.
Ms. Lady works-out with Ms. Beetle; her average
crawling time has increased to 4 feet per minute, while
Ms. Beetle, who is used to eating Hot Cheetos and
watching TV, averages 2.5 feet per minute. While at
Senn's Elm Tree-house, the three decide to experiment
with linear equations. The objective is to end up at the
Rose Bush at the same time. Senn still averages 5 feet per
minute. How much of a head start does he need to give
each of his friends in order for their function rules to
intersect at 92 feet (the rose bush). What is the equation
for each bug which makes their experiment successful?
Create a table and graph representing the situation.

Answer:

100,000

Step-by-step explanation:

89678 rounded to the nearest hundred thousand is 100,000.

Answer: 512/9 and 6,144/81

Step-by-step explanation:

The sequence is:

18, 24, 32, 128/3, ...

Now, is easy to see that it is not an arithmetic sequence, so we can jump to see if this is a geometric sequence.

To see this, we must see at the quotient of two consecutive numbers in the sequence, and that quotient must be the same for any pair of consecutive elements.

24/18 = 1.33...

32/24 = 1.33...

(128/3)/32 = 1.33....

The quotient is constant, then this is a geometric sequence.

Then we can write the n-th term as:

Aₙ = Aₙ₋₁*1.33...

And we first should write 1.33 in a way that is easier to use:

1.33... = 1 + 0.33...

The left side can be writen as:

0.33... = 0.33...*(10/10) = (3.3.../10)

Now we can subtract the initial number:

(3.33..../10) - 0.33... = 3/10 = 0.33...*(9/10)

0.33... = (3*10)/(9*10) = 30/90 = 3/9

then we have:

1.33... = (1 + 3/9) = (9/9 + 3/9) = (12/9)

Then the two next terms are:

(128/3)*(12/9) = 128*4/9 = (512/9)

And the next term is:

(512/9)*(12/9) = (6,144/81)

Then the first six terms are:

18, 24, 32, 128/3, 512/9, 6,144/81

Answer:8 pounds to make 20 apple pies

Answer:

24,840,000

Step-by-step explanation:

The number in the ten thousands place is 3.  The number to the right of it is 7.  Since 7 ≥ 5, we round up the 3 to a 4.

24,837,618 ≈ 24,840,000

Answer:

198 degrees

Step-by-step explanation:

Such a shape is called a 20-gon, such shapes have an interior angle of 162. Hence, the exterior angle = 360 (Complete angle) - 162 (The interior anlge) = 198 degrees, Hope my answer helps you, Thank you, and please add me as brainliest! Thanks

Answer:

Step-by-step explanation:

Such a shape is called a 20-gon, such shapes have an interior angle of 162. Hence, the exterior angle = 360 (Complete angle) - 162 (The interior anlge) = 198 degrees, Hope my answer helps you, Thank you, and please add me as brainliest! Thanks and Godbless

Answer:

$1672.68

Step-by-step explanation:

Answer:

1. See Explanation for Sample Space

2. [tex]P(10) = \frac{1}{12}[/tex]

3. [tex]P(6) = \frac{5}{36}[/tex]

Step-by-step explanation:

Given

Roll of Two die

Solving (1): The Sample Space

Represent the first dice with S1 and the second with S2

[tex]S_1 = \{1,2,3,4,5,6\}[/tex]

[tex]S_2 = \{1,2,3,4,5,6\}[/tex]

The sample space of both die is:

[tex]S = (1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)[/tex][tex](4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(55,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)}\}[/tex]

Solving (2): Probability of Sum being 10

First, we need to add the outcome of each roll in (1) above:

[tex]S = \{2,3,4,5,6,7, 3,4,5,6,7,8, 4,5,6,7,8,9, 5,6,7,8,9,10, 6,7,8,9,10,11 7,8,9,10,11,12\}[/tex][tex]n(S) = 36[/tex]

[tex]n(10) = 3[/tex]

The required probability is:

[tex]P(10)= \frac{3}{36}[/tex]

[tex]P(10) = \frac{1}{12}[/tex]

Solving (3): Probability of Sum being 6

[tex]n(S) = 36[/tex]

[tex]n(6) = 5[/tex]

The required probability is:

[tex]P(6) = \frac{5}{36}[/tex]

Answer:

1:00 PM

Step-by-step explanation:

1500 hours is 3 PM. 3-2 = 1 So that would be 1 o'clock PM.

Answer:

175°

Step-by-step explanation:

Since, [tex] \overrightarrow{BD} [/tex] is in the interior of [tex] \angle ABC[/tex]

[tex] \therefore m\angle ABC = m\angle ABD + m\angle CBD\\

\therefore (14x + 21)\degree = (2x + 3)\degree + 150\degree \\

\therefore (14x + 21)\degree = (2x + 153)\degree\\

\therefore 14x + 21 = 2x + 153\\

\therefore 14x - 2x = 153 - 21\\

\therefore 12x = 132\\

\therefore x = \frac{132}{12}\\

\therefore x = 11\\\\

m\angle ABC = (14x + 21)\degree\\

m\angle ABC = (14\times 11+ 21)\degree\\

m\angle ABC = (154+ 21)\degree\\

\huge\red {\boxed {m\angle ABC = 175\degree}} \\[/tex]

Answer:

x=1+√334, x=1−√334

Step-by-step explanation:

ANSWER is C on edge for those of you looking

Step-by-step explanation:

Answer:

she would run 6.4 miles in 48 min

Step-by-step explanation:

hope it helps

Answer:

Yes it is.

Step-by-step explanation:

-(5/12) = -*5/12 = -5/12

5/-12 = -5/12

Best of Luck!

Answer:

36 units^2

Step-by-step explanation:

The area of a triangle is 1/2*base*height. Knowing this is just 2 triangles means you solve for 1 triangle, then multiply that by 2

Answer:

[tex]A=36\text{ units}^2[/tex]

Step-by-step explanation:

The area of a rhombus is given by the formula:

[tex]A=\frac{d_1\cdot d_2}{2}[/tex]

Namely, it is half of one diagonal multiplied by the other diagonal.

So, to find the area, we just need to find the length of AC and BD, multiply them together, and then divide by 2.

To find their lengths, we can use the distance formula. The distance formula is:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]

So, let's find the lengths of each diagonal:

AC:

Point A is (-1,0) and Point C is (-1,-6). Let (-1,0) be (x₁, y₁) and let (-1,-6) be (x₂, y₂). Substitute this into our formula:

[tex]d=\sqrt{(-1-(-1))^2+(-6-0)^2[/tex]

Simplify:

[tex]d=\sqrt{(-1+1)^2+(-6-0)^2[/tex]

Add or subtract:

[tex]d=\sqrt{(0)^2+(-6)^2[/tex]

Square:

[tex]d=\sqrt{36}[/tex]

Take the square root:

[tex]d=6[/tex]

So, the length of diagonal AC is 6.

BD:

Point B is at (5,-3) and Point D is at (-7,-3). Let (5,-3) be (x₁, y₁) and let (-7,-3) be (x₂, y₂). Substitute this into our formula:

[tex]d=\sqrt{(-7-5)^2+(-3-(-3))^2[/tex]

Simplify:

[tex]d=\sqrt{(-7-5)^2+(-3+3)^2[/tex]

Add or subtract:

[tex]d=\sqrt{(-12)^2+(0)^2[/tex]

Square:

[tex]d=\sqrt{144}[/tex]

Take the square root:

[tex]d=12[/tex]

So, our second diagonal is 12 units long.

Now, to find the area, substitute 6 and 12 into our formula. So:

[tex]A=\frac{d_1\cdot d_2}{2}[/tex]

Substitute 6 for d₁ and 12 for d₂. So:

[tex]A=\frac{(6)(12)}{2}[/tex]

Multiply:

[tex]A=\frac{72}{2}[/tex]

Divide:

[tex]A=36\text{ units}^2[/tex]

So, the area of the rhombus is 36 squared units.

And we're done!

Notes:

Of course, instead of using the distance formula, you can also just count :)

Answer:

34

Step-by-step explanation:

b+115°+31°= 180° (sumof all angles of triangle)

b=146°-180°

b=34°

hope it helps you!

steffie matt

I think the question is incorrect please repeat again.....

28x + 44y = 964.40

21x + 33y = 723.30

Let's multiply the first equation by 4 and the second by -4

84x + 176y = 3857.6

-84x - 132y = -2893.2

Add the equations together.

0 + 44y = 964.4

Simplify

44y = 964.4

Divide both sides by 44

y = 964.4/44

Since we have the value of y, let's plug 964.4/44 into y for the first equation.

28x + 44(964.4/44) = 964.40

Simplify the left side

28x + 964.4 = 964.4

Subtract 964.4 from both sides

28x = 0

Divide both sides by 0

x = 0

In conclusion,

y = 964.4/44

x = 0

Answer: 13.71

Step-by-step explanation:

20+6+17+10+19+15+9=96

96/7=13.71

Answer:

3

Step-by-step explanation:

Each of the lines lengths multiply by 3.

Answer: 8/15

Step-by-step explanation: find the LCD which is 15 in this case,  then multiply 1/3 by 5/5 which equals 5/15. then multiply 1/5 by 3/3 which equals 3/15 then add them together =8/15

Answer:

= -2

-7(5+3)+216/4

-7(8)+216/4

-56+54

= -2

Answer:

[tex]B(x_2,y_2)= (20,12)[/tex]

Step-by-step explanation:

Given

[tex]A = (0,0)[/tex]

[tex]Ratio; m : n = 1 : 3[/tex]

[tex]Point\ at\ 1 : 3 = (5,3)[/tex]

Required

Coordinates of B

This question will be answered using line ratio formula;

[tex](x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})[/tex]

In this case:

[tex](x,y) = (5,3)[/tex]

[tex](x_1,y_1) = (0,0)[/tex]

[tex]m : n = 1 : 3[/tex]

Solving for [tex](x_2,y_2)[/tex]

[tex](x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})[/tex] becomes

[tex](5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})[/tex]

[tex](5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})[/tex]

[tex](5,3) = (\frac{x_2}{4},\frac{y_2}{4})[/tex]

Comparing the right hand side to the left;

[tex]\frac{x_2}{4} = 5[/tex] -- (1)

[tex]\frac{y_2}{4} = 3[/tex] -- (2)

Solving (1)

[tex]x_2 = 5 * 4[/tex]

[tex]x_2 = 20[/tex]

Solving (2)

[tex]y_2 = 3 * 4[/tex]

[tex]y_2 = 12[/tex]

Hence;

[tex]B(x_2,y_2)= (20,12)[/tex]

Answer:

The area of the surface over R is [tex]\mathbf{ 2 \sqrt{17} + \dfrac{1}{2} \ In ( \sqrt{17} +4)}[/tex]

Step-by-step explanation:

From this study,

The surface area of f(x,y) is expressed by:

[tex]A = \iint_R \sqrt{1 +f^2_x+f^2_y}} \ dA[/tex]

where

[tex]0 \leq x \leq 2 \ and \ 0 \leq y \leq 2[/tex]

Given that:

f(x,y) = 9 - x²

Thus, [tex]f_x = -2x[/tex] and   [tex]f_y = 0[/tex]

However, the area becomes:

[tex]A = \iint_R \sqrt{1+(-2x)^2+0^2} \ dxdy[/tex]

[tex]A = \iint_R \sqrt{1+4x^2} \ dxdy[/tex]

From above, replacing x with [tex]\dfrac{1}{2} \ tan \ u[/tex]

then [tex]dx = \dfrac{1}{2} sec^2 \ udu[/tex]

∴

[tex]\sqrt{1 + 4x^2 } \ dA= \dfrac{1}{2} \iint \sqrt{1 + 4u^2 } \ sec^2 \ udu[/tex]

[tex]\sqrt{1 + 4x^2 } \ dA= \dfrac{1}{2} \iint sec^2 \ udu[/tex]

[tex]\sqrt{1 + 4x^2 } \ dA= \dfrac{1}{2} ( \sqrt{4x^2 + 1x} + \dfrac{1}{2} In \sqrt{4x^2 + 1}+2x)[/tex]

Hence;

[tex]\mathsf{A = \int \limits ^2_0 \begin {bmatrix} \dfrac{1}{2}(\sqrt{4x^2 +1 x}+ \dfrac{1}{2} In ( \sqrt{4x^2+1}+2x \end {bmatrix}^2_0 \ dy}[/tex]

[tex]\mathbf{A = 2 \sqrt{17} + \dfrac{1}{2} \ In ( \sqrt{17} +4)}[/tex]

Therefore, the area of the surface over R is [tex]\mathbf{ 2 \sqrt{17} + \dfrac{1}{2} \ In ( \sqrt{17} +4)}[/tex]

Answer:

16

Step-by-step explanation:

The mean of a group of values is calculated as

mean = [tex]\frac{sum}{count}[/tex]

Given 5 numbers with a mean of 12, then

[tex]\frac{sum}{5}[/tex] = 12 ( multiply both sides by 5 )

sum = 60

let the number removed be x , then

[tex]\frac{60-x}{4}[/tex] = 11 ( multiply both sides by 4 )

60 - x = 44 ( subtract 60 from both sides )

- x = - 16 ( multiply both sides by - 1 )

x = 16

The number removed was 16

Answer:

please put the full question

x = some unknown number

x+8 = sum of the number and 8

2(x+8) = product of 2 and the sum of a number and 8

Answer:

b

Step-by-step explanation:

Answer:

B

Step-by-step explanation: