Jim makes a mixture which contains 10 mg of salt, 30 mg of sand, and some iron filings. The total mass of the mixture is 100 mg
Which amount of iron filings does Jim use in the mixture?
A10
B30
C40
D60

Answers

Answer 1

Answer:

Amount of iron fillings in mixture = 60 mg

Explanation:

Given:

Total mass of mixture = 100 mg

Amount of salt in mixture = 10 mg

Amount of sand in mixture = 30 mg

Find:

Amount of iron fillings in mixture

Computation:

Using Law of Conservation of mass;

Total mass of mixture = Amount of salt in mixture + Amount of sand in mixture + Amount of iron fillings in mixture

100 = 10 + 30 + Amount of iron fillings in mixture

100 = 40 + Amount of iron fillings in mixture

Amount of iron fillings in mixture = 100 - 40

Amount of iron fillings in mixture = 60 mg


Related Questions

When sodium chloride is dissolved in water, the freezing point of water _________. A. increases B. first increases, then decreases C. does not change D. decreases

Answers

The answer is D; it decreases as there are now foreign particles in the water that disperse the water molecules pushing them apart and making it harder for ice to form properly

The presence of a non-volatile salt will decrease the freezing point of water and this process is called depression in freezing point. Thus option D is correct.

What is freezing point?

Freezing point of a substance is the temperature at which it converts from its liquid state to solid state where, both the states are in equilibrium. Freezing point of water is zero degree celsius.

The freezing point of a solvent depends on some parameters such as the bond type, molecular weight, temperature, pressure etc.

When a non-volatile solute is added to the solvent its freezing point decreases from its initial value. Because presence of non-volatile salts will affect the intermolecular attraction and thereby the energy that must be applied to freeze the compound.

Therefore, the freezing point of water decreases, when sodium chloride is added into it. Thus option D is correct.

To find more about freezing point, refer the link below;

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PLEASE HELP!! NO LINKS PLEASE REAL ANSWER!!!!!
What will be volume of 20.0 g of CH4 gas at a pressure of 0.950 atm and temperature of 21.0 oc?Question 1 options:

A. 21.8 L
B. 31.8 L
C. 2.27 L
D. 4.27 L

Answers

The answer is (C) or (D)

The volume of a sample of carbon dioxide gas is 26.42 L at 73.0°C. What will its volume be at 92.0°C at constant pressure?

Answers

Answer:

[tex]V_2=27.87L[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the Charles' law a directly proportional relationship to understand the volume-temperature behavior:

[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]

Thus, we solve for the final volume, V2, and make sure the temperature are in Kelvin as shown below:

[tex]V_2 =\frac{V_1T_2}{T_1} \\\\V_2=\frac{26.42L(92+273.15)K}{(73+273.15)K} \\\\V_2=27.87L[/tex]

Regards!

3. At 34.0°C, the pressure inside a nitrogen-filled tennis ball with a volume of 148 cm3 is 212
kPa. How many moles of N2 are in the tennis ball?

Answers

Answer:

0.0123 mol

Explanation:

Step 1: Convert 34.0 °C to Kelvin

We will use the following expression.

K = °C + 273.15 = 34.0 + 273.15 = 307.2 K

Step 2: Convert 148 cm³ to L

We will use the conversion factors:

1 cm³ = 1 mL1 L = 1000 mL

[tex]148cm^{3} \times \frac{1mL}{1cm^{3}} \times \frac{1L}{1000mL} = 0.148L[/tex]

Step 3: Convert 212 kPa to atm

We will use the conversion factor 1 atm = 101.325 kPa.

212 kPa × 1 atm / 101.325 kPa = 2.09 atm

Step 4: Calculate the moles of nitrogen gas

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 2.09 atm × 0.148 L / (0.0821 atm.L/mol.K) × 307.2 K = 0.0123 mol

Observe the above circuit diagram, if the gap is filled with a plastic wire, will the bulb glow? Justify your answer

Answers

Answer:

YES THE BULB WILL GLOW.

Explanation:

BECAUSE THE CIRCUIT UPPER AREA IS MADE OF PLASTIC SO THE PLASTIC CONDUCTS THE ELECTRICITY SO THE BULB WILL GLOW.

True or False: Both molecules and compounds are pure substances.

Answers

Answer:

False

Explanation:

Hope this helps!

Answer:

True

Explanation:

It's because both compounds and elements are considered pure substances and a molecules is considered an element.

What is the initial and final mass of the zinc and copper?

Answers

Answer:the final mass of copper is  3.84 g. There was an increase in mass of 1.84 g from the initial mass of 2.0 g.

Explanation:

Show your work. 37.2 moles CO2 to oxygen atoms.

Answers

4 moles of oxygen (6.0zzx10

To obtain pure lead, lead (II) sulfide is burned in an atmosphere of pure oxygen. The products of the reaction are lead and sulfur trioxide (SO3). Write a balanced chemical equation for this process. How many grams of lead will be produced if 2.54 grams of PbS is burned with 1.88 g of O2? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer. (Hint: be sure to work the problem with both PbS and O2).

Answers

Answer: 2.20 g Pb

They gave us the masses of two reactants and asked us to determine the mass of the product. We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:       239.27   32.00        207.2

           2PbS   +   3O₂   ⟶  2Pb   +   2SO₃

m/g:      2.54        1.88

1. Watch how the solubility of a gas changes as pressure is increased and then decreased during the run. Which of the following statements correctly explain the relationship between the solubility of a gas and its pressure?
A. As pressure decreases, the concentration of gas molecules in the solution increases.
B. The concentration of gas particles in the solution is higher at 4.25 atm than at 1.00 atm.
C. The solubility of a gas decreases with a decrease in pressure.
D. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm.
E. Fewer gas molecules are soluble at higher pressures.
F. More gas molecules are soluble as pressure is increased.
G. As pressure is increased, the rate at which gas molecules enter the solution decreases.
2. At a certain temperature, the solubility of N2 gas in water at 3.08 atm is72.5mg of N2 gas/100 g water. Calculate the solubility of N2 gas in water, at the same temperature, if the partial pressure of N2 gas over the solution is increased from 3.08 atm to 8.00 atm .

Answers

Answer:

A. As pressure decreases, the concentration of gas molecules in the solution increases.

D. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm.

F. More gas molecules are soluble as pressure is increased.

The solubility is 188.3 mg of N2 gas/100 g water.

Explanation:

As the pressure on the gas decreases, the volume of gas molecules in the solution increases due to having distance from each other. The solubility of nitrogen gas at 2.00 atm is twice the solubility of the gas at 1.00 atm because there is more pressure on the gas molecules so due to more compression, the gas becomes more soluble. More gas molecules are soluble as pressure is increased. The solubility is 188.3 mg of N2 gas/100 g water if the atmospheric pressure is increases from 3.08 atm to 8.00 atm. This value is calculated with the help of formula i.e. P2/P1 = S2/S1.

determine the maximum amount of NaN03 that was produced during the experiment. Explain how you determined the amount

Answers

Answer:

9 moles of NaNO3 is obtained

Explanation:

The balanced chemical reaction equation for the reaction is;

Al(NO3)3 + 3NaCl-------> 3NaNO3 + AlCl3

Now, we have to determine the limiting reactant. The limiting reactant yields the least amount of NaNO3.

1 mole of Al(NO3)3 yields 3 moles of NaNO3

4 moles of Al(NO3)3 yields 4 * 3/1 = 12 moles of NaNO3

Also,

3 moles of NaCl yields 3 moles of NaNO3

9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO3

Hence, NaCl  is the limiting reactant and 9 moles of NaNO3 is obtained.

9 moles of NaNO₃ is obtained.

Balanced chemical reaction:

[tex]Al(NO_3)_3 + 3NaCl-----> 3NaNO_3 + AlCl_3[/tex]

From the reaction, it is seen that the limiting reactant yields the least amount of NaNO₃.

1 mole of Al(NO₃)₃ yields 3 moles of NaNO₃

4 moles of Al(NO₃)₃ yields 4 * 3/1 = 12 moles of NaNO₃

Also,

3 moles of NaCl yields 3 moles of NaNO₃

9 moles of NaCl yields 9 * 3/3 = 9 moles of NaNO₃

Hence, NaCl  is the limiting reactant and 9 moles of NaNO₃ is obtained.

Find more information about Balanced chemical reaction here:

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Acts as the digestive system inside a cell. It helps to break down old or unneeded parts of the cell, and substances that have been brought into the cell from the outside. WHO I AM?

Answers

Answer:

I think it is enzymes

Explanation:

Why do scientist conduct experiments on animals?

Answers

Answer:

Animals are used in scientific research to help us understand our own bodies and how they work. This is necessary to develop new medicines. Animals are also used to safety test potential medicines before they are tested in people and to check the safety of other chemicals.

Explanation:

What is the molarity of a solution?



the answer is The number of moles of a solute per kilogram of solvent

Answers

Molar concentration is a measure of the concentration of a chemical species, in particular of a solute in a solution, in terms of amount of substance per unit volume of solution.



Read about reverse osmosis and multistage flash distillation .Then identify at least three advantages and three

disadvantages for each process

Answers

Answer:

Meaning, Advantages & Disadvantages of - Osmosis, Multiflash Distillatiob

Explanation:

Osmosis is movement of solvent (like water) through semi permeable membrane (like living cell) into solution of higher solute concentration.

Advantages - It assists equalising concentration of solute on two sides of membrane. Reverse Osmosis is used for efficient water softening, it is easy to maintain.

Disadvantages - It needs a lot of energy. A lot of pressure is required for deionisation. Water acidity level increases, as minerals get deionised.

Multistage flash distillation refers to desalination water distilling seawater, by flashing water portions in steams in various stages of concurrent heat exchangers.

Advantages - Its Cost efficient , distillation uses waste heat. It has High gain output ratio. Quality of feedwater is less significant, compared to reverse osmosis.

Disadvantages - It has high operating cost in case of waste heat unavailability. High temperature imply high corrosion & scale formation.

In the area with a large population of valuable ocean organisms is called a(n)

Answers

Answer:

fishery

An area with a large population of valuable ocean organisms is called a fishery. If it was correct mark me as brainiest

State the number of neutrons in an atom of Ne-20 and the number of neutrons in an atom of Ne-22. choose two answers * 1 point Ne 20: 10 Ne 20: 11 Ne 22: 12 Ne 22: 13

Answers

Answer:

Ne 20: 10

and

Ne 22: 12

Explanation:

Ne-20:

N = A - Z = 20 - 10 = 10 neutrons

Ne-22:

N = A - Z = 22 - 10 = 12 neutrons

N: number of neutrons

A: mass number

Z: atomic number

How many grams water will condense when 56,500 joules of energy is removed from steam at its boiling point

Answers

Answer:

Start your streak by answering any question. You'll get bonus points from day 2.

Calculate the specific heat of a substance given that 49 joules of heat is required to raise the temperature of 25.0 g of the substance from 92.6 ºC to 99.4 ºC.

Answers

Answer:

0.29 J/g.°C

Explanation:

Step 1: Given data

Added heat (Q): 49 JMass of the substance (m): 25.0 gInitial temperature: 92.6 °CFinal temperature: 99.4 °C

Step 2: Calculate the temperature change (ΔT)

ΔT = 99.4 °C - 92.6 °C = 6.8 °C

Step 3: Calculate the specific heat of the substance (c)

We will use the following expression.

Q = c × m × ΔT

c = Q / m × ΔT

c = 49 J / 25.0 g × 6.8 °C = 0.29 J/g.°C

Given the reaction: N2(g) +2O2(g) ⇌ 2NO2(g) The forward reaction is endothermic. Determine which of the following changes would result in more product being produced.


I. Increase NO2
II. Decrease O2
III. Add a catalyst
IV. Increase the temperature
V. Increase the pressure

A. I and II
B. II, III, and V
C. IV and V
D. II and IV

Answers

Answer:

C

Explanation:

increasing the temperature will favour the forward reaction therefore the reaction system will try to counteract that by producing more heat and NO2 therefore increases the amount of products produced

increasing the pressure will favour the forward reaction as it has more moles of substance therefore if the forward reaction is favored, more product will be produced

Answer:

C.) lV and V

Explanation:

I got it correct on founders edtell

2+4 help please i will fail 6th grade

Answers

Answer:

6

Explanation:

lol

Help solve the types of chemical reactions

Answers

[tex]1) \: decomposition[/tex]

[tex]2) \:hydrocarbon \: combustion[/tex]

[tex]3) \: formation[/tex]

[tex]4) \: double - replacement[/tex]

[tex]5 \: double - replacement[/tex]

[tex]6) \: formation[/tex]

[tex]7)double \: - replacement[/tex]

[tex]8) \: double - replacement[/tex]

Determine which base will work to deprotonate each compound in an acid/base extraction.

Benzene ring with a carboxylic acid on one carbon and a methyl ester group on the opposite carbon __________
Benzene ring with a three carbon chain attached to one carbon. At the other end of the three carbon chain is a hydroxyl group. ___________
Benzene ring with a hydroxyl group attached to one carbon and a tertbutyl group attached to the opposite carbon __________-

Answers

Answer:

A common method is to perform an acid-base reaction, which can ... acid is not particularly water-soluble due to its nonpolar aromatic ring, ... An acid-base extraction can be used to extract carboxylic acids from ... carbonic acid (H2CO3) can decompose to water and carbon dioxide gas.

Explanation:

The bases that will work to deprotonate the compounds are :

NaHCO₃ or NaOH.metal alkoxidesNaOH

The Benzene ring with carboxylic acid which is a weak acid can be deprotonated using NaOH or NaHCO₃ because of the weakness of the carboxylic acid.

Metal alkoxides like potassium tertiary butoxide can be used to deprotonate a Benzene ring with three carbon chain attached to a single carbon, and also containing a hydroxyl group  is a very weak acid hence the use of Metal alkoxides.

Benzene ring with a hydroxyl group attached  is also a weak acid just like the Benzene ring with carboxylic group hence it can also be deprotonated using NaOH

Learn more : https://brainly.com/question/24664427

What answer is it and how ? please help !!!!!! ill mark brainlyest if right

Answers

Answer:

The answer is B

Brainliest please!

A balloon is inflated with 1.25 L of helium at a temperature of 298K. What is
the volume of the balloon when the temperature is 310K?

Answers

Answer:

What is

the volume of the balloon when the temperature is 310K?

Which best describes the total mass of substances before and after a
combustion reaction?
A. The mass is the same because atoms are not created or
destroyed.
B. The mass is greater after the reaction because the number of
atoms increases.
C. The mass is the same because the molecules do not change.
D. The mass is less after the reaction because gases are produced.

Answers

Answer:

B. The mass is greater after the reaction because the number of

atoms increases.

What volume is occupied by 2.0 mol of gas at 3.0 atm
and 27 °C?

Answers

STP conditions imply a temperature of 273.15 K and a pressure of 100 kPa. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. Likewise, 0.5 moles will occupy half the volume 1 mole occupies.

A helium-filled balloon contains 0.16 mol He at 101 kPa and a temperature of 23°C. What is
the volume of the gas in the balloon?

Answers

V = 3.9 L

Explanation:

Given:

T = 23°C + 273 = 296K

n = 0.16 mol He

P = 101 kPa = 0.997 atm

R = universal gas constant = 0.08205 L-atm/mol-K

V = ?

Using the ideal gas law,

PV = nRT

V = nRT/P

= (0.16 mil He)(0.08205 L-atm/mol-K)(296K)/(0.997 atm)

= 3.9 L

How many moles of ammonia would be required to react exactly with 0.554 moles of copper(II) oxide in the following in chemical reaction? 2 NH3(g) + 3 CuO(s)= 3Cu(s) + N2(g) + 3 H2O(g)

Answers

The mole of ammonia in this chemical equation is 0.36933 moles of NH3... I hope it helped? :)

2x²=8.pls help me i really need it​

Answers

Explanation:

2x²=8

x²=8/2

x=√4

x=2

hope it helps.

Answer:

[tex]\huge \fbox \pink {A}\huge \fbox \green {n}\huge \fbox \blue {s}\huge \fbox \red {w}\huge \fbox \purple {e}\huge \fbox \orange {r}[/tex]

[tex] {2x}^{2} = 8 \\ {x}^{2} = \frac{8}{2} \\ {x}^{2} = 4 \\ x = \sqrt{4} \\ x = 2[/tex]

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

[tex] \huge\purple{ \mid{ \underline{ \overline{ \tt ꧁❣ ʀᴀɪɴʙᴏᴡˢᵃˡᵗ2²2² ࿐ }} \mid}}[/tex]

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