {300}^{ \circ} ) [/tex]

remember unit circle:

[tex] \rm \displaystyle a = - \sqrt{3} - 2 + \frac{3\sqrt{ 3} }{2} + 2 \cdot \frac{1}{2} [/tex]

simplify which yields:

[tex] \rm \displaystyle a = \frac{ \sqrt{3} }{2} - 1[/tex]

and we are done!

disclaimer: also refer the attachment I did it first before answering the question

Answer:

my school

Step-by-step explanation:

block me from sieng the image

Answer:

answer: Hi = 15

Step-by-step explanation:

the larger shape is the same as the smaller shape just flipped over and bigger of course so to find this out you have to take 2 simular angles and find out what multiplied by the small angle will get the big angle so I see angles gh and ba are simular I try 4.5 ÷ 1.5 = 3 so 3 is how much the shape is being multiplied by so bc is simular to hi so I do 5 x 3 = 15 and theres are answer 15 is the length of hi hope this helps you!