%
Only 30% of the donuts are left in the box after the party. I counted the
donuts and there are 18 donuts left. How many donuts were in the box to
start with?
donuts

Answers

Answer 1

Answer:

It's be 60 because 30% of 60 is 18. Hope that helped :)


Related Questions

Rewrite the quadratic function f(2) = 5x2 + 10x – 8 in standard form, f(x) = a (x – h)? + k, and give the vertex.

Answers

Answer: [tex]f(x) = 5(x+1)^{2} - 13[/tex]

Vertex = (-1, -13)

Step-by-step explanation:

[tex]f(x) = 5x^{2} + 10x - 8\\f(x) = 5(x^{2}+2x)-8\\f(x) = 5(x^{2}+2x+1-1)-8\\f(x) = 5((x+1)^{2}-1)-8\\f(x) = 5(x+1)^{2}-5-8\\f(x) = 5(x+1)^{2}-13[/tex]

Vertex = (h, k) = (-1, -13)

y-5=2(x-3) slope intercept.​

Answers

Answer:

y=2x-1

Step-by-step explanation:

Because this equation is in point-slope form and we need it in slope-intercept form, all we need to do is simplify y-5=2(x-3).

y-5=2x-6     Distribute.

 +5     +5     Add 5 to both sides of the equation.

y=2x-1

Hope this helped! Have a great day ♥

(d) Given that the fifth and the seventh terms of the G.P form the first two consecutive terms of an arithmetic sequence, calculate the sum of the first 20 terms of the sequence ​

Answers

Step-by-step explanation:

the answer is shown in the photo

Translate the sentence into an inequality.

Six times the sum of a number and 20 is greater than 16.

Use the variable c for the unknown number.

Answers

Answer:

6 (20 + c) > 16

Step-by-step explanation:

the sum of the number and 20 is 20 + c. so you multiply that equation by 6 giving you 6 (20 + c)

The approximate average distances from the sun to Mars and Mercury are listed
below:
Mars: 2.28 x 108 kilometers
Mercury: 5.79 x 107 kilometers
How many times farther from the sun is Mars? Write your answer in standard
notation, rounding to the nearest tenth.

Answers

Answer:

  3.9

Step-by-step explanation:

Your calculator will tell you ...

  (2.28×10^8)/(5.79×10^7) ≈ 3.9

Mars is about 3.9 times as far from the sun as Mercury.

Round 523,009.974 to the nearest tenth

Answers

Answer:

Step-by-step explanation:

523,010.0

In trapezoid DEFG, EG = 24.3 and DH = 9.4. Identify HF.

Answers

Answer:

HF = 14.9

Step-by-step explanation:

Heheh... uhm, yeah, I don't do best with algebraic questions-

Answers

Answer:it's a for sure I think

25. Solve for x:
4x-3/2=5/3

Answers

Answer:

X = 19/24

Step-by-step explanation:

Move the constant: 4x = 5/3 + 3/2

Add The Fractions: 5/3 + 3/2 = 19/6

Divide Both sides by 4: 4x/4 = 0. 19/6 ÷ 4 = 19/24

It is estimated that world reserves of oil currently stand at 2625
billion units. Oil is currently extracted at an annual rate of 45.5
billion units and this is set to increase by 2.6% a year. After how
many years will oil reserves run out

Answers

Answer:

  35.4 years

Step-by-step explanation:

The annual consumption (in billions of units) is described by the exponential function ...

  f(t) = 45.5·1.026^t

The accumulated consumption is described by the integral ...

  [tex]\displaystyle\int_0^t{f(x)}\,dx=45.5\int_0^t{1.026^x}\,dx=45.5\left(\dfrac{1.026^t-1}{\ln{1.026}}\right)[/tex]

We want to find t such that the value of this integral is 2625, the estimated oil reserves.

  2625 = 45.5/ln(1.026)·(1.026^t -1)

  2625·ln(1.026)/45.5 +1 = 1.026^t ≈ 1.480832 +1 = 1.026^t

Taking natural logs, we have ...

  ln(2.480832) = t·ln(1.026)

  t ≈ ln(2.480832)/ln(1.026) ≈ 35.398

After about 35.4 years, the oil reserves will run out.

Which of the following is equivalent to [picture]

A) a0 + a1 + a2 + a3 + a4 + a5

B) a1 + a2 + a3 + a4 + a5

C) a0 + a1 + a2 + . . .

D) a1 + a2 + a3 + . . . + a∞

Answers

Answer:

A) a0 + a1 + a2 + a3 + a4 + a5

Step-by-step explanation:

Answer:

A) a0 + a1 + a2 + a3 + a4 + a5

Step-by-step explanation:

What is the answer to this question?

Answers

Answer:

linear = 3x+y = 12, y = x/2 -3, y=x

nonlinear y = 6/x -2, y=3x³+5

solve systems of equations 6x+2y=1 y=-3x+3 using substition??? Need answers quickly!!!!!

Answers

This might be incorrect but I tried my best. My answer is 0.416 but the 6 is repeating

The area
of this figure
is square inches.
20 in
28 in
30 in.
7 in
25 in.

Answers

Answer:

946 square Inches

Step-by-step explanation:

First, you should split up the shape into parts.

1st part 28x7

2nd part 30x25

We are multplying simply because

Area = Length x Width

Now that we have split up the parts lets multply them and add them togeher.

28 x 7 =  196

30 x 25 = 750

196 +750 = 946

So the area of this figure is 946 square inches.

Figure B is a scale image of Figure A, as shown.
7
2.5
Figure A
Figure B
Enter the scale factor applied to Figure A to produce Figure B.
Enter your answer as a fraction, like this: 42/53

Answers

Answer:    14/5

Explanation:

Divide the side length for B over the corresponding side length for A.

scale factor = B/A = 7/(2.5) = 2.8

Let's now convert this to a fraction

2.8 = 2 + 0.8 = 2 + 8/10 = 20/10 + 8/10 = (20+8)/10 = 28/10

Then reduce that fraction

28/10 = (14*2)/(5*2) = 14/5

Note that 14/5 = 2.8

How does the value of 2 dimes compare to the value of 2 dollars

Answers

Answer:

The 2 dollars has $1.80 more than the two dimes.

Step-by-step explanation:

2.00-0.20=1.80

How do we graph ​y+6=45(x+3)?

Answers

Answer:

.....,....................

It takes cadence 36 hours to read 12 books. Write a unit rate that models the situation.

Answers

Answer:

three hours every 1 book

Step-by-step explanation:

36-12

6-2

3-1

A rock is 7 feet below the surface of a river. If its position can be recorded as −7 feet, what would the position of 0 represent? (5 points)

Question 3 options:

1)

On the surface of the river


2)

At the bottom of the river


3)

7 feet above the surface of the river


4)

7 feet below the surface of the river

Answers

Answer:

A on the surface of the river

Step-by-step explanation:

100 persent correct

2x+7y+7x=18
Find the value of Y​

Answers

Answer:

y=−9/7x+18/7

Step-by-step explanation:

2x+7y+7x=18

9x+7y=18

Step 1: Add -9x to both sides.

9x+7y+−9x=18+−9x

7y=−9x+18

Step 2: Divide both sides by 7.

7y/7=−9x+18/7

y=−9/7x+18/7

Given :

2x + 7y + 7x = 18

To Find :

The value of y

Solution :

[tex]\qquad { \dashrightarrow \: { \sf{2x + 7y + 7x = 18}}}[/tex]

Adding the like terms :

[tex]\qquad { \dashrightarrow \: { \sf{ 7y + 9x = 18}}}[/tex]

Transposing 9y to the other side which then becomes negative :

[tex]\qquad { \dashrightarrow \: { \sf{ 7y = 18 - 9x}}}[/tex]

Dividing both sides by 7 :

[tex]\qquad { \dashrightarrow \: { \sf{ \dfrac{7y}{7} = \dfrac{18 - 9x}{7} }}}[/tex]

[tex]\qquad { \dashrightarrow \: { \sf{ y = \dfrac{18 - 9x}{7} }}}[/tex]

Therefore, the value of y = 18 – 9x/7 .

Which is equivalent to the following expression? (2x - 1)(x + 3)

Answers

Answer:

2x2+5x−3

Step-by-step explanation:

Expand the polynomial using the FOIL method.

3 2/3 + 2 3/5 + x = 8

Answers

Answer: x= [tex]-\frac {109}{15}[/tex]

A helicopter starting on the ground is rising directly
into the air at a rate of 25 ft/sec. You are running on the
ground starting directly under the helicopter at a rate of 10
ft/sec. What is the rate at which the distance between you and the helicopter is changing when the helicopter has risen to a height of 60 ft in the air, assuming that, initially, it was 30 ft above you?
I want to understand how any why this is solved. So images/diagrams, detailed step by step breakdowns solutions are VERY much appreciated. Thanks!

Answers

Answer:

Oook, quick setup: pick a cartesian plane, be [tex](0;y(t))[/tex]the position of the helicopter as time passes, and [tex](x(t);0)[/tex] your position as you start running. In my horrible sketch, the green line is the distance when you start running, the red line is the distance you need,  in general what you want is to move one end of the segment up, the other right, and stretch it.

That distance is easily found with the formula for the distance between two points in the plane, or [tex]d=\sqrt{(\Delta x)^2+(\Delta y)^2}= \sqrt{x^2(t)+y^2(t)}[/tex] (playing a bit with the squares). At this point we need to write down expressions for both [tex]x(t), y(t)[/tex] and find at what value of t we need to evaluate our distance.

For the sake of semplicity, let's start measuring times the moment you start running. Since speed is constant, both expressions will be of the form [tex]s=vt+s_0[/tex]

The equation for the runner becomes simply [tex]x(t)=10t[/tex], since you haven't moved until the heli is high enough.

The equation of the helicopter is [tex]y=25t+30[/tex] since the heli is 30ft above ground when you start running.

Finally, we need to know how many seconds have passed when the heli is at 60 ft above ground. that happens when [tex]60=25t+30 \rightarrow t=\frac{30}{25} = 1.20s[/tex]. in this time, you are at  [tex]x(1.2)=10(1.2)=12ft[/tex] from the origin.

Plugging it in the distance formula you get: [tex]\sqrt{12^2+60^2}= \sqrt{144+3600}=4\sqrt {234}\approx 61.2ft[/tex]

How many sides does the regular polygon have if each interior angle measure is four times the (1 point)

measure of each exterior angle measure?

Answers

Answer:

The exterior and interior angles must add up to 180 degrees. Thus, 180 divided by five gives the exterior angle as 36 degrees (and hence the interior angles as 144 degrees).

Answer:

10 Sides

Step-by-step explanation:

Int Angle + Ext Angle = 180

4Ext + Ext = 180

Ext = 36 degrees

-----

360/36 = 10 sides

Examine the figure. What is the measure of angle b?

Answers

Answer:

b =146

Step-by-step explanation:

34 and b form a straight line so they add to 180

b+34 = 180

b = 180-34

b =146

Determine the slope from the given graph below:

The slope is−17
The slope is 5
The slope is 7
The slope is -5

Answers

Answer:

The slope is positive 7

Step-by-step explanation:

The y-intercept is -5, and the next point going upwards is positive 2. (Sorry I'm bad at explaining)

Answer:

The slope is 7

Step-by-step explanation:

(1,2)(0,-5)

[tex]m=\frac{-5-2}{0-1} ==\frac{-7}{-1} =7[/tex]

Hope this helps

8. A company makes electronic components for TV's. 95% pass final inspection (and 5% fail and need to be fixed). 120 components are inspected in one day. (10 points) b.What is the variance of the number that pass inspection in one day

Answers

Using the binomial distribution, it is found that the variance of the number that pass inspection in one day is 5.7.

For each component, there are only two possible outcomes, either it passes inspection, or it does not. The probability of a component passing inspections is independent of any other component, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability, and has variance given by:

[tex]V(X) = np(1 - p)[/tex]

In this problem:

95% pass final inspection, hence [tex]p = 0.95[/tex]120 components are inspected in one day, hence [tex]n = 120[/tex].

The variance is given by:

[tex]V(X) = np(1 - p) = 120(0.95)(0.05) = 5.7[/tex]

The variance of the number that pass inspection in one day is 5.7.

To learn more about the binomial distribution, you can take a look at https://brainly.com/question/24863377

What is the quotient of the following division problem?
71= 2 = ?
O A. 37 11
B. 35r1
O C. 35r2
O D. 34 r1

Answers

Answer:

35 remainder 1

Step-by-step explanation:

71 ÷ 2 = 35.5

The 35 is the whole number part of your answer. The .5 part of the answer is .5 of 2, which is 1

OR you can think that

35 × 2 =70. The 1 is the remaining part from 71.

A rectangular garden is 24 feet wide. Its length is 4 feet more than twice the width. What is the area of the garden?

Answers

Answer:

1248

Step-by-step explanation:

w = 24feet

L=2w+4feet that means L= 2*24+4 =52

aera is 24*52=1248

Find an equation in the form y=ax^2+bx+c for the parabola passing through the points.
(3,25) (1,3) (-5,-15)
Thanks for the help! :)

Answers

Answer: [tex]x^2+7.0x-5.0x[/tex]

Step-by-step explanation:

Other Questions
5. Identify the type of function and the degree of the function: f(x)=6x +3x -11A. Quadratic, degree 3B. Quadratic, degree 2C. Cubic, degree 6D. Quartic, degree 11 Building a String LibrarySometimes when programming you need to introduce a new data type and develop a library of functions for manipulating instances of that data type. Often this is done as methods on a new class but not always.In this assignment, you'll be defining a collection of functions on strings, most of which already exist as methods on the str class. However, you should pretend that they don't already exist and define them as functions. Of course, you can't just use the existing methods. This will give you a bunch of practice on manipulating strings and also on defining functions.In this assignment, you'll be defining a collection of functions on strings. You should define each of these as a new function with a function header as below. The description of each is in the comment supplied. Recall that strings are immutable, so you will have to return a new copy of the string for those that call for you to return a string. If you are returning the same string as the input, just return it; there is no need to make a new copy, and it wouldn't anyway.The only string functions/methods to use:ord, chrindexing and slicingappend (i.e., ``+'')len, in, not inequality comparison (== or !=))Looping over strings (while or for loops) and selection (if statements) are allowed. BUT You cannot convert the strings to other types such as lists.Define each of the following functions, with semantics as indicated by the comment. In each of the following ch is a single character, str, str1, str2 are strings, and i is a non-negative integer. You do not have to validate the inputs, except as indicated; you can assume these types.At least one question asks you to return two values. That really means returning a tuple (pair) of values. You do that as follows: return value1, value2This actually returns the pair (value1, value2). The caller can then assign the members of the pair to two variables: x, y = pairReturningFunction() # assumes function returns a pair z, w = (value1, value2) # assigning a tuple to 2 variablesIf you like, you can use earlier functions in later ones, or define helper functions, though it shouldn't really be necessary. Note that some of these are trivial to write, while others are a bit harder. I have done the first one for you.def myAppend( str, ch ): # Return a new string that is like str but with # character ch added at the end return str + chdef myCount( str, ch ): # Return the number of times character ch appears # in str.def myExtend( str1, str2 ): # Return a new string that contains the elements of # str1 followed by the elements of str2, in the same # order they appear in str2.def myMin( str ): # Return the character in str with the lowest ASCII code. # If str is empty, print "Empty string: no min value" # and return None.def myInsert( str, i, ch ): # Return a new string like str except that ch has been # inserted at the ith position. I.e., the string is now # one character longer than before. Print "Invalid index" if # i is greater than the length of str and return None.def myPop( str, i ): # Return two results: # 1. a new string that is like str but with the ith # element removed; # 2. the value that was removed. # Print "Invalid index" if i is greater than or # equal to len(str), and return str unchanged and Nonedef myFind( str, ch ): # Return the index of the first (leftmost) occurrence of # ch in str, if any. Return -1 if ch does not occur in str.def myRFind( str, ch ): # Return the index of the last (rightmost) occurrence of # ch in str, if any. Return -1 if ch does not occur in str.def myRemove( str, ch ): # Return a new string with the first occurrence of ch # removed. If there is none, return str.def myRemoveAll( str, ch ): # Return a new string with all occurrences of ch. # removed. If there are none, return str.def myReverse( str ): # Return a new string like str but with the characters # in the reverse order. Expected output:>>> from MyStringFunctions import *>>> s1 = "abcd" >>> s2 = "efgh">>> myAppend( s1, "e" )'abcde'>>> myCount( s1, "e")0>>> myCount( s1, "a")1>>> myCount( "abcabc", "a")2>>> myExtend( s1, s2 )'abcdefgh'>>> myMin( "" )Empty string: no min value # Note the None doesn't print>>> myMin( "zqralm" )'a'>>> myMin( "Hello World!" )' '>>> myInsert( "abc", 0, "d")'dabc'>>> myInsert( "abc", 2, "d")'abdc'>>> myInsert( "abc", 4, "d") Invalid index # Note the None doesn't print>>> myPop( "abcd", 1 )('acd', 'b')>>> myPop( "abcd", 0 )('bcd', 'a')>>> myPop( "abcd", 5)Invalid index('abcd', None)>>> myFind( "abcdabcd", "a")0>>> myFind( "abcdabcd", "c")2>>> myFind( "abcdabcd", "f")-1>>> myRFind("abcdabcd", "d")7>>> myRFind("abcdabcd", "e")-1>>> myRemove( "abcdabcd", "a")'bcdabcd'>>> myRemove( "abcdabcd", "x")'abcdabcd'>>> myRemove( "abcdabcd", "d")'abcabcd'>>> myRemoveAll("abcabcabca", "a")'bcbcbc'>>> myReverse( "abcd" )'dcba'>>> myReverse( "" )'' if 240 slices of cake are shared into the same ration 3:5 among the boys and girls how many slices will each students recieve GCF and LCM: word problems. 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