Answer:
51.9 miles
Step-by-step explanation:
distance = speed * time
d = 59.3 * 7/8
d = 51.8875 miles
rounded
51.9 miles
Can someone please help me I will mark u brilliant
Answer:
the whole number 5 goes to the left of the decimal
Step-by-step explanation:
so think about it this way...
I have 10 dots .......... that is 1.0 but if I only have 5 of the 10 I have 0.5. if you have anymore questions just ask and ill help
Dylan had 300 5p coins in a box last month. He now has 360 5p coins. Find the percentage increase.
Therefore the percentage increase is 72
72Can you help please?
Answer:
Step-by-step explanation:
Use the table below to answer the following question,
2:
хо 1 2 3 4 5 6
y 100 200 400 800 1,600 3,200 6,400
Which equation BEST fits the data given in the table?
se 3:
Of(x) = { (200)*
Of(x) = 100(2)*
uge 4
f(x) = 200)
age 5
Of(x) = 200(2)*
5
Previous Page
Next Page
Page 2 of 11
Answer Of(x) = 200(2)
Step-by-step explanation:
Of(x) = 200(2)
Write money amounts using a leading zero if necessary & with 2 decimal places (For example: 0.80 or 0.72 or 1.23)
630 miles in 10 hours
miles per hour
donut hole per kid
24 donut holes for 8 kids
$
$3.50 for 5 lbs. of apples
$32 for a 14 2/9 km taxi ride.
per pound
per km
$
9514 1404 393
Answer:
63 mph3 donut holes per kid$0.70 per pound$2.25 per kmStep-by-step explanation:
In this context, "per" and "for" mean "divided by."
630 mi/(10 h) = 63 mi/h(24 dh)/(8 kid) = 3 dh/kid$3.50/(5 lb) = $0.70 /lb$32/(14 2/9 km) = $32/(128/9 km) = $(9/4)/km = $2.25 /kmIf
x
=
4
and
y
=
7
, evaluate the following expression:
2
(
4
x
+
3
y
)
Answer:
expression.
2(4x+3y)
2(4(4)+3(7))
2(16+21)
2( 37)
74
plz help i only need this question who ever get its right will get 77 point
Answer:
Ok, so I think it's x= 2.5 and y= 306.1 plz forgive me if I'm wrong.
2. Suppose that you are looking for a student at your college who lives within five miles of you. You know that 55% of the 25,000 students do live within five miles of you. You randomly contact students from the college until one says he or she lives within five miles of you.
(a) What is the probability that you need to contact four people?
(b) How many students from the college you expect to contact until you find one lives within five miles of you?
(C) What is the standard deviation of the number of students to be contacted until one says who lives within five miles of you?
(d) Suppose you randomly ask 5 students at your college, what is the probability that 3 of them live within five miles of you?
(e) Suppose you randomly ask 5 students at your college, what is the expected number of students who live within five miles of you?
Using the binomial distribution, it is found that:
a) There is a 0.0501 = 5.01% probability that you need to contact four people.
b) You expect to contact 1.82 students until you find one who lives within five miles of you.
c) The standard deviation is of 1.22 students.
d) 0.3369 = 33.69% probability that 3 of them live within five miles of you.
e) It is expected that 2.75 students live within five miles of you.
For each student, there are only two possible outcomes. Either they live within 5 miles of you, or they do not. The probability of a student living within 5 miles of you is independent of any other student, which means that the binomial distribution is used to solve this question.
Binomial probability distribution
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes. n is the number of trials. p is the probability of a success on a single trial.In this problem:
55% live within five miles, hence [tex]p = 0.55[/tex].Item a:
This probability is P(X = 0) when n = 3(none of the first three) multiplied by 0.55(the fourth does live within five miles), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{3,0}.(0.55)^{0}.(0.45)^{3} = 0.091125[/tex]
[tex]p = 0.091125(0.55) = 0.0501[/tex]
0.0501 = 5.01% probability that you need to contact four people.
Item b:
The expected number of trials in the binomial distribution until q successes is given by:
[tex]E = \frac{q}{p}[/tex]
In this problem, [tex]p = 0.55[/tex], and 1 trial, thus [tex]q = 1[/tex], hence:
[tex]E = \frac{1}{0.55} = 1.82[/tex]
You expect to contact 1.82 students until you find one who lives within five miles of you.
Item c:
The standard deviation of the number of trials until q successes are found is given by:
[tex]S = \frac{\sqrt{q(1 - p)}}{p}[/tex]
Hence:
[tex]S = \frac{\sqrt{0.45}}{0.55} = 1.22[/tex]
The standard deviation is of 1.22 students.
Item d:
This probability is P(X = 3) when n = 5, hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 3) = C_{5,3}.(0.55)^{3}.(0.45)^{2} = 0.3369[/tex]
0.3369 = 33.69% probability that 3 of them live within five miles of you.
Item e:
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
Hence:
[tex]E(X) = 5(0.55) = 2,75[/tex]
It is expected that 2.75 students live within five miles of you.
A similar problem is given at https://brainly.com/question/25343741
Convert
161 oz = ____ lb ______oz
Answer:
161oz = 10.0625 (then you round)
Step-by-step explanation:
Solve for k:
k + 6 > -37
Answer:
[tex]\sf k + 6 > -37[/tex]
[tex]\sf k+6-6>-37-6[/tex]
[tex]\boxed{\sf k>-43}[/tex]
Answer:
Subtract 6 from both sides:
K +6 - 6 > - 37 - 6
Simplify the arithmetic:
k > - 37 - 6
Simplify the arithmetic
k > - 43
Today only, a sofa is being sold at a 32% discount. The sale price is $289.
What was the price yesterday?
Answer:
425$Step-by-step explanation:
Today only, a sofa is being sold at a 32% discount. The sale price is $289.
What was the price yesterday?
289 is 68% (100% - 32% = 68%)
289 : 68 * 100 =
425
--------------------------
check
425 - 32% = 289
the answer is good
Simplify.
81‾‾‾√
18
9
−3
−18
9514 1404 393
Answer:
(b) 9
Step-by-step explanation:
Maybe you want to simplify ...
[tex]\sqrt{81}=\sqrt{9^2} =\boxed{9}[/tex]
Solve for L:
P=2L+2W
Answer:
[tex]L=\frac{1}{2}P-W[/tex]
Step-by-step explanation:
Let's solve for L.
[tex]P=2L+2W[/tex]
Step 1: Flip the equation.
[tex]2L+2W=P[/tex]
Step 2: Add [tex]-2W[/tex] to both sides.
[tex]2L+2W+-2W=P+-2W[/tex]
[tex]2L=P-2W[/tex]
Step 3: Divide both sides by [tex]2[/tex].
[tex]\frac{2L}{2}=\frac{P-2W}{2}[/tex]
[tex]L=\frac{1}{2}P-W[/tex]
Answer:
[tex]L=\frac{1}{2}P-W[/tex]
evaluate the expression 5+3
some one answer me with a question not a link
Answer:
8
Step-by-step explanation:
Add 5 and 3
-Lexi
Please help I need this done ASAP
Answer: No solution
The two lines don’t meet at any point(s). So, there are no solutions.
:)
Solve the equation.
2x - 3 + 4x = 21
A)x = -12
B)x= -6
C)x= 4
D)x = 6
Answer:
C. X=4
Step-by-step explanation:
Find the median of the list of data.
12, 18, 21, 25, 30, 43
Answer:
23
Step-by-step explanation:
the median is the "Middle" number of the set.21 and 25 are the middle numbers of the set. so now find the middle of 21 and 25.
21 22 23 24 25
23 is the median of the data set
Which of the following Statements are true?
Statement 1: A STOP sign is a regular
octagon.
Statement 2: An equilateral triangle has
three angles.
Answer:
C. Both statements are true
problem referred below
Answer:
Step-by-step explanation:
(f/g)(-4) = (-4² - 13) / (4 - (-4)) = 3/8
A submersible is a type of underwater vessel. Suppose a submersible starts at a depth of 40 feet below sea level, represented by –40 feet. The table shows the submersible's change in depth from one minute to the next.
Answer the questions to find the depth of the submersible after 3 minutes.
1. Write and evaluate a subtraction expression to find the depth of the submersible at 2:16 p.m. (2 points)
2. Write and evaluate a subtraction expression to find the depth of the submersible at 2:17 p.m. (2 points)
3. Write and evaluate a subtraction expression to find the depth of the submersible at 2:18 p.m. (3 points)
4. If the submersible dove straight down, what is the distance between the submersible's starting position at 2:15 and its position at 2:18? Show your work. (3 points)
1. -40 - 180 = -220
2. -40 - 175 = -135
3. -40 - 185 = -225
4. 2:15 = -40
2:18 = 185
distance b/w them is = -40 - 185 = - 225
hope this answer helps you dear! btw I'm not sure but hope so this helps...!!
I agree with the first person that answered.
What is the equation of the line that has a slope of 3 and goes through the point (-3,5)?
A. Y=3x +4
B. Y= 3x - 14
C. Y= 3x - 4
D. Y= 3x + 12
Answer:
C. y=3x-4
Step-by-step explanation:
I just know trust me
Tp 3 Work Backwards
1. Bowser, Abby, and Chuckles are 3 dogs with a
combined age of 44. Bowser is 6 years older than
Abby. Abby is 2 years younger than Chuckles, c.
Which expression could be used to find the age of
Chuckles?
Answer:
Your equation option is possibly in here somewhere.
Step-by-step explanation:
A = C - 2
B = A + 6 → A = B - 6
C - 2 = A = B - 6 → B = C + 4
44 = C + B + A
44 = C + (C + 4) + (C - 2)
44 = 3C + 2
42 = 3C
C = 7
Derivative this Problem.
[tex]\\ \sf\longmapsto {\displaystyle{\lim_{x\to 1}}}\dfrac{x^2-1}{x-1}[/tex]
[tex]\\ \sf\longmapsto {\displaystyle{\lim_{x\to 1}}}\dfrac{x^2-1^2}{x-1}[/tex]
[tex]\\ \sf\longmapsto 2(1)^(2-1)[/tex]
[tex]\\ \sf\longmapsto 2(1)[/tex]
[tex]\\ \sf\longmapsto 1[/tex]
Step-by-step explanation:
[tex] \tt \lim \limits_{x \to1} \frac{ {x}^{2} - 1 }{x - 1} = ...[/tex]
[tex] = \tt \lim \limits_{x \to1} \frac{(x + 1) \cancel{(x - 1)}}{ \cancel{(x - 1)}} [/tex]
[tex] = \tt \lim \limits_{x \to1}(x + 1)[/tex]
[tex] = \tt1 + 1[/tex]
[tex] = \boxed{ \bold{ \blue{ \underline2}}}[/tex]
Mr. quick bought new computer system. The regular price was 1,580 , but he got a 15% discount. How much did he actually pay?
Answer:
$1343
Step-by-step explanation:
The equation would be
x= 1580 (1-0.15)
x represents how much he actually pays.
1-0.15=0.85.
1580×0.85=1343
If an object's position over time is given by the function d(t)=(t^2 +3)e^-1/2 for greater than 0 , on what interval is the object's position increasing and concave down ?
Answer:
Step-by-step explanation:
[tex]d(t)=(t^2+3)e^\frac{-1}{2} \\d'(t)=2t e^{-\frac{1}{2} }\\it~ is~ increasing ~if~d'(t)>0\\e^{-\frac{1}{2} } =\frac{1}{e^\frac{1}{2} } >0\\so~t>0\\and~decreasing~if~t<0\\[/tex]
so it is concave upward at t=0
Rachel invests $25,000 at age 25. She hopes the investment will be worth $125,000 when she turns 50. If the interest compounds continuously, approximately what rate of growth will she need to achieve her goal? Round to the nearest tenth of a percent.
The rate of growth will she need to achieve her goal is 2.8%
The formula for finding the compound amount is expressed as:
[tex]A =P(1+\frac{r}{n} )^{nt}[/tex]
P is the amount invested = $25000
t is the time in years = 25 years
A is the amount = $125000
r is the rate in %
Substitute the given parameters into the formula to have:
[tex]125000 =25000(1+r )^{25}\\5 =(1+r)^{25}\\log5=25log(1+r)\\log(1+r)=\frac{log5}{25} \\log(1+r)=0.02796\\1+r = e^{0.02795}\\1+r=1.0283\\r = 1.0283 -1\\r = 0.0283\\[/tex]
Hence the rate of growth will she need to achieve her goal is 2.8%
Learn more about compound amount here: https://brainly.com/question/18442810
What is the interior degree measure of angle A?
Answer:
in the pictureStep-by-step explanation:
opposite corners first, then adjacent corners, and so on
Today only, a table is being sold at a 33% discount. The sale price is 201.
What was the price yesterday?
Due Tomorrow: Answer question 21 with steps
[tex]\\ \sf\longmapsto tan28=\dfrac{BC}{AC}[/tex]
[tex]\\ \sf\longmapsto 0.5317=\dfrac{BC}{29.3}[/tex]
[tex]\\ \sf\longmapsto BC=29.3(0.5317)[/tex]
[tex]\\ \sf\longmapsto BC=15.5mi[/tex]
Now
[tex]\\ \sf\longmapsto AB^2=29.3^2+15.5^2[/tex]
[tex]\\ \sf\longmapsto AB^2=848.49+240.25[/tex]
[tex]\\ \sf\longmapsto AB^2=1088.74[/tex]
[tex]\\ \sf\longmapsto AB=32.9mi[/tex]
Describe the slope of the line. Then find the slope. What’s the slope?
Hello there!
We are given two points.
We use the following formula:
[tex]\frac{y2-y1}{x2-x1}[/tex]
[tex]\frac{4-7}{0-(-1)}[/tex]
[tex]\frac{4-7}{0+1} \\\frac{-3}{1} \\-3[/tex]
So the slope is -3. Hope it helps!
~Just a cheerful teen
#CarryOnLearning
[tex]SilentNature[/tex]
Answer:
[tex]\boxed{\boxed{\sf Slope: -3}}[/tex]
Step-by-step explanation:
To find the slope of a line given the coordinates of two points on the line, use the slope formula.
[tex]\boxed{\sf {Slope}=\cfrac{y_2-y_1}{x_2-x_1}}[/tex]
x1 and y1 are the coordinates of the first point. The second point's coordinates are x2, y2.
[tex]\sf Points: \left(-1,\:7\right)\: and\: \left(0,\:4\right)[/tex]
[tex]\boxed{\sf \left(x_1,\:y_1\right):\left(-1,\:7\right)}[/tex]
[tex]\boxed{\sf \:\left(x_2,\:y_2\right):\left(0,\:4\right)}[/tex]
[tex]\longmapsto\sf slope\:(m)=\cfrac{4-7}{0-\left(-1\right)}[/tex]
[tex]\longmapsto\sf slope\:(m)=-3[/tex]
_________________________________