What is the area of a rectangle with a length of 5/8foot and a width of 4/9 foot?

Answer:

Your question is in what base please?

Answer:

g = 21/4


Decimal form:

g = 5.25


Mixed Number:

5 1/4

Answer:

B(-6,4)

Step-by-step explanation:

Basically, it's the same as reflecting it over the origin, so you transform the sign to its opposite and keep the points.

Answer:

x = 105 degrees

Step-by-step explanation:

First, figure out the interior angle, we can do this ading the two angles and then subtracting the sum from 180 (since the interior angle of a triangle adds up to 180 degrees)

180 - (55 + 50) = 75

next, we can figure out x by taking the sum (75) and subtracting that from 180 since it is a supplementary angle:

180 - 75 = 105

x = 105

Answer:

105 degrees!

Step-by-step explanation:

all the angles in a triangle must add to 180.

50+55= 105

therefore, the missing angle would be 75

x+75 must also add to 180 so the answer would be: 105 because 75+105= 180

Hope this helps!!

Answer:

(3,8)

Step-by-step explanation:

THIS IS AN EXAMPLE FOR ANY PROBLEM!!

Get the equation in the form y = ax2 + bx + c.

Calculate -b / 2a. This is the x-coordinate of the vertex.

To find the y-coordinate of the vertex, simply plug the value of -b / 2a into the equation for x and solve for y. This is the y-coordinate of the vertex.

- Good luck!

Answer:

$81.95

Step-by-step explanation:

0.07 * 55 = 3.85

(3.85 * 7) + 55

26.95 + 55

81.95

Ok so I’m going to try my best:
I’m guessing you would do $960 times 6.1 but you move the decimal point twice to the left which would be: .061
This is how we find out each month
58.56
So, we start out with $960 we keep adding 58.56 or to do faster we can multiply
Adding 58.56:
1 = 1018.56
2 = 1077.12

Multiplying 58.56 by 13:
KEEP IN MIND THAT WE START FROM $960 and we need TO GET TO $1,720
58.56 times 13 equals 761.28
Then we add
960 + 761.28
1721.28

So it would have to be 12 months since it needs to be less or “to the nearest year”
Therefore, the answer would be a year

I hope this helps! :) good luck

It’s 12 months I think I’m sorry if it’s wrong.

Answer:

[tex]\displaystyle f'(1) = \frac{3}{2}[/tex]

[tex]\displaystyle f''(1) = \frac{3}{4}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right

Algebra II

Exponential Rule [Rewrite]:                                                                            [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Exponential Rule [Root Rewrite]:                                                                   [tex]\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}[/tex]

Calculus

Derivatives

Derivative Notation

Basic Power Rule:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Quotient Rule]:                                                                           [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Step-by-step explanation:

Step 1: Define

f(x) = x√x

f'(1) is x = 1 for 1st derivative

f''(1) is x = 1 for 2nd derivative

Step 2: Differentiate

[1st Derivative] Product Rule:                                                                       [tex]\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[\sqrt{x}][/tex][1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         [tex]\displaystyle f'(x) = \frac{d}{dx}[x]\sqrt{x} + x\frac{d}{dx}[x^{\frac{1}{2}}][/tex][1st Derivative] Basic Power Rule:                                                                 [tex]\displaystyle f'(x) = (1 \cdot x^{1 - 1})\sqrt{x} + x(\frac{1}{2}x^{\frac{1}{2}-1})[/tex][1st Derivative] Simply Exponents:                                                               [tex]\displaystyle f'(x) = (1 \cdot x^0)\sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})[/tex][1st Derivative] Simplify:                                                                                 [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2}x^{\frac{-1}{2}})[/tex][1st Derivative] Rewrite [Exponential Rule - Rewrite]:                                 [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2x^{\frac{1}{2}}})[/tex][1st Derivative] Rewrite [Exponential Rule - Root Rewrite]:                         [tex]\displaystyle f'(x) = \sqrt{x} + x(\frac{1}{2\sqrt{x}})[/tex][1st Derivative] Multiply:                                                                                 [tex]\displaystyle f'(x) = \sqrt{x} + \frac{x}{2\sqrt{x}}[/tex][2nd Derivative] Rewrite [Exponential Rule - Root Rewrite]:                     [tex]\displaystyle f'(x) = x^{\frac{1}{2}} + \frac{x}{2x^{\frac{1}{2}}}[/tex][2nd Derivative] Basic Power Rule/Quotient Rule [Derivative Property]: [tex]\displaystyle f''(x) = \frac{1}{2}x^{\frac{1}{2} - 1} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{(2x^{\frac{1}{2}})^2}[/tex][2nd Derivative] Simplify/Evaluate Exponents:                                           [tex]\displaystyle f''(x) = \frac{1}{2}x^{\frac{-1}{2}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{\frac{d}{dx}[x](2x^{\frac{1}{2}}) - x\frac{d}{dx}[2x^{\frac{1}{2}}]}{4x}[/tex][2nd Derivative] Basic Power Rule:                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^{1 - 1})(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{1}{2} - 1})}{4x}[/tex][2nd Derivative] Simply Exponents:                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{(1 \cdot x^0)(2x^{\frac{1}{2}}) - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Simplify:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{2} \cdot 2x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(x^{\frac{-1}{2}})}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule - Rewrite]:                               [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - x(\frac{1}{x^{\frac{1}{2}}})}{4x}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{2x^{\frac{1}{2}} - \frac{x}{x^{\frac{1}{2}}}}{4x}[/tex][2nd Derivative] Simplify:                                                                             [tex]\displaystyle f''(x) = \frac{1}{2x^{\frac{1}{2}}} + \frac{x^{\frac{1}{2}}}{4x}[/tex][2nd Derivative] Rewrite [Exponential Rule  - Root Rewrite]:                     [tex]\displaystyle f''(x) = \frac{1}{2\sqrt{x}} + \frac{\sqrt{x}}{4x}[/tex]

Step 3: Evaluate

[1st Derivative] Substitute in x:                                                                     [tex]\displaystyle f'(1) = \sqrt{1} + \frac{1}{2\sqrt{1}}[/tex][1st Derivative] Evaluate Roots:                                                                     [tex]\displaystyle f'(1) = 1 + \frac{1}{2(1)}[/tex][1st Derivative] Multiply:                                                                                 [tex]\displaystyle f'(1) = 1 + \frac{1}{2}[/tex][1st Derivative] Add:                                                                                       [tex]\displaystyle f'(1) = \frac{3}{2}[/tex][2nd Derivative] Substitute in x:                                                                   [tex]\displaystyle f''(1) = \frac{1}{2\sqrt{1}} + \frac{\sqrt{1}}{4(1)}[/tex][2nd Derivative] Evaluate Roots:                                                                 [tex]\displaystyle f''(1) = \frac{1}{2(1)} + \frac{1}{4(1)}[/tex][2nd Derivative] Multiply:                                                                             [tex]\displaystyle f''(1) = \frac{1}{2} + \frac{1}{4}[/tex][2nd Derivative] Add:                                                                                     [tex]\displaystyle f''(1) = \frac{3}{4}[/tex]

Answer:

C

Step-by-step explanation:

7 - 2 = 5

11 - 3(2)

11 - 6 = 5

4(2) - 3

8 - 3 = 5

C is the only one that doesn't equal 5

Step-by-step explanation:

The power can come to the front according to logarithm rule.

Answer:

w+w+w+w=p

w x4=p

Answer:

6:8 and 8:14

Step-by-step explanation:

Add them both up and divided by 2, 52+45=97. 97/2 =48.5

Step-by-step explanation:

I’m sorry I didn’t know that you were going to be in there until about it later this week and then he came back and forth

Answer:

Is there any answer choices? If not I would think its 5$

                                                                                      5$

                                                                                      4$

Step-by-step explanation:

Answer:

3.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Does Daniela Works every day?

Do Daniela Work every day?

Does Daniela Work every day?

Did Daniela Work every day?

4.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Margarita don't brushes her car

Margarita doesn't brush her car

Margarita doesn't brushes her car

Margarita didn´t brush her car

5.LOOK AND  CHOOSE THE CORRECT SENTENCES

(1 Punto)

Do Camilo and Diana dances in the class?

Do Camilo and Diana dance in the class

Does Camilo and Diana dance in the class?

Do Camilo and Diana dance in the class?

6.LOOK AND CHOOSE THE CORRECT SENTENCES

(1 Punto)

You don't read a book

You don't reads a book

You doesn't read a book

7.LOOK AND CHOOSE THE CORRECT SENTENCES  

INTERROGATIVE  

____ he ___ better than you?

(1 Punto)

Does- plays

Does- play

Do- play

Do . plays

8.LOOK AND CHOOSE THE CORRECT SENTENCES  

NEGATIVE

It  ___ snow in summer.

(1 Punto)

doesn't

don't

9.LOOK AND CHOOSE THE CORRECT SENTENCES  

AFFIRMATIVE  

My cousin _____ English very well.

(1 Punto)

Speak

Speaking

Speaks

10.LOOK AND CHOOSE THE CORRECT SENTENCES  

AFFIRMATIVE  

We _____  our bikes

(1 Punto)

Wash

Washes

Washing

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Step-by-step explanation:

Answer:1. Use substitution to solve the system of equations:

   -x + 2y=7

    x - 3y = 3

2. Solve the system of equations by the elimination method

a.  2x+ y = -17

   x - y = 2

b. 3x + y = -15

  x + 2y = -10

Answer:

(0, 1)

Step-by-step explanation:

You can solve this by using the substitution or elimination method. For this problem, I'm going to use the substitution method. First, rewrite -4x-2y=-2 in slope-intercept form, which would be y=-2x+1. Substitute the y value in -9x+3y=3 (which would be -9x+3(-2x+1)=3) and solve.

-9x+3(-2x+1)=3

-9x-6x+3=3

-15x=0

x=0

Now, substitute the x value in for the x in any equation. You can do -4(0)-2y=-2 or -9(0)+3y=3. I'm going to use -9(0)+3y=3.

-9(0)+3y=3

3y=3

y=1

Answer:

10.67 or 10.7

Step-by-step explanation:

32/3= 10.67 or 10.7

Answer:

10.6666666667 converted into a fraction (sorry if im wrong)

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\text{Given that:}[/tex]

[tex]y = 1+ sec(x) \ \ y =3[/tex]

[tex]\text{we draw the graph and the curves intersect at:}[/tex]

[tex]x = - \dfrac{\pi}{3} \ and \ x = \dfrac{\pi}{3}[/tex]

[tex]\text{Applying washer method;}[/tex]

[tex]f(x) _{outer} - g(x) _{inner} --- (1)[/tex]

[tex]V= \int ^b_a A(x) \ dx --- (2)[/tex]

[tex]\text{outer radius = 3 - 1 = 2}[/tex]

[tex]\text{inner radius =}[/tex] [tex]( 1 + sec(x) ) - 1 = sec (x)[/tex]

[tex]A(x) = \pi ((2)^2 -(sec(x)^2) \\ \\ A(x) = \pi (4 - sec^2 (x)) ---- (3)[/tex]

[tex]\text{The volume V =}\int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ A(x) \ dx[/tex]

[tex]V = \int ^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ \pi (4- sec^2 (x) ) \ dx[/tex]

[tex]V = 2 \pi \int ^{\dfrac{\pi}{3}}_{0}( 4 - sec^2 (x)) \ dx[/tex]

[tex]V = 2 \pi \int ^{\pi/3}_{0} 4 . \ dx - 2 \pi \int ^{\pi/3}_{0} sec^2 (x) \ dx[/tex]

[tex]V = 2 \pi(4) \int ^{\pi/3}_{0} 1 . \ dx - 2 \pi \Big( tan (x)\Big )^{\dfrac{\pi}{3}}_{0}[/tex]

[tex]V = 8 \pi(x)^{\dfrac{\pi}{3}}_{0} - 2 \pi \Big( tan \dfrac{\pi}{3} -tan (0)\Big )[/tex]

[tex]V = 8 \pi({\dfrac{\pi}{3}}-{0}) - 2 \pi \Big( tan \sqrt{3}-(0)\Big )[/tex]

[tex]V = 8 \pi({\dfrac{\pi}{3}}) - 2 \pi \Big( \sqrt{3}\Big )[/tex]

[tex]\mathbf{V = 2 \pi \Big(\dfrac{4\pi}{3}- \sqrt{3} \Big)}[/tex]

480,, I think this is the correct answer.

Answer: 7 degrees of freedom.

Step-by-step explanation:

Answer: B

We all know that area= LxW
The width that is being shown is 8ft. The length is 20ft. Therefore, you multiply 8 x 20 which gives you 160ft squared. Hope this this helps :)

Answer:

D.324

Step-by-step explanation:

Answer:

D. 324 Sq in

Step-by-step explanation:

Painted area = area of rectangle + Area of square + Area of triangle

[tex] = 60 \times 4 + {8}^{2} + \frac{1}{2} \times 8 \times 5 \\ \\ = 240 + 64 + 20 \\ \\ = 324 \: {in}^{2} [/tex]

Use math-way to solve and check, it gives you all the answers, with a small explanation.

Answer:

y=35

Step-by-step explanation:

3(2y - 5) = 5(y + 4)

6y - 15 = 5y +20

6y - 5y = 20 + 15

y = 35

Answer:

416,000

Step-by-step explanation:

per hour 9*100=900

per week 900*40=36,000

per year 36,000*52=1,872,000

with raise

11*100=1,100

1,100*40=44,000

44,000*52=2,288,000

difference equals

416,000

Answer:

-6

Step-by-step explanation:

2 x -3 = -6

1 positive and a negative integer multiplied will get a negative answer

The answer is -6 ! Good luck!

Answer:

There is no diagram. If you repost the question, I may be able to help you

Step-by-step explanation:

Answer:

No diagram

Step-by-step explanation:

Answer:

Quadratic and Trinomial

Step-by-step explanation:

It has a degree of 2, making it a quadratic. It has 3 terms, so it's a trinomial.

Answer:

The United States of America mostly and maybe Canada

Answer:

The Answer should be Quadrant III

Step-by-step explanation:

Hope this helped!